\[\mathsf{Q}^{\mu}_{\nu}\left(0\right)=-\frac{2^{\mu-1}\pi^{1/2}\sin\left(\frac{%
1}{2}(\nu+\mu)\pi\right)\Gamma\left(\frac{1}{2}\nu+\frac{1}{2}\mu+\frac{1}{2}%
\right)}{\Gamma\left(\frac{1}{2}\nu-\frac{1}{2}\mu+1\right)},\]