\[\dfrac{2}{\pi^{2}}\int_{0}^{2\pi}\dfrac{\cos t\sin t\operatorname{me}_{\nu}%
\left(t,h^{2}\right)\operatorname{me}_{-\nu-2m}\left(t,h^{2}\right)}{{\sinh}^{%
2}z+{\sin}^{2}t}\,\mathrm{d}t=(-1)^{m}\mathrm{i}\gamma_{\nu,m}\operatorname{D}%
_{0}\left(\nu,\nu+2m,z\right),\]