\[\frac{\mathrm{d}c^{\prime}}{\mathrm{d}\nu}=\frac{2c^{\prime}}{{c^{\prime}}^{2}%
-\nu^{2}}\*\int_{0}^{\infty}({c^{\prime}}^{2}\cosh\left(2t\right)-\nu^{2})\*K_%
{0}\left(2c^{\prime}\sinh t\right)e^{-2\nu t}\,\mathrm{d}t,\]