Ejercicio 4

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TAB= 630 lb

∑F = 0 = P + TAB + TAC + TAD

= Pj + 630 lb . λ AB + TAC + TAD

AB = (-45i – 90j +30k) ft

AB = √ -(45)2 +(90 ¿ ¿2+¿

AB = 105 ft

AC= (38i - 90j + 65k) ft

AC = √ (38)2-(90 ¿ ¿2+¿ ft

AC = 115 ft

AD = (20i – 90j - 60k) ft

AD = √ (20)2-(90 ¿ ¿2+¿ ft

AD = 110 ft

630lb
TAB = (-45i – 90j + 30k) ft = (-270i lb -540j lb + 180k lb)
105 ft
TAC
TAC= (30i - 90j + 60k) ft = (0.26i lb – 0.78j lb + 0.57k lb) TAC
115 ft
TAD
TAD = (20i - 90j – 60k) ft = (0.18i lb – 0.82j lb – 0.55k lb) TAD
110 ft

∑Fx = 0

-270 lb+ 0.26 TAC + 0.18 TAD = 0

0.26 TAC + 0.18 TAD = 270 lb


∑Fy = 0

-540 lb – 0.78 TAC – O.82 TAD + P = 0

-0.78 TAC – 0.82 TAD + P = 540 lb

∑Fz = 0

180 lb + 0.57 TAC – 0.55 TAD = 0

0.57 TAC – 0.55 TAD = 180 lb

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