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Deflection Check

The document contains calculations to check the deflection of two simply supported beams under a maximum applied load. For the first beam, which is 1 meter long, the maximum calculated deflection is 4.289 mm, which is less than the allowable deflection of 5 mm. The maximum allowable load is also greater than the applied load, so the beam passes the deflection check. For the second, longer beam of 4.3 meters, the maximum deflection is 1466.175 mm, which exceeds the allowable deflection of 21.5 mm. The maximum allowable load is also less than the applied load, so this beam does not pass the deflection check.

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Myat Thu Zar Khine
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289 views1 page

Deflection Check

The document contains calculations to check the deflection of two simply supported beams under a maximum applied load. For the first beam, which is 1 meter long, the maximum calculated deflection is 4.289 mm, which is less than the allowable deflection of 5 mm. The maximum allowable load is also greater than the applied load, so the beam passes the deflection check. For the second, longer beam of 4.3 meters, the maximum deflection is 1466.175 mm, which exceeds the allowable deflection of 21.5 mm. The maximum allowable load is also less than the applied load, so this beam does not pass the deflection check.

Uploaded by

Myat Thu Zar Khine
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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Calculations for:

Deflection Check

DEFLECTION
Beam length L L = 1.0 m
For simply supported beam δallow L / 200 = 5.0 mm

Max dead Load = 1.45 kN / m


Max imposed load = 5.00 kN / m
Applied load wmax = 6.45 kN / m
Youngs' modulus of steel, E E = 235 N / mm2
Min reqd sec mt of inertia IXX, min reqd = 7 148 cm4
Moment of inertia about major axis IXX, prov = 8 333 cm4
Max defection δmax = 5 w L / 384 EI
4
= 4.289 mm < L / 200 (OK!)

Max allowable UDL wallow = 384 E I δallow / 5 L4 = 8 kN / m > wmax (OK!)

DEFLECTION
Beam length L L = 4.3 m
For simply supported beam δallow L / 200 = 21.5 mm

Max dead Load = 1.45 kN / m


Max imposed load = 5.00 kN / m
Applied load wmax = 6.45 kN / m
Youngs' modulus of steel, E E = 235 N / mm2
Min reqd sec mt of inertia IXX, min reqd = 568 285 cm4
Moment of inertia about major axis IXX, prov = 8 333 cm4
Max defection δmax = 5 w L4 / 384 EI = 1466.175 mm > L / 200 (NOT OK!)

Max allowable UDL wallow = 384 E I δallow / 5 L4 = 0.09 kN / m < wmax (NOT OK!)

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