Duplicated with #117

You can use read method for the purpose. please see API document
https://py7zr.readthedocs.io/en/latest/api.html#py7zr.SevenZipFile.read

Here is sample code.

targets = ['siivagunner_pages_current.xml']
with SevenZipFile('siivagunner_pages_current.xml.7z', 'r') as zip:
     for fname, bio in zip.read(targets).items():
         print(bio.read())

Thanks for the example @miurahr

If my targets are text files, should I made further conversions to the output of bio.read()?
When using print(bio.read()) I see a b' at their beginning i.e.
b'my text file content
where I would expect
my text file content

Also, regarding your linked example code in documentation:

filter_pattern = re.compile(r'scripts.*')
with SevenZipFile('archive.7z', 'r') as zip:
     allfiles = zip.getnames()
     targets = [f for f in allfiles if filter_pattern.match(f)]
with SevenZipFile('archive.7z', 'r') as zip:  # <--- why this line? do we need to close and reopen?
     for fname, bio in zip.read(targets).items():
         print(f'{fname}: {bio.read(10)}...')

Are we opening the compressed file twice?
Wouldn't it work the same if we put the for inside the first with?

Sorry if these are pretty basic python questions, non py7zr related. But just in case

Thanks
@abubelinha

Bing chat answered

When you use bio.read(), it returns a bytes object. The b' at the beginning of the output indicates that it is a bytes object. If you want to convert it to a string, you can use the .decode() method. For example, bio.read().decode() will return the string without the b' at the beginning.