RATIO & PROPORTION Ratio as a bridging element helps us in establishing the

Introduction relationship between more than two quantities. This can

Ratio is a quantity that expresses the relationship be further understood with the following example:
between two similar quantities. It expresses a magnitude Suppose conversion rate of our currency Rupee is given
by which one quantity is a part of or a multiple of another with respect to US dollar and also with respect to Pound
quantity. sterling. If we have to find the conversion ratio of US dollar
If the value of A and B are 8 and 6, respectively, then they with respect to pound sterling, we can do it by making
are in the ratio 8:6 (read as 8 is to 6). Ratio can be rupee as the bridge between US dollar and pound sterling.
understood also as the relationship which one quantity
bears with the other of the same kind. Due to this reason, Example 2 The ratio of the age of A and B is 2:5 and ratio
we cannot compare salary of one person with the of the age of B and C is 3:4. What is the ratio of the age of A,
percentage expenditure of another person. B, and C?

The ratio of two quantities A and B is written as A:B. Here, Solution Since B is the common platform that associates
A is known as an antecedent and B is known as a A and C, so we will try to make B equal in both the cases.
consequent. It can also be said that A:B = kA:kB, where k is Age of A : Age of B = [2:5] × 3
any constant known as constant of proportionality, k ≠ 0. Age of B : Age of C = [3:4] × 5
Or, Age of A : Age of B = 6:15 (i)
If the antecedent is more than the consequent (or, the Age of B : Age of C = 15:20 (ii)
numerator is more than the denominator), then the ratio is Since ratio of B is same in both the cases, hence, age of
known as an improper ratio. A:Age of B : Age of C = 6:15:20.
For example, 5/3, 55/29, etc.
Example 3 Given that
If the antecedent is less than the consequent (or, the Salary of A:Salary of B = 1:2
numerator is less than the denominator), then the ratio is Salary of B : Salary of C = 3 : 4
known as a proper ratio. Salary of C : Salary of D = 5 : 6
For example, 3/7, 7/18, etc. Salary of D : Salary of E = 7 : 8
Salary of E : Salary of F = 9 : 10
Since ratio compares two similar quantities, it cannot have What is the ratio of the salaries of A, B, C, D, E, and F?
any units.
Solution Salary of A : Salary of B : Salary of C : Salary of D
Example 1 Consider any ratio . Now, x is added to the : Salary of E : Salary of F = (1 × 3 × 5 × 7 × 9) : (2 × 3 × 5 × 7
numerator and the denominator of this fraction. Which of × 9) : (2 × 4 × 5 × 7 × 9) : (2 × 4 × 6 × 7 × 9) : (2 × 4 × 6 × 8 ×
9) : (2 × 4 × 6 × 8 × 10)
the following is greater: or ?
(Understand the above mechanism with the help of the
Solution It depends upon the following two factors: method given in Example 2. In these cases, this method
i. If the ratio is proper or improper. can be used as a shortcut to find the ratios in the following
ii. x is positive or negative. way : For A, take all the leftmost digits, and now keep
shifting towards the right digits by quitting one by one all
If > 1 and x > 0, or, < 1 and x < 0 the leftmost digits. So, B = Right digit of 1st ratio and so on
for C, D, E, and F.)

Example 4 If A:B = 3:4,

B:C = 5:7
and if > 1 and x < 0, or, < 1 and x > 0 C:D = 10:11
What is the ratio of A:D?

Solution A = 3 × 5 × 10 and D = 4 × 7 × 11
So, the ratio = 150:308
RATIO Alternatively, (A/B) × (B/C) × (C/D) = (3/4) × (5/7) ×
(10/11) = (3 × 5 × 10)/(4 × 7 × 11) = 150:308
Ratio can be understood in the following two ways:
Example 5 A, B, C, and D purchase a gift worth Rs.60. A
1. Ratio as a bridging element
pays 1/2 of what others are paying, B pays 1/3rd of what
2. Ratio as a multiplier
others are paying and C pays 1/4th of what others are
Ratio as a Bridging Element paying. What is the amount paid by D?

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Solution Since A is paying 1/2 of what others are paying, the cat exactly at the exit. What is the ratio of the speed of
so A is paying 1/3rd of the total amount. the train and the speed of the cat?
(To understand this, let us assume that B, C, and D are
paying Rs.2x. So, A is paying Rs.x. The total amount being Solution
paid by A, B, C, and D = 3x = Rs.60, hence, the amount paid
by A = x/3x = 1/3rd of the total.)
So, the amount paid by A = 60/3 = Rs.20
Similarly, B is paying 1/4th of the total and C is paying
1/5th of the total. Initially, this was the position of the train and the cat.
Hence, the amount paid by B and C are Rs.15 and Rs.12, Now, let us assume that the cat is moving towards exit B.
respeffectively. The moment the cat covers 3/8th of AB distance in the
So, the amount paid by D = Rs.13 direction of exit B, the train will be at the entrance A.

Ratio as a Multiplier
The moment we say that the ratio of two numbers A and B
is 5:1, what we mean to say that A is 5 times of B. Now, if the cat moves in the direction of exit B, the train is
It can also be seen that A:B:C in A/2:B/3:C/4 = K is not catching up with the cat at the exit B. So, in the time cat
same as A:B:C = 1/2:1/3:1/4 since multiplier of A, B, and C covers 2/8th distance, the train is covering the whole
are not the same in both the cases. distance from A to B.
Ratio of A:B:C in A/2:B/3:C/4 = K can be calculated in the So, the ratio of the distance covered by train and the
following way: distance covered by the cat = 4:1
Since A/2 = B/3 = C/4 = K, so A = 2K, B = 3K, and C = 4 K So, the ratio of speed = 4:1
Hence, the ratio of A:B:C = 2:3:4
While calculating the ratio of A, B, and C in A:B:C = Example 8 Pranesh can do a work in 15 days. In how
1/2:1/3:1/4, we will multiply each of A, B, and C by the many days, will the work be completed by his brother
LCM of the denominator of all the ratios, that is, 12. Saket if efficiency of Saket is 60% more than that of
So, A:B:C = 6:4:3 Pranesh?

Example 6 Ten persons can cut 8 trees in 12 days. How Solution Since the ratio of efficiency of Pranesh and
many days will 8 persons take to cut 6 trees? Saket = 100:160 = 5:8, the number of days taken by
Pranesh and Saket will be in the ratio of 8:5.
Solution Let us see this question in a changed Since Pranesh takes 15 days to do this work, Saket will
perspeffective. take 15 × 5/8 = 9.37 days
Suppose if the question is—10 persons can cut 8 trees in
12 days. How many days will 10 persons take to cut 4 Comparison of Ratio
trees?
This is one of the most important calculations and is
Answer to this question is:Since the amount of work is extensively used in DI. On an average, if somebody does
getting halved, so the number of days will also get halved. 100 calculations in DI at least 8 to 10 calculations will be
There are three factors, namely the number of men, the from comparing the ratios. Normally, there are two
number of days and the number of trees, which are methods to compare two or more than two ratios:
responsible for the final answer.
Since the number of men are less in the final situation, so Cross Multiplication Method
more number of days will be required. Hence, multiplier =
10/8 (had there been 12 persons, multiplier would have
been 10/12). Example Let us compare and
The number of trees are less in the final situation, so less
number days will be required. So, multiplier = 6/8
Hence, the total number of days = 12 × 10/8 × 6/8 = 90/8 Cross multiplying numerator of first fraction with the
= 11.25 days denominator of second fraction and denominator of first
fraction with the numerator of second fraction,
Example 7 A train approaches a tunnel AB. Inside the 11 × 18 13 × 15
tunnel, a cat is sitting at a point that is 3/8th of the 198 195
distance of AB measured from the entrance A. When the
train whistles, the cat runs. If the cat moves to the entrance
Since, 198 is greater than 195 the first fraction ( ) is
of the tunnel A, the train catches the cat exactly at the
entrance. If the cat moves to the exit B, the train catches greater than the second fraction ( ).

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 2. Componendo
Decimal Calculation
If , then
( )= 0.733( ) = 0.722
3. Dividendo
Obviously, here the first fraction ( ) is greater than the 4.
If , then
second fraction ( ).
However, if we have to compare and then using 4. Componendo and Dividendo
any of the above two methods becomes cumbersome and
time-consuming. If , then
Here, we will compare ratios with the help of percentage.
5. Invertendo
PROPORTION
If , then
In case of an analogy, two quantities share same kind of
relationship. For example, what Macbeth is to William
6. Alterando
Shakespeare, Dr Zivago is to Boris Pasternak.
In QA, the same is true for proportion. It is basically the
If , then
equality of the two ratios.

7. =

In general, if = ....= K
When A, B, C, and D are in proportion, then A and D are
known as ‘extremes’, and B and C are known as ‘means’.
Therefore, we can say, Then, = ....= K =
Product of extremes = Product of means
= (any combination of the numerator/any combination of
Example 9 What is the value of x in the following the corresponding denominator)
expression? For example, 1/2 = 3/6 = 4/8 =…= (1 + 3 + 4)/ (2
+ 6 + 8) = (3 + 4)/(6 + 8)
8. If we multiply the numerator and the denominator of
a ratio by any number N (N ≠ 0), then the ratio
remains same. A/B = NA/NB
Solution 9. If we divide the numerator and the denominator of a
ratio by any number N (N ≠ 0), then the ratio remains
⇒x= = 7 5. same. A/B = (A/N)/(B/N)
10. If a/b, c/d, e/f …etc., are all unequal ratios, then the
value of (a + c + e +…)/(b + d + f +…) lies in between
It can be calculated with the help of percentages also. In
the minimum and the maximum of all these ratios.
this question, the percentage increase in the denominator
is 50%, so the numerator will also increase by 50%.

Standard Results/Definitions on APPLICATION OF RATIO, PROPORTION,

Ratio/Proportion AND VARIATION
1. Continued proportion
a, b, and c are said to be in continued proportion Income−Expense Ratio

if When the ratio of incomes and expenses of two persons

are given and their savings is being asked.
So, b2 = ac. Here, b is known as the mean proportion. Example 12 The ratio of the incomes of Mr Vinay Singh
Similarly, if a, b, c, and d are in continued proportion, and Mr Arun Sharma is 3:5 and the ratio of their expenses
then we get: is 1:3. Who is saving more?

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Solution Let us assume the values of income and expenses 6. Rs.180contained in a box consists of one rupee,50
of A and B. paise and 23 paise coins in the ratio 2 : 3 : 4.What is
Income Expense Savings the number of 50 piece coins?
Vinay 3 1.5 1.5 (a) 60 (b) 110
Arun 5 4.5 0.5 (c) 150 (d) 180
7. By mistake instead of dividing Rs.117 among,
So, Vinay saves more than Arun. A,B,C. in the ratio 1/2: 1/3: 1/4 it was divided
In the other case,
in the ratioof 2 : 3: 4.Who gains the most andhow
Income Expense Savings
much. (а) A, Rs. 28 (b) B, Rs. 3
Vinay 3 1 2
(c) C, Rs. 20 (d) C, Rs. 25
Arun 5 3 2 8. DivideRs.1250 among A, B, C so that Agets g ofB's
share and C gets 2/9 of B's share and C get ¾ of A’s
So, savings of both of them is equal. share.
Income Expense Savings (a) Rs. 200, Rs. 800, Rs. 250 (b) Rs. 200, Rs. 900, Rs.
Vinay 3000 1600 1400 150
Arun 5000 4800 200 (c) Rs. 150, Rs. 800 Rs. 300 (d) Rs. 200, Rs. 900 Rs.
75
So, in this case, Mr Singh is saving less than Mr Sharma. 9. If P:Q = r : s,t: u =2: 3, then (mp + nr + ot) :(nq + ns +
Therefore, it is di cult to determine who is saving more. ou)is equal to:
The concept tells us: If the value of the ratio of income is (a) 1 : 3 (b) 1 : 2
more than the value of the ratio of expenses, then we (c) 2 : 3 (d) 3 : 2
cannot determine who is saving more. If the value of the 10. Ifa : b = c : d = e : f = 1 : 2,then (pa + qc + re):(pb + qd +
ratio of expenses is more than the value of the ratio of rf) is
income, then we can determine who is saving more. (Ratio (a) p : (q+r) (b) (p+q) : r
should be taken in such a way that the value of ratio is less (c) 2:3 (d) 1:2
than 1, i.e., the numerator should be less than the 11. If x : y =3: 1then x3 – y3 : x3 + y3 = ?
denominator.) (a) 13: 14 (b) 14: 13
In the above case, the value of the ratio of income = 3/5 = (c) 10: 11 (d) 11 : 10
0.6 and value of ratio of expenses = 1/3 = 0.33 12. The fourth proportional to 12,21,8 is:
Since the value of ratio of expenses < value of the ratio of (a) 8.9 (b) 56
income, we cannot determine who is saving more. (c) 14 (d) 17
However, in the above question, if we take the ratio of 13. The ratio 21.5 : 20.5 is the same as :
income of Vinay and Arun as 3:5 and the ratio of their (a) 2 : 1 (b) 3: 1
expenses as 3:1, then Arun is saving (c) 6: 1 (d) 3 : 2
14. If m : n = 3 : 2, then (4m +5n) : (4m - 5n) is equal to :
1. If a : b = 7: 9 and b: c = 5:7, then what is a : c (a) 4: 9 (b) 9: 4
(a) 5: 9 (b) 3: 5 (c) 11 : 1 (d) 9 : 1
(c) 7: 21 (d) 7: 15 15. The sum of two numbers is 40 and their difference is
2. If x = 1/3 y and, then x : y : z, is equal to 4, The ratio of the number is
(a) 3 : 2 : 1 (b) 1: 2: 6 (a) 21: 19 (b) 22: 9
(c) 1 : 3 : 6 (d) 2:4: 6 (c) 11: 9 (d) 11 : 18
3. The ratio of two numbers is3 : 8 and their difference is 16. If a sum of money is to be divided A, B, C such that A's
115. The smaller of two number is : shareto twice B's share and B's share is 4 times C's
share then their shareare in the ratio :
(a) 184 (b) 194
(a) 1 : 2 : 4 (b) 1: 4: 1
(c) 69 (d) 59 (c) 8: 4: 1 (d) 2 : 4: 1
4. Four number are in the ratio 1 : 2: 3 : 4. Their sum is 17. How many sides does a regular polygon have whose
16, The sum of the first and fourth number is equal to: interior and exterior angles are in the ratio 2 : 1 ?
(a) 5 (b) 8 (a) 3 (b) 5
(c) 10 (d) 80 (c) 6 (d) 12
5. A and B have money in the ratio 2 : 1. If A gives Rs .2 to 18. The smallest integer, which subtracted from both the
B, The money will be in the ratio 1 :1. What were the terns of 6 : 7gives a ratio less than 16 : 21 is:
initial amount they had? (a) 5 (b) 4
(a) Rs. 12 and Rs. 6 (b) Rs. 16 and Rs. 8 (c) 3 (d) 2
(c) Rs. 8 and Rs. 4 (d) Rs. 6 and Rs. 3

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19. A man leaves Rs.8,600 to be divided among 5 sons, 4 (c) 200 (d) 400
daughters and 2 nephews, If each daughter receives 30. The students in three classes are in the ratio 2 : 3 : 5. If
four times as much as each nephew and each son 20 students are increased in each class, the ratio
receives five times as much as each nephew, how changes to 4: 5 : 7. Originally the total number of
much does each daughter receive ? students was :
(a) Rs. 100 (b) Rs. 600
(c) Rs. 800 (d) Rs. 1000 (a) 50 (b) 90
20. If A : B = 3: 4, B : C = 5 : 7 and C : D = 8 : 9 then A : D is (c) 100 (d) 150
equal to: 31. Zinc and copper are in the ratio of 5 : 3 in 200 gm of an
(a) 3: 7 (b) 7: 3 alloy. How much grams of copper be added to make
(c) 21: 10 (d) 10: 21 the ratio as 3 : 5?
21. Harsha is 40 years old and Ritu is 60 years old. How (a) 400/3 (b) 1 / 200
many years ago was the ratio of their ages 3 : 5 ? (c) 72 (d) 66
(a) 10 years (b) 20 years 32. The ratio of copper and zinc in brass is 13 : 7.How
much zinc will be there in 100 kg of brass?
(c) 37 years (d) 5 years
(a) 22 kg. (b) 55 kg.
22. The ratio of present age of two brothers is 1 : 2 and 5 (c) 35 kg. (d) 40 kg.
years back the ratio was 1 : 3. What will be the ratio of 33. In 30 litres mixture of acid, the ratio of acid and water
their age after 5 years ? is 2 : 3. What amount of water should be added to the
(a) 1 : 4 (b) 2: 3 mixture so that the ratio of acid and water becomes 2 :
(c) 3 : 5 (d) 5: 6 5?
23. Four years ago, the ratio of the age of A and B was 2 : 3 (a) 10 litres (b) 15 litres
and after four years it will becomes 5 : 7. Find their (c) 18 litres (d) 12 litres
present age. 34. A and B have monthly incomes in the ratio 5 : 6 and
(a) 36 years and 40 years (b) 32 years and 48 monthly expenditures in the ratio 3 : 4. If they save Rs
1800 and Rs.1600 respectively, find the monthly
years
income of B
(c) 40 years and 56 years (d) 36 years and 52
years (a) Rs 3400 (b) Rs. 2700
24. The ratio of two numbers is 10 : 7 and their difference (c) Rs. 1720 (d) Rs. 7200
is 105. The sum of these numbers is: 35. The ratio of income of two persons is 5 : 3 and that of
(a) 595 (b) 805 their expenditures is 9 : 5, find the income of each
(c) 1190 (d) 1610 person, if they save 1,300 and R 900 respectively.
25. The product of two positive integers is 1575 and their (a) Rs.4,000,Rs.2,400 (b) Rs.3,000, Rs.1,800
ratio is 9 : 7. The smaller integer is: (c) Rs. 5,000, Rs. 3,000 (d) Rs. 4,500, Rs. 2,700
36. Divide Rs. 7500 among A, B and C such that A’s share
(a) 25 (b) 35
to B’sshare is in ratio5 : 2and B’sshare to C’sshare is in
(c) 45 (d) 70 the ratio 7 : 13.How much will B receive?
26. Two numbers are in the ratio 5 : 7. On diminishing (a) Rs. 1,400 (b) Rs 3,500
each of there by 40, they become in the ratio 17 : 27. (c) Rs 2,600 (d) Rs 7,000
The difference of the numbers is : 37. A sum of R 1240 is distributed among A, B and C such
(a) 18 (b) 52 that the ratio of amount received by A and B is 6 : 5
(c) 137 (d) 50 and that of B and C is 10 : 9 respectively. Find the
27. The ratio of the number of boys and girls of a school share of C.
with 504 students is 13 : 11. What will be the new (a) Rs 480 , (b) Rs 360
ratio if 12 more girls area admitted.? (c) Rs 400 (d) Rs 630
(a) 91: 81 (b) 11 : 91 38. A and B together have 158, C has 101 less than what A
and B together have, and B has Rs. 23 more than C. The
(c) 9 : 10 (d) 10 : 9 amount of A is :
28. Two numbers are in the 3/2 : 8/3 when each ofthese is (a) Rs. 80 (b) Rs. 78 (b) Rs. 57 (d) Rs.
increased by 15, they become in the ratio 5/3 : 5/2. 88
The greater of the numbers is : 39. If a : b = 2/9 : 1/3 , b : c = 2/7 : 5/14 and d : c = 7/10 :
(a) 27 (b) 36 3/5 then a : b : c : d is
(c) 48 (d) 64 (a) 4 : 6 : 7 : 9 (b) 16 : 24 : 30 : 35
29. The students in three classes are in the ratio 2 : 3 : 5. If (c) 8 : 12 : 15 : 7 (d) 30 : 35 : 24 : 16
40 students are increased in each class, the ratio 40. The ratio of age of two boys is 5: 6. After two years the
changes to 4: 5: 7. Originally, The total number of ratio will be 7 : 8. The ratio of their age after 12 years
students was : will be:
(a) 100 (b) 180 (a) 22/24 (b) 15/16

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 (c) 17/18 (d) 11/12 52. A bag contains Rs. 90 in coins of nominations of 50
41. Three numbers are in the ratio of 3 : 2 : 5 and the sun paise, 25 paise and 10 paise. If coins of 50 paise, 25
of their squares is 1862, The smallest of these number paise and 10 paise are in the ratio 2 : 3 : 5, then the
is number of 25 paise coins in the bag is
(a) 24 (b) 21 (a) 80 (b) 120
(c) 14 (d) 35 (c) 100 (d) 135
42. The sum of three numbers is 116. The ratio of second 53. Rs. 3400 is divided among A, B, C, D in such a way that
to the third is 9 : 16 and the first to the third is: 4, The the share of A and B, B and C, C and D may be as 2 : 3, 4
second number is: : 3 and 2 : 3 respectively. The sumof shares of B and D
(a) 30 (b) 32 is:
(c) 34 (d) 36 (a) Rs. 2040 (b) Rs. 1680
43. The sum of three numbers is 98. If the ratio of the first (c) Rs. 2000 (d) Rs. 1720
to the second is 2 : 3 and that of the second to the third 54. A sumof Rs. 370 is to be divided among A,B and C such
is 5 : 8, then the second number is that A’s share (in rupees ) is
(a) 49 (b) 48
(a) 240 (b) 120
(c) 30 (d) 20
44. Two numbers are in the ratio 5 : 7. If 9 is subtracted (c) 100 (d) 90
from each of them, their ratio becomes 7 : 11. The 55. Two numbers are in the ratio 17: 45.One third of the
difference of the numbers is: smalleris less than 1/5 ofthe bigger by 15. The smaller
(a) 6 (b) 12 number is:
(a) 51/2 (b) 135/2
(c) 15 (d) 18
45. Two numbers are in the ratio 3 : 5. If 9 is subtracted (c) 153/2 (d) 173/2
from each then they are in the ratio 12 : 23. Find the 56. Rs.6200divided into three parts proportional to ½ :
smaller number : 1/3 : 1/5 area respectively.
(a) 27 (b) 33 (a) Rs. 3000, Rs. 2000 , Rs. 1200 (b) Rs. 3500, Rs.
(c) 49 (d) 55 1500, Rs. 1200
46. In an alloy, the ratio of copper and zinc is 5 : 2 .If 1250 (c) Rs. 2500, Rs. 2000, Rs. 1700 (d) Rs. 2200 , Rs.
kg.of zinc is mixed in 17 kg 500 gm of alloy then the 3000 , Rs. 1000
ratio of copper and zinc will be. 57. In a 45 litres mixture of milk and water, the ratio of
(a) 2: 1 (b) 2 : 3 the milk to water is 2 : 1. When some quantity of water
(c) 3 : 2 (d) 1 : 2 is added to the mixture, this ratio becomes 1 : 2. The
47. Amixture containsspirit and water in the ratio 3 : 2. If quantity of water added is:
it contains 3 litres more spirit than water the quantity (a) 10 litres (b) 21 litres
of spirit in the mixture is (c) 35 litres (d) 45 litres
(a) 10 litres (b) 12 litres 58. A barrel contains a mixture of wine and water in the
(c) 8 litres (d) 9 litres ratio 3 : 1. How much fraction of the mixture must be
48. A mixture of 30 litres contains milk and water in the drawn off and substituted by water so that the ratio of
ratio of 7 : 3 . How much water should be added to it wine and water in the resultant mixture becomes 1 : 1
so that the ratio of milk and water become3: 7 ? ?
(a) 40 litres (b) 49 litres (a) 1/4 (b) 1/3
(c) 56 litres (d) 63 litres (c) 3/4 (d) 2/3
49. The income of A, B and C are in the ratio 7 : 9 : 12 and 59. A man spends a part of his monthly income and saves
their spending are in the ratio 8 : 9 :15. If A saves ¼ a part of it, the ratio of his expenditure to his saving is
th.of his income then the saving of A, B and C are in the 26 : 3. If his monthly income is Rs. 7250. what is the
ratio of : amount of his monthly savings ?
(a) 56 : 99 : 69 (b) 69 : 56 : 99 (a) Rs. 350 (b) Rs. 290
(c) 99 : 56: 69 (d) 99 : 69 : 56 (c) Rs. 750 (d) Rs. 780
50. The ratio of income of P and Q is3 : 4 and the ratio of 60. There are 225 consisting of one rupee, 50 paise and 25
their expenditures is2 : 3. If both of them save 6000 , paise coins, the ratio of their numbers in that order is
the incomeof P is: 8: 5 : 3. The number of one-rupee coins is :
(a) Rs. 20000 (b) Rs. 12000 (a) 80 (b) 112
(c) Rs. 18000 (d) Rs. 24000 (c) 160 (d) 172
51. If 378coins consists of 1 rupee, 50 paise and 25 paise 61. Rs.750 are divided among A, B and C in such a manner
coins,whose values are in the ratio 13:11 :7.The that A : B is 5 : 2 and B : C is 7: 13. What is A's share ?
number of 50 paise coins will be: (a) Rs. 350 (b) Rs. 260
(a) 132 (b) 128 (c) Rs. 140 (d) Rs. 250
(c) 136 (d) 133 62. An amount of money is to be distributed among P, Q
and R in the ratio of 2 : 7 : 9. The total of P's and Q's

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 share is equal to R's share. What is the difference (a) 72,84,108 (b) 60,72,96
between the shares of P and Q? (c) 72,84,96 (d) 72,96,108
(a) Rs, 5000 (b) Rs. 7500 76. The students in three classes are in the ratio 2 : 3 : 5. lf
(c) Rs. 9000 (d) Information inadequate 20 students are increased in each class, the ratio
63. IfA:B= 3:4,B : C= 5: 7and C : D = 8 : 9then A: Dis equal changes to 4 : 5 : 7. Originally the total number of
to students was :
(a) 3: 7 (b) 7: 3 (a) 50 (b) 90
(c) 21 : 10 (d) 10 : 21 (c) 100 (d) 150
64. 94 is divided into two parts in such a way that the fifth 77. There is 81 litres pure milk in a container. One-third of
part of the first and the eight part of the second are in milk is replaced by water in the container. Again one-
the ratio 3 : 4. the first part is: third of mixture is extracted and equal amount of
(a) 30 (b) 36 water is added. What is the ratio of milk to water in
(c) 40 (d) 28 the new mixture ?
65. If a : b = 5 : 7 and c : d = 2a : 3b then a:c : b:d is : (a) 1 : 2 (b) 1 : 1
(a) 20: 38 (b) 50 : 147 (c) 2 : 1 (d) 4: 5
(c) 10 : 21 (d) 50 : 151 78. In 80 litres mixture of milk and water the ratio of
66. If x : y = 3 : 2, then the ratio 2x2+3y2 : 3x2 -2y2 is equal amount of milk to that of amount of water is 7: 3. In
to: order to make this ratio 2 : 1, how many litres of water
(a) 12: 5 (b) 6: 5 should be added ?
(c) 30 : 19 (d) 5 : 3 (a) 5 (b) 6
67. If a: b = b : c, then a4 : b4 is equal to: (c) 3 (d) 4
(a) ac:b2 (b) c2 : a2 79. The annual income of A and B are in the ratio 4 : 3 and
(c) c : a
2 2 (d) b2 : ac the ratio of their expenditures is 3: 2. If each of then
68. If A : B = B : C= andC : D = then the ratio A saves Rs. 600 in the year, the annual income of A is
(a) Rs. 4800 (b) Rs. 1800
: B : C : Dis :
(c) Rs. 1200 (d) Rs. 2400
(a) 6 : 4 : 8 : 10 (b) 6 : 8 : 9 : 10
80. The ratio of income of two persons is 5:3 and that of
(c) 8 : 6 : 10 : 9 (d) 4 : 6 : 8 : 1
their expenditures is 9 : 5. If they save Rs. 2600 and Rs.
69. IfA : B : C = 2 : 3 : 4then ratio is equal to: 1800 respectively. Their incomes are :
(a) 8 : 9 : 16 (b) 8 : 9 : 12 (a) Rs. 8000 : Rs. 4800 (b) Rs. 6000 : Rs. 3600
(c) 8 : 9 : 24 (d) 4 : 9 : 12 (c) Rs. 10000 : Rs. 6000 (d) Rs. 9000 : Rs. 5400
70. Ifa : b = c : d = e : f = 1 : 2, then (3a + 5c + 7e) : (3b + 5d 81. The monthly income of two persons are in the ratio 2 :
+ 7f) is: 3 and their monthly expenses are in the ratio 5 : 9. If
(a) 8 : 7 (b) 2 : 1 each of them saves Rs. 600 per Month, then their
(c) 1 : 4 (d) 1 : 2
monthly incomes are
71. The ratio of present age of two brothers is 1 : 2 and 5
(a) Rs. 1,500 : Rs. 2,2250 (b) Rs. 1,200 : Rs. 1,800
years back the ratio was 1 : 3. What will be the ratio of
(c) Rs. 1,600 : Rs. 2,400 (d) Rs. 2,100 : Rs. 1,400
their age after 5 years ?
82. Rs.68000 is divided among A, B and C in the ratio of
(a) 1 : 4 (b) 2 : 3.
½:¼: 5/16 .Thedifference of the greatest and the
(c) 3 : 5 (d) 5 : 6
smallest part is :
72. The ratio of the present age of Puneet and Appu is 2: 3.
(a) Rs. 6000 (b) Rs. 14440
After 3 years the ratio of their age will be 3 : 4. The
(c) Rs. 9200 (d) Rs. 16000
present age of Puneet is:
83. Theratio of the first and second class train fares
(a) 3 years (b) 6 years
between two stations is 3 : 1 and that of the numbers
(c) 9 years (d) 4 years
of passengers travelling between the two stations by
73. Of the three numbers, the ratio of the first and the
first and second classes is 1 : 50.If on a particular day
second is 8 : 9 and that of the second and third is 3 : 4.
Rs. 1325 are collected from passengerstravelling
If the product of the first and third number is 2400,
between the two stations.Then the amount collected
then the second number is :
from the second class passengers is:
(a) 45 (b) 40
(a) Rs. 1,250 (b) Rs. 1,000
(c) 24 (d) 10
(c) Rs.850 (d) Rs. 750
74. Two numbers are in the ratio 2 : 3. If 2 is subtracted
84. Ifp : q : r = 1 : 2 : 4, then √5p2+ q2 + r2is equal to
from the first and 2 is added to thesecond . the ratio
(a) 5 (b) 2q
becomes 1 :2.Thesum of the numbers is:
(c) 5p (d) 4r
(a) 30 (b) 28
85. The mean proportional between(3 + √2)and (12 -
(c) 24 (d) 10
√32) is:
75. The numbers are in the ratio½ : 2/3: 3/4.The
(a) √7 (b) 2√7
difference between the greatest and the smallest
number is 36.The numbers are:

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 (c) 6 (d)
√ 97. If a : b : c =7: 3: 5 , then (a + b + c)(2a + b - c)is equal to:
(a) 1 : 2 (b) 3: 2
86. Ifx : y = 2 : 3, then the value of is equal to :
(c) 3 : 4 (d) 5 : 4
(a) 11/4 (b) 4/11 98. If A : B = 2 : 3 and B : C = 4 : 5,then A: B : C is:
(c) 1/2 (d) 5/14 (a) 2 : 3 : 5 (b) 5 : 4 : 6
87. If a, b, c are three numbers such that a : b = 3 : 4 and b : (c) 6 : 4 : 5 (d) 8 : 12 : 15
c = 8 : 9thena : c isequal to 99. If two times of A is equal to three times of B and also
(a) 1 : 3 (b) 2: 3 equal to four times of C, then A:B: C is:
(c) 3 : 2 (d) 1 : 2
(a) 2 : 3 : 4 (b) 3 : 4 : 2
88. The ratio of the ages of a father and his son 10 years
hence will be 5 : 3. while 10 years ago it was 3 : 1. The (c) 4 : 6 : 3 (d) 6 : 4 : 3
ratio of the age of the son to that of the father at 100. IfA : B=2: 3 , B : C = 2 : 4 and C : D = 2 : 5,then A : D is
present is: equal to:
(a) 2 : 15 (b) 2 : 45
(a) 1 : 2
(c) 1 : 5 (d) 3 : 5
(c) 2: 3 (b) 2 : 1 (d) 2 : 5 101. 33630 area divided among A, B and C in such a
89. The ratio of the number of boys and that of girls in a manner that the ratio of the amount of A to that of B is
school having 504 students is 13 : 11. What will be the 3 : 7 and the ratio of the amount of B to that of C is 6 :
new ratio if 3 more girls are admitted ? 5.The amount of money received by B is :
(a) 7 : 6 (b) 6: 7 (a) Rs. 14868 (b) Rs. 16257
(c) 10: 11 (d) 13: 14 (c) Rs. 13290 (d) Rs. 12390
90. The ratio of the number of ladies to that of gents at a 102. The sum of the age of a father and his son is 100 years
party was 3 : 2, When 20 more gents joined the party, now.5 years ago their age were in the ratio of 2 : 1.The
the ratio was reversed. The number of ladies present ratio of the age of father and son after 10 years will be:
at the party was (a) 5 : 22 (b) 4 : 3
(a) 36 (b) 32 (c) 10 : 7 (d) 5 : 3
103. the ratio of present ages of Rahul and Rashmi is 2 : 1.
(c) 24 (d) 16 The ratio of their ages after 30 year will be 7 : 6. What
91. Vessels A and B contain mixtures of milk and water in is the present age of Rahul?
the ratio 4: 5 and 5 : 1 X respectively.In what ratio (a) 6 years (b) 10 Years
should quantities ofmixture be taken from A form a (c) 12 years (d) 20 years
mixture in which milk to water is inthe ratio 5 : 4?
104. The sum of three nuymbers is 68. If the ratio
(a) 2 : 5 (b) 4: 3
(c) 5:2 (d) 2: 3 of the first to the second be 2 : 3and that of
92. A man has in all Rs. 640 in the denominations of one- the second to the third be 5 : 3,then the
rupee, five-rupee and ten-rupee notes. The number of
second number is:
each type of notes are equal. What is the total number
of notes he has ? (a) 30 (b) 58
(c) 20 (d) 48
(a) 150 (b) 120
105. Two numbers are in the ratio 4 : 5 and their L.C.M.is
(c) 100 (d) 90 180.The smaller number is:
93. A bag contains three types of coins 1 rupee-coins, 50p- (a) 9 (b) 15
coins and 25 p-coins totaling 175 coins, If the total (c) 36 (d) 45
value of the coins of each kind be the same, the total 106. In a school having strength 286, the ratio for boys and
amount in the bag is : girls get admitted into the school, the ratio of boys and
(a) Rs. 75 (b) Rs. 175 girls becomes:
(c) Rs. 300 (d) Rs. 126 (a) 12 : 7 (b) 10 : 7
94. If a : b : c = 2 : 3 :4 and2a – 3b + 4c = 33, then the value (c) 8 : 7 (d) 4 : 3
of c is: 107. 200 liters of a mixture contains milk and water in the
(a) 6 (b) 9 ratio 17: 3.After the addition of some more milk to it,
(c) 12 (d) 66/7 the ratio ofmilk to water in the resulting mixture
95. Ifa : b = c : d, then is equal to : becomes 7 : 1.The quantity of milk added to it was :
(a) a/b (b) c/d (a) 20 liters (b) 40 liters
(c) (d) (c) 60 liters (d) 80 liters
108. The milk and water in a mixture and in the ratio 7 :
96. The ratio of a and b is 4 : 5and that of B to C is 2 : 3.IfA
5.When 15 litres of water are added to it.,the ratio of
equals 800,C equal to :
milk and water in thenew mixture becomes 7 : 8. The
(a) 1000 (b) 1200
total quantity of water in the new mixture is:
(c) 1500 (d) 2000

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 (a) 35 liters (b) 40 liters 120. A jar contained a mixture of two liquids A and B in the
ratio 4 : 1. When 10 litres of the mixture was taken out
(c) 60 liters (d) 96 liters
and 10 litres of liquid B was poured into the jar, this
109. The ratio of incomes of A and Bis 5 : 6.If A gets
ratio became 2: 3. The quantity of liquid A contained in
Rs.11,100 less than B, their total income (in rupees)is :
the jar initially was :
(a) 9900 (b) 122100
(a) 4 litres (b) 8 litres
(c) 14400 (d) 10000
(c) 16 litres (d) 40 litres
110. A box contains 1 rupee, 50paise and 25 paise cons in
121. In a mixture of 75 litres, the ratio of milk to water is 2:
the ratio 8 : 5 : 3.If the total amount of money in the
1. The amount of water to be further added to the
box is Rs.112.5the number of 50 paise cons is:
mixture so as to make the ratio of the milk to water 1 :
(a) 80 (b) 50
2 will be :
(c) 30 (d) 42
111. In A bag,there are three types of coins,1 –rupees,50 – (a) 45 liters (b) 60 liters
paise,and 25 paise in the ratio of 3 : 8 : 20.their total (c) 75 liters (d) 80 liters
value is Rs.372. the total number of cons is: 122. A and B area two alloys of gold and copper prepared
(a) 1200 (b) 961 by mixing metals in the ratio 5: 3and 5 : 11
(c) 744 (d) 612 respectively.Equal quantities of the alloys are melted
112. In an innings of a cricket match three players A,Band C to forma third alloy- C.The ratio of gold and copper in
scored a total of 361 runs.If the ratio of the number of alloy C is:
runs scored by A to that scored by B and also number (a) 25 : 23 (b) 33 : 25
of runs scored by B to that scored by C be 3 : 2, the (c) 15 : 17 (d) 17 : 15
number of runs scored by A was: 123. Two types of alloy possess gold and silver in the ratio
(a) 171 (b) 181 of 7 : 22and 21: 37.In what ratio should these alloys be
mixed so as to have a new alloy in which gold and
(c) 185 (d) 161
silver would exist in the ratio 25: 62?
113. In an examination,the number of those who passed
(a) 13: 8 (b) 8: 13
and the number of those who failed were in the ratio
(c) 13 : 12 (d) 6: 9
25 : 4. If five more had appeared and the number of
124. In an alloy, zinc and copper are in the ratio 1 : 2. In the
failures was 2 less than earlier,the ratio of passers to
second alloy, the same elements are in the ratio 2 : 3. If
failures would have been 22 : 3.Total number who
these two alloys be mixed to form a new alloy in which
appeared at the examination is:
two elements are in the ratio 5 : 8, the ratio of these
(a) 145 (b) 150 two alloys in the new alloy is:
(c) 155 (d) 1180 (a) 3 : 10 (b) 3: 7
114. If a : b : c = 3: 4 : 7,then the ratio (a + b + (c) 10: 3 (d) 7 : 3
c) : C is equal to 125. A box has 210 coins of denominations one rupee and
fifty paise only. The ratio of their respective values is
(a) 2 : 1 (b) 14 : 3
13 : 11, The nu I1ber of one-rupee coins is:
(c) 7 : 2 (d) 1 : 2
(a) 65 (b) 66
115. IfA andB are in the ratio 3 : 4,and B and C in the ratio
12 : 13.then A and C will be in the ratio: (c) 77 (d) 78
126. A boy has a few coins of 50 paise, 25 paiseand 10 paise
(a) 3 : 13 (b) 9 : 13
in the of 1 : 32 : 3. If the total amount the coins is Rs.
(c) 36: 13 (d) 13: 9 8.80, The number of 10 paise coins is:
116. If A : B = 3 : 2 and B : C = 3 : 4 then A : C is equal to:
(a) 5 (b) 10
(a) 1 : 2 (b) 2 : 1
(c) 15
(c) 8 : 9 (d) 9 : 8 (c) 30
117. If 2/3ofA= 75%ofB=0.6of C,ThenA : B : C is 127. The salaries of A,B , and C are in the ratio 1 : 3 : 4.If the
(a) 2 : 3 : 3 (b) 3 : 4 : 5 salaries are increased by 5% , 10% and 15%
(c) 4 : 5 : 6 (d) 9 : 8 : 10 respectively.then the increased salaries will be in the
118. If A : B = 3 : 5and B : C = 4 : 7,then A : B : Cis: ratio:
(a) 6 : 9 : 14 (b) 3 : 4 : 7
(a) 20:66 : 95 (b) 21: 66 : 95
(c) 12 : 20 : 21 (d) 12 : 20 : 35
119. In 40 litres mixture of milk and water the ratio of milk (c) 21 : 66 : 92 (d) 19 : 66 : 92
to water is 7 : 1. In order to make the ratio of milk and 128. Total marks obtained by Arun in English and
water 3: 1, the quantity of water (in litres) that should Mathematics are 170. If the difference between his
be added to the mixture will be (a ) 6 (b) marks in these two subjects is 10. Then the ratio of his
13/2 marks in these subjects is
(c) 20/3 (d) 27/4 (a) 7 : 8 (b) 8 : 7

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 (c) 9 : 8 (d) 9 : 7 (a) Rs. 400 (b) Rs. 500
129. Ifx : y= 2 : 1,then(x2- y2) (c) Rs. 600 (d) Rs. 800
(a) 3 : 5 (b) 5 : 3 140. If W1 : W2 = 2: 3 and W1 : W2 = 1 :2 then W2: W3 is:
(c) 4 : 5 (d) 5 : 6 (a) 3 : 4 (b) 4: 3
130. There are three numbers A, B, C such that twice A is (c) 2: 3 (d) 4 : 5
equal to thrice B and four times B is equal to five times 141. If3.x = 5y =42, then x : y : z is equal to:
C, Then the ratio between A and C is: (a) 9 : 12 : 16 (b) 20: 12: 15
(a) 3: 4 (b) 8 : 15 (c) 15: 10 : 9 (d) 8: 5 : 3
(c) 15 : 8 (d) 4 : 3
142. If A:B = 3:4 and B:C = 6:5 then A :(A+C) is equal to
131. The two numbers are in the ratio 2 : 3 and their (a) 9:10 (b) 10:9
product is 96. The sum of the numbers is :
(c) 9:19 (d) 19:9
(a) 5 (b) 20
(c) 101 (d) 102 143. If a and b area rational numbers and a+ b√3 = √ ,
132. The ratio between two number is 3 : 4.If each number then a : b is equal to:
is increased by 6, the ratio becomes 4:5.The difference (a) 2 : 1 (b) 2 : 3
between the numbers is: (c) √3 : 1 (d) - √3 : 1
(a) 1 (b) 3 144. IfA : B = 3 : 4 and B:C = 8 : 9, then A : B :C is:
(a) 8 : 6 : 9 (b) 9 : 8
(c) 6 (d) 8
(c) 6 : 8 : 9 (d) 3 : 32 : 9
133. Three numbers are in the ratio 5 : 6 : 7,If the product
145. IfA =¼ BandB = ½ C,then A :B : C is :
of the numbers is 5670, then the greatest number is:
(a) 8 : 4: 1 (b) 4:3: 1
(a) 15 (b) 18
(c) 1 : 4: 8 (d) 1 : 2: 4
(c) 21 (d) 28
146. If 2A = 3B =4C, then A : B : C is :
134. Which number when added to each of the numbers
6,7,15, 17 will make the resulting numbers (a) 2: 3: 4 (b) 4 : 3 : 2
proportional? (c) 6 : 4: 3 (d) 3 : 4: 6
(a) 6 (b) 5 147. The ratio 43.5 : 25 is the same as:
(c) 4 (d) 3 (a) 4: 1 (b) 2 : 1
135. In a glass, milk and water are mixed in the ratio 3 : 5 (c) 1: 2 (d) 1 : 4
and in another. glass they are mixed in the ratio 6 : 1. 148. If A : B = 1 : 2, B : C = 3: 4, C : D =6 : 9 and D : E = 12 : 16
In what ratio should the contents of the two glasses be then A : B : C : D is equal to:
mixed together so that the new mixture contains milk (a) 1 : 3: 6:12: 16 (b) 2 : 4 : 6 : 9 : 16
and water in the ratio 1 : 1? (c) 3 : 4: 8: 12: 16 (d) 3: 6:8: 12: 16
(a) 20: 7 (b) 8 : 3 149. If x : y = 2: 5 then (5x+3y) : (5x-3y) is equal to:
(c) 27 : 4 (d) 25: 9 (a) 5 (b) 3
136. Incomes of A and B are in the ratio 4 : 3 and their (c) - 3 (d) – 5
annual expenses in the ratio 3: 2. If each save Rs. 150. The ratio of the age of a father tothatof his son is 5 : 2.
60,000 at the end of the year, the annual income of A If the product of their age in years is 1000 then the
is: father age (in year) after 10 years will be:
(a) Rs. 1,20,000 (b) Rs. 1,50,000 (a) 50 (b) 60
(c) Rs. 2,40,000 (d) 3,60,000 (c) 80 (d) 100
137. The weight of Mr. Gupta and Mrs. Gupta are in the 151. What number should be added to leach of 6, 14, 18and
ratio 7: 8 and their total weight is 120 kg. After taking 38,so that the resulting numbers make a proportion.
a dieting course Mr. Gupta reduces by 6 kg and the
(a) 1 (b) 2
ratio between their weights changes to 5 : 6, So Mrs.
Gupta has reduced by : (c) 3 (d) 4
(a) 2 kg (b) 4 kg 152. Two numbers are in the ratio 3 : 4 and theirLCM is
(c) 3 kg (d) 5 kg 180. The first number is:
138. The ratio of the first and second class fares between (a) 15 (b) 60
two railway stations is 4 : 1. and that of the number of (c) 36 (d) 45
passengers travelling by first and second classes is 1 :
40. If on a day Rs. 1,100 are collected as total fare, the 153. Two numbers are in the ratio 3 : 5 and theirLCM is
amount collected from the first class passengers is 225. The smaller number is:
(a) Rs. 315 (b) Rs. 275 (a) 45 (b) 60
(c) Rs. 137.50 (d) Rs. 100 (c) 75 (d) 90
139. If Rs. 1000 is divided between A and B in the ratio 3 : 154. The ratio of two numbers is 3 : 4 and their LCM is 48 .
2, then A will receive: The sum of the two numbers is :

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 (a) 32 (b) 28 166. At present the ratio of the age of Maya and Chhaya is 6
: 5 and fifteen years from now, the ratio will get
(c) 26 (d) 24
changed to 9 : 8. Maya’s present age
155. What must be added to each term of the ratio 7 : 11, so
(a) 21 years (b) 24 years
as to make it equal to 3 : 4 ?
(c) 30 years (d) 40 years
(a) 8 (b) 7.5 167. The ratio of the age of Ram and Rahim 10 years ago
(c) 6.5 (d) 5 was 1 : 3. The ratio of their age five years hence will be
156. Two number are in the ratio 7 : 11. If 7 is added to 2 : 3. Then the ratio of their present age is:
each of the numbers. The ratio becomes 2 :3. The (a) 1 : 4 (b) 3 : 5
smaller number is : (c) 3 : 4 (d) 2 : 5
(a) 39 (b) 49 168. If the sum of two quantities is equal to three times
(c) 66 (d) 77 their difference, then the ratio of the two quantities is:
157. Two numbers are in the ratio 3 : 5. If each number is (a) 1 : 3 (b) 3 : 1
increased by 10. the ratio becomes 5:7, The smaller (c) 2 : 1 (d) 2: 3
number is: 169. Three numbers are in the ratio 3 : 4 : 5, The sum of the
(a) 9 (b) 12 largest and the smallest equals the sum of the second
(c) 15 (d) 25 and 52, The smallest number is:
158. The monthly salaries of A, B and C are in the ratio 2 : 3 (a) 20 (b) 27
: 5. If C's monthly salary is Rs. 12,000 more than that of (c) 39 (d) 52
A, then B's annual salary is : 170. A vessel contains a mixture of two liquids A and B in
(a) Rs. 1,20,000 (b) Rs. 1,44,000 the ratio 7 : 5. When 9 litres of Inixture is drawn off
(c) Rs. 1,80,000 (d) Rs. 2, 40,000 and the vessel is filled with B, the ratio of A and B
159. The ratio of income and expenditure of a person is 11 : becomes 7 : 9. Litres of liquid A contained in the vessel
10. If he saves Rs. 9,000 per annum, his monthly initially was:
income is: (a) 10 (b) 20
(c) 21 (d) 25
(a) Rs. 8,000 (b) Rs. 8,800
171. A container contains two liquids A and B in the ratio 7
(c) Rs. 8,500 (d) Rs. 8,250 : 5. When 9 litres of mixture are drawn off the
160. The ratio of the numbers of boys and girls in a school container isfilled with B theratio of A and B becomes 1:
was 5 : 3. Some new boys and girls were admitted to 1.How manylitres of liquid A was in thecontainer
the school, in the ratio 5 : 7. At this, the total number of initially?
students in the school became 1200, and the ratio of (a) 26 (b) 147/2
boys to girls changed to 7:5, The number of students in (c) 27/4 (d) 107/4
the school before new admissions was: 172. The vessels A and B contain milk and water mixed in
(a) 700 (b) 720 the ratio 4 : 3 and 2 : 3.The ratio in which these
(c) 900 (d) 960 mixtures be mixed to form a new mixture containing
161. Three persons walk from place A to place B. Their falf milk and half water is:
speeds are in the ratio 4 : 3 : 5, The ratio of the time (a) 7 : 5 (b) 6 : 5
taken by them to reach B will be : (c) 5: 6 (d) 4 : 3
(a) 10: 15 : 13 (b) 2: 3: 4 173. The ratio of the volume of water and glycerine in
(c) 15 : 20 : 12 (d) 16 : 18: 15 240cc of mixture is 1 : 3. The quantity of water (in cc)
162. Marks of two candidates P and Q are in the ratio 2 : 5 if that should be added to the mixture so that the new
them marks of P are 120, marks of Q are ratio of the volumes of water and glycerine becomes 2
(a) 120 (b) 240 : 3 is:
(c) 300 (d) 360 (a) 55 cc (b) 60 cc
163. If A : B = 4: 9 and A : C = 2 : 3 then (A+B) : (B+C) is: (c) 62.5 cc (d) 64 cc
(a) 15: 13 (b) 10: 13 174. In a mixture of 25 litre the ratio of acid to water is 4 :
(c) 3 : 10 (d) 13 : 15 1. another 3 litre of water is added to the mixture . The
164. If x : y = 3 : 4, then the value of ratio of acid to water in the new mixture is:
(a) 5 : 2 (b) 2: 5
(a) 7/25 (b) 7/23 (c) 3 : 5 (d) 5 : 3
(c) 7/29 (d) 7/17 175. Two equal vessels are filled with the mixtures of water
165. If x : y = 3 : 4, then the value of (4x -y} : (2x +3y) is: and milk in the ratio of 3: 4 and 5 : 3 respectively. If
(a) 4: 9 (b) 8: 9 the mixtures are poured into a third vessel, the ratio of
(c) 4: 3 (d) 8: 3 water and milk in the third vessel will be:
(a) 15 : 12 (b) 53: 59
(c) 20: 9 (d) 59: 53

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176. Two vessels A and B contains acid and water in the 185. From each of the two given unequal number.Half the
ratio 4 : 3 and 5 : 3 respectively.Then the ratio in smaller number is subtracted. then, of is five times
which these mixtures to be mixed to obtain a new then the larger one is five times then the smaller one.
mixture in vessel C containing acid and water in the Then the ratio of the larger to smaller one is:
ratio 3 : 2 is: (a) 2 : 1 (b) 3 : 2
(a) 5: 8 (b) 7: 8 (c) 3 : 1 (d) 1 : 4
186. 94 is divided into two parts in such a way that the fifth
(c) 7 : 5 (d) 4: 7
part of the first and the eight part of the second are in
177. Two containers have acid and water mixed
the ratio 3 : 4.The first part is:
respectively in the ratio 3 : 1 and 5 : 3. To get a new
(a) 30 (b) 36
mixture with ratio of acid to water as 2 : 1 the two
(c) 40 (d) 28
types have to be mixed in the ratio :
187. The third proportional to 0.8 and 0.2 is:
(a) 1:2 (b) 2 : 1
(a) 0.05 (b) 0.8
(c) 2 : 3 (d) 3:1.
(c) 0.4 (d) 0.032
178. Acid and water are mixed in a vessel A in the ratio of 5
188. On mixing two classes A and B of students having
: 2 and If the vessel B in the ratio 8 :5. In what
average marks 25 and 40 respectively. The over all
proportion should quam tities be taken out from the
average obtained is 30. Find the ratio of the students
two vessels so as to form a mixture in which the acid
in the class A arid B.The mixing two classes A and B of
and water will be in the ratio of 9 : 4?
(a) 2 : 1 (b) 5 : 8
(a) 7: 2 (b) 2 : 7
(c) 5 : 6 (d) 3 : 4
(c) 7 : 4 (d) 2 : 3
189. A fruit seller sold big, medium and small sized apples
179. The ratio of spirit and water in towmixtures of 20 litre
for Rs. 15, Rs.10 andRs.5 respectively.The total
and 36 litres is 3 : 7 and 7 : 5 respectively. Both the
number of apples sold were in the ratio 3 : 2 : 5. Find
mixtures are mixed together. Now the ratio of the
the average cost of apples.
spirit and water in the new mixture is :
(a) 8 Rs. (b) 10 Rs.
(a) 25 : 29 (b) 9 : 10
(c) 9 Rs. (d) Rs. 7
(c) 27 : 29 (d) 27 :31
190. In a school the ratio of boys to girls is 4 : 3 and the
180. An alloy contains copper, zinc and nickel in the ratio of
ratio of girls,to teachers is 8 : 1.The ratio of students is
5 : 3: 2. The quantity of nickel (in kg) that must be
and teacher is:
added to 100 kg of this alloy to have the new ratio 5 : 3
: 3 is: (a) 56 : 3 (b) 55 : 1
(a) 8 (b) 10 (c) 49 : 3 (d) 56 : 1
(c) 12 (d) 15 191. If , then the value of x is
181. The ratio of the income to the expenditure of a family (a) 11 (b) 19
is 10 : 7. If the family's expenses are 10,500, then (c) 23 (d) 7
savings of the family is 192. A, B and C are Batsmen. The ratio of the runs scored by
(a) Rs. 4,500 (b) Rs. 10,000 them in a certain match are A : B =5 : 3, and B : C = 4 :
5. In all they scored 564 runs. The number of runs
(c) Rs. 4,000 (d) Rs. 5,000
182. The ratio of weekly income of A and B is 9 : 7 and the scored by B is : (a 124 (b) 104
ratio of their expenditures is 4 : 3. If each saves R 200 (c) 14 (d) 144
193. A milkman makes 20%profit by selling milk mixed
per week, them the sum of their weekly income is
with water at Rs. 9 per liter.If the cost price of 1 liter
(a) Rs. 3,600 (b) Rs. 3,200 pure milk is Rs.10, then the ratio of milk and water in
(c) Rs. 4,800 , (d) Rs. 5,600 the mixture is true.
183. The income of A and B are in the ratio 2 : 3 and their (a) 3 : 1 (b) 4 : 1
expenditures are in the ratio 1 : 2, If each saves K. (c) 3 : 2 (d) 4 : 3
24,000, find As income. 194. The ratio between sumit’s and Prakash’s age at
presentis 2 :3.Sumit is 6 years younger than
(a) Rs. 24,000 (b) Rs. 72,000
Prakash.The ratio of Sumit’s age to Prakash’s age after
(c) Rs. 19,200 (d) Rs. 48,000 6 years will be:
184. Ratio between the monthly incomes of A and B is 9 : 8 (a) 2 : 3 (b) 1 : 2
and the ratio between their expenditures is 8 : 7 .If (c) 4 : 3 (d) 3 : 4
they save Rs. 500 each, find A’s monthly income: 195. The number to be added to each of the numbers7 , 16,
(a) Rs. 3500 (b) Rs. 4000 43, 79to make the numbers in proportion is:
(c) Rs. 4500 (a) 2 (b) 3
(c) Rs. 5000 (c) 5 (d) 1

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196. Two numbers are such that the ratio between thenis 4 becomes 7 : 9, how many litres of liquid. A was
: 7. If each is increased by 4, the ratio becomes 3 : 5. contained by the vessel initially ?
The larger number is: (a) 10 litres (b) 20 litres
(a) 36 (b) 48 (c) 21 litres (d) 25 liters
206. If the annual income of A,B and C are in the ratio 1 : 3 :
(c) 56 (d) 64
7 and the total annual income of A and C is Rs. 800000,
197. The students in three classes are in the ratio 4 : 6 : 9.If
then the monthly salary of B (In Rs.) Is :
12 students are increased in each class the ratio
changes to 7 : 9 : 12.Then the total number of students (a) 20000 (b) 25000
in the three classes before the increase is: (c) 30000 (d) 15000
(a) 95 (b) 76 207. Annual incomes of Amit and Veer are the ratio 3 : 2,
(c) 100 (d) 114 while the ratio of their expenditure is 5 : 3. If at the
198. If there is a reduction in the number of workers in a énd of the year each saves Rs. 1,000. The annual
factory in the ratio 15 : 11 and an increment in their income of Amit is:
wage in the ratio 22 : 25, then the ratio by which the (a) Rs. 9,000 (b) Rs. 8,000
total wage of the workers should be decreased is:
(c) Rs. 7, 000 (d) Rs. 6,000
(a) 6 : 5 (b) 5 : 6 208. The ratio of the income of A and B as well as of B and C
(c) 3 : 7 (d) 3 : 5 is 3 : 2 If one third of A's income exceeds one fourth of
199. Two numbers are in the ratio of3: 5 .If 9 be subtracted C's income by 3 1000, what is B's income in Rs. ?
from each, then they are in the ratio of 12 : 23.Find the
numbers. (a) 3000 (b) 2500
(a) 15, 28 (b) 36, 115 (c) 3500 (d) 4000
(c) 33, 55 (d) 60 , 69 209. The price of a refrigerator and a television set are in
200. A and B are two alloys of gold, and copper prepared by the ratio 5 : 3, If the refrigerator costs Rs. 5500 more
mixing metals in ratios 7 : 2 and 7 : 11 respectively. If than the television set, then the price of the
equal quantities of the alloys are melted to form a refrigerator is :
third alloyC, the ratio of gold and copper in C will be : (a) Rs. 27500 (b) Rs. 8250
(a) 7: 5
(c) Rs. 13750 (d) Rs. 16500
(c) 9: 5 (b) 5:9 (d) 5: 7
210. The ratio of successful and unsuccessful examinees in
201. A container contains 60 litre of milk. From this
an examination in a school is 6 : 1. The ratio would
container 6 litre of milk was taken out and replaced by
have been 9 : 1 if 6 Imore examinees had been
water. This process was repeated 207, further two
successful. The total number of examinees is:
times. The amount of milk left in the container is
(a) 140 (b) 120
(a) 34.24 litre (b) 39.64 litre
(c) 200 (d) 160
(c) 43.74 litre (d) 47.6 litre
211. A box filled with paper bundles weights 36 kg. If the
202. Two vessels A and B contain milk and water mixed in
weight of the box and paper bundles respectively are
the ratio 8: 5 and 5 :2 respectively. The ratio in which
in the ratio of 3 : 2j then the weight of paper (in
these two mixtures be mixed to get a new mixture
grams) is:
containing 900/13 % milk:
(a) 30680 grams (b) 30710 grams
(a) 3 : 6 (b) 5 : 2
(c) 3 1500 grams (d) 31680 grams
(c) 5 : 7 (d) 2 : 7
212. Two numbers are such that the square of one is 224
203. Two vessels contains milk and water in the ratio 3 : 2
less than 8 times the square of the other. If the
and 7 : 3. Fiond the ratio in which the contents of the
numbers are in the ratio of 3 : 4, then their values are :
two vessels have to be mixed to get a new mixture in
which the ratio of milk and water is 2 : 1. (a) 12, 16 (b) 6,8
(a) 2 : 1 (c) 9, 12 (d) 12,9
(c) 4: 1 (b) 1 : 2 (d) 1 : 4 213. If A : B is 2 : 3, B : C is 6 : 11, then A : B : C is:
204. In two types of stainless steel the ratio of chromium (a) 2: 3:11 (b) 4: 6: 22 (с) 4 : 6 : 11 (d) 2: 6
and steel are 2 :11 and 5: 21 respectively. In what : 11
proportion should the two types be mixed so that the 214. If two- third of A is four-fifth of B, then A : B = ?
ratio of chromium to steel in the mixed type becomes (a) 5:6 (b) 6:5
7: 32 ? (c) 10 : 9 (d) 9 : 10
(a) 2: 3 (b) 3: 4 215. If (a +b) : (b+c) : (c + a) = 6:7: 8 and (a+b+c) = 14, then
(c) 1 : 2 (d) 1 :3 the value of c is:
205. A vessel contains a mixture of two liquids A and B in (a) 6 (b) 7
the ratio 7 : 5, When 9 litres of mixture is drained off (c) 8 (d) 14
and the vessel is filled with B, the ratio of A and B 216. If 5.5 of a = 0.65 of b, then a : b is equal to :

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 (a) 13: 11 (b) 11 : 13 (a) 145 (b) 185
(c) 13:110 (d) 110:13 (c) 295 (d) 155
217. The ratio of boys and girls in a college is 5 :3. If 50
229. The ratio of number of balls in bags x, y is 2 : 3. Five
boys leave the college and 50 girls join the college, the balls are taken from bag y and are dropped in bag
ratio becomes 9 :7. The number of boys in the college number of balls are equal in each bag now, Number of
is :
balls in each bag now is:
(a) 300 (b) 450
(c) 500 (d) 600 (a) 45 (b) 20
218. A person distributes his pens among four friends A, B, (c) 30 (d) 25
C, D in 1/3, 1/4, 1/5, 1/6. What is the ratio minimum 230. If the square of the sum of two numbers is equal to 4
number of pens that the person should have? times of their product, then the ratio of these numbers
(a) 57 (b) 65 is:
(c) 75 (d) 45 (a) 2:1 (b) 1 : 3
219. If A 2/3 of B and B = 4/5 of C, then A:B:C is. (c) 1: 1 (d) 1 : 2
(a) 12:8: 10 (b) 15: 10 : 8 231. Three numbers are in the ratio 2 : 3 : 4. If the sum of
(c) 10: 15 : 12 (d) 8 : 12 : 15 their squares is 1856, then the numbers are:
220. The ratio of 252.5 : 53 is same as (a) 8, 12 and 24 (b) 16 , 24 and 32
(a) 5 : 3 (b) 5 : 6 (c) 12, 18 and 24 (d) None of these.
(c) 1 : 25 (d) 25 : 1 232. Three numbers are in the ratio 1 : 2 : 3. By adding 5 to
221. The third proportional of 12 and 18 is: (а) 3 each of them, the new numbers are in the ratio 2 : 3 : 4.
(b) 6 The numbers are:
(c) 27 (d) 144 (a) 10,20,30 (b) 15,30,45
222. If x runs are scored by A, y runs by B and z runs by C, (c) 1,2,3 (d) 5,10,15
then x : y = y : z = 3 : 2. scored by A, B and C is 342, the 233. Ram got twice as many marks' in English as in Science,
runs scored by each respectively. His total marks in English, Science and Maths are 18O.
(a) 144,96, 64 (b) 162,108,72 If the ratio of his marks in English and Maths is 2 : 3, .
(c) 180,120, 80 (d) 189, 126,84 what is his marks in Science?
223. If A : B =3: 4 and B : C = 6: 5, then C : A is: (a) 30 (b) 60
(a) 10 : 9 (c) 72 (d) 90
(c) 8 : 9 (b) 9:10 (d) 9 : 8 234. The ratio in which a man must mix rice at Rs. 10.20
224. Find two mean proportional between 2 and 54, per kg and Rs. 14.40 per kg so as to make a mixture
(a) 6 and 18 (b) 6 and 12 worth Rs. 12.60 per kg. is:
(c) 12 and 18 (d) 6 and 9
(a) 4: 3 (b) 2 : 5
225. A man ordered 4 pairs of black socks and some pairs
of brown socks. The price of a pair of black socks is (c) 18: 24 (d) 3 : 4
double that of a brown pair. While preparing the bill 235. The proportion of acid and water in three samples is 2
the clerk interchanged the number of black and brown : i, 3 : 2 and 2 5 : 3, A mixture containing equal
pairs by mistake which increased the bill by 50%. The quantities of all three samples is made. The ratio of
ratio of the number of black and brown pairs of socks acid and water in the mixture is:
in the original order was : (a) 12: 133
(a) 2 : 1 (b) 1 : 4 (c) 3:8 (b) 227 : 133 (d) 5:11
(c) 1 : 2 (d) 4 : 1 236. Two alloys are both made up of copper and tin. The
226. The ratio of two boys is 5 : 6. After two years the ratio ratio of copper and 23. tin in the first alloy is 1 : 3 and
will be 7 : 8. The ratio of their are after 12 years will in the second alloy is 2 : 5. In what ratio should the
be: two alloys be mixed to obtain a new alloy in which the
ratio of tin and copper be 8: 3 ?
(a) 22/24 (b) 15/16
(a) 3 : 5 (b) 4: 7
(c) 17/18 (d) 11/12
227. . The resent age of two persons are36 and 50 years (c) 3 : 8 (d) 5: 11
respectively. If after years the ratio of their age will be 237. A mixture contains alcohol and water in the ratio 4 : 3,
3: 4, then the value of n is: If 5 litres of water is added to the mixtures the ratio
becomes 4 : 5. The quantity of alcohol in the given
(a) 4 (b) 7
mixture is :
(c) 6 (d) 3
(a) 3 litres (b) 4 litres
228. Of three positive numbers, the ratio of 1st and 2nd is 8
: 9, that of 2nd and 3rd is 3 : 4. The product of 1st and (c) 15 litres (d) 10 litres
3rd is 2400. The sum of the three numbers is: 238. In two alloys A and B, the ratio of zinc to tin is 5 : 2 and
3 : 4 respectively. 7 kg. of the alloy A and 21 kg. of the

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 alloy B are mixed together to from a new alloy. What (a) 150,250,300 (b) 160,240,300
will be the ratio of zinc and tin in the new alloy? (c) 150,250,290 (d) 150,240,310
(a) 2 : 1 (b) 1 : 2
249. Divide Rs. 2600 among A,B,C in the ratio 1/2 : 1/3 :
(c) 2 : 3 (d) 1 : 1 1/4. Find the share of each.
239. Zinc and copper are in the ratio 5 : 3 in 400 gm of an
alloy. How much of copper (in grams ) should be (a) Rs. 1,200, Rs. 600, Rs. 800 (b) Rs. 1,200, Rs.
added to make the ratio 5 : 4 ? 800, Rs.600
(a) 50 gm (b) 66 gm (c) Rs. 600, Rs. 800, Rs.1,200 (d) Rs. 800, Rs. 600, Rs.
1,200
(c) 72 gm (d) 200 gm 250. A sum of k 300 is divided among P,Q and R in such a
240. A person bought some rice and wheat for Rs. 380. The
way that Q gets R 30 more than P and R gets Rs. 60
ratio of weight of rice and wheat is 4 : 3 and the price
of equal amount of rice and wheat is in the ratio 5 : 6. more than Q. The ratio of their share is :
The rice was bought of worth (a) 5 : 3: 2 (b) 2: 3: 5
(a) Rs. 380 (c) 3:2: 5 (d) 2 : 5 : 3
(c) Rs. 200 (b) Rs. 300 (d) Rs. 180 251. Rs. 900 is divided among A, B, C, the division is such
241. The ratio of monthly incomes of A and B is 6 : 5 and that ½ of A’s money 1/3 of B's money =1/4 of C’s
their nonthly expenditures are in the ratio of 4 : 3. If money. Find the amount(in Rs.) received by A, B, C.
each of then saves Rs. 400 per month, find the sum of (a) 300,400,200 (b) 350,450,100
their monthly incomes, (c) 200,300,400 (d) 400,150,350
(a) 2300 (b) 2400 252. If Rs. 126.50 is divided among A,B, and C in the ratio of
(c) 2200 (d) 2500 2 : 5 :4, the share of B exceeds that of A by
242. There are 480 coin of half rupees, quarter rupees and (a) Rs. 36.50 (b) Rs. 35.50
10 paise coins and their values are proportional to 5 : (c) Rs. 34.5) (d) Rs. 33.50
3 : 1. The number of coins in each case are: 253. A sum of Rs. 76 is divided among A, B and C in such a
(a) 100,290, 180 (b) 50,30,400 way that A gets Rs. 7 more than B gets and B gets Rs. 6
(c) 150, 180 , 150 (d) 300,90,90 more than what C gets. the ratio of their share
243. A box contains 420 coins of 1 rupees 50 paise and 20 (a) 19 : 24 : 33 (b) 32 : 25 : 19
paisa coins, The ratio of their values is 13 : 11 : 7. The (c) 32: 24 : 20 (d) 19: 25 : 33
number of 50 paise coins is: 254. Rs. 3000 is divided between A,B and C so that A
(a) 42 (b) 78 receives 1/3 as much as B and C together receive and
B receives 2/3 as much as A and C together receive
(c) 66 (d) 132 than. then the share of C is:
244. A box contains Rs. 56 in the form of coins of one rupee,
50 paise and 25 paise. The number of 50 paise coins is (a) 600 (b) 525
double the number of 25 paise coins and four times (c) 1625 (d) 1025
the number of one rupee coins. How many 50 paise 255. Which of the following represents a correct
coins are there in the box? proportion?
(a) 52 (b) 64 (a) 12: 9:16 :: 12 (b) 13: 11 :: 5: 4 (b) 30: 45::13 :
(c) 32 (d) 16 24 (d) 3 : 5 :: 2: 5
245. Rs. 738 is divided among A, B, C so that their shares 256. If 8, x and 50 are in continued proportion, then the
are in the ratio of 2 : 3 : 4. B's share is : value of x is:
(a) Rs. 328 (b) Rs. 246 (a) 30 (b) 20
(c) Rs. 264 (d) Rs. 164 (c) 5 (d) 32
246. 1740 is divided among A, B, and C such that 0.5 of A = 257. If A : B = 7 : 9 and B : C = 3 : 5 then A : B : C is equal to:
0, 6 of B = 0.75 of C. Then C will get (a) 7 : 9 : 5 (b) 21: 35 : 45
(a) Rs. 580 (b) Rs. 696 (c) 7: 9 : 15 (d) 7 : 3 : 15
(c) Rs. 348 (d) Rs. 464 258. The ratio of the length of a school ground to its width
247. A sum of Rs. 53 is divided among A, B and C in such a is 5 : 2. If the width is 40 m, then the length is :
way that A gets Rs. 7 more than what B gets and B gets (a) 200m (b) 100m
Rs. 8 more than what C gets. The ratio of their share is: (c) 50 m (d) 80 m
259. The ratio of the ages of two persons is 4 : 7 and the age
(a) 16:9 : 18 (b) 25: 18 : 10
of one of them is greater than that of the other by 30
(c) 18: 25 : 10 (d) 15: 8 : 30 years. the sum of their ages (in years) is:
248. Rs. 700 is divided among A, B, C in such a way that the (a) 110 (b) 100
ratio of the amount of A and B is 2: 3 and that of B and (c) 700 (d) 40
C is 4 : 5. Find the amount (in & ) each received, in the 260. The sum of the numbers is equal to 20 and the
order A, B, C, difference is 25. The ratio of the two number is:

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 (a) - 9 : 1 (b) – 7 : 9 (c) 65 (d) 78
(c) 3 : 5 (d) 2 : 7 271. Two alloys contain tin and iron in the ratio of 1 : 2 and
261. What number should be subtracted from both terms of 2 : 3. If the two alloys are mixed in the proportion of 3:
the ratio 11 : 15 so as to make it as 2 : 3 ? 4 respectively (by weight), the ratio of tin and iron in
(a) 2 (b) 3 the newly formed alloy is:
(c) 4 (d) 5 (a) 14: 25 (b) 10: 21
262. There are two containers of equal capacity. The ratio (c) 12: 23 (d) 13: 22
of milk to water in the first container is 3 : 1 and in the 272. If two number are in the ratio 2: 3 and the Ratio
second container is 5 : 2. If they are mixed up, the ratio becomes 3 : 4when 8 is added to both the number,
of milk to water in the mixture will be: then the ratio of two number is:
(a) 28 : 41
(a) 90 (b) 50
(c) 15: 41 (b) 41: 28 (d) 41 : 15 (c) 60 (d) 40
263. Two equal glasses filled with alcohol and water in the 273. If x/y = ¾, the ratio of (2x + 3y) and (3y – 2x) is:
proportions 2 : 1 and 3:2 are emptied into a third
(a) 2 : 1 (b) 3 : 2
glass. The proportion of alcohol and water in the third (c) 3 : 1 (d) 1 : 1
glass will be: 274. Incomes of x and y are in the ratio 4 : 3. Their
(a) 13: 17 (b) 19: 17 expenditures are in the ratio 12 : 7, Both salve Rs.
(c) 13 : 11 (d) 19: 11 3200 at the end of the month, then the income of x is ?
264. A box contains 280 coins of one rupee, 50-paise and (a) Rs. 4000 (b) Rs. 6000
25- paise. The values of each of the coins are in the 8: 4 (c) Rs. 8000 (d) Rs. 2000
: 3. Then the number of 50 paise coins is: 275. A and B have their monthly incomes in the ratio 8:5
(a) 70 (b) 60 while their monthly expenditures are in the ratio 5 : 3,
If they have saved Rs. 12,000 and Rs. 10,000 monthly
(c) 80 (d) 90
respectively, then the difference in their monthly
265. Rs. 555 was to be divided among A, B and C in the ratio
income is:
of 1/4: 1/5 : 1/6. But by mistake it was divided in the
(a) 42000 (b) 52000
ratio 4 : 5 : 6, The amount in excess received by C was:
(c) 46000 (d) 4000
(a) Rs. 72 (b) Rs. 75
276. In a school there were 1554 students and the
(c) Rs. 22 (d) Rs. 52
266. A man divides his property so that his son's share to ratio of the number of the boys and girls was 4
his wife's and wife's share to his daughter's are both : 3. After few days, 30 girls joined the school
as in the ratio 3 : 1. If the daughter gets R 10,000 less
than son, the value (in rupees) of the whole property but few boys left: as a result the ratio of the
is: boys and girls became 7 : 6. the number of
(a) Rs. 16,250 (b) Rs. 16,000
boys who left the school is:
(c) Rs. 18,250 (d) Rs. 17,000
267. A policeman starts to chase a thief. When the thief (a) 76 (b) 84
goes 10 steps the policeman moves 8 steps and 5 steps (c) 86 (d) 74
of the policeman are equat to 7 steps of the thief. The 277. If (x3 –y3) : (x2 +xy +y2) = 5:1 and (x2 – y2) : (x - y) = 7 :
ratio of the speeds of the policeman and the thief is: 1, then the ratio equals :
(a) 25: 28 (b) 25 : 26 (a) 3 : 2 (b) 2 : 3
(c) 28 : 25 (d) 56 : 25 (c) 4 : 3 (d) 4: 1
268. Tom is chasing Jerry. In the same interval of tire Tom 278. If A : B = ½ : 1/3, B:C = 1/6 : 1/3 then (A + B) : (B + C)
jumps 8 times while Jerry jumps 6 times. But the is equal to:
distance covered by Tom in 7 jumps in equal to the (a) 5: 8 (b) 15: 16
distance covered by Jerry in 5 jumps. The ratio of (c) 9 : 10 (d) 6: 15
speed of Tom and Jerry is : 279. In a library the ratio of story books and other books is
7 : 2 and there are 1512 story books. Due to collection
(a) 48 : 35 (b) 28 : 15
of some more story books the said ratio becomes 15 :
(c) 24 : 20 (d) 20 : 21 4. The number of story books collected is:
269. If A and B are in the ratio 4 : 5 and the difference of (a) 108 (b) 205
their squares is 81, what is the value of A P? (c) 100 (d) 97
(a) 36 (b) 445 280. 2 kg mixture of copper and aluminium, 30% is copper.
(c) 15 (d) 12 How much aluminium powder should be added the
270. What must be added to each term of the ratio 2 : 5 so mixture so that the quantity of copper becomes 20%?
that it may equal to 5 : 6 ? (a) 900 gms (b) 800 gms
(a) 12 (b) 13 (c) 1000 gms (d) 1200 gms

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281. A bag contains coins of Rs. 1, 50 paise and 25 paise in 19 c 20 d 21 a 22 c 23 d 24 a
the ratio 2 : 3 : 5. If the total value of these coins is Rs. 25 b 26 d 27 a 28 c 29 c 30 c
228, then the number of 50 paise coins in that bag 31 a 32 c 33 d 34 d 35 a 36 a
was:
37 b 38 b 39 b 40 c 41 c 42 d
(a) 144 (b) 124
(c) 112 (d) 96 43 c 44 b 45 b 46 a 47 d 48 a
282. Divide 27 into two parts so that 5 times the first and 49 a 50 c 51 a 52 b 53 a 54 d
11 times the second together equals to 195. Then ratio 55 c 56 a 57 d 58 b 59 c 60 c
of the first and second parts is: 61 a 62 d 63 d 64 a 65 b 66 c
(a) 3 : 2 (b) 17: 10 67 b 68 c 69 c 70 d 71 c 72 b
(c) 2 : 7 (d) 5 : 4 73 a 74 a 75 d 76 c 77 d 78 d
283. A mixture contains milk and water in the ratio 5 : 1. On 79 d 80 a 81 c 82 d 83 a 84 c
adding 5 litres of water, the ratio of milk and water 85 b 86 b 87 b 88 a 89 a 90 c
becomes 5:2. The quantity of milk in the mixture is: 91 c 92 b 93 a 94 c 95 b 96 c
(a) 16 litres (b) 25 litres
(c) 32.5 litres (d) 22.75 litres
97 d 98 d 99 d 100 a 101 a 102 d
284. The sides of a triangle are in the ratio of 7:9:12. The 103 c 104 a 105 c 106 d 107 b 108 b
difference between the lengths of largest and smallest 109 b 110 b 111 b 112 a 113 b 114 a
sides is 15 cm. The length of the largest sides would 115 b 116 d 117 d 118 d 119 c 120 c
be: 121 c 122 c 123 a 124 a 125 d 126 d
(a) 36 cm (b) 12 cm 127 c 128 c 129 a 130 c 131 b 132 c
(c) 60 cm (d) 24 cm 133 c 134 d 135 a 136 c 137 b 138 d
285. The three successive angles of a cyclic quadrilateral
are in the ratio 1:3:4, find the measure of the forth
139 c 140 a 141 b 142 c 143 a 144 c
angle? 145 c 146 c 147 a 148 d 149 d 150 b
(a) 72° (b) 30° 151 b 152 d 153 a 154 b 155 d 156 b
(c) 36° (d) 108° 157 c 158 b 159 d 160 d 161 c 162 c
286. The current ages of Sonali and Monali are in the ratio 5 163 d 164 c 165 a 166 c 167 b 168 c
: 3. Five years from now, their ages will be in the ratio 169 c 170 c 171 c 172 a 173 b 174 a
10 : 7 Then, Monali current age is: 175 d 176 b 177 a 178 a 179 c 180 b
(a) 3 years (b) 5 years
(c) 9 years (d) 15 years 181 a 182 d 183 b 184 c 185 c 186 a
287. If A : B = 2 : 1 & A. : C = 1: 3, then A : B : C is : 187 a 188 a 189 c 190 a 191 b 192 d
(a) 2 : 1 : 6 (b) 1 : 3 : 2 193 a 194 d 195 c 196 c 197 b 198 a
(c) 1 : 2 : 6 (d) 3: 2 : 1 199 c 200 a 201 c 202 d 203 b 204 c
288. Two numbers are in ratio 5 : 8, If their difference is 48, 205 c 206 b 207 d 208 a 209 c 210 a
then then smallest numbers is: 211 d 212 b 213 c 214 b 215 a 216 c
(a) 64 (b) 80 217 c 218 a 219 d 220 d 221 c 222 b
(c) 96 (d) 128 223 a 224 a 225 b 226 c 227 c 228 a
289. If a/b = 7/9, b/c = 3/5, then the value of a:b:c is: 229 d 230 c 231 b 232 d 233 a 234 d
(a) 7 : 3 : 15 (b) 7: 9 : 15
235 b 236 b 237 d 238 d 239 a 240 d
(c) 7 : 9 : 5 (d) 21: 35 : 45
290. If a:b = 4:5, b:c = 5:6, and c:d = 6:7, then a:c is: 241 c 242 c 243 d 244 b 245 b 246 d
а) 5 : 6 (b) 3: 4 247 b 248 b 249 b 250 b 251 c 252 c
(c) 2:3 (d) 4 : 5 253 b 254 d 255 a 256 b 257 c 258 b
291. If a/b = c/d = 5, then equal to : 259 a 260 a 261 b 262 d 263 d 264 c
(a) 5 (b) 20 265 a 266 a 267 c 268 d 269 d 270 b
(c) 60 (d) 15 271 d 272 d 273 c 274 c 275 a 276 a
292. If x : y = 3 : 5 and x – y = - 2, then the value of x : y is: 277 d 278 b 279 a 280 c 281 a 282 b
(a) 8 (b) 2 283 b 284 a 285 a 286 c 287 a 288 b
(c) 3 (d) 5 289 b 290 c 291 a 292 a
ANSWER :
1a 2c 3c 4b 5c 6b Detailed solutions
7d 8b 9c 10 d 11 a 12 c 1. (a) a : b and b : c
13 a 14 c 15 c 16 c 17 c 18 c 7:9 5:7

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 a:b
6. (b) 1 Rs. : 50 p : 25 p
b : c 2 : 3 :4
 
7 :9
5 : 7

35 : 45 : 63
a : c 
35 : 63
5 :9  number of coins of (50 p)
2. (c)  40×3 = 120
3 x = y and 2 y = z 7. (d) A : B : C
x:y y:z
1:3 1:2 Original ratio
x:y:z 
1:3
6:4:3
1:2
1 :3 : 6 
A = 9×6 = 54
3. (c) A : B B = 9×4 = 36 (original)
3x : 8x C = 9×3 = 27
Given, 8x – 3x = 115 But A : B : C
5x = 115 2 : 3 : 4 (Erroneous ration
x = 23
 smaller number
= 23 × 3 = 69
3 : 8 A = 13×2 = 26 (by mistake)
5 units B = 13×3 = 29 money
Alternate : C = 13×4 = 52 distributed
5 units = 115  C gains most
1 unit = 23 52–27  25
3 units = 23×3 = 69
4. (b) A : B : C : D 8. (b)
1 : 2 : 3 : 4 9A = 2B 4C = 3A
A : B and C : A
2:9 3:4
B:A:C
A+D 9:2
= 8
4:3
5. (c) A:B
Before 2 :1  36 : 3 : 6
After 1 :1 18 : 4 : 3
 A gives B two rupees 
 =  A = 4×50 = 200
B = 18×50 = 900
4 C = 3×50 = 150
 A = 2×4 = 8
B = 1×4  8 9. (c) p : q r : s t : 4

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 2:3 2:3 2:3


 Let p =

14. (c) m : n = 3 : 2


= (4m+5m) = (4m–5n)
 ( )
 
= ( )

=   

11 : 1
10. (d) a:b=c:d=e:f 15. (c) A +B = 40
1:2 1:2 1:2 A–B=4
 A = 22
Let B = 18
A : B = 22 : 18 = 11 : 9
16. (c) A : B : C

2:1

4:1
 =8:4:1
17. (c) each exterior angle of a n sided
11. (a) polygon is = ( )

and each internal angle of n sided polygon
( )
 
( )

( )
=
( )
Taking common
 
18. (c)
12. (c) 12, 21, 8,
12 : 21 : : 8 : 126 – 21x < 112 – 16x
For the proportional 126 – 112 < 21x – 16x
= 12 × = 21×8 14 < 5x
14
# a : B :: c : d 2.8 <
(d) Fourth proportional
a×d= b×c 19. (c) son : Daughter : nephew
# a : b :: b : c S :D : N
(c) Third proportional D:N S:N
4:1 5:1

13. (a) 2
1.5
: 20.5  5 son =

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 4 Daughter = B1 : B2
2 nephew = Present 2 : 4
 1
(total money) 5 years 1 : 3
Back 2
1 unit = 5 years
 each daughter = 200×4 Ages of B1 and B2 after 5 years
= 800 Rs. (2+1) : (4+1)
3 : 5
20. (d) A : B B : C C:D
3 :4 5:7 8:9 23. (d) A : B
1
4 years ago 2×2 : 3×2

4 years after 5 : 7
2
A : D = 10 : 21 The difference between ages always remains
21. (a) Harsha = 40 same, so multiply
Ritu = 60 By 2 in 4 years ago ratio

 let x years ago their ages ratio

Was 3 : 5 A : B
 4 years ago → 4 : 6
1
4 years after→ 5 : 7
1 unit = 8 year
Or Ages of A and B after 4 years are
Harsha : Ritu A = 5×8 = 40 years.
20 B = 7×8 = 56 years.
Now → 40 : 60 Hence, Present ages of A & B = 36, 52

Before → : 24. (a) A : B = 10 : 7

2
The difference between ages always
remains same, so multiply by 10 in  sum  A + B
The before ratio.
So, 17×35  595
Now 40 60 Alternate : -
10 3
Before 30 50 Ratio = 10 : 7
60–50 = 10 years 3 unit → 105
1 unit →35
22. (c) B1 : B2 Sum of numbers
1 = 10+7 = 17 units
Present 1×2 : 2×2 = 17×35 = 595

5 years 1 : 3
Back 2 25. (b) A : B
The difference between ages al- 9 : 7
ways remains same, so multiply
by 2 in present ratio

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 63 = 1575 2 2 2
 25 4:5:7 after adding 40
student in
each class
 smaller number
2 units = 40
= 5×7 = 35
1 unit = 20
Largest number
= 5×9 = 45  originally
26. (d) a : b = 5 : 7 A:B:C
Now reducing 40 from each 2×20+3×20+5×20
40+60+100 = 200 students.
30. (c) A:B:C
  originally 2:3:5
  2 2 2
  after adding 4 : 5 : 7
 25 20 student in
Difference = A – B  each class
2 unit = 20
1 unit = 10
27. (a) Boys : Girls = 13 : 11  originally
 2×10+3×10+5×10
 504 20+30+50 = 100

 number of Boys 31. (a) Zinc : Coper

= 21×13 = 273 5 : 3
Number of Girls
= 11×21 = 231
Now 12 more girls admitted
231+12  243 Zinc =
 Boys : Girls Coper =
273 : 243  after adding gram coper ratio becomes 3 : 5
   
28. (c) A : B
3x, 400 = 3x
(take L.C.M of denominator
gm.
and multiply)
 32. (c) Coper : Zinc
= 13 : 7
After adding 15 in each we get 13x + 7x = 100 kg
   20x = 100
= cross multiply X = 5kg
Zinc = 7×5 = 35 kg
   Zinc is 35 kg
 

smaller number
= 9×3 = 27
Greatest number
= 16×3 = 48
29. (c) A : B : C 33. (d) acid : water = 2x : 3x
2:3:5 originally 5x : 30 given
x=6

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 acid = 6×2 = 12
water = 3×6 = 18 37. (b) A:B B : C
 Let x gram of water added to make it 2 : 5 6:5 10 : 9
   A:B:C
6:5
x
24 = 2x
10 : 9
x = 12 ltr
60 : 50 : 45
ALTERNATE : -
12 : 10 : 9
Acid : water
x + 10x + 9x x
2 : 3
31x = 1240
Same 2
X = 40
2 : 5
Total = 2+3 = 5 unit = 30 ltr.  Share of C = 9×40 = 360
1 unit = 6 ltr.
2 units = 6×2 = 12 ltr.(water) 38. (b) A + B = 158
C = 158 – 101 = 57 Rs.(given)
34. (d) Income = Expenditure = saving B = 57+13 = 80 Rs.
A : B – 80 = 78 Rs.
Income 5x : 6x 39.
(b) a : b =2:3
Expenditure 3y : 4y
Saving 1800 : 1600 b:c =4:5
  d:c =7:6
x – 7200 = 18x – 4800 A : B : C : D
2x = 2400 x : y
x = 1200
 income of B = 1200×6 = 7200 p q
35. (a) A : B
Income 5 : 6 m : n
Expenditure 9 : 5 xpm : ypm : yqm : yqn
Saving 1300 : 900
 40. (c) B1 : B2
1
 25x – 6500 = 27x – 8100
Present 5 : 6
2x = 1600
2 2
X = 800
After 2 years 7 : 8
 Incomes of A & B are
1
A = 5x = 5×800 = 4000 Rs.
2 units = 2 years
B = 3x = 3×2400 = 7200 Rs.
1 unit = 1 year
 Present ages
36. (a) A : B B:C
B1 : 5×1 = 5 years
5:2 7 : 13
B2 : 6×1 = 6 years
A:B:C
 after 12 years
5:2
B1 : B2
5+12 6+12
 7 : 13
17 : 18
35 : 14 : 26
 35x + 14x + 26x x =
75x = 7500
x = 100
B  14×100 = 1400 Rs.

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

41. (c) A : B : C 7 : 11 7 : 11 7 : 11
3 : 2 : 5 4
3x : 2x : 5x  3 unit = 9
A2 + B2 + C2 = (3x)2 + (2x)2 + (5x)2 1 unit = 3
9x2 + 4x2+25x2 = 38x2  B – A = 14 – 10 = 4 units
x2 = 1862 = 4×3 = 12
x2 =   49
x=7 45. (b) A : B = 3: 5
 A = 3×7 = 21
B = 2×7 = 14  69x – 207 = 60x – 108
C = 5×7 = 35 69x – 60x = 207 = 60x – 108
Hence, smallest is 14 9x = 99  x = 11
 smaller no. is
42. (d) A + B + C = 116 3×11 = 33
A:B:C Alternate :
9 : 16 A : B A : B A : B
2
1 : 4 Initially 3 : 5 3 ×11 : 5×11 33 : 55
16 : 36 : 64  9
 16x+36x+64x = 116 9
116x = 116 New 12 : 23 12 ×2 : 23×2 24 :
X=1 46
 B = 36x = 36×1 = 36 11
 Number are 33, 55.
43. (c) A + B + C = 98 Hence , smaller is 33
A : B : C 46. (a) copper : zinc
2 : 3 5 : 2
5x : 2x
5 : 8 5x + 2x =  7x =
10 : 15 : 24
10x + 15x + 24x = 49x 
49x = 98  copper
X=2  5x
 2nd number (B)
Zinc  2x =
2×15 = 30
Now, after adding 1.250 kg zinc
44. (b) A : B  zinc become
5x : 7x 5 + 1.250 = 6.250 kg
=
 (cross multiply)
 New ratio becomes
55x – 99 = 49x–63
Copper : Zinc =
 6x = 36  x = 6
Difference = 7x – 5x = 2x =2 : 1
= 2×6 = 12 47. (d) spirit : water
Alternate : 3x : 2x
X = 3 liter
A : B A : B A : B  Spirit = 3×3 = 9 liters
2
5 : 7 5 ×2 : 7×2 10 : 14 
 

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 52. (b) Total rupees = 90 Rs.
 50p : 25p : 10paise
48. (a) milk : water Coins 2x : 3x : 5x
7 : 3
Values
7x + 3x = 10x
10x = 30 liter  
X = 3 liter
Milk = 7×3 = 21 =90
Water = 3×3 = 9 90 x = 3600
let water be added y liters
So, = =40

147 = 27+3y 25 paise coins are 25 = 40×3 = 120

3y = 147 – 27
3y = 120 53. (a) A : B : C : D = 3400
Y = 40 liter A : B : C : D
2 : 3
49. (a) Let, income of A, B and C are 7x, 9x and 12x
respectively 4 : 3
 and expenditure of A, B and C are 8y, 9y and
15y respectively 2 : 3
 income of 16 : 24 : 18 : 27
 16 : 24 : 18 : 27
16x 24x + 18x + 27x = 3400
 7x – 8y = 85x = 3400
 28x–32y = 7x  40
21x = 32y share of B + D is = 24x + 27x = 51 x
 32 : 21 = 51×40 = 2040 Rs.
 The ratio of saving of A, B and C
(7x–8y) : (9x–9y) : (12x–15y) 54.
(d)
(7×32–8×21) : (9×32–9×21)
(12×32–15×21) A:B:C
(224–168) : (288–189) : (384–315) 3:4
56 : 99 : 69 3:4
50. (c) 1 unit = 600 Rs. 9 : 12 : 16
 Income of P = 3 units = 3×6000 = 18000 9x + 12x + 16x = 370
= 37x = 370
X = 10
 9x–18000 = 8x – 12000 A’s share is
 x = 6000 = 9×10 = 90
income of P = 3x = 3×6000 = 18000 Rs.
51. (a) Total coins = 378 55. (c) A : B
Ratio of values → 13 : 11 : 7 17 : 45
In Rs. 1, no. of Rs. 1 coins = 1 17x : 45x (given)
In Rs. 1, no. of 50 p coins = 2 
In Rs. 1, no. 25 p coins = 4
  9x
Ratio of Rs. 1, 50 p, 25 p coins
= 1 : 11×2 : 7×4 17x +45 = 27x
= 1 22 : 28 10x = 45
=
smaller number

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 Finally (1 : 1) ×2 = 4
2 : 2
Now, we have to add water so, we
have to equalize wine proportion
56. (a) A : B : C Wine : Water Wine : Water
(3 : 1)×2 6 : 2
4
Take LCM of 2,3, 5 = 30 (2 : 2)×3 6 : 6  quantity
A : B : C 4 of mixtures
: : Required Part =
15 : 10 : 6
 15x + 10x + 6x = 6200 59. (c) Income  expenditure + saving
31x = 6200 Now given
X = 200 Expenditure : saving
A = 15×200 = 3000 26x : 3x
B = 10×200 = 2000 Income = 26x +3x = 29x
C = 6×200 = 1200 29x = 7250
57. (d) milk : water X  250
2 : 1  savings = 250×3 = 750
2x +x = 45 60. (c) Rs. 1: 50 paise : 25 paise
X = 15 No. of coins 8x : 5x : 3x
 milk = 2×15 = 30 liter
Value of coins
Water = 1×15 = 15 liter
   
x Given = 225
X = 45 liter 45x = 225×4
X = 5×4 = 20
Alternate : -
 no. of one rupees coins
M : W M : W M : W
= 20×8 = 160
Old ratio 2 : 1 2 : 1 2 : 1
3 61. (a) A : B : C
New Ratio 1 : 2 1×2 : 2×2 2 : 4 5 : 2
Because quantity of milk is same 7 : 13
in both cased. So, we multiplied
35 : 14 : 26
by 2 to make quantity of milk
35x + 14x + 26x = 75x = 750
same in both ratio.
X = 10
Previous quantity
A’s share
= 2+1 = 3 units = 45 ltr.
= 35x = 35×10 = 350 Rs.
1 unit = 15 ltr.
62. (d) P : Q : R = 2 : 7 : 9
 quantity of water added = 3 units, From
P + Q = R (given)
above diagram
2x +7x = 9x
 Quantity of water added = 3×15 = 45 ltr.
Here we don’t have sufficient data
58. (b) Wine : Water
to insure the values of A, B & C
Initially 3 : 1
63. (d) A:B B:C C:D
Finally 1 : 1
3:4 , 5:7 , 8:9
Now, we have to substitute the mixture
with water so, the quantity of mixture , ,
remains same
 Wine : Water 
Initially 3 : 1 =4

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 A : D = 10 : 21 4 : 3
3 : 5
10 : 9

64. (a) A + B = 94 8 : 6 : 10 : 9
69. (c) A : B : C = 2 : 3 : 4
Given =3:4
Let
  A = 2x , B = 3x , C = 4x


A : B  
15 : 32 Multiply by the L.C.M of denominator
15x + 32x = 47x to remove fraction.
47x = 94 So, L.C.M of (3,4,1) = 12
X= 2  : :
 A = 15×2 = 30
B = 32×2 = 64 : :
65. (b) a : b c : d 8 : 9 : 24
5: 7 2a : 3b 70. (d) a : b = 1: 2
C:d=1:2
e:f=1:2
ac : bd = a = x c=x e=x
b = 2x d = 2x f = 2x
= 50 : 147


66. (c) x : y = 3 : 2 

71. (c) B 1 : B2 B1 : B2 B1
( ) : B2
= 2
( ) 5 years back 1 : 3 1 ×11 : 3×11 1
:3
=  
1
67. (b) a : b = b : C Present age 1 : 2 1×2 : 2×2 2
:4
I
b2 = ac I unit = 5 years
b4 = a2c2 Present age of B1 = 2 units = 2×5 = 10 years
Present age of B2 = 4 units = 4×5 = 20 years
a4 : b4 =  5 years after ages will be
a2 : c2 B1 = 10+5 = 15
B2 = 20+5 = 25
68. B1 : B2
(c) A : B =
15 : 25
B : C= 3:5

C : D=
A : B: C : D

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 X = 12
 Numbers are
 A = 6×12 = 72
 B = 8×12 = 96
 C = 9×12 = 108
76. (C) A : B : C
Initially 2 : 3 : 5
+2 +2 +2
After adding 4 : 5 : 7
72. (b) Puneet : Appu 20 students
1 In each class 2 unit = 20
Present age 2 : 3 1 = 10
1 Initially students are
After 3 3 : 4 = 2×10+3×10+5×10
Years 1 = 20+30+50  100
1 unit = 3 years 77.
 present age of Puneet = 2×3 = 6 years (d) take ratio =
Present age of Appu = 3×3 = 9 years Milk Initially Finally milk
3 2
Alternate :
3 2
 8x + 12 = 9x + 9 9 4
x=3 9 = 81
 Puneet = 2x = 2×3 = 6 9
Appu = 3x = 3×3 = 9 36
 milk 6
73. (a) A:B:C Water 81–36 = 45
8:9  milk : water
3:4 36 : 45
8 : 9 : 12 4 : 5
8x : 9x : 12x Alternate :
 8x × 12x = 2400 Final milk = Initial milk
x2  ( )
x=5 =
 B  9×5 = 45
74. (a) A : B = 2x : 3x ( ) =

Now, ( )
4x – 4 = 3x + 2 = 81× = 36
X6 Final water
 A = 2×6 = 12 = 81 – 36 = 45
B = 3×6 = 18 Required ratio
Sum of no. = A+B =
= 12+18 = 30
78. (d) milk : water
75. (d) A : B : C
7 : 3
: : 2 : 1
     Now water is added so, the
6 : 8 : 9 milk proportion remains same
6x : 8x : 9x For this
9x – 6x = 3x Milk : Water
3x = 36 Initially (7 : 3)×2

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 Finally (2 : 1)×7 17x = 68000
= milk : water X = 4000
14 : 6 = 80 liter (given)  A = 4000×8 = 32000
14 : 7 B = 4000×4 = 16000
1 unit C = 5×4000 = 20000
 20 unit = 80 liter Required difference
1 unit = 4 liter = 16000 Rs.
 water added 83. (a) Ist class IInd class
= 1×4 = 4 liter Fare 3 : 1
79. (d) A : B Passenger × 1 : × 50
Income 4 : 3 Total fare 3+50 = 53x
(1) (–) : (–) (1) 53x = 1325
Expenditure 3 : 2 X=
1 1  Amount collected from IInd Class = 50x
Saving (×) (×)  25×50 = Rs. 1250
600 600 84. (c) P : q : r
1 unit = 600 1 : 2 : 4
 Income of A x : 2x : 4x
= 600×4 = 2400
√
B = 600×3 = 1800
80. (a) Let Incomes of A and B are =√
A : B √ 5x
Income 5x : 3x = 5p
Expenditure 9y : 5y 85. (b) (3+√2) : x : (12 – √32)
Saving 2600 : 1800 a : b : c
 mean proportion
b2 = a×c
 25x – 13000 = 27x – 16200 x2 = (3+√2) × (12 – √32)
2x = 16200 – 13000 = (3+√2) × (12 – 4√2) = 28
2x = 3200 X = √28 = 2√7)
X = 1600 86. (b) x : y
 Income of A = 5x 2: 3
= 5×1600 = 8000 Rs.
 =
B = 3x = 3×1600 = 4800 Rs.
81. (c) A : B
Income 2x : 3x
Expenditure 5y : 9y ( )
Saving 600 : 600 ( )
( )

= 18x – 5400 = 15x – 3000
3x  2400 87. (b) a : b : c
X = 800 3 : 4
 Incomes of A & b are 8 : 9
A = 2x = 2×800 = 1600 24 : 32 : 36
B = 3x = 3×800 = 2400 6 : 8 : 9
82. (d) A : B : C a : c
: : 6 :
2 : 3
: :
8 : 4 : 5 Or
8x + 4x + 5x = 68000

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 5x = 40
X=8
 Initially ladies = 3×8 = 24
Gents = 2×8 = 16
 after gents becomes = 16+20 = 36
Ladies remains same = 24
91. (c) milk : water
A 4 : 5 9
B 5 : 1 6
88. (a) 5 : 4 9
Father son Take L.C.M of amount 9, 6, 9
2 L.C.M = 3×3×2 = 18
After 10 years 5 : 3 2 unit = 10+10 = 20  Equalize the amount of all mixtures
+3 Milk : water
1 unit = 10 years
A (4 : 5 )×2 = 8 : 10
Before 10 years 3 : 1
B (5 : 1 )×3 = 15 : 3
2
After mixing (5 : 4)×2 = 10 : 8
 10 years ago ages
 A B
Father : Son
8 15
30 : 10
Father = 40
10
Son = 20
Present age
# 5 : 2
Father : Son
Or
40 : 20
2 : 1
Son : father
 10 3
=1 : 2
8
89. (a) Boys : girls
13 : 11
# 5 : 2
 13x +11 x = 504
24x = 504
92. (b) Rs. 1 : Rs. 5 : Rs. 10
X = 21
No. of notes 1 : 1 : 1
Boys = 21×13 = 273
x : x : x = 3x no. of notes
Girls = 21×11 = 231
Now, no. of values x : 5x : 10x = 16x values of
3 more girls admitted note
So, x + 5x + 10x  640
No. of girls 16x = 640
= 231+3 = 234 X = 40
 new  no. of notes = 40×3  120
Boys : Girls
273 : 234 93. (a)
91 : 78 Let Rs. 1 : 50p : 25p
7 : 6 Value of coins x : x : x
90. (c) ladies : gents No. of coins x : 2x : 4x = 7x
Initially 3 : 2 7x = 175
3x : 2x = 25
 value of total amount
9x = 4x + 40 = 3x = 25×3 = Rs. 75

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

94. (c) a : b : c 3 :7
2 : 3 : 4 6 :5
Let 2x : 3x : 4x 18 : 42 : 35
2a – 3b + 4c = 33 18x + 42x + 35x  95 x
2 × 2x – 3 × 3x + 4 × 4x = 33 95x = 33630
4x – 9x + 16x = 33 X = 354
11x = 33  money received by B = 42x = 42×35 = 14868
X=3 Note : To save time check unit digit for example
  4×3 = 12 42 × 354 = unit digit is 2×4 = 8
Check option with unit digit 8.
95. (b) a:b=c:d There is only one.
Option 14868
and
102. (d) father (f) + son(s) = 100
( ) ( ) F + S = 100 ------ (i)
=
( ) ( )
96. (c) A : B :C (F – 5) = 2 (S – 5)
4 : 5 F – 5) = 2S – 10
2 :3 F – 2S = –5 ------(ii)
8 : 10 : 15 By I & II
8x : 10x : 15x F + S = 100
A = 8x = 800 given F – 2S = –5
X = 100 –+ +present age
 C 15x = 15×100 = 1500 3S = 105
97. (d) a : b : c S = 35
7: 3 :5 F = 100 – 35 = 65
ratio of age after 10 years
Father : son
65+10 : 35+10
75 : 45
=5:4 5:3
103. (c) Rahul : Rashmi
1
98. (d) A : B :C Present age 2 : 1
2 : 3 5
after 30 years 7 : 6
4 : 5 1
8 : 12 : 15 5 units = 30 years
99. (d) 2A = 3B = 4C 1 unit = 6 years
Divide by LCM of 2,3,4 i.e. = 12 Present age of Rahul = 2×6 = 10 years

104. (a) A + B +C = 68
A: B : C
A:B:C 2:3
6:4:3 5: 3
100. (a) A : B B : C C : D 10 : 15 : 9
2 : 3, 2 : 4, 2 : 5 10x + 15x + 9x = 34x
 34x = 68
  x=2
A = 2×10 = 20
 A : D = 2 : 15
B = 2×15 = 30
101. (a) A : B : C

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 C = 9×2 = 18 17+3 = 20 units → 200 ltr.
1 unit → 10 ltr.
4 unit → 40 ltr.
108. (b) Milk : water
Initial 7 : 5
105. (c) A : B Final 7 : 8
4:5 adding 15 liter water
4x : 5x
L C M = 4 × 5 × x = 20x
20x = 180 8x = 5x +15
x=9
Smallest number is = 4×9 = 36 x=5
Largest number is = 5×9 = 45 at present = milk : water
106. (d) Boys : girls = 7x : 8x
8 : 5 water = 8x = 8×5 = 40 ltr.
8x : 5x 109. (b) A : B
8x + 5x = 13x 5:6
13x = 286 5x : 6x
x = 22 B – A = 6x – 5x
Boys = 8×22 = 176 x = 11100
Girls = 5×22 = 110 Total income A + B
 no. of girls at present after = 5x ÷ 6x = 11x
adding 22 girls is 110+22 = 132 11×11100 = 1,22,100
Boys : girls 110. (b) Rs. 1 : 50p : 25p
176 : 132 no. of coins 8x : 5x : 3x
44 : 33
4 : 3 value of coins 8x : :
107. (b) milk : water
17x : 3x
17x + 3x = 200 liter
20x = 200
x = 10 liter
milk : water x = 10
170 : 30 50 paise coins are = 5x = 5×10 = 50
after adding x liter of milk the ratio 111. (b) Rs. 1 : 50p : 25p
becomes no. of coins 3x : 8x : 20x = 31x
Milk : water
value of coins 3x : :
7 : 1
3x + 4x + 5x = 12x
12x = 372
= 170 + x = 210
x = 31
x = 40
Total no. of coins  31x
ALTERNATE :
= 31×31 = 961
M : W
112. (a) Given total runs of A, B, C (A+B+C = 361)
Before 17 : 3
A:B:C
After 7 : 1
3:2
Water is same in both conditions
3:2
Make water same in above ratio
9:6:4
M:W M : W
9x +6x +4x = 361
Before 17 : 3 17 : 3
19x = 361
4
x = 19
After 7×3 : 1×3 21 : 3

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 runs scored by A 
 9x = 9×19 = 171

Multiply L.C.M of (2,3,3) = 6
A : B : C
: :
113. (b) Passed student : Failed student A : B : C
P : F 9 : 8 : 10
25 : 4 118. (d) A : B : C
25x : 4x  29x total student 3 : 5
 
4 : 7
After admitting 5 more students,
= 12 : 20 : 35
Total students
 29x + 5
119. (c) milk : water
New failure students
7 : 1
 4x –2
Let 7x : x
New ratio 
7x + x = 8x
P : F
8x = 40 liters (given)
22 : 3  25 y x=5
milk = 7×5 = 35 liter
water = 5 liter
 Let ‘y’ liter of water is added
100x – 50 = 87x +15
 13x = 65 ( Cross multiply)
x=5 35 = 15 +3y
Total student appeared in the exam was 3y = 20
= 29x + 5 = 150 y=
114. (a) ALTERNATE :
a : b : c M : W M : W M : W
3 : 4 : 7 Before 7 : 1 7 ×3 : 1×3 21 : 3
3x : 4x : 7x  14x 4
a + b + c = 14x After 3 : 1 3×7 : 1×7 21 : 7
c = 7x NOTE : Milk is same in both condition, so make
(a + b + c) : c same value of milk in above ratio.
= 14x : 7x = 2 : 1 21+3 = 24 units = 40 ltr.
115. (b)A : B : C
1 unit =
3 : 4
4 units = ltr.
12 : 13
36 : 48 : 52
9 : 12 : 13
A : C = 9 : 13

116. (d) A : B : C
3 : 2
3 : 4
9 : 6 : 8
A : C =9 : 8
117. (d) of A = 75% of B = 0.6 of C

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 A→5 : 3 = 8×2 = 16  10 : 6
B→ 5 : 11 = 16×1 = 16  5 : 11
Gold : Copper = (10+5) : (6+11)
= 15 : 17
123. (a) Gold : Copper LCM
A 7 : 22 = 29×3 = 174  42 : 132
B 21 : 37 = 58×3 = 174  63 : 111
120. (c) When any quantity of mixture mixture 25 : 62 = 87 ×2 = 174  50 : 124
is taken out from the mixture then apply alligation
the ratio of the remaining mixture A B A B
remains the same = 4 : 1 42 63 132 111
A:B A:B
Initially→ 4 : 1 → 4 : 1 50 or 124
5
Finally →(2 : 3)×2 → 4 : 6 Required ratio→13 : 8 13 : 8
Now mixture is taken out and liquid
B is added. So, make A proportion 124. (a) Zinc : Copper
Equal. A 1 : 2 = 3 ×[3×5]  65 : 130
5 units = 10 ltr. B 2 : 3 = 5 ×[3×5]  78 : 117
1 unit = 2 ltr. mixture 5 : 8 = 13×[3×5]  75 : 120
Quantity of solution = 4+6
= 10 units  A B A B
= 10×2 = 20 liters 65 78 130 117
Initially ratio of
A : B 75 or 120
4 : 1
4x + x = 20 ltr. Required ratio→3 : 10 3 : 10
B = 4×1 = 4 ltr.
121. Milk : Water 125. (d) 1 Rs. : 50p
2 :1 values 13x : 11x
2x : x coins 13x : 22x
3x = 75  x = 25 13x +22x = 35x
Milk = 2x = 2×25 = 50 ltr. 35x = 210
Water = x = 25 ltr. =6
Let y liter of water is added
 coins of 1 Rs.
= 13x = 13×6 = 78
25+y = 100 50p coins
y = 100–25 = 75 liters = 22×6 = 132
ALTERNATE : 126. (d)
M : W M : W M : W 50p : 25 p : 10p
Before 2 : 1 2 : 1 2 : 1 No. of coins 1x : 32x : 3x
3 value of coins
After 1 : 2 1×2 : 2×2 2 : 4 in paise x × 50 : 32x × 25 : 3x × 10
NOTE : Milk is same in both condition, so 50x : 800x : 30x
Make value of milk in above ratio.  50x + 800x + 30x = 880x
2+1 = 3 units = 3 ltr. 880x = Rs. 8.80 = 880p
1 unit = 1 ltr.
75 units = 75 ltr.
No. of 10 paise coins are
= 30x = 30×1 = 30
122. (c) Gold : Copper LCM
127. (c) A 0 B : C

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 1 : 3 : 4 15x +30 = 16x + 24
Let 100x : 300x : 400x x6
+5% +10% +15% A = 6×3 = 18
Let 105x : 330x : 460x B = 4×6 = 24
105 : 330 : 460 Difference between numbers
21 : 66 : 92 A – B = 24 – 18 = 6
ALTERNATE :
A : B
3 : 4
128. (c) Marks in 1 1
 Math + English = 170 4 : 5
 Math – English = 10 1 unit = 6
Math  Difference = (4–3)
__________________________ = 1 unit = 6
English  80 133. (c) A : B : C
Math : English 5 : 6 : 7
90 : 80 Let 5x : 6x : 7x
9 : 8  Product of numbers
129. (a) x : y A×B×C =5x × 6x × 7x = 210 x3
2 : 1  210x3 = 5670 (given)
Let 2x : x  x3 = 27
3
 : x = 27
  x=3
A = 5×3 = 15
 B = 6×3 = 18
130. (c) 2A = 3B and 4B = 5C C = 7×3 = 21
A : B B : C Greatest numbers is c
3 : 2 5 : 4 = 21
A : B : C 134. (d) 6,7, 15, 17
3 : 2 if a : b : c : d are in
× × × proportion then
5 : 4 a×d=b×c
15 10 : 8 Let x is added to each number
A : C (6+x) : (7+x) :: (15+x) : (17x+x)
15 : 8 (6+x)× (17x+x) = (7+x)× (15+x)
x2+23x+102 = x2+22x+105
131. (b) A : B x=3
2 : 3 NOTE : you can directly go
Let 2x : 3x through option to save your
A × B  2x × 3x = 6x2 Valuable time. (by putting value of
6x2 = 96 x from option)
Given x2 = 16 135. (a)
x =4 Zinc : Copper
sum of numbers A 3 : 5 = 8 ×(7×2)
= (A + B ) = 2x + 3x = 5x = 5×4 = 20 B 6 : 1 = 7(2×8)  112 units
132. (c) A : B C 1 : 1 = 2×(8×7)
2 : 3  Milk Water
Let 3x : 4x A 42 : 70
If each no. is increased by 6 B 96 : 16
Then, (given) C 56 : 56
 By alligation

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 A B A B 2 : 3 1 : 2
42 96 70 16 W2 : W1 : W3
3 : 2
× ×
56 or 56 ×
1 : 2
40 : 14 40 : 14 3 2 : 4
Required ratio→20 : 7 20 : 7 W2 : W3
3 : 4
136. (c) A : B
Income 4x : 3x 141. (b) 3x = 5y = 4z
Expenses 3y : 2y x : y : z
Saving 60000 5×4 : 4×3 : 5×3
Income  Expenses + saving 20 : 12 : 15
142. (c) A : B B : C
8x – 120000 = 9x – 180000 3 : 4 6 : 5
x = 60000 A : B : C
Income of A 3 : 4
× ×
= 4×60000 = 240000 ×
137. (b) Mr. : Mrs. 6 : 5
Before 7x : 8x 18 24 : 20
After 5y : 6y 9 : 12 : 10
 before 7x+8x = 120 A + C  9+10 = 19
15x = 120 A : A + C = 9 : 19
x=8 143. (a) a+b √3 =
√
Mr. gupta = 7×8 = 56 √ √

Mrs. Gupta = 8×8 = 64 √ √

after losing 6 kg by Mr. gupta = 2+√3

the ratio be comes 5 : 6 by rationalization of denominator
 Let Mrs. Gupta loss x kg  a + b√3 = 2 +√3
 Now compare the rational & irrational parts
a=2
300= 320 – 5x b=1
5x = 20 2:1
x = 4 kg. 144. (c) A : B : C
138. (d) Ist : IInd 3 : 4
× ×
Fare 4x : x ×
Passengers 1 : 40 8 : 9
Total fare 4x : 40x = 44x 24 32 : 36
44x = 1100 6 8 : 9

145. (c) A = 4A = B
Fare = Ist class amount received
= 4x = 4×25 = 100 B : A
139. (c) A : B 4 : 1
3 : 2 B 2B = C
3x : 2x B :C
 3x +2x = 1000 1 : 2
5x = 1000 A : B : C
x = 200 1 : 4
A = 3×200 = 600 × × ×

140. (a) W 1 : W2 W1 : W 3 1 : 2

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 1 4 : 8 = 60 years
Age of son = 20+10
146. (c) 2A = 3B = 4C = 30 years
A : B : C 151. (b) 6,14, 18, 38
3×4 : 2×4 : 2×3 If a, b, c, d are in proportion
12 : 8 : 6  a : b :: c : d
6 : 4 3 then ad = bc
Let x is added in the sequence
147. 43.5 : 25 = : 25 = 22×3.5 : 25 number as to make it in proportion
= 2 = 2 = 2 .2 : 25 = 22 : 1
7 5 2 (6+x) : (14+x) :: (18+x) : (38+x)
=4:1 (6+x)(38+x) = (18+x) (14+x)
148. (d) A : B B : C C : D D : E Now to save valuable time put
1 : 2 3 : 4 6 : 9 12 : 16 value of x from options to make it
 A : B : C proportion
1 : 2 (6+x)(38+x) = (18+x) (14+x)
× × ×
 x2+44x+228 = x2+32x+252
3 : 4 12x  252 – 228
3 6 : 8 12x  24
 A : B : C : D x  2 Ans.
3 : 6 : 8 152. (d) A : B
3 : 4
6 : 9 Let 3x : 4x
18 : 36 : 48 : 72 LCM of A & B is
3 : 6 : 8 : 12 = 3 × 4 × x = 12x
A : B : C : D : E 12x = 180 Given
3 : 6 : 8 : 12 x = 15
12 16 A = 3x = 3×15 = 45
 3 : 6 : 8 : 12 16 B = 4x = 4×15 = 60
153. (a) A : B
149. (d) x : y 3 : 5
2 : 5 Let 3x : 5x
Let 2a : 5a LCM of A & B is
= 3 × 5 × x = 15x
15x = 225 Given
x = 15
 A = 15×3 = 45
 B = 15×5 = 75
Smaller number is = 45
150. Father : son
154. (b) A : B
F : S
3 : 4
5 : 2
Let 3x : 4x
Let 5x : 2x
LCM of A & B is = 3 × 4 × x = 12x
given, 5x × 2x = 1000
12x = 48
10x2 = 1000
Given
x2 = 100
x=4
x = 10
A = 3×4 = 12
Father’s present age
B = 4×4 = 16
= 10×5 = 50
Sum of numbers
Son’s present age
A + B = 12+16 = 28
= 2 × 10 = 20
155. (d) Given
After 10 years
Age of Father = 50+10 Let x be added to both A & B

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

  Let 5x : 3x = 8x
Cross multiply the equation  New comers
28+4x = 33+3x 5y : 7y =12y
x=5 8x+12y = 1200
 2x+3y = 300 …..(i)
again, =
156. (b) A : B 25x+25y = 21x+49y
7 : 11  4x–24y = 0
Let 7x : 11x 4x = 24y
Now after adding 7 to each number x = 6y ……(ii)
 From equation …..(i)
21x +21 = 22x +14 12y+3y = 300
x=7
 A = 7×7 = 49 x = 120
 B = 11×7 = 77 The number of students initially
Smaller number = 49 8x = 8×120 = 960
157. (b) A : B 161. (c)  x : y : z
3 : 5 are three persons
Let 3x : 5x Speed 4 : 3 : 5
Now after adding 10 to each number Time : :

Speed ∞ ,
21x +70 = 25x +50
LCM of 4,3 and 5 = 60
4x = 20
x=5 time : :
A = 3×5 = 15 15 : 20 : 12
 B = 5×5 = 25 162. (c) P : Q
2 : 5
158. (b) A : B : C Let 2x : 5x
2 : 3 : 5 P = 2x = 120 (given)
Let 2x : 3x : 5x x = 60
 C – A = 5x – 2x = 3x = 12000 marks of Q = 60×5 = 300

Monthly salary of B is
= 3x = Rs. 12000
Annual salary of B
= 12×12000 = Rs. 1,44,000
159. (d) Income : Expenditure
I : E
11 : 10
–
11 – 10 = 1  saving
163. (d) A : B
1 = 9000
A : B
annual incomes
4 :9
= 9000×11 = Rs. 99000
2 : 3
Monthly income
B : A : C
=  Rs. 8250 9 :4
2 : 3
160. (d) A : B  18 : 8 : 12
5 : 3 (A+B) : (B + C)

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

  (18+8) : (18+12) 168. (c) Let two quantity are A, B
26 : 30 Given, A + B = 3(A – B)
13 : 15  A +B = 3A – 3B
164. (c) x : y  A – 3A = – 3B – B
3 : 4  – 2A = – 4B
( ) A = 2B
 A:B=2:1
( ) 169. (c) A : B : C
3 : 4 : 5
  Let 3x : 4x : 5x
Sum of (smallest + largest)
165. (a) x : y = 3 : 4 A + C  8x
8x = 4x +52
4x = 52
( ) x = 13
  smallest numbers = A
( )
 13×3 = 39
170. (c) when any quantity of mixture
  
is taken out from the mixture
4 : 9 then the ratio of the remaining
166. (c) Maya : Chhaya mixture remains the same
Present age 6 : 5 A : B
8 – 5 = 3units 7 : 5
15 years hence 9 : 8 7 : 9
3 units = 15 years Given that 9 liter of mixture is
1 units = 5 years taken out & 9 liter of B is added.
present age So, the ‘A’ part remains constant
Maya → 6×5 = 30 years Difference between B
Chhaya → 5×5 = 25 years =5–9=4
167. (b) Ram : Rahim 4 units → 9
10 years ago 1 : 3 1 unit →
+2
total quantity = A +B  7x + 9x  16x
5 years hence 2 : 3  36 liters
+1
15 years difference
Initially,
Ram : Rahim
A : B
(1 : 3)×1 1 : 3
7 : 5 = 12 = 36 liters
=3 3
A = 7×3 = 21 liters
(2 : 3)×2 4 : 6
171. (c) A : B
3 units → 15 years
Initially 7 : 5
1 unit → 5 years
Finally 7 : 9
10 years ago ages of Ram and Rahim are
 9 liters of mixture is taken out
= 1×5 = 5 years
and B is added so, part ‘A’ remains
3×5 = 15 years
same for this multiply by 7 the
Present age of Ram
new ratio
= 5+10 = 15 years
 But quantity of mixture remains same
Rahim = 15+10 = 25 years
A : B
Ratio of present ages are
Before 7 : 5
= Ram : Rahim
7–5=2
15 : 25
New 7 : 7 .
3 : 5
2 units

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 2 units = 9 175. (d) Water : Milk
1 units = A 3 : 4 = 7×8
Quantity of mixture B 5 : 3 = 8×7
= 7+7 = 14 units  make quantities of A & B equal
 water : milk
= = 63 liters
A 24 : 32
 Initial ratio of A : B B 35 : 21
7 : 5 59 : 53
A= = = So, ratio of water and milk in new mixture
liters = 59 : 53
176. (b) Acid : Water
A 4 : 3 = 7 ×(8×5)
172. (a) Milk : water
B 5 : 3×(7×5)
A 4 : 3
new mixture 168 : 112 = 280
B 2 : 3
(Acid in mixture) (Acid in mixture)
New mixture 1 : 1
A B
A B
160 175

168 Acid in final mixture

7 : 8
7 : 5 Or
A B
173. (b) water : glycerin
1 : 3 = 240 cc
 60 : 180
Let x liter of water added

180 + 3x = 360 7 : 8
3x = 180
x = 60
Alternate :
W : G
1 : 3 = 4 units
2 : 3
4 units = 240cc
1 unit =
174. (a) Acid : water
4 : 1
Let 4x + x = 5x 177. (a) Acid : water
4x + x = 25 A 3 : 1
x=5 B 5 : 3
Acid = 5 × 4 = 20 C 2 : 1
Water = 5×1 = 5 By alligation method
3 liters water is added A B
So, new quantity of water
= 5+3 = 8
Acid : Water
20 : 8
5 : 2

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 1 : 2 = 1 unit = 10 kg.

178. (a) Acid : water 181. (a) Income : Expenditure

A 5 : 2 = 7×13 10x : 7x
B 8 : 5 = 13×7 Saving = Income – expenditure
New 9 : 4 = 13 ×7 10x – 7x = 3x
Make quantities equal Given, Expenditure = 7x = 10500
Acid : water x = 1500
A 65 : 26 = 91 Saving = 3x = 3×1500 = 4500
B 56 : 35 = 91 182. (b) A : B
New 63 : 28 = 91 Income 9 : 7
By alligation Expense 4 : 3
A B Income – Saving = Expenditure
65 56
 27x – 600 = 28x – 800
63 x = 200
Sum of weekly income
7 : 2 = 9x+7x = 16x
16×200 = Rs. 3200
OR A B 183. (d) A : B
26 35 Income 2 : 3
1 1
28 Expenditure 1 : 2
Saving 1 1
7 : 2 × ×

24000 24000
1 unit = 24000
179. (C) Spirit : Water Income of A = 2 units
A 3x : 7x = 24000×2 = Rs. 48000
3x+7x = 20 ALTERNATE : -
x=2
Spirit in A = 3×2 = 6 liters
 4x – 48000 = 3x – 24000
Water in A = 7×2 = 14 liters
 x  24000
Spirit : Water
Income of A
B 7x : 5x
= 24000×2 = Rs. 48000
7x+5x = 36
x=3
Spirit in B = 7×3 = 21 liters
Water in B = 5×3 = 15 liters
Spirit : Water
(6+21) : (14+15)
184. (c) A : B
27 : 29
Income 9 : 8
180. (b) Copper : Zinc : Nicked
(–) (–)
Old 5 : 3 : 2
Expenditure 8 : 7
1 unit
Saving 1 1
New 5 : 3 : 3 × ×
Now old ratio
500 500
= 5x+3x+2x = 10x
1 unit = 500
10x = 100 kg.
Income of A = 500×9
1 unit = 10 kg.
= Rs. 4500
Nickel added to mixture

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185. (c) Let two number be x and y. of students becomes (x + y) and
x<y average
( ) ( ) Total marks = 30(x + y )
 25x+40y = 30(x + y)
 ( ) 25x+40y = 30x+30y
x = 2y
3x = y x:y=2:1
x:y
1:3 189. (c) Big : Medium : Smaller
Ratio of larger to smaller Rates(Rs.) 15 : 10 : 5
y:x Quantity (kg.) 3 : 2 : 5
3:1 Total cost (Rs.) 45 + 20 : 25
186. (a) A + B = 94 Total cost = 45+20+25 = Rs. 90
Total quantity = 3+2+5 = 10
=3:4
Average cost = = Rs. 9
190. (a) Boys : Girls
= Girls : Teacher
A : B B : G
15 : 32 G : T
Let 15x : 32x 4 : 3
15x +32x = 47x 8 : 1
47x = 94 B : G : T
x=2 4 : 3
× ×
A = 2×15 = 30 ×
B = 32×2 = 64 8 : 1
187. (a) 0.8, 0.2, x 32 24 : 3
if a, b, c are three number Total students = B + G
these a : b : c = 32 +24 = 56
b2 = a × c Student : Teachers
c = third proportion 56 : 3
Let, 0.8 : 0.2 :: 0.2 : x 191. (b)
x be the third proportion  Cross multiply the equation
0.2×0.2 = x × 0.8 9x + 15 = 10x – 4
x = 19
 
 0.05 = x
188. (a) By alligation
A B
25 40
192. (d) A : B : C
30
5 : 3
× ×
×
2 : 1
4 : 5
Let, no. of students in class A be x 20 12 : 15
no. of student in B be y Let, 20x : 12x : 15x
 Total marks of class A 20x+12x+15x = 47x
Total marks of class B = 40y 47x = 564
Total marks of A + B
= (25x + 40y)  12
 Now on mixing the two class no. number scored by B

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 = 12x = 12×12 = 144 x=5
Hence, if 5 is added to make it
193. (a) Profit = 20% = a proportion
 CP = 100 196. (c) A : B
P = 20 4x : 7x
SP = 120 Now 4 is added to each number
(By selling at Rs. 9 are earns 20% 
Profit so, SP = 9Rs.  20x+20  21x+12
120→ = Rs. 9 x8
1→ smaller number is
4×8 = 32
100→
larger number is
CP→  7×8 = 56
By alligation 197. (b) A : B : C
Pure Milk Water No. of students 4x : 6x : 9x → 19x
10 initially
After admitting 12 7x : 9x : 12x →
28x
students more in 3x 3x 3x
each class
3 : 1 3x = 12
NOTE : Water is added so, price of x=4
Water is taken zero. Initially the no. of student
194. (d) Sumit’s age : Prakash’s age = 19×4 = 76
S : P 198. (a) Old : New
2 : 3 No. of workers 15 : 11
2x : 3x Wages 22 : 25
Total wages 330 : 275
(–) 66 : 55
3x – 2x = x 6 : 5
given x = 6
 Present age of sumit 199. (c) A : B
= 6×2 = 12 3x : 5x
Present age of Prakash If 9 is subtracted from each number
= 3×6 = 18 
Age of Sumit after 6 years 69x – 207  60x – 108
= 12+6 = 18 years 9x  99
Age of Prakash after 6 years x  11
= 18+6 = 24 years Numbers are = 3×11 = 33
Sumit : Prakash = 5×11 = 55
18 : 24
3 : 4 200. (a) Gold : Copper
195. (c) 7, 16, 43, 79 A(7 : 2)×2 = 9×2  14 : 4
if a, b, c, d are in proportion B 7 : 11 = 18  7 : 11
a:b:c:d  equal quantities of A & B are
the ad = bc mixed so, make quantity equal
Let k is added to make if a proportion Gold : Copper
 (7+x) : (16+x) : (43+x) : (79+x) A 14 : 4
 (7+x)(79+x) = (16+x)(43+x) B 7 : 11
x2+86x+553 = x2+59x+688 C 21 : 15
27x = 135

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 7 : 5

201. (c) The proportion taken out

 =
2 : 7
originally milk : After taken out
(1) Time 10 : 9 203. (b) Milk : Water
(2) Time 10 : 9 A 3 : 2 =5
(3) Time 10 : 9 . B 7 : 3 = 10
1000 units : 729 units New mixture 2 : 1=3
1000 units → 60 liters given A B
1 unit → liters
729 units →
  43.74 liters
ALTERNATE :
Final quantity = ( ) 1 : 2

204. (c) Chromium : Steel

= 43.74 liters A 2 : 11 = 13 x(2×3)
202. (d) B 5 : 21 = 26×3
= New mixture 7 : 32 = 39×2
Make amount equal by taking
Milk : Water
LCM
A 8 : 5 = 13×7
= 13, 26, 39 = 13×2×3
B 5 : 2 = 7×13
Chromium : Steel
C 9 : 4 = 13×7
A 12 : 66
 make quantities equal
B 15 : 63
 Milk : Water
New mixture 14 : 64
A 56 : 35
A B
B 65 : 26
12 15
C 63 : 28
By alligation method
14
A B
56 65
1 : 2
63 OR
A B
2 : 1 66 63

64
OR
A B
35 26 1 : 2

28 205. (C) A : B
Initial 7 : 5
2 : 7 4 units
Final 7 : 9
4 units = 9 ltr.
 or we can directly do it →
A B 1 unit = ltr.
B is added so, A part remains

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 same and quantity of mixture Price 5 : 3
remains same Let 5x : 3x
Amount of mixture Given 5x – 3x = 2x
 7+16 = 16 units 2x = 5500
16× = 36 liters x = 2750
Initial ratio Price of refrigerator
A : B  5×2750 = Rs. 13750
7x : 5x 210. (a) Passed : Failed = Total
12x = 36 liters 6 : 1 = 7
Let 6x : x = 7x
x = = 3 liters
Now is passed student exceeds
A = 7×3 = 21 liters by 6 the ratio becomes :
B = 5×3 = 15 liters Passed : Failed  Total
9 : 1  10
206. (b) A : B : C

Annual Income 1 : 3 : 7
Let x : 3x : 7x (Initially)
given A + c  x +7x = 8x = if
8x = 8,00,000 
x = 1,00,000
= 60x + 60 = 63x
= 300000
3x = 60
Monthly salary
x = 20
= Rs. 25000 Total no. of examinees are
= 7×20 = 140
207. (d) Amit : Veer
Income 3 : 2 211. (d) box : paper bundle
Expenses 5 : 3 weight 3 : 22
Saving 1000 : 1000 let 3x : 22x
Income  expenses + savings Total weight = 3x + 22x
= 25x = 36 kg.
9x – 3000 = 10x – 5000 grams
x = 2000 (1 kg = 1000 grams)
Annual income of Amit is Weight of paper bundles
= 3x = 3×2000  22x
= Rs. 6000 = 22×1440 grams = 31680 grams
208. (a) A : B : C
3 : 2
× ×
×
3 : 2
Annual 9 : 6 : 4
Income 9x : 6x : 4x
Given,
212. (b) Let number be x & y

Given x : y
3x – 1000 = x 3 : 4
2x = 1000  3a : 4a
x = 500 Now, given that
Income of B is  8(3a)2  (4a)2+224
6x = 6×500 = Rs. 3000 72a2 = 16a2 + 224
56a2 = 224
209. (c) Refrigerator : Television

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 a2 = 4 A : B : C : D
a=2 : : :
numbers are Total pens
x = 3×2 = 6 20+15+12+10 = 57
y = 4×2 = 8 219. A=
213. (c) A : B : C
2 : 3 and B =
6 : 11 3A = 2B 5B = 4C
12 : 18 : 33 A : B B : C
4 : 6 : 11 2 : 3 4 : 5
A : B : C
214. (b) 2 : 3
 10A = 12B 4 : 5
=A : B 8 : 12 : 15
12 : 10 220. (d) (25)2.5 : 53
6 : 5 (5)25.5×2 : 53
215. (a) (a+b) : (b+c) : (c+a) 53 : 53
a 2
Let 6 : 7 : 8 5 .5 : 53
a+b+b+c+c+a  6x+7x+8x 52 : 1
2a+2b+2c  21x 25 : 1
2(a+b+c) = 21x
221. (c) Three numbers are

a : b : c
a+b+c = 14 given 2
then b = ac
 third proportional

a+b = Let third proportion of 12, 18 is x

a+b+c = 14 12 : 18 :: 18 : x
c = 14 – 8 = 6 = 18×18 = 12 × x
216. (c) 5.5a = 0.65b

a : b = 65 : 550 = 13 : 110
217. (c) Boys : Girls
5 : 3
Let 5x : 3x
 Now 50 boys leave the college
and 50 girls joins the college

 35x – 350 = 27x + 450

8x = 800
x = 100
no. of boys = 5x 222. (b) x : y : z
= 5×100 = 500 3 : 2
218. (a) A : B : C : D 3 : 2
: : : 9 : 6 : 4
runs scored by A + B + C = x + y + z
Take L.C.M of 3, 4, 5, 6
= 9x + 6x + 4x = 19x
= 3×2×2×5 = 60
 A + B + C = 342 (given)

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 runs scored by A 40x + 16 = 42x + 14
= 9x = 9×18 = 162 2x = 2
runs scored by B x=1
= 6x = 6×18 = 108 Present age
runs scored by C A = 5×1 = 5
= 4x = 4×18 = 72 B = 6+12 = 18
(162, 108, 72)
223. (b) A : B : C
227. (C) Present ages of A & B are 36, 50
3 : 4
After n years
6 : 5
18 : 24 : 24 
9 : 12 : 10 144+4n = 150+3n
C : A n=6
10 : 9 228. (a) Ist : IInd : IIIrd
224. (a) If there are four numbers 8 : 9
a, b, c, d 3 : 4
then 24 : 27 : 36
a : b :: c : d 8 : 9 : 12
two mean proportions are, b and c Let 8x : 9x : 12x
a×d=b×c Ist × IIIrd
Now let mean proportion of 8x × 12x = 2400
2 & 54 are x, y x2 = = 25
= 2 : x : y : 54 x=5
xy = 54×2 = 108 Sum of three numbers
go through options Ist + IInd + 3rd
options A satisfying 8x+9x+12x 
(18, 6) 29×5 = 145 Ans.
225. (b) Black : Brown
pairs 4 : x 229. (d) x : y
price 2 : 1 No. of balls 2 : 3
8 : x 2x : 3x
original bill = 8 + x  Now 5 ball are taken out of
Black : Brown bag if and put in bag x
pairs x : 4
price 2 : 1
2x : 4  2x + 5 = 3x – 5
new bill = 2x + 4 x = 10
According to the question No. of balls in each bag is
3(8+x) = 2(2x+4) x  2×10+5 = 25
 24+3x = 4x+8 y  3×10–5 = 25
x = 16
Brown pairs = 16
black pairs = 4
ratio = 1 : 4

226. (c) ratio of ages of Boys A & b 230. (c) Let numbers are x and y
A : B (x+y)2 = 4xy
Present age 5x : 6x x2 + y2 + 2xy = 4xy
after two years x2 + y2 – 2xy = 0
x=y

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 x:y Milk : Water
1 : 1 A 2 : 1 = 3×(8×5) = 120  80 : 40
231. (b) A : B : C B 3 : 2 = 2×(3×8) = 120  72 : 48
2 : 3 : 4 C 5 : 3 = 8×(5×3) = 120  75 : 45
Let 2x : 3x : 4x  Make quantity equal in all the three mixture.
Sum of squares So, all three are mixed
A2+B2+C2 Acid : Water
=4x2+ 9x2+16x2 = 29x2 A 80 : 40
 29x2 = 1856 B 72 : 45
x2 = 64 C 75 : 45
x=8 227 : 133
A = 2×8 = 16
B = 3×8 =24
C = 4×8 = 32
232. (d) A : B : C
Original 1 : 2 : 3
(–) (2–1) (–)(3–1) (– ) (4–3)

After adding 5 in 2 : 3 : 4
each number 1 : 1 : 1
1 unit = 5
numbers are = A = 1×5 = 5
B = 2×5 = 10
C = 3×5 = 15
233. (a) Marks in English, math & science
are E, M, S respectfully
given 2S = E
S : E =1 : 2
E : M =2 : 3
S : E : M 236. (b)
1 : 2 Copper : Tin
2 : 3 A 1 : 3 = 4×(11×7)
1 : 2 : 3 B 2 : 5 = 7×(4×11)
Let, x : 2x : 3x New mixture 3 : 8 = 11 ×(7×4)
x+2x+3x = 6x = 180  Copper : Tin
x = 30 A 77 : 231
Marks in Science B 88 : 220
= 1×30 = 30 New 84 : 224
Marks in English A B
= 2×30 = 60 77 88
Marks in Math’s
= 3×30 = 90 84
234. (d) by alligation
A B 4 : 7
10.20 14.40
OR
12.60 A B
231 220
1.80 : 2.40
18 : 24 224
3 : 4
235. (b) 4 : 7

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 38 units = Rs. 380
237. (d) Alcohol : Water 1 unit = Rs. 10
4 : 3 Price of total rice
Let 4x : 3x  18×10 = Rs. 180
5 liters of water is added to 241. (c) A : B
the mixture Income 6 : 5
 = Expense 4 : 3
 20x = 12x +20 Saving 400 : 400
8x = 20
18x – 1200 = 20x – 1600
Quantity of alcohol 2x = 400
x = 200
 = 10 liters Income of A
238. (d) Zinc : Tin 6×200 = 1200
A 5x : 2x = 7x Income of B
B 3y : 4y = 7y 5×200 = 1000
 A  7X = 7 kg Total sum of (A + B)
x = 1 kg = 1200 + 1000 = Rs. 2200
Zinc in alloy A  5 kg.
Tin in alloy A  2 kg.
 B  7y = 21 kg.
y = 3 kg.
Zinc in alloy B  3×3 = 9 kg.
Tin in alloy B  3×4 = 12 kg.
and tin in new alloy
 Zinc : Tin
A 5 : 2
B 9 : 12
A+B 14 : 14
1 : 1 242. (C) Half rupee = 50 paise
Quarter rupee = = 25 paise
239. (a) Zinc : Copper
50P : 25P : 10P
5 : 3
Value of coins 5x : 3x : x
Let 5x : 3x
 no. of coins
given, 5x+3x = 400 g
5x × 2 : 3x × 4 : x × 10
8x = 400 g
10x : 12x : 10x
x = 50 g
 Given, 10x + 12x + 10x = 32x
Zinc : Copper
32x = 480
250 g : 150 g
Let, A gram of Copper is added
 No. of coins in each case
 50P : 25P : 10P
 1000 = 750 + 5a
10x : 12x : 10x
 250 = 5a
10×15 : 12×15 : 10×15
a = 50 g
150 : 180 : 150
243. (d) Rs. 1 : 50P : 20P
240. (d) Wheat : Rice
values 13x : 11x : 7x
Weight 4 : 3
No. of coins 13x × 1 : 11x × 2 : 7x × 5
Rice 5 : 6
13x : 22x : 35x
Total price 20 + 18 = 38
Given, Total coins
20+18 = 38 units
= 13x + 22x + 35x = 70x

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 70x = 420  x = 6 Ratio of their shares
No. of 50 paise coins are A : B : C
= 22x = 22×6 = 132 = (x +15) : (x + 8) : (x)
244. (b) Rs. 1 : 50P : 25P = 25 : 18 : 10
2 : 1 248. (b) A : B : C
1 : 4 . 2 3
2 : 8 : 4
No. of coins → 2x : 8x : 4x : 4 : 5
Values of coins→ 2x × 1 : 8x × : 4x × 8 : 12 : 15
Total value → 2x + 4x : x→  8x + 12x + 15x = 700
7x  35x = 700
7x = Rs. 56 (Given) x = 20
x = Rs. 8 A → 20×8 = 160
Value of 50 paise coins are B → 20×12 = 240
= 4x = 4×8 = Rs. 32 C → 20×15 = 300
No. of coins of 50 paise are
= 32×2 = 64
245. (b) A : B : C
2 : 3 : 4
Let 2x : 3x : 4x
Total 2x + 3x + 4x
= 9x
 9x = 738 Given
x = 82 249. (b) A : B : C
Share of A = 82×2 = Rs. 164 : :
Share of B = 82×3 = Rs. 246 (Take LCM of denominator)
Share of C = 82×4 = Rs. 328 
246. (d)  0.5A = 0.6B = 0.75C 6 : 4 : 3
 6x : 4x : 3x
  13x = 2600
 10A = 12B = 15C x = 200
 A : B : C A = 6×200 = Rs. 1200
B = 4×200 = Rs. 800
12×15 : 10×15 : 10×12
C = 3×200 = Rs. 600
 180 : 150 : 120
 6x : 5x : 4x 250. (b) Let P get Rs. X
Total 6x + 5x + 4x = 15x Q get Rs. (x+30)
15x = 1740 R get Rs. (x+30+60)
Total = P + Q + R
 = Rs. 116
= x + x + 30 + x + 90
Share of C is = Rs. (3x + 120)
4x = 4×116 = Rs. 464  3x + 120 = 300
247. (b) Let C get x rupees 3x = 180
B get x + 8 rupees x = Rs. 60
A get x + 8 + 7 rupees P : Q : R
Total A + B + C 60 : 90 : 150
 x + 15 + x + 8 +7 = 3x + 23 2 : 3 : 5
 3x + 23 = Rs. 53 (given) 251.
3x = 30 (C)
x = 10 A : B : C
x = Rs. 10 2 : 3 : 4

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 2x : 3x : 4x = 900 256. (b) 8 : x : 50
9x = 900 x2 = 50×8
x = 100 x2 = 400
A = 200 x = 20
B = 300 257. (c) A : B : C
C = 400 7 : 9
252. (C) A : B : C
2 : 5 : 4 3 5
2x + 5x + 4x = 11x 21 : 27 : 45
11x = Rs. 126.50 7 : 9 : 15
x = Rs. 11.50 258. (b) Length : Width
 Share of B = 5x 5x : 2x
Share of A = 2x Width  2x  40 m
Share of (B – A) = 3x x  20 m
 3×11.50 = Rs. 34.50 length  5×20 = 100m
253. (b) Let C get x rupees
B get x + 6 rupees
A get x + 6 +7 rupees
= A + B + C  (3x + 19)
3x + 19 = 76
3x = 76 – 19  57
x = 19
A get = 19+13 = Rs. 32
B get = 19+6 = Rs. 25
C get = Rs. 19 259. (a) A : B
A : B : C age 4 : 7
32 : 25 : 19 4x : 7x
254. (d) A+B+C = Rs. 3000 (given) 7x – 4x = 3x
 (Given)  3x = 30 years (Given)
 B+C = 3A x = 10 years
A+3A = 3000 Age of A = 4×10 = 40 years
age of B = 7×10 = 70 years
A= Rs. 750
sum of age of A + B
Again, = B Given = 40+70 = 110 years
 2(A+C) 3B 260. (a) A + B = 20
 2(A+B+C) = 2×3000 A – B = 25
2(A+C) + 2B = Rs. 6000 2A = 45
3B + 2B = 6000

A+B+C = 3000 A : B
= 750+1200+C = 3000
:
C = 3000 – 1950 = Rs. 1050
255. (a) a : b :: c : d =–9
a×d = b×c 261. (b) A : B
So, go through options 11 : 15
(a) 9×16 = 12×12 (√)  Let x be subtracting from both numbers
(b) 13×4 = 11×5 (×)  
(c) 30×24 = 45×13 (×) = 33 – 3x = 30 – 2x
(d) 3×5 = 5×2 (×) x=3
So, answer is 12 : 9 :: 16 : 12 262. (d) Milk : Water

MOCKTIME.COM ONLINE TEST SERIES CORRESPONDENCE COURSE

 A 3 : 1 = 4×7 Share of daughter = x
B 5 : 2 = 7 ×4 = Difference between share of
 Milk : Water son and share of daughter
A 21 : 7 9x – x = 8x = 10000
B 20 : 8 x = Rs. 1250
New mixture 41 : 15 Total property = 13x = 13×1250 = Rs. 16250
263. (d) Alcohol : Water 267. (c) The distance covered by
A 2 : 1 = 3 ×5 policeman in 5 steps is equal to
B 3 : 2 = 5 ×3 that of thief in 7 steps
 Alcohol : Water  5P=7T
A 10 : 5 P : T
B 9 : 6 7 : 8 (distance covered in
New mixture 19 : 11 each step)
264. (c) Rs. 1 : 50P : 25P  and policeman goes 8 steps
Value of coins 8x : 4x : 3x while thief moves 10 steps
No. of coins 8x × 1 : 4x × 2 : 3x × 4 Policeman : Thief
8x : 8x : 12x Steps 8 : 10
Total coins Distance in each steps 7 : 5
 8x+8x+12x = 28x 56 : 50
28x = 280 (Given) Speed = 28 : 25

No. of 50P coins are

= 8x = 8×10 = 80
265. (a) A + B + C = 555
A : B : C
Original ratio 268. (d) Tom : Jerry
Jumps 8 : 6
(LCM = 60)
Distance each jump 5 : 7
Speed = 40 : 42
= 15 : 12 : 10 20 : 21
15x + 12x +10x = 37x 269. (d) Let number be 4x and 5x
According to question
(5x)2 – (4x)2 = 81
C get  10×15 = Rs. 150
9x2 = 81
 By mistake the ratio of
x2 = 9
A : B : C (Taken)
x=3
4 : 5 : 6
value of A = 4×3 = 12
4x + 5x + 6x = 15x
270. (b) Let x is added
15x = 555

 12+6x = 25+5x
C get  6x = 37×6 = Rs. 222
 x = 13
Amount of C exceeds
So, x = 13 will be added
= 222 – 150
271. (d) According to the question
= Rs. 72
Sn Fe
266. (a) Share of son : Wife : Daughter are
A → 1 : 2 = 3)×5
S : W : D
B → 2 : 3 = 5)×3
3 : 1
Making quantity equal
3 : 1
Sn Fe
9 : 3 : 1
A → 5 : 10 = 15)×3
Total  9x + 3x + x = 13x
B → 6 : 9 = 15)×4
= Share of son = 9x

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 ×222 ×222
Sn Fe
A → 15 : 30 888 666
B → 24 : 36 (Boys) (Girls)
39 : 66 7 units = 888 + 666 = 1554
In final mixture 1 unit = 222
sn : Fe = 39 : 66 ATQ
= 13 : 22 [ x number of boys left]
272. (d) According to the question, 6 × 888 – 6x = 7×696
 5328 – 6x = 4872
 8x + 32 = 9x + 24 6x = 456  x = 76
8=x 277. (d) According to the question,
Let the 2 numbers (2x, 3x),
Therefore, the sum of the two
numbers is
= 2x + 3x x–y=5 ……..(i)
= 5x
= 5×8 = 40
273. (c) Given :
x + y = 7 ……….(ii)
 Solve equation (i) and (ii)
x=6
= y=1
This is required ratio 3 : 1
274. (b) Let their income 4x and 3x
Their saving = Rs.3200 each
278. (b) A : B = = (3 : 2)×3
According to the questions,
 B : C = = (3 : 5)×2
 A : B : C = 9 : 6 : 10
(A + B) : (B + C) = (9+6) : (6+10)
 7x–5600 = 9x–9600
= 15 : 16
 2x = 9600–5600
279. (a) According to the question,
 2x = 4000
A = 2000
 Income of A = 4x Story books = 1512
= 4×2000 = Rs. 8000 7 units → 1512
275. (a) Let their monthly income 8x and 5x 1 unit → = 216
According to the question 2 units → 216×2 = 432
other books = 432
[Income – Saving = Expenditure] New ratio of
 24x – 36000
As we know that only story books
= 25x – 50000 are added
x = 14000 4 units → 432
Diff. in monthly income
= 8x – 5x = 3x 1 units →
x = 14000 15 units → 108×15 = 1620
3x = 14000×3 = Rs. 42000 New collection of story books = 1620
276. (a) 1554(Total student) Number of story books are added
= 1620 – 1512 = 108
280. (c) According to the question,
4 : 3 Mixture of copper and aluminum

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 = 2000 gm thus, largest sides = 36 cm
30% is copper means = 285. (a)
= 600 gm copper d c
4x
Copper aluminum
600 gm 1400 gm x 3x
20% = 600 + 288 a b
1 unit = 30 (sum of opposite angles in cyclic
30 x quadrilateral are 180˚)
20% 80%  x + 4x = 180˚
1400 + x = 2400 gms  5x = 180˚
x = 1000 gms  x = 36˚
∠b = 3x  3 ×36  108˚
281. (a) According to the question,
∠b = 180˚ – 108˚  72˚
Rs 1 50 paise 25 paise
Ratio of 2 3 5 The fourth angle = 72˚
quantity 286. (c) Let,
 Sonali’s age = 5x
value in
 Monali’s age = 3x
Rupees
According to the question,
Total value in rupees = Rs. 4.75
4.75 unit ___________ 288 
1 unit ______________ 
3 unit _____________ 48×3 = 144  7x + 7 = 6x + 10
50 paise coins = 144 coins x=3
282. Let the first part is = x  So Monali’s present age = 3 x
second part is = y = 3×3 = 9 years
According to the question ,
5x + 11y = 195 ………….(i) 287. (a) B : A : C
x + y = 27 ……………(ii) 1 : 2
Solve equation (i) and (ii)
x=7 1 : 3
y = 10 1 : 2 : 6

So, A : B : C
283. (b) 2 : 1 : 6
Milk : water 288. (b) Assume no. = 5x, 8x
5 : 1 According to the question,
1 unit increase 8x – 5x = 48
= 5 liters 3x = 48
5 : 2 x = 16
×5 Smallest no. = 5x
1 unit → 5 ltr = 5×16 = 80
25 liter 5 unit → 25 ltr 289. (b)
The quantity of milk in mixture = 25 ltr a : b =7 : 9
b : c = 3 : 5 = 9 : 15 [ B is same]
284. (a) Ratio of sides a : b : c = 7 : 9 : 15
7 : 9 : 12 36 cm 290. (c) a : b = 4 : 5
b : c =5 : 6
×3 c : d =6 : 7
diff = 5 unit 15 cm
a : b :c : d
1 unit = 3cm 4 : 5 :6 : 7
12 units = 12×3 = 36 cm a : c =4 : 6

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 =2 : 3
291.
(a)
a=c=5
b=d=1

s
292. (a) x : y = 3 : 5
x – y =–2
Let number be 3A and 5A
3A – 5A = – 2
–2A = – 2
A=1
x + y = 8A
= 8×1
=8

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