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Chapter Four Plantain Soap

The document presents a series of titration results for different concentrations and times, showing final, initial, and titer values across three trials. It calculates the average titer for each condition and provides the molarity of the base used in the titrations. The results indicate consistent molarity values across various conditions.

Uploaded by

Peter Dindah
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© © All Rights Reserved
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65 views17 pages

Chapter Four Plantain Soap

The document presents a series of titration results for different concentrations and times, showing final, initial, and titer values across three trials. It calculates the average titer for each condition and provides the molarity of the base used in the titrations. The results indicate consistent molarity values across various conditions.

Uploaded by

Peter Dindah
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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50:20

1st 2nd 3rd


Final 4.90 9.70 14.80
Initial 0.00 4.90 9.70
Titer 4.90 4.80 5.10

4.90 + 4.80 + 5.10 = 14.40 = 4.93


3 3

1st 2nd 3rd


Final 4.90 9.70 14.80
Initial 0.00 4.90 9.70
Titer 4.90 4.80 5.10
100:20

1st 2nd 3rd


Final 4.00 7.10 12.50
Initial 0.00 4.00 7.10
Titer 4.00 3.10 5.40

4.00 + 3.10 + 5.40 = 12.50 = 4.2


3 3
150:20

1st 2nd 3rd


Final 4.10 8.20 12.00
Initial 0.00 4.10 8.20
Titer 4.10 4.10 3.80

4.10 + 4.10 + 3.80 = 12 = 4


3 3
200:20

1st 2nd 3rd


Final 3.70 6.60 10.10
Initial 0.00 3.70 6.60
Titer 3.70 2.90 3.50

3.70 + 2.90 + 3.50 = 10.10 = 3.4


3 3
250:20

1st 2nd 3rd


Final 3.50 9.30 9.10
Initial 0.00 3.50 6.30
Titer 3.50 2.80 2.80

3.50 +2.80 + 2.80 = 9.10 = 3.03


3 3
300:20

1st 2nd 3rd


Final 2.80 5.60 8.50
Initial 0.00 2.80 5.60
Titer 2.80 2.80 2.90

2.80 + 2.80 + 2.90 = 8.50 = 2.83


3 3
Table for constant water ration and Variable Time

10 Minites

1st 2nd 3rd


Final 3.20 7.00 11.30
Initial 0.00 3.20 7.00
Titer 3.20 3.80 4.30

3.20 + 3.80 + 4.30 = 11.30 = 3.8


3 3
20 Minutes

1st 2nd 3rd


Final 3.80 8.00 13.20
Initial 0.00 3.80 8.00
Titer 3.80 4.20 5.20

3.80 + 4.20 + 5.20 = 13.20 = 4.4


3 3
30 Minutes

1st 2nd 3rd


Final 4.90 10.30 15.10
Initial 0.00 5.10 10.30
Titer 4.90 4.80 4.80

4.90 + 4.80 + 6.10 = 15.80 = 5.3


3 3
40 Minutes

1st 2nd 3rd


Final 5.10 10.30 15.10
Initial 0.00 5.10 10.30
Titer 5.10 5.20 4.80

5.10 + 5.20 + 4.80 = 15.10 = 5.03


3 3
50 Minutes

1st 2nd 3rd


Final 5.40 10.60 15.50
Initial 0.00 5.40 10.60
Titer 5.40 5.20 4.90

5.4 + 5.60 + 4.30 = 15.30 = 5.2


3 3
60 Minutes

1st 2nd 3rd


Final 5.90 11.00 16.10
Initial 0.00 5.90 11.00
Titer 5.90 5.10 5.10

3.20 + 3.80 + 4.30 = 16.10 = 5.4


3 3
MAVA = nA
MBVB B

Were MA = Molarity of Acid


MB = Molarity of Base =
VB = Value of Base = 20
HCl + KOH KCl + H2O(c)

50:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

100:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20
MB = 0,12325

150:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

200:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

250:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

300:20

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

10min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325
20min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

30min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

40min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20
MB = 0,12325

50min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

60min

0.5 X 4.93 = 1
MB x20 1

2.4 65 = 20MB
20MB 20

MB = 0,12325

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