B+G+20 RESIDENTIAL BUILDING, KOLKATA
PLUMBING
I. SWIMMING POOL
1. Balancing Tank Sizing
Area:
Swimming Pool = 102.1 m2
Volume:
= 102.1m2 x 1.5m (Approximately. Ht 1.5m)
= 153.15m3
Bathing Loads:
< 1.5 m deep : 1.394 m2/person
> 1.5 m deep : 1.819 m2/person
Total number of bathers = 75 Persons
Amount of Displaced Water = Wave Displacement + Bather Displacement
a. Wave Displacement = Pool Area x 0.02 m
= 102.1 x 0.02 m
= 2.04 m3
b. Bather Displacement = No. of bathers x 0.05 m3/p
= 75 x 0.05 m3/p
= 3.75 m3
Total Required Volume = 2.04 + 3.75
= 5.79 m3
+ 10% = 6.34 m3
Balancing Tank = (3.0 x 1.5 x 1.5 Depth)
2. Filter Calculation
Total Volume = 153.15 m3
Turnover Rates:
Pool = 6 hrs.
153.15 m3
Total Q =
6 hr
= 25.53 m3/hr
= 425.5 L/min
Say 425.5 L/min (112.4 GPM)
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B+G+20 RESIDENTIAL BUILDING, KOLKATA
PLUMBING
Using 4-pump systems
(3-nos. pump duty; 1-no. standby)
Filter Pump = 141.83 L/min (37.47 GPM)
≈ 8.51 m3/h
Compute for TDH
1.Min.Residual - 15 psi. 34.65 ft.
2.Diff.Pressure - 20 psi. 46.20 ft.
3.Static Head - 4m 13.12 ft.
4.Head Loss due to friction -
4.1 Length of pipe 100m. - 328 ft.
4.2 Fittings – Ø 100 pipe
Quantity Head Loss Sub-Total
(ft)
Elbows 8 14 112
Tee 12 21 252
Gate Valve 7 2.7 18.9
Check Valve 3 22 66
448.90 ft
Friction Head loss Rate = 42.28 ft/1000 ft = 0.04
Total losses at piping = 328 + 448.90 = 776.90 ft
Head loss due to friction = 776.90 x 0.04 = 31.08 ft
TDH = 125.05 ft ≈ 54.13 psi
3.73 bar
Hp 56.2 gpm (125.05 ft)
=
3960 x 0.55
= 7027.81
2,178.00
Hp = 3.23
Based on filter capacity of 37.07 m3/hr/m2
540 gpm
=
158.849 gpm/m2
= 3.40m2 (36.60ft2)
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B+G+20 RESIDENTIAL BUILDING, KOLKATA
PLUMBING
Based on hi-rate filter having an area of 43.0 ft 2
36.60ft2
=
43.0
= 0.851ft2
say = 2.0 nos. 1 filter + 1 spare
3. Back Wash Tank
Vol. = Backwash rate in gpm/ft2 x area of filter in ft2 5 min.
= (20.0 gpm/ft2) (20.0ft2) (5min.)
= 2000 gals
≈ 7.57 m3 (2.5 x 2.1 x 1.5m D)
4. Chlorination
1 lb. of chlorine per 10,000 gals of pool water every 8 hours
Volume of Pool = 153.15 m3
Chlorination ≈ 40457.95gals.
40457.95gals
Chlorination ≈
10,000 gals/1 lb. Chlorine
= 4.05 lbs/8 hrs.
= 0.51 lbs/hrs x 24 hrs/day
= 12.24 lbs/day
Say = 12.5 lbs/day
Assume 5% strength of solution
Chemical
5 = x 100
(Water + Chemical)
12.5 lbs
5 = x 100
(Water + 12.5 lbs)
Water = 237.5 lbs.
237.5 lbs.
Vol. Of H2O =
62.4 lbs/ft3
= 3.81 ft3
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B+G+20 RESIDENTIAL BUILDING, KOLKATA
PLUMBING
5. Pipe Sizing
Velocity = 4 m/s (max)
Turnover = 6 hrs. (main pool)
25.53 m3/hr.
Required cross sec. Area of suction piping
a. Suction Pipe b. Delivery Pipe
Required cross sec. Area of suction piping
Q = AV 25.53 m3/hr
Area =
25.53 m3/hr = A (4 M/s) 4 M/s x 3, 600
0.00709 m3/s = A (4 M/s) Area = 0.00177 m2
A = 0.00177 m2
Dia,
4 x 0.00177 4 x 0.00177
D = D =
3.1416 3.1416
D = 0.0475 m D = 0.0475 m
D = 47.5 mm = 47.5 mm
Say = 50 mm Say = 50 mm
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