COMPOSITION OF
ATOM
   Engr. Charito Ilagan
• The atom is a basic unit of an element that can enter
 into chemical combination.
• It has a dense central nucleus surrounded by a cloud
 of negatively charged electrons.
 The atomic nucleus contains a mix of positively
charged protons and electrically neutral neutrons
(except in the case of hydrogen-1, which is the only
stable nuclide with no neutrons).
• The electrons of an atom are bound to the nucleus by
 the electromagnetic force. Likewise, a group of atoms
 can remain bound to each other by chemical
 bonds based on the same force, forming a molecule.
• An atom containing an equal number of protons and
 electrons is electrically neutral, otherwise it is positively
 or negatively charged and is known as an ion.
• An atom is classified according to the number of
 protons and neutrons in its nucleus:
   the number of protons determines the chemical
  element and the number of neutrons determines
  the isotope of the element.
• Atoms can only be observed individually using special
 instruments such as the scanning tunneling microscope.
• Over 99.94% of an atom's mass is concentrated in the
 nucleus, with protons and neutrons having roughly equal
 mass.
 Their masses in kilograms :
    Neutron (n0) = 1.6749286 x 10-27 kg
    Proton (p+) = 1.6726231 x 10-27 kg
    Electron(e-) = 9.1093897 x 10-31 kg
• The electrons determine the chemical properties of an
 element, and strongly influence an atom’s magnetic
 properties.
• The principles of quantum mechanics have been
 successfully used to model the observed properties of
 the atom.
➢EARLY ATOMIC THEORY
• Early thoughts concerning atoms were proposed by a
 Greek philosopher named Democritus.
 He suggested that the world was made of two things:
 an empty space and tiny particles called atoms. His
 belief , however, was not supported by experimental
 evidence.
➢DALTON’S ATOMIC THEORY
 John Dalton postulated the following in 1803:
 ▪ Each element is composed of extremely small
   particles called atoms.
    All atoms of a given element are identical , having
    the same size, mass, and chemical properties.
   The atoms of one element are different from the
    atoms of all other elements.
▪ Compounds are composed of atoms of more than
  one element.
  In any compound the ratio of the number of
  atoms of any two of the elements present are
  either an integer or a simple fraction.
▪ A chemical reaction involves only the separation,
 combination or rearrangement of atoms; it does
 not result in their creation or destruction.
➢Dalton’s theory explains several simple laws of
 chemical combination:
 ▪The Law of Definite Composition states that
  different samples of the same compound
  always contains its constituent elements in the
  same proportion by mass.
▪ The Law of Multiple Proportion states that if two
 elements can combine to form more than one
 compound, the masses of one element that combine
 with the fixed mass of the other are in the ratios of
 small whole numbers.
▪ The Law of Conservation of Mass states that the total
 mass of materials present after the reaction is the
 same as the total mass before the reaction.
• Substances which chemically react are called reactants and
 the newly formed substances are called products.
• A French chemist, Antoine Lavoisier, who is known as the
 father of modern chemistry, changed chemistry from a
 qualitative to a quantitative science. He proved that the
 mass of the products in a chemical reaction is equal to the
 mass of the reactants. There are no more atoms at the end
 of the chemical reaction than there were at the beginning.
▪ The Law of Conservation of Mass states that
 matter can neither be created nor destroyed in
 a chemical reaction.
▪ Applying the Law of Definite Composition
  1. A 0.001 g sample of magnesium when combined with
     oxygen yields 0.166g of magnesium oxide. A second
     magnesium sample with a mass of 0.144g is also
     combined with oxygen. What mass of magnesium oxide
     is produced from this second sample?
    Given: 1st sample            2nd sample
       m of Mg = 0.001 g         m of Mg = 0.144 g
       m of MgO = 0.166 g        m of MgO = ?
•   Required: m of MgO in the second sample
    Solution:
        1st sample       2nd sample
       𝑚𝑎𝑠𝑠 𝑜𝑓 𝑀𝑔         𝑚𝑎𝑠𝑠 𝑜𝑓 𝑀𝑔
                     =
       𝑚𝑎𝑠𝑠 𝑜𝑓 𝑀𝑔𝑂        𝑚𝑎𝑠𝑠 𝑜𝑓 𝑀𝑔𝑂
2) Use the information provided in first sample in
  problem no. 1 to determine the mass of magnesium
  contained in 0.500 g of MgO.
▪ Law of Conservation of Mass
 1) A 0.455g sample of magnesium is allowed to burn in 2.315g
    oxygen gas. The sole product is magnesium oxide. After the
    reaction, the mass of unreacted oxygen is 2.015 g. What
    mass of magnesium oxide was produced?
   Given:
       Before the reaction          After the reaction
       mMg = 0.445g                 munreacted O = 2.015 g
       mO = 2.315 g
     Required: mass of magnesium oxide
Solution:
            Mg + O2              MgO + unreacted O2
       Before the reaction   =     After the reaction
2) A 7.12 g sample of magnesium is heated with 1.8 g
  bromine. All the bromine were used up and 2.07 g
  of magnesium bromide is the only product.
▪ Law of Multiple Proportion
 1) A student finds that 15.2 g of nitrogen will react with 17.37g,
    34.74g or 43.43g of oxygen to form three different
    compounds. What is the ratio of oxygen per gram of
    nitrogen in each compound?
    Given :
         mN = 15.2 g        m1 O = 17.37 g
                            m2 O = 34.74 g
                            m3 O = 43.43g
     Required: Ratio of oxygen per g of nitrogen
Solution:
                   17.37 𝑔
  Compound 1   =             =
                   15.2 𝑔
                   34.74𝑔
  Compound 2 =               =
                   15.2 𝑔
                   43.43𝑔
  Compound 3 =               =
                   15.2𝑔
   Ratio =
2) A chemist prepares three compounds containing
   9.8g fluorine in 23.2g, 16.6g and 19.3g of sulfur.
   Determine the ratio of the amount of sulfur per
   gram of fluorine.
Early Research on Atomic
        Principles
      General Chemistry
▪ The first cathode ray tube (CRT) was made by Michael
 Faraday in 1830.
▪ In passing electricity through the evacuated glass
 tubes, he discovered cathode rays (a type of radiation
 emitted by the negative terminal of the tube or
 cathode)
▪ All subsequent experiments using the cathode ray lead
 to the discovery of the following:
1) Protons - in 1896 by Eugene Goldstein
2) Electrons – in 1897 by LJ Thomson
3) Neutons in 1932 by James Chadwick
4) X-rays in 1895 by Wilhelm Roentgen
5) Radioactivity – in 1896 by Antoine Henri
                   Becquerel
Early Atomic Model
    General Chemistry
                   PLUM PUDDING MODEL
In 1897, J. J. Thomson
• imagined an atomic model with a
 large and massive positively charged
 entity, with tiny, far less massive
 electrons embedded therein.
NUCLEUS MODEL
• In 1909, Ernest Rutherford discover that the positive charged
 in an atom was concentrated in a very small volume called
 the "atomic nucleus," rather than being spread out.
BOHR MODEL
  In 1913, Niels Bohr
• depicts the atom as small, positively charged nucleus surrounded by
 electrons that travel in circular orbits around the nucleus—similar in
 structure to the solar system, but with attraction provided by
 electrostatic forces rather than gravity.
SOMMERFELD’S MODEL
• In 1916, Sommerfield refined the assumptions of Bohr. He
 believed that lower energy electrons revolved in a circular
 path around the nucleus and the higher energy electrons
 flow an elliptical path.
• WAVE MECHANICAL MODEL
• Physicists W. Heisenberg, L. de Broglie and E. Schrodinger
 developed a model of an atom, which was based on
 quantum mechanics advanced by Max Planck and Albert
 Einstein.
• Quantum mechanics provides a mathematical description of
 much of the dual particle-like and wave-like behavior and
 interactions of energy and matter
• In 1924, L. de Broglie originated the idea that an
 electron has dual properties – a particle and a wave.
• Schrodinger provided mathematical calculations of
 the energy of each electron in an atom.
• This model shows that electrons occupy various
 energy levels and sublevels.
• QUANTUM MECHANICAL MODEL
 Schrodinger’s mathematical model for the atom led to the
 present quantum mechanical model. The probability of
 finding an electron is in a given region of space called
 orbital.
• In 1926, Heisenberg proposed the Uncertainty Principle which
 states that it is impossible to determine simultaneously the
 exact position and exact momentum of a body as small as an
 electron.
• Thus the precise description of the path of an electron in an
 atom is impossible using Bohr’s approach.
• Instead Schrodinger used de Broglie’s relation to develop an
 equation that describes the electron in terms of its wave
 character.
➢Atomic Number and Mass Number
 Each atom is characterized by its atomic number, Z,
 and its mass number, A.
  It is represented by a chemical symbol for the element
 with the atomic number of the element placed at the
 lower left and the mass number placed at the upper
 left.
• The atomic number gives the number of protons; it
 also refers to the number electrons in an electrically
 neutral atom.
• The mass number refers to the total number of
 protons and neutrons.
• Each element has at least one isotope with an
 unstable nucleus that can undergo radioactive
 decay.
• This can result in a transmutation that changes the
 number of protons or neutrons in a nucleus.
• Isotopes are atoms of the same element with the
 same atomic number but differ in their atomic
 masses.
• Example:   35Cl   37Cl
• The average atomic mass is found by multiplying the
 exact atomic mass of each isotope by its percent
 abundance, then take the sum of their products.
Example:
 1. Solve for the average atomic mass of chlorine given its 2
    isotopes and their corresponding masses and the %
    abundance:
      35Cl – isotopic mass = 34.969 amu % abundance = 75.53%
      37Cl – isotopic mass = 36.966 amu % abundance = 24.47%
     Solution:
      35Cl = 34.969 ( 0.7553) = 26.410
       37Cl = 36.966( 0.2447) = 9.046
                                    35. 458amu
2) Given:
   12Carbon:   isotopic mass = 12 amu   % abundance = 98.892%
  13Carbon:  isotopic mass = 13.00335 % abundance = 1.108%
   Solve for the average atomic mass.