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Gravity: Gravity: Where Does It Fit In?

1) Gravity is the weakest of the fundamental forces but dominates on large scales due to its infinite range and always being attractive. 2) Newton formulated his universal law of gravitation, describing gravity as an inverse-square law force between all masses. This explained Kepler's laws of planetary motion and allowed Cavendish to calculate the mass of the Earth. 3) Near Earth's surface, gravitational acceleration g varies slightly due to the Earth's rotation and non-uniform density distribution but is approximated as a constant for simplicity. The gravitational potential well allows definition of gravitational potential energy.

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0% found this document useful (0 votes)
57 views10 pages

Gravity: Gravity: Where Does It Fit In?

1) Gravity is the weakest of the fundamental forces but dominates on large scales due to its infinite range and always being attractive. 2) Newton formulated his universal law of gravitation, describing gravity as an inverse-square law force between all masses. This explained Kepler's laws of planetary motion and allowed Cavendish to calculate the mass of the Earth. 3) Near Earth's surface, gravitational acceleration g varies slightly due to the Earth's rotation and non-uniform density distribution but is approximated as a constant for simplicity. The gravitational potential well allows definition of gravitational potential energy.

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1

Gravity Notes for PHYS 1121-1131. Joe Wolfe, UNSW

Gravity: where does it fit in?


Gravity Weak Strong
Electric Colour
[general nuclear nuclear
force* force
relativity] force force
intermediate
gravitons photons vector bosons pions gluons

electro-weak

Grand Unified Theories

Some tries
for classical
gravity

Theories Of Everything
* Electromagnetism "unified" by Maxwell, and also by Einstein: Magnetism
can be considered as the relativistic correction to electric interactions which
applies when charges move.

• Only gravity and electric force have macroscopic ("infinite")


range.
m graviton? = mphoton = 0
• Gravity weakest, but dominates on large scales because it is
always attractive

Greeks to Galileo:
i) things fall to the ground ('natural' places)
ii) planets etc move (variety of reasons)
but no connection (in fact, natural vs supernatural)
Newton's calculation: acceln of moon

= rmωm2
2
= (3.8 108 m) (27.3 242π 3600)
= 2.7 10-3 m.s-2
acceln of "apple" = 9.8 ms-2

aapple rm 385000 km
amoon = 3600; Re = 6370km = 60;
 rm  2
 R  = 3600
 e
Newton's brilliant idea: What if the apple and the moon accelerate according to the same law? →
What if every body in the universe attracts every other, inverse square law?
2

Newton's law of gravity:

m1m2 Negative sign means


F = −G _ // − r_
F
r2
Why is it inverse square? Wait for Gauss' law in electricity.

_ 12 = − F
F _ 21 Newton 3

Newton already knew Kepler's empirical law:


For planets, r3 ∝ Τ2 orbit radius and period
1
Now if F ∝ ac ∝ 2
r
then constant = acr = rω2r2 = r3ω2
2

Planet r from sun T ω rω2 r3ω2


million km Ms rad.s-1 ms-2
Mercury 58 7.62 8.25 10-7 3.95 10-5 1.31 1020 m3s-2
Venus 108 19.4 3.23 10-7 1.13 10-5 1.32 1020 m3s-2
Earth 150 31.6 1.99 10-7 5.94 10-6 1.33 1020 m3s-2
etc
3
How big is G? Cavendish's experiment (1798)

m1m2
F = −G
r2
From deflection and spring constant, calculate F, know m1 and m2, ∴ can
calculate G. G = 6.67 10-11 Nm2kg-2 ( or m3kg-1s-2
m.Me
Now also weight of m: |W| = mg ≅ G
Re2
∴ Cavendish first calculated mass of the earth:
gr 2 9.8 m.s-2 x (6.37 106 m)2
Me = e = = 6.0 1024 kg
G 6.67 10-11 Nm2kg-2
see http://www.physicscentral.com/action/action-01-5-print.html
and http://physics.usask.ca/~kolb/p404/cavendish/

Some numbers
What is force between two oil tankers at 100 m?
m m
F = − G 12 2
r
What happens when more there are ≥ 3 bodies?
Superposition principle.
_ all objects together = Σ F
F _ individual
_1 = Σ F
force on m 1
or F _ 1i due to masses m i
i
continuous F
_1 = ∫ dF
_
body body
4
Shell theorem
A uniform shell of mass M causes the same gravitational
force on a body outside is as does a point mass M located at the
centre of the shell, and zero force on a body inside it.

r
dθ Fg
m
F=0 R

M dm GMm
Fg =
R2

Example. If ρearth were uniform (it isn't), how long would it take
for a mass to fall through a hole through the earth to the other
side?

Mr = ρ.43 πr3

mρ.43 πr3
∴ Fr = − G
r2
F = − Kr where K = Gmρ.34 π

√ m
K
∴ motion is SHM with ω = Simple Harmonic Motion: discussed later

2π 2π 2π
Τ = ω = = = .... = 84 minutes
 π
√ Gρ.43 
√ GM/R3

∴ falls through (one half cycle) in 42 minutes (actually faster for real density profile)
5
Gravity near Earth's surface
Mm
W = |F g | = G 2
Re
Mm
W = mgo = G e2
r
go is acceln in an inertial (non-rotating) frame
M
go = G 2e
r
Usually, r ≅ Re, but
Me  R 2
go = G = gs  R +e h
(Re + h) 2  e 
 1 2 where g s is
= gs  1 + h/R 
 e g o at surface
Other complications:
i) Earth is not uniform (especially the crust) useful for prospecting
ii) Earth is not spherical
iii) Earth rotates (see Foucault pendulum)

(Weight) = − (the force exerted by scales)


At poles, _ − N
F _ = 0
At latitude θ, _F − N
_ = ma _
where a = rω2 = (Re cos θ)ω2
= .... = 0.03 ms-2 at equator
= 0 at poles
N
_ _ − ma_
F
We define − _ g = =
m m
So g_ is greatest at the poles, least at the equator, and does not
(quite) point towards centre.

horizontal _| g_
Earth is flattened at poles
6
Puzzle: How far from the earth is the point at which the
gravitational attractions towards the earth and that towards the sun
are equal and opposite? Compare with distance earth-moon
(380,000 km)

|Fe|= |Fs|
GMem GMsm
=
d2 (re - d)2
Me(re − d)2 = Msd2
M
re2 − 2red + d2 = M s d2
e
Ms 
 M − 1 d2 + 2red − re2 = 0
 e 
d = .... = ?

Gravitational field. A field is ratio of force on a particle to some


property of the particle. For gravity, (gravitational) mass is the
property:
F
_ grav
m = g_ = g_(r_) is a vector field
_Felec
cf electric field
q =E _ (r_) later in syllabus
Gravitational potential energy. Revision:
Potential energy
For a conservative force _F (i.e. one where work done against it, W =
_)) we can define potential energy U by ∆U = Wagainst. i.e.
W(r
f
∆U = − ∫ F_ . dr
__
i
_ ≅ constant
near Earth's surface, _Fg = mg
f
= − ∫ (-mgk
_) . (dx_i + dyj_ + dzk
_)
i
f
= mg _k . k
_ ∫ dz = mg (zf - zi)
i
choose reference at zi = 0, so U = mgz

Gravitational potential energy of m and M.


M m
r

Fg ds
f f
f Mm 1 1
∆Ug ≡ − ∫ F ds = ∫ Fgdr
_ g . __ = ∫ G 2 dr = − GMm[r − r ]
i i i r f i
GMm
Convention: take ri = ∞ as reference: U(r) = − r
U = work to move one mass from ∞ to r in the field of the other. Always negative.
Usually one mass >> other, we talk of U of one in the field of the other, but it is U of both.
7
Escape "velocity".
Escape "velocity" is minimum speed ve required to escape, i.e.
to get to a large distance (r → ∞).

v
M
r
R m
Projectile in space: no non-conservative forces so
conservation of mechancial energy
K i + U i = Kf + U f
1
mv 2 − GMm = 0 + 0
2 e R

√R
2GM
vesc =

For Earth: vesc =


√
2 6.67 10-11 m3kg-1s-2 5.98 1024 kg

= 11.2 km.s-1 = 40,000 k.p.h.


6.37 106 m

Put launch sites near equator: veq = Reωe = 0.47 km.s-1

Question In Jules Verne's "From the Earth to the Moon", the


heros' spaceship is fired from a cannon*. If the barrel were 100 m
long, what would be the average acceleration in the barrel?
vf2 − vi2 = 2as
v 2-0 (1.12 104 ms-2)2
a = e2s =
2 x 100 m
= 630,000 ms-2 = 64,000 g

* why? If you burn all the fuel on the ground, you don't have to
accelerate and to lift it. Much more efficient.

Planetary motion
"The music of the spheres" - Plato
Leucippus & Democritus C5 B.C.
heliocentric universe
Hipparchus (C2 BC) & Ptolemy (C2 AD) geocentric universe
Tycho Brahe (1546-1601) - very many, very careful, naked eye
observations.
Johannes Kepler joined him. He fitted the data to these empirical
laws:
Kepler's laws:
1 All planets move in elliptical orbits, with the sun at one
focus.
Except for Pluto and Oort cloud objects, these ellipses are ≅ circles.
M sun >> mplanet, so sun is ≅ c.m.
2 A line joining the planet to the sun sweeps out equal areas in
equal time.
Slow at apogee (distant), fast at perigee (close)
3 The square of the period ∝ the cube of the semi-major axis
Slow for distant, fast for close
8
Newton's explanations:
Law of areas:

Area = 21 r.rδθ
1
i.e. for same δt, 2 r2δθ = constant
Conservation of angular momentum L
_ . Sun at c.m.
momentum
∴ _ | = |r_ x _p| = |r_ x mv_|
|L = p. see later
= mrvtangential
δθ
= mr.rω = mr2
δt
m
= δt r2δθ = constant.
_ ⇒ Kepler 2.
Conservation of L
Law of periods: (we consider only circular orbits)
Kepler 3: T2 ∝ r3
Newton 2 → F = ma = m rω2
Mm  2π 2
G 2 = mr  T 
r  
 4π2 
T2 =  GM r3 → Kepler 3
(works for elipses with semi-major axis a instead of r)
Newton 2 &
Newton's gravity ⇒ Kepler 3
Newton 2 &
also ⇒ Kepler 1
Newton's gravity

Example What is the period of the smallest earth orbit? (r ≅ Re)


What is period of the moon? (rmoon = 3.82 108 m)

 √

 4π2  3 4 π2
T1 =  r = (6.37 10 6 ) 3 s
 GM 6.67 10 -11 5.98 10 2 4
= 84 min
Kepler 3: T2 ∝ r3
T2  r2 3/2  3.82 108 3/2
=   =   = 464
T1  r1  6.37 106
T2 = 464 T1 = 27.2 days

For other planets: most have moons, so the mass of the planet
can be calculated from
 4π2 
T2 =  GM r3
9
Orbits and energy
No non-conservative forces do work, so mechanical energy is
constant:
E = K + U
GMm
= 1 mv2 −
2 r
Let's remove v. Consider circular orbit:
v2 F GMm
r = ac = m = r2m

∴ 1
mv2 = 1 GMm
2 2 r
E = K + U
GMm GMm
= 1 − r
2 r
GMm
= − 2r

i.e. E = 21 U, or K = − 12 U, or K = − E.
Small r ⇒ U very negative, K large. (inner planets fast, outer slow)

Example A spacecraft in orbit fires rockets while pointing


forward. Is its new orbit faster or slower?

ds ∴ Work done on craft


_ // __
F
W = ∫F _ . __
ds > 0.
GMm
∴ E = − 2r increases, i.e. it becomes less negative. (R is
larger). K = - E, ∴ K smaller, so it travels more slowly.
called "Speeding down"
Quantitatively:
Ki = − Ei Kf = − Ef = − (Ei + ∆E)
Kf = Ki − ∆E
1
mvf2 = 21 mvf2 − W
2
Looks odd, but need lots of work to get to a high, slow orbit.
10
Manœuvring in orbit.

To catch up, vessel 1 fires engines backwards, and loses energy.


It thus falls to a lower orbit where it travels faster, until it catches
up. It then fires its engines forwards in order to slow down (it
climbs back to the original, slower orbit).

Example: In what orbit does a satellite remain above the same


point on the equator?
Called the Clarke Geosynchronous Orbit
i) Period of orbit = period of earth's rotation
ii) Must be circular so that ω constant
T = 23.9 hours
 4π2 
T2 =  GM r3



3
GMT2
r = = .....
4π2
= 42,000 km popular orbit!

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