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TABLE 56
KILOGRAMS PER LITRE AT 15°C AND LITRES AT 15°C
PER METRIC TON AGAINST DENSITY AT 15°C
(Density in this table is mass per unit volume at 15°C expressed in
kilograms per litre.)
This table gives the weight in air in kilograms of 1 L of oil at 15°C and the
volume in litres at 15°C occupied by 1 metric ton in air of oil both for values
of density at 15°C in the range 0.500 to 1.100 kg/L.
When a weight in kilograms is calculated by multiplication of the deter-
mined density by the volume in litres at the same temperature, the result is
a weight in vacuo. Such weight, for comparison with direct weighing or for
conversion to the corresponding weight in the U.S. system or the British
system of’ measurement, must be corrected for the buoyancy of air. This
correction has been incorporated into the values in this table.
In those countries where metric weights are legally required to be weights
in vacuo (that is, mass), this table should be used only in process that
involve direct weighing, as for example, when volumetric quantities are
being filled into containers by weight. The table may, however, be used in
these countries in conjunction with the following short table which gives
factors for the conversion of weight in air to weight in vacuo and vice versa:
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Factor for Convert- Factor for Convert-
Density at 15°C | ing Weightin Vacuo | Density at 18°C | ing Weight in Air to
(kg/L) to Weight in Air (kg/L) Weight in Vacuo
0.5000 to 0.5191 0.99775 0.5000 to 0.5201 1.00225
0.5192 to 0.5421 0.9785 0.5202 to 0.5432 1.00215
0.5422 to 0.5673 0.99795 0.5433 to 0.5684 1.00205
0.5674 to 0.5950 0.99805 0.5685 to 0.5960 1.00195
0.5951 to 0.6255 0.99815 0.5961 to 0.6265 1.00185
0.6256 to 0.6593 0.99825 0.6266 to 0.6603 1.00175
0.6594 to 0.6970 0.99835 0.6604 to 0.6980 1.00165
0.6971 to 0.7392 0.99845 0.6981 to 0.7402 1.00155
0.7393 to 0.7869 0.99855 0.7403 to 0.7879 1,00145
0.7870 to 0.8411 0.99865 0.7880 to 0.8421 1.00135
0.8412 to 0.9034 0.99875 0.8422 to 0.9044 1.00125
0.9035 to 0.9756 0.99885 0.9045 to 0.8766 1.00115
0.9757 to 1.0604 0.99895 0.9767 to 1.0614 1.00105
1.0605 to 1.1000 0.99905 1.0615 to 1.1000 1.00095
This table must be entered with density at 15°C.
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EXAMPLES
1. It is required to fill cans with exactly 2 L of an oil measured at 15°C,
using a weight-filling machine. If the density of the oil is 0.8943 kg/L at
15°C, what weight should be set on the scale of the machine?
Enter the table with 0.894 kg/L density and note that the weight of
BNI sy sania pare nroaes poumegess ot arene smaaeeneye ves 0.8929 kg.
Likewise, enter the table with 0.895 kg/L density and note that the
weight of I L is 0.8939 ke.
This represents an increase in weight of 0.0010 kg for an increase
of 0.0010 kg/L in density. Therefore, by simple proportion, an in-
crease in density from 0.894 to 0.8943 kg/L increases the weight by
0.3 x 0.0010 or 0.0003 kg
Hence, | L of oil having a density of 0.8943 kg/L at 15°C weighs 0.8929
+ 0.0003 or . 0.8932 kg
Then, 2 L of the oil at 15°C weigh 2 x 0.8932 or 1.7864 ke
The filling machine is therefore set a 1.787 kg.
2. A quantity of oil having a density of 0.9418 kg/L at 15°C has been
invoiced as 1368.231 metric tons in air. What is the volume in litres at 15°C?
Enter the table with 0.941 kg/L density and note that the volume
occupied by I metric ton iS ........-eec eee eee eeee ees 1063.9 L
Likewise, enter the table with 0.942 kg/L density and note that
the volume occupied by I metric ton is... : 1062.8 L.
This represents a decrease in volume of 1.1 L for an increase of
0.001 kg/L in density. Therefore, by simple proportion, an
increase in density from 0.941 to 0.9418 kg/L decreases the
volume by 0.8 X L.1 or 0.88 L.
Hence, | metric ton of oil having a density of 0.9418 kg/L at 15°C
occupies a volume of 1063.9 ~ 0.88 or ........00.0ec0 00 1063.02 L.
Then, 1368.231 metric tons of this oil at 15°C occupy a volume of
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DENSITY (15 DEGC?
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KILOGRAMS CUBIC TRS.
DENSITY
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PER
TONNE
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PAGE 5 OF TAME 56
DENSITY
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