0% found this document useful (1 vote)
554 views31 pages

Introduction To Long Division

Long division is used to solve division problems with large numbers that cannot be done mentally. It involves four simple steps: divide, multiply, subtract, and bring down. The steps are: 1) Divide the first digit of the dividend by the divisor, 2) Multiply the divisor by the quotient, 3) Subtract and 4) Bring down the next digit to repeat the process until there are no more digits remaining. If the subtraction results in a remainder of 0, the final quotient is the answer.

Uploaded by

qweer
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
0% found this document useful (1 vote)
554 views31 pages

Introduction To Long Division

Long division is used to solve division problems with large numbers that cannot be done mentally. It involves four simple steps: divide, multiply, subtract, and bring down. The steps are: 1) Divide the first digit of the dividend by the divisor, 2) Multiply the divisor by the quotient, 3) Subtract and 4) Bring down the next digit to repeat the process until there are no more digits remaining. If the subtraction results in a remainder of 0, the final quotient is the answer.

Uploaded by

qweer
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 31

Introduction to

Long Division
Introduction to
Long Division
Long division is a way to solve division
problems with large numbers. These
are division problems you cannot do in
your head.
Example
110 10  =

85 5=

96 4=
Four Simple Steps:

D Divide

M Multiply

S Subtract

B Bring Down
Acronym:

D Dad

M Mother

S Sister

B Brother
85 5 =
1. Divide using the division house.

I
5 I 85
How many 5s can fit in 8?

I
5 I 85
5x1=5

5 x 2 = 10
Since 5 x 2 = 10, we know that it exceeds
8. We use 1 instead. 

I
5 I 85
5x1=5

5 x 2 = 10
1
I
5 I 85
2. Multiply 1 and 5.

1
I
5 I 85
2. Multiply 1 and 5.

1
I
5 I 85
5
3. Subtract 8 and 5.

1
I
5 I 85
-
5
3
4. Bring down 5.

1
I
5 I 85
-
5
35
Divide 35 by 5.

1
I
5 I 85
-
5
35
Divide 35 by 5.

17
I
5 I 85
-
5
35
If we multiply 7 and 5, we get exactly 35.

17
I
5 I 85
-
5
35
35
Subtract 35 and 35.

17
I
5 I 85
-
5

-
3 5
35
0
If our subtraction ends in 0, our quotient, 17, is the
final answer.

17
I
5 I 85
-
5

-
3 5
35
0
85 5 = 17
Let's try more examples!
96 4=
D-Divide I
4 I 96
M-Multiply
S-Subtract
B-Bring Down
66 3=
D-Divide I
3 I 66
M-Multiply
S-Subtract
B-Bring Down
54 2=
D-Divide I
2 I 54
M-Multiply
S-Subtract
B-Bring Down
77 7=
D-Divide I
7 I 77
M-Multiply
S-Subtract
B-Bring Down
72 4=
D-Divide I
4 I 72
M-Multiply
S-Subtract
B-Bring Down
Nice Work!

You might also like