100% found this document useful (11 votes)
21K views6 pages

Sample Calculation For FM 200 Clean Agent: STEP 1: Determined Room Volume

The document provides steps to calculate the quantity of FM 200 clean agent needed to extinguish a fire in a room measuring 10m x 5m x 3m. It determines the room volume is 150 cubic meters, with no solid objects. Using the NFPA 2001 formula, it calculates the required weight of FM 200 as 81.94 kg. It then selects a 100 liter cylinder, one nozzle, and checks the piping can discharge the agent within 10 seconds.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
100% found this document useful (11 votes)
21K views6 pages

Sample Calculation For FM 200 Clean Agent: STEP 1: Determined Room Volume

The document provides steps to calculate the quantity of FM 200 clean agent needed to extinguish a fire in a room measuring 10m x 5m x 3m. It determines the room volume is 150 cubic meters, with no solid objects. Using the NFPA 2001 formula, it calculates the required weight of FM 200 as 81.94 kg. It then selects a 100 liter cylinder, one nozzle, and checks the piping can discharge the agent within 10 seconds.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 6

SAMPLE 

CALCULATION FOR FM 200 CLEAN AGENT

3
10
5

STEP 1: Determined Room Volume

L x W x H 

10m x 5m x 3m = 150 m³

STEP 2: Determined Solid Object Volume
• Calculate volume of beam/duct/pillars or solid 
object from in the room STEP 3: Minimum Agent Concentration
• NOTE : Assume this room to extinguish Class C Fire.
Solid Object = 0 m³
Hence, Design Concentration is = 7.5
Hence, Reduce Volume = 150 – 0 = 150 m³
SAMPLE CALCULATION FOR FM 200 CLEAN AGENT

STEP 4: Determine FM 200 Gas Quantity Note that 

NFPA 2001 formula can be used; V = 150 m³ , c = 7.20% , 

v C Take Room Temperature say 21°C
W =   x 
s 100 C
Hence, 
W = Weight of  agent required in Kg (lb)
S = 0.1269 + 0.0005 (21)  m
kg
³
= 0.1374 m
kg
³

V = Hazard volume in m³

m³ ft³ Hence,
S = specific vapor volume in   or  
kg lb
150 7.5
W =  x  = 81.94 Kg
where S = 0.1269 + 0.0005 T  m ³ 0.1374 100 7.5
kg 100

or 1.885 + 0.0046 T ftlb³
SAMPLE CALCULATION FOR FM 200 CLEAN AGENT

STEP 5: Adjust Quantity For Agent With Altitude Correction Factor

For this calculation take altitude height at sea level

Hence, correction factor = 1

Wcorrection = weight of gas x altitude correction factor

Wcorrection = 81.94 x 1 = 81.94 Kg
SAMPLE CALCULATION FOR FM 200 CLEAN AGENT

STEP 6: Cylinder Selection

Note that 1 liter = 1 Kg

Hence;

Our Gas Weight is 81.94 Kg »» 82 Kg = 82 Liter 

Cylinder selection must to nearest higher cylinder selection = 100 liter capacity
SAMPLE CALCULATION FOR FM 200 CLEAN AGENT

STEP 7: Nozzle Selection

Area of Room = L x W = 10 x 5 = 50 m²

Say we want to used 8 port type of nozzle 

NOTE : Nozzle Maximum coverage area = 237.8 m²

Hence,

Area Of Room Covered


Quantity Of Nozzle Required =  Area of Nozzle Coveraged

50
=   = 0.21 unit »» 1 Unit 
237.8

So we will install only 1 Nozzle in the room
STEP 8: Piping selection

Check what is the FM200 discharge time?
NOTE: FM200 is discharged into the risk within 10 seconds or less and suppresses the 
fire immediately.

Hence,
81.94
Wper second = Weight of the gases
=   =  8.19 Kg
Discharge Time 10 s

Refer Pipe Chart (from manufacturer cataloged) ;

You might also like