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Jaringan Komputer: Nama: Ilham Ramdani Kelas: Ti - Ie

1) The document discusses subnetting three IP addresses: 192.168.1.55/28, 192.168.1.37/29, and 192.168.2.111/25. It provides the subnet mask, number of IP addresses, network ID, broadcast IP, starting IP, ending IP, and next network for each. 2) For the 192.168.1.55/28 network, the subnet mask is 255.255.255.240, there are 14 IP addresses, and the next networks are 16, 32, 48, etc. 3) For 192.168.1.37/29, the subnet mask is 255.255.255.248,

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132 views10 pages

Jaringan Komputer: Nama: Ilham Ramdani Kelas: Ti - Ie

1) The document discusses subnetting three IP addresses: 192.168.1.55/28, 192.168.1.37/29, and 192.168.2.111/25. It provides the subnet mask, number of IP addresses, network ID, broadcast IP, starting IP, ending IP, and next network for each. 2) For the 192.168.1.55/28 network, the subnet mask is 255.255.255.240, there are 14 IP addresses, and the next networks are 16, 32, 48, etc. 3) For 192.168.1.37/29, the subnet mask is 255.255.255.248,

Uploaded by

Beno Digo
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© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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JARINGAN KOMPUTER

NAMA : ILHAM RAMDANI


KELAS : TI - IE
IP ADDRESS 192.168.1.55/28

11111111.11111111.11111111.11110000 X=4 dan Y=4


128 64 32 16 8 4 2 1

1 1 1 1 0 0 0 0

128 + 64 + 32 + 16 = 240
 Subnet Mask = 255.255.255.240

Jumlah Subnet Mask = 2x


= 44 = 16 gang
o Host = 2y – 2
= 24 – 2 = 14 pc
o Broadcast = 256 – 240
= 16 (0, 16, 32, 48, n)

Table Subnetting
IP Network 192.168.1.0 192.168.1.16 192.168.1.32 192.168.1.48

IP Awal 192.168.1.1 192.168.1.17 192.168.1.33 192.168.1.49

IP Akhir 192.168.1.14 192.168.1.30 192.168.1.46 192.168.1.63

IP Broadcast 192.168.1.15 192.168.1.31 192.168.1.47 192.168.1.15


IP ADDRESS 192.168.1.37/29

11111111.11111111.11111111.11111000 X=5 dan Y=3

128 64 32 16 8 4 2 1
1 1 1 1 1 0 0 0
128 + 64 + 32 + 16 + 8 = 248
 Subnet Mask = 255.255.255.248

Jumlah Subnet Mask = 2x


= 25 = 32 gang
o Host = 2y – 2
= 23 – 2 = 6 pc
o Broadcast = 256 – 248
= 8 (0, 8, 16, 24, n)

Table Subnetting

IP Network 192.168.1.0 192.168.1.8 192.168.1.16 192.168.1.24


IP Awal 192.168.1.1 192.168.1.9 192.168.1.17 192.168.1.25
IP Akhir 192.168.1.6 192.168.1.14 192.168.1.22 192.168.1.30
IP Broadcast 192.168.1.7 192.168.1.15 192.168.1.23 192.168.1.31
IP ADDRESS 192.168.2.111/25

11111111.11111111.11111111.10000000 X=1 dan Y=7

128 64 32 16 8 4 2 1

1 0 0 0 0 0 0 0

128
 Subnet Mask = 255.255.255.128

Jumlah Subnet Mask = 2x


= 21 = 2 gang
o Host = 2y – 2
= 27 – 2 = 126 pc
o Broadcast = 256 – 128
= 128 (0, 128)

Table Subnetting

IP Network 192.168.2.0 192.168.2.128


IP Awal 192.168.2.1 192.168.2.129
IP Akhir 192.168.2.126 192.168.2.254
IP Broadcast 192.168.2.167 192.168.2.255
KESIMPULAN
 192.168.1.55/28
Subnet Mask = 255.255.255.240
Jumlah IP Address = 14 IP Address
Network ID = 192.168.1.0
IP Broadcast = 192.168.1.15
IP Awal = 192.168.1.1
IP Akhir = 192.168.1.14
Network Selanjutnya = (16, 32, 48, n)
 192.168.1.37/29
Subnet Mask = 255.255.255.248
Jumlah IP Address = 6 IP Address
Network ID = 192.168.1.0
IP Broadcast = 192.168.1.7
IP Awal = 192.168.1.1
IP Akhir = 192.168.1.6
Network Selanjutnya = (8, 16, 24, n)
 192.168.2.111/25
Subnet Mask = 255.255.255.128
Jumlah IP Address = 126 IP Address
Network ID = 192.168.2.0
IP Broadcast = 192.168.2.127
IP Awal = 192.168.2.1
IP Akhir = 192.168.2.126
Network Selanjutnya = 192.168.2.128

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