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ASTM Table 56

ASTM table
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100% found this document useful (5 votes)
4K views8 pages

ASTM Table 56

ASTM table
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© © All Rights Reserved
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6:10 PM all stl 40 2 GD () — @ scribd.com/document/ 3° = §3 SCRIBD ( Search Q ‘his content inappropriate? Report this Document A Saved API MPMS#11-) VOL*XI/XII 82 MM 0732290 O52buS2 635 mm TABLE 56 KILOGRAMS PER LITRE AT 15°C AND LITRES AT 15°C PER METRIC TON AGAINST DENSITY AT 15°C (Density in this table is mass per unit volume at 15°C expressed in kilograms per litre.) This table gives the weight in air in kilograms of 1 L of oil at 15°C and the volume in litres at 15°C occupied by 1 metric ton in air of oil both for values of density at 15°C in the range 0.500 to 1.100 kg/L. When a weight in kilograms is calculated by multiplication of the deter- mined density by the volume in litres at the same temperature, the result is a weight in vacuo. Such weight, for comparison with direct weighing or for conversion to the corresponding weight in the U.S. system or the British system of’ measurement, must be corrected for the buoyancy of air. This correction has been incorporated into the values in this table. In those countries where metric weights are legally required to be weights in vacuo (that is, mass), this table should be used only in process that involve direct weighing, as for example, when volumetric quantities are being filled into containers by weight. The table may, however, be used in these countries in conjunction with the following short table which gives factors for the conversion of weight in air to weight in vacuo and vice versa: hat is Scribd? A Saved Factor for Convert- Factor for Convert- Density at 15°C | ing Weightin Vacuo | Density at 18°C | ing Weight in Air to (kg/L) to Weight in Air (kg/L) Weight in Vacuo 0.5000 to 0.5191 0.99775 0.5000 to 0.5201 1.00225 0.5192 to 0.5421 0.9785 0.5202 to 0.5432 1.00215 0.5422 to 0.5673 0.99795 0.5433 to 0.5684 1.00205 0.5674 to 0.5950 0.99805 0.5685 to 0.5960 1.00195 0.5951 to 0.6255 0.99815 0.5961 to 0.6265 1.00185 0.6256 to 0.6593 0.99825 0.6266 to 0.6603 1.00175 0.6594 to 0.6970 0.99835 0.6604 to 0.6980 1.00165 0.6971 to 0.7392 0.99845 0.6981 to 0.7402 1.00155 0.7393 to 0.7869 0.99855 0.7403 to 0.7879 1,00145 0.7870 to 0.8411 0.99865 0.7880 to 0.8421 1.00135 0.8412 to 0.9034 0.99875 0.8422 to 0.9044 1.00125 0.9035 to 0.9756 0.99885 0.9045 to 0.8766 1.00115 0.9757 to 1.0604 0.99895 0.9767 to 1.0614 1.00105 1.0605 to 1.1000 0.99905 1.0615 to 1.1000 1.00095 This table must be entered with density at 15°C. §3 SCRIBD Trusted by over 1 million members ry Scribd FREE for 30 days to access over 125 hat is Scribd? SS afl ) - ome Books Audiobooks Documents SCRIBD Search cy G A Saved EXAMPLES 1. It is required to fill cans with exactly 2 L of an oil measured at 15°C, using a weight-filling machine. If the density of the oil is 0.8943 kg/L at 15°C, what weight should be set on the scale of the machine? Enter the table with 0.894 kg/L density and note that the weight of BNI sy sania pare nroaes poumegess ot arene smaaeeneye ves 0.8929 kg. Likewise, enter the table with 0.895 kg/L density and note that the weight of I L is 0.8939 ke. This represents an increase in weight of 0.0010 kg for an increase of 0.0010 kg/L in density. Therefore, by simple proportion, an in- crease in density from 0.894 to 0.8943 kg/L increases the weight by 0.3 x 0.0010 or 0.0003 kg Hence, | L of oil having a density of 0.8943 kg/L at 15°C weighs 0.8929 + 0.0003 or . 0.8932 kg Then, 2 L of the oil at 15°C weigh 2 x 0.8932 or 1.7864 ke The filling machine is therefore set a 1.787 kg. 2. A quantity of oil having a density of 0.9418 kg/L at 15°C has been invoiced as 1368.231 metric tons in air. What is the volume in litres at 15°C? Enter the table with 0.941 kg/L density and note that the volume occupied by I metric ton iS ........-eec eee eee eeee ees 1063.9 L Likewise, enter the table with 0.942 kg/L density and note that the volume occupied by I metric ton is... : 1062.8 L. This represents a decrease in volume of 1.1 L for an increase of 0.001 kg/L in density. Therefore, by simple proportion, an increase in density from 0.941 to 0.9418 kg/L decreases the volume by 0.8 X L.1 or 0.88 L. Hence, | metric ton of oil having a density of 0.9418 kg/L at 15°C occupies a volume of 1063.9 ~ 0.88 or ........00.0ec0 00 1063.02 L. Then, 1368.231 metric tons of this oil at 15°C occupy a volume of $3683 HSNOGIOR GE iscsi nar wivasinicissies on ateanrenits oa 1454 457 L hat is Scribd? eos alll sul) 4G 2 GD 6:03 PM A Saved ¥S aWYL 401 3o¥e (4930 $1) ALIgNa 900" ¥EL UL vOOT OS (BWMUL) NOL D1MLde 9d BaKLae ITUND ONY 3ML3H I1BN2 MBd SATADUTIX ° 2 : 2 : , o aad ele (aaae $s) aie we (9930 $1) «ie ele (aa $1 n 0) Audiobooks Doctuments Rooks = a 0 S oS A Saved (2930 $1) anteNa0 vooz*t soz"! 271 szeett 1 1 uz") ose") suum 31en2 ores wim a1un2 ua Savesorr® 0007 0S¥ (9930 $1) ALiuNaa 1 000° 0RL Sain 31409 9S avi 40.2 30ve Saves «9930 $1) 441830 Sain 21609 Snvsoo7y (3930 $1) ALISN3G ft mo] 2 qua 1?) n ds os) © <= ) Books Audiobooks Documents tome A saved (9930 $1) ALteNaa QnnoL wad Suan atwna eam 21¥n2 13¢ SavHvOI x ovorozs 01 ov0*0Ke c29au st) ‘AaIsn30 osetth 3nnod uae Suan 21un2 9S Fel sof 99¥e Maw 18nd 3a ‘Snv¥ouTIx «9930 $1) Aaisnag 3NNOL uae swan a1und aun ITHN ae Snee2011¥ «39ay $1) Auigwag C mo) pe} ta [S) 17) ees ~ © a= 4 Docun Audiobooks Books RA Saved DENSITY (15 DEGC? 920,000 TA 1010,000 PAGE 0 0F FAME Sb 918.8 Denatry 15 EGC) What is Scribd? $5 aa 6d E Home Books Audiobooks Docun A saved KILOGRAMS CUBIC TRS. 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