DESIGN OF COLUMN
DATA:
Size of column = 500x500mm
Pu = 2000KN
M25 Grade of concrete and Fe415 steel
Mux = 75 KNm
Muy = 60 KNm
d’ = 50mm
SOLUTION:
STEP 1: EQUIVALENT MOMENT
CALCULATION
Mu = 1.15 √Mux2 + Muy2
= 110 KNm
STEP 2: NON –DIMENSIONAL PARAMETERS:
Pu / Fck b D = 2000x103/ 25x500x500 =0.32
Mu / Fck b D2 = 110 x 106/ 25x500x5002 = 0.035
d’/ D = 50/500 = 0.10
refer chart SP 16
p/Fck = 0.06
p = 0.06x25 = 1.5
STEP 3 : REINFORCEMENT CALCULATION:
Asc = pxbxD / 100
= 1.5x500x500 / 100 = 3750mm2
Provide 25mm dia bars
No of bars required = 3750/490.87 = 8 nos
Actual % of r/f = 8 x π/4 x 252 = 3927mm2
Pa = Asc x 100 / b D = 1.57
Pa / Fck = 1.57/25 = 0.32
STEP 4 : MOMENT CALCULATION:
Mux1 / Fck b D2 = 0.038
Mux1 = 118 KNm ,Similarly
Muy1 = 118 KNm
STEP 5 : AXIAL LOAD CALCULATION:
Puz = 0.45 Fck Ac + 0.75 Fy Asc
= 3990 KN
Pu / Puz = 2000/3990 = 0.50
α n = 1.6
STEP 6: CHECK FOR SAFETY
[(Mux/Mux1) αn + (Muy/Muy1) αn ] ≤ 1
( 0.48 + 0.33) ≤ 1
0.81 ≤ 1
Hence design is safe.
STEP 7: LATERAL TIES
Dia of ties = 8 mm
Pitch = Minimum of 300
< 16 x 25 = 400mm
< 500mm
Provide 8mm dia lateral ties @ 300 mm c/c spacing.