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Guide Question 5

To standardize 0.05M NaOH using 30 mL of base, 0.31 grams of potassium hydrogen phthalate (KHP) should be weighed into a flask. The molar mass of KHP is calculated to be 204.22 g/mol. The balanced equation for the reaction shows a 1:1 mole ratio between KHP and NaOH.

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Davinci Legaspi
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50 views1 page

Guide Question 5

To standardize 0.05M NaOH using 30 mL of base, 0.31 grams of potassium hydrogen phthalate (KHP) should be weighed into a flask. The molar mass of KHP is calculated to be 204.22 g/mol. The balanced equation for the reaction shows a 1:1 mole ratio between KHP and NaOH.

Uploaded by

Davinci Legaspi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Guide Question 5

5. How many grams of potassium hydrogen phthalate (KHP/ KHC 8H4O4) should be weighed into a flask
to standardize 0.05M NaOH if you wish to use 30 mL of base for the titration.
Solution:

Given:
30 ml (0.03 L)
0.05M NaOH

Molar Mass of KHP or KHC8H4O4


C8 = 12.011 X 8 96.088
H5 = 1.008 X 5 5.04
K = 39.098 39.098
O4 = 16 X 4 64
204.22 g/mol

Balanced Equation:
1 KHP + 1NaOH  H2O + NaKP
or
KHC8H4O4 + NaOH  H2O +NaKC8H4O4

g KHP = 0.03 L x 0.05 M NaOH x 1 mole KHP x 204.2 g KHP =


L 1 mole NaOH 1 mole KHP 0.31 g

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