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DUCTING DESIGN
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EQUAL FRICTION METHOD EXAMPLE
Duct system for general office ;
Total air quantity
18 air terminals
Operating pressure for all terminals
Radius elbows
5400 cfm
300 cfm each
-0.15 in.wg
R/D = 1.25
Find ;
1. Initial duct velocity, area, size and friction rate in the duct
2. Total equivalent length of duct run, with highest resistance
3. Total static pressure required at Fan discharge
DUCT LAYOUT
SELECT AN INITIAL VELOCITY
RECOMMENDED MAX DUCT VELOCITIES FOR LOW VELOCITY SYSTEMS
 Velocity dipilih 1700 fpm
 Duct area : 5400 cfm/1700 fpm
= 3.18 sq.ft
Duct size (TABLE 6)
 Duct size : 22 in x 22 in
Circular equiv. diameter
Initial friction rate
 Friction rate ; 0.145 in wg per 100 ft of
eauivalent length
Percent section area in branches
 Percent of cfm = air quantity in duct
section/ total air quantity
 It appears that the duct run from the Fan
to terminal 18 has the highest resistance
Friction of rectangular Elbow
 The total friction loss in the ductwork frfom
the Fan to terminal 18 :
 Loss
= total equiv length x friction rate
= 229 ft x (0.145/100 ft)
= 0.332 in. wg
Total pressure at Fan Discharge
 The sum of the terminal operating
pressure and the loss in the ductwork
 0.332 in. wg + 0.15 in.wg = 0.482 in.wg
Friction losses