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Water Balance

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Cyril Mahumoc
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0% found this document useful (0 votes)
22 views6 pages

Water Balance

Uploaded by

Cyril Mahumoc
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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ontinues.

Precipitation
Precipitation

transpiration
Interception

Detention
Infiltration storage Depression
storage Overland Evaporation
Percolation flow
Capillary rise

Groundwater Table Subsurface flow


Sea
Groundwater storage
Channel
storage
Fig 1.1 The Hydrologic Cycle

The Water Balance Concept


Air Moisture Above Land

Transpiration Precipitation Evaporation

Interception

Depression/Detention

Overland Flow
Infiltration

Subsurface Channel Storage


Moisture Storage flow

Capillary Rise Percolation Seepage


Influent (+), Surface
Effluent (-) Runoff

Groundwater Storage

Symbols

Ocean Storage
Storage

Process
N

O1

O2

The catchment area increases as the outlet is moved downstream. For outlet O 1 the catchment boundary is O1MNPO1
and for outlet O2 the boundary is O2MNPO2.
Hall (1996)
Clear Lake has a surface area of 708 000 m2. For the month of March, this lake had an inflow of 1.5
m3/sec and an outflow of 1.25 m3/sec. A storage change of +708 000 m3 was recorded. If the total
depth of rainfall recorded at the local raingauge was 225 mm for the month, estimate the combined
evaporation and percolation losses from the lake. State any assumptions that you make in your
calculations.

P E
Qi
Q
Gi o
Pe G
rc o
P + Qi – (E+Perc) – Qo = V(f)- V(i)

(E+Perc) =P + Qi– Qo - [V(f)- V(i)]


m
P 225mm( )(708000m 2 ) 159300m 3 / mos
1000mm
m3 s day
Qi 1.5 (86400 )(31 ) 4017600m3 / mos
s day mos
m3 s day
Qo 1.25 (86400 )(31 ) 3348000m3 / mos
s day mos
S
V ( f )  V (i )  708000m 3 / mos
t
Therefore : ( E  Perc ) 159300  4017600  3348000  708000
m3
( E  Perc ) 120900
mo

or (E+Perc)=171 mm over the lake.

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