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2.50 KG 3.90 KG .850 M/s 11.5 Kgm/s 2.06 M/s 5.10 KG 1.00 KG 0.900 M/s 4.60 M/s - 4.60 M/s

This document provides information about momentum and 1D collisions through a PhET simulation lab. It defines momentum and the momentum-impulse theorem. The procedure has students use the simulation to explore elastic and inelastic collisions by changing masses and velocities of objects and observing how momentum is transferred or not. It concludes by having students calculate momentum, velocity, force, and energy values for various collision scenarios.

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80 views

2.50 KG 3.90 KG .850 M/s 11.5 Kgm/s 2.06 M/s 5.10 KG 1.00 KG 0.900 M/s 4.60 M/s - 4.60 M/s

This document provides information about momentum and 1D collisions through a PhET simulation lab. It defines momentum and the momentum-impulse theorem. The procedure has students use the simulation to explore elastic and inelastic collisions by changing masses and velocities of objects and observing how momentum is transferred or not. It concludes by having students calculate momentum, velocity, force, and energy values for various collision scenarios.

Uploaded by

caleb f
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOC, PDF, TXT or read online on Scribd
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Name: __________________

Momentum and Simple 1D Collisions PhET Lab

Introduction: When objects move, they have momentum. Momentum, p, is


simply the product of an object’s mass (kg) and its velocity (m/s). The unit
for momentum, p, is kgm/s. During a collision, an object’s momentum can be transferred to impulse,
which is the product of force (N) and time (s) over which the force acts. This allows us to write the
momentum-impulse theorem: p  mv  Ft

Procedure: 3.90 kg .850 m/s 11.5 kgm/s 2.06 m/s


Play 2.50 kg
5.10 kg 1.00 kg 0.900 m/s 4.60 m/s -4.60 m/s

KE stands for Kinetic Energy KE  1 mv and is measured in joules. Note that kinetic energy is not a vector
2
2
quantity. Describe the effect of an elastic collision on the total kinetic energy of the two-object system.

____________________________________________________________________________________________

Perfectly Inelastic Collisions: To begin a collision: To restart a collision:

 Take some time to familiarize yourself with 1D inelastic collisions. Play. Investigate. Learn.
 Contrast an inelastic collision with an elastic collision. ______________________________________________
 Complete the below table without the simulation and check your work in the simulation.

m1 m2 v1 v2 ptotal v12’
1.20 kg 1.20 kg +1.50 m/s -1.80 m/s

2.40 kg 4.80 kg +1.30 m/s 7.00 kgm/s

1.50 kg 5.50 kg +3.20 m/s +.800 m/s

2.50 kg 1.20 m/s 0.0 m/s

Describe the effect of an inelastic collision on the total kinetic energy of the two-object system.

____________________________________________________________________________________________

Conclusion Questions:

1. A collision where both momentum and kinetic energy are conserved is an elastic / inelastic collision.

2. A 500. gram cart moving at 0.360 m/s has how much momentum? (careful...units!) ______________
3. If the above 500. gram cart was to bounce back and return with a velocity of -0.240 m/s, what is its change in

momentum? ______________

4. How fast must a 250. gram cart be traveling to have a momentum of 0.450 kgm/s? ______________

5. A 0.230 kg baseball is thrown with a speed of 41 m/s. What is the ball’s momentum? ______________

6. If the above ball comes to rest in the catcher’s mitt in 0.085 seconds, how much force does the ball apply on the

catcher’s mitt? (hint: use the impulse-momentum theorem) ______________

7. Imagine you are ice skating with your BFF. Both of you at rest, when you shove him/her away from you. You have a

mass of 65 kg and he/she has a mass of 55kg. When you shove off, you move away with a velocity of 2.0 m/s. With what

velocity does your BFF move away from you? ______________

8. If a 250. gram cart moving to the right with a velocity of +0.31 m/s collides inelastically with a 500. gram cart traveling to

the left with a velocity of -0.22 m/s, what is the total momentum of the system before the collision? ______________

9. What is the resulting velocity of the above two-car system (stuck together)? ______________

10. A 9.0 kg bowling ball races down the lane at 15 m/s before striking a bowling pin (at rest) with a mass of 0.85 kg. If the

0.85 kg pin bounces backward with a velocity of 45 m/s, what is the velocity of the bowling ball after the collision?

_______________

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