192.168.10.
1 /24
11111111 11111111 11111111 00000000
255 255 255 0
(angka 1) x = (angka 0) y = 8
128 64 32 16 8
0 0 0 0 0
0 0 0 0 0
Tentukan :
a. Subnet : 2x 1
b. Host : 2y-2 254
c. Block Subnet : 256 - end 256
d. Table Subnetting :
IP Network 192.168.10.0 192.168.10.256
IP Awal 192.168.10.1
IP Akhir 192.168.10.254
IP Broadcast 192.168.10.255
1 gang
255.255.255.0
4 2 1
0 0 0
0 0 0
0
Banyaknya Gang
Banyaknya PC
( 0 , 256 )
192.168.75.40 /25
11111111 11111111 11111111 10000000
255 255 255 128
(angka 1) x = 1 (angka 0) y = 7
128 64 32 16 8
1 0 0 0 0
128 0 0 0 0
Tentukan :
a. Subnet : 2x 2
b. Host : 2y-2 126
c. Block Subnet : 256 - end 128
d. Table Subnetting :
IP Network 192.168.75.0 192.168.75.128 192.168.75.256
IP Awal 192.168.75.1 192.168.75.129
IP Akhir 192.168.75.126 192.168.75.254
IP Broadcast 192.168.75.127 192.168.75.255
1 gang 2 gang
255.255.255.128
4 2 1
0 0 0
0 0 0
128
Banyaknya Gang
Banyaknya PC
( 0 , 128 , 256 )
192,168,100,100 /26
11111111 11111111 11111111 11000000
255 255 255 192
(angka 1) x = 2 (angka 0) y = 6
128 64 32 16 8
1 1 0 0 0
128 64 0 0 0
Tentukan :
a. Subnet : 2x 4
b. Host : 2y-2 62
c. Block Subnet : 256 - end 64
d. Table Subnetting :
IP Network 192.168.100.0 192.168.100.64 192,168,100,128 192,168,100,192
IP Awal 192.168.100.1 192.168.100.65 192,168,100,129 192,168,100,193
IP Akhir 192.168.100.62 192,168,100,126 192,168,100,190 192,168,100,254
IP Broadcast 192.168.100.63 192,168,100,127 192,168,100,191 192,168,100,255
1 gang 2 gang 3 gang 4 gang
255.255.255.192
4 2 1
0 0 0
0 0 0
192
Banyaknya Gang
Banyaknya PC
( 0 , 64, 128 , 192, 256 )
192,168,100,256
192.168.50.50 /27
11111111 11111111 11111111 11100000
255 255 255 224
(angka 1) x = 3 (angka 0) y = 5
128 64 32 16
1 1 1 0
128 64 32 0
Tentukan :
a. Subnet : 2x
b. Host : 2y-2
c. Block Subnet : 256 - end
d. Table Subnetting :
IP Network 192.168.50.0 192.168.50.32 192.168.50.96
IP Awal 192.168.50.33
IP Akhir 192.168.50.94
IP Broadcast 192.168.50.31 192.168.50.95 192.168.50.127
1 gang 2 gang 3 gang
255.255.255.224
8 4 2 1
0 0 0 0
0 0 0 0
224
8 Banyaknya Gang
30 Banyaknya PC
32 ( 0 , 32, 64, 96, 128, 160, 192, 224, 256 )
192.168.50.128 192.168.50.160
192.168.50.159 192.168.50.191
4 gang
192.168.200.200 /28
11111111 11111111 11111111 11110000
255 255 255 240
(angka 1) x = 4 (angka 0) y = 4
128 64 32 16
1 1 1 1
128 64 32 16
Tentukan :
a. Subnet : 2x
b. Host : 2y-2
c. Block Subnet : 256 - end
d. Table Subnetting :
IP Network 192.168.200.160 192.168.200.176 192.168.200.192
IP Awal 192.168.200.193
IP Akhir 192.168.200.206
IP Broadcast 192.168.200.207
gang 11 gang 12 gang 13
255.255.255.240
8 4 2 1
0 0 0 0
0 0 0 0
240
16 Banyaknya Gang
14 Banyaknya PC
16 0 16 32 48 64
1 2 3 4 5
192.168.200.208 192.168.200.224
192.168.200.223 192.168.200.239
gang 14 gang 15
80 96 112 128 144 160 176 192 208 224 240
6 7 8 9 10 11 12 13 14 15 16
192.168.10.1 /30
11111111 11111111 11111111 11111100
255 255 255 252
(angka 1) x = 5 (angka 0) y = 3
128 64 32 16
1 1 1 1
128 64 32 16
Tentukan :
a. Subnet : 2x
b. Host : 2y-2
c. Block Subnet : 256 - end
d. Table Subnetting :
IP Network 192.168.25.112 192.168.25.120 192.168.25.128
IP Awal 192.168.25.113 192.168.25.121 192.168.25.129
IP Akhir 192.168.25.118 192.168.25.126 192.168.25.134
IP Broadcast 192.168.25.119 192.168.25.127 192.168.25.135
gang 15 gang 16 gang 17
Gang Kelipatan
1 0
255.255.255.252 2 8
3 16
4 24
8 4 2 1 5 32
1 1 0 0 6 40
8 4 0 0 7 48
252 8 56
9 64
10 72
32 Banyaknya Gang 11 80
6 Banyaknya PC 12 88
4 13 96
14 104
15 112
16 120
17 128
18 136
19 144
20 152
21 160
22 168
23 176
24 184
25 192
26 200
27 208
28 216
29 224
30 232
31 240
32 248