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Structural Design for Engineers

The document outlines the design of a grid floor slab with dimensions of 8m x 10m and ribs spaced at 2m. It involves 3 steps: 1) Adopting a slab thickness of 100mm and rib depth of 400mm with a width of 200mm and overall depth of 600mm 2) Calculating loads such as weight of slab, beams, finish, and live load totaling to 508.8 kN 3) Determining bending moments Mx of 72 kNm and My of 46 kNm in the x and y directions respectively at the center of the grid for a 2m width.

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Harini Ramesh
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100% found this document useful (1 vote)
744 views3 pages

Structural Design for Engineers

The document outlines the design of a grid floor slab with dimensions of 8m x 10m and ribs spaced at 2m. It involves 3 steps: 1) Adopting a slab thickness of 100mm and rib depth of 400mm with a width of 200mm and overall depth of 600mm 2) Calculating loads such as weight of slab, beams, finish, and live load totaling to 508.8 kN 3) Determining bending moments Mx of 72 kNm and My of 46 kNm in the x and y directions respectively at the center of the grid for a 2m width.

Uploaded by

Harini Ramesh
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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DESIGN OF GRID FLOOR SLAB

Size of grid= 8*10 m


Spacing of ribs= 2 m c/c
M25 grade concrete
Fe 415 HYSD bars
STEP1: DIMENSIONS OF SLAB AND BEAMS
Adopt thickness of slab= 100 mm
Depth of ribs= Span/20
= 8000/20
= 400 mm
Width of rib= 200 mm
Adopt overall depth of ribs= 600 mm
STEP2: LOADS
Weight of slab= 0.1×24= 2.4 kN/m2
Total weight of slab= 2.4×8×10= 192 kN
Weight of the ribs= 0.2×0.5×24= 2.4 kN/m
Total weight of beams (x-direction)= 4×2.4×8
= 76.8 kN
Total weight of beams (y-direction)= 3×2.4×10
= 72 kN
Total weight of floor finish= 0.6×8×10= 48 kN
Total live load= 1.5×8×10= 120 kN
Total dead and live load= 508.8 kN
Load per m2= 508.8/8*10 = 6.36 kN/m2
STEP 3: MOMENTS
q1= q ( by4/(ax4+by4)) = 6.36 (104/84+104)
= 4.5 kN/m2
q2= q ( ax4/(ax4+by4)) = 6.36 (84/84+104)
= 1.84 kN/m2
MOMENTS IN X AND Y DIRECTIONS AT CENTRE OF
GRID FOR 2 m WIDTH
Mx= q1b1a2/8 = 4.5×2×82/8
= 72 kNm
My= q2b2a1/8 = 1.84×2×102/8
= 46 kNm
Qx = (4.5×2×8)/2 = 36 kN
Qy = (1.84×2×10)/2 = 18.4 kN

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