0% found this document useful (0 votes)
20 views6 pages

Unit 6

1) The document contains 15 multiple choice questions related to applications of partial differential equations. 2) The questions cover topics like one-dimensional wave equations, one-dimensional heat equations, two-dimensional heat equations, and their general solutions subject to given boundary and initial conditions. 3) The correct answers to each question are provided.

Uploaded by

Aditya Nanekar
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
0% found this document useful (0 votes)
20 views6 pages

Unit 6

1) The document contains 15 multiple choice questions related to applications of partial differential equations. 2) The questions cover topics like one-dimensional wave equations, one-dimensional heat equations, two-dimensional heat equations, and their general solutions subject to given boundary and initial conditions. 3) The correct answers to each question are provided.

Uploaded by

Aditya Nanekar
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 6

Unit VI: Applications of Partial Differential Equations

Multiple Choice Questions

1) The partial differential equation of one-dimensional wave is. (01)

u 2 2u
a) =c
t x2
2u
2  u
2
b) = c
t2 x2
u u
c) + =0
t x
2u 2 u
d) 2 + c x = 0
x

2y
2) The most suitable general solution of one-dimensional wave equation, = c2
t2
2y
, where y(x, t) be the deflection of string, which satisfies all boundary and
x2
initial conditions, is (01)

a) y(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct )


b) y(x, t) = C1 cos mx + C2 sin mx + C3 cos mct + C4 sin mct
2 2
c) u (x, t) = ( C1 cos mx + C2 sin mx ) e– c m t
d) u(x, y) = ( C1 cos mx + C2 sin mx )  ( C3 cosh my + C4 sinh my )

3) The partial differential equation of one-dimensional heat is (01)

u 2 2u
a) =c
t x2
2u
2  u
2
b) = c
t2 x2
u u
c) + =0
t x
2u 2 u
d) 2 + c x = 0
x
4) If u ( x , y ) = 0 as y → , x in (0,L) then the most suitable general solution of two
2u 2u
dimensional heat equation , + = 0 , where u(x, y) be the
x2 y2
the temperature of plate, which satisfies all boundary and initial conditions, is. (01)

a) u(x, y) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct )


b) u (x , y) = ( C1 emx + C2 e–mx ) ( C3 cos my + C4 sin my )
2 2
c) u (x , t) = ( C1 cos mx + C2 sin mx) e– c m t
d) u(x , y) = ( C1 cos mx + C2 sin mx ) ( C3 emy + C4 e – my )

5) The most suitable general solution of one-dimensional heat equation, (01)


u u
2
= C2 , where u(x, t) be the temperature of a rod, which satisfies all
t x2
boundary and initial conditions is.

a) u(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct )


b) u(x, y) = C1 cos mx + C2 sin mx + C3 cos mct + C4 sin mct
2 2
c) u (x, t) = ( C1 cos mx + C2 sin mx ) e– c m t
d) u(x, y) = ( C1 cos mx + C2 sin mx )  ( C3 cosh my + C4 sinh my )

2y 2y
6) The most suitable general solution of one-dimensional wave equation, =9 2 ,
t2 x
where y(x, t) be the deflection of string, which satisfies all boundary and initial
conditions, is (01)

a) y(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos 3mt + C4 sin 3mt )


b) y(x, t) = C1 cos mx + C2 sin mx + C3 cos 3mt + C4 sin 3mt
– 9 m2 t
c) y(x, t) = ( C1 cos mx + C2 sin mx ) e
d) y(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos 9mt + C4 sin 9mt )

7) If u ( x , y ) = 0 as x → , x in (0,L) then the most suitable general solution of two-


2u 2u
dimensional heat equation , + =0 ,
x2 y2
where u (x, y) be the temperature of plate, which satisfies all boundary and initial
conditions, is. (01)

a) u(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct )


b) u (x , y) = ( C1 emx + C2 e–mx ) ( C3 cos my + C4 sin my )
2 2
c) u (x , t) = ( C1 cos mx + C2 sin mx) e– c m t
d) u(x , y) = ( C1 cos mx + C2 sin mx ) ( C3 emy + C4 e – my )
2y 2
2y
8) If the most suitable general solution of one-dimensional wave Equation, =c
t2 x2
which satisfies all boundary and initial conditions, is.
y(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct ), then by using
boundary condition y(0 , t) = 0 ; t , the value of arbitrary constant C1 is ----- (01)

a) − 𝑛𝜋⁄𝐿
b) 𝑛𝜋
c) 𝑛𝜋⁄
𝐿
d) 0

9) The most suitable general solution of one-dimensional heat equation,

u 2u
= 25 2 , where u(x, t) be the temperature of a rod, which satisfies all boundary
t x
and initial conditions is. (01)

a) u(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos 5mt + C4 sin 5mt )


b) u(x, y) = C1 cos mx + C2 sin mx + C3 cos 5mt + C4 sin 5mt
2
c) u (x, t) = ( C1 cos mx + C2 sin mx ) e– 25m t
2
d) u (x, t) = ( C1 cos mx + C2 sin mx ) e– 5 m t

10) If the most suitable solution of one dimensional heat equation : (01)

u 2u
= c2 , where u(x, t) be the temperature of a rod, which satisfies all boundary and
t x2
2 2
initial conditions is. u (x , t) = ( C1 cos mx + C2 sin mx) e– c m t

Then by using boundary condition u(0, t) = 0; t , the value of arbitrary constant C1 is –

a) − 𝑛𝜋⁄𝐿
b) 𝑛𝜋
c) 𝑛𝜋⁄
𝐿
d) 0

2y 2 y
2
11) The differential equation of stretched string is , t2 = c x2 (01)

with the boundary conditions ,(i)y(0, t) = a sin pt ; t (ii) y(l, t) = a sin pt ; t .


where , y(x, t) - be the displacement of string at any time t.
The most suitable solution is
y(x, t) = (C1 cos mx + C2 sin mx) (C3 cos mct + C4 sin cmt) …(1)
By using condition ( i ), we get
a sin pt = C1 C3 cos cmt + C1 C4 sin cmt. Then the value of C3 is equal to
a) Cm
b) 0
a
c) C
1
d) None of the above

12) If the most suitable general solution of two dimensional heat equation : (01)
u
2
u2
2 + = 0 where u(x, t) be the temperature of a plate, which satisfies all
x y2
Boundary and initial conditions and as y → , solution is
u(x, y) = ( C1 cos mx + C2 sin mx ) (C3 emy + C4 e– my ) …(1)
Then by using boundary condition u (x, ) = 0; x , the value of arbitrary constant
C1 is -----

a) − 𝑛𝜋⁄𝐿
b) 𝑛𝜋
c) 𝑛𝜋⁄
𝐿
d) 0

13) If the most suitable solution of one dimensional heat equation : (01)
u u2
= c2 , where u(x, t) be the temperature of a rod, which satisfies all boundary
t x2
2 2
and initial conditions is. u (x , t) = ( C1 cos mx + C2 sin mx ) e– c m t ……… (1)
By using conditions.
(i) u (0, t) = 0 ; t (ii) u (L, t) = 0 ; t we get C1 = 0 and m = n ; n = 1, 2, 3, . . .
Then equation (1) becomes


2
( n )  c2 t
(a) u (x, t) =  bn sin (n) x  e
n=1

– ( n ) 2  c2 t
(b) u (x, t) =  bn sin (n ) x  e
n=1

– ( n ) 2  c2 t
(c) u (x, t) =  bn cos (n ) x  e
n=1

(d) u (x, t) =  bn sin (n ) x


n=1

2u 2u
14) For the equation x2 + y2 = 0 with condition (01)

(i)u = 0 when y→ ∞ ∀ 𝑥 then………


(a) C3 = 0
(b) C2 = 0
(c) C1 = 0
(d) C4 = 0
15) An infinitely long uniform metal plate is enclosed between lines y = 0 and y = L for
x > 0. The temperature is zero along the edges: y = 0, y = L and at infinity. The most
suitable general solution is (01)

a) u(x, t) = ( C1 cos mx + C2 sin mx )  ( C3 cos mct + C4 sin mct )


b) u (x , y) = ( C1 emx + C2 e–mx ) ( C3 cos my + C4 sin my)
2 2
c) u (x , t) = ( C1 cos mx + C2 sin mx) e– c m t
d) u(x , y) = ( C1 cos mx + C2 sin mx ) ( C3 emy + C4 e – my )


𝑛𝜋𝑥 𝑛𝜋𝑥
16) If u(x, t) = bn sin 𝑙
cos 𝑙 then by using condition (01)
n=1
𝑛𝜋𝑥
u(x, 0) = a sin , u(x, t) = ………………….
𝑙

𝜋𝑥 𝜋𝑐𝑡
a) u(x, t) = a sin 𝑙 cos 𝑙
𝜋𝑥
b) u(x, t) = sin 𝑙
𝜋𝑐𝑡
c) u(x, t) = a sin cos 𝑙
1 𝜋𝑐𝑡
d) u(x, t) = a sin 𝑙
cos 𝑙

2u 2u
17) 2 + = 0 two dimensional heat flow is also known as (01)
x y2

a) Fourier equation
b) Laplace equation
c)Wave equation
d) None of these

18) An infinitely long uniform metal plate is enclosed between lines y = 0 and y= l for x > 0. The
temperature is 0 along the edges y= 0, y= l and at infinity. If the edge x= 0 is kept at a constant
temperature u0 then using the most general solution u(x, y) = (C1 𝑒 𝑚𝑥 + C2 𝑒 − 𝑚𝑥 ) (C3 cos my+ C4 sin
my) the value of C3=……. (01)

a) 0
b) 1
c) 2
d) 3

2y 2 y
2
19) The differential equation of stretched string is , t2 = c x2 (01)

with the boundary conditions , (i) y(0, t) = 0 t (ii) y(l, t) = 0 ; t .


where , y(x, t) - be the vibration of string of length l fixed t both ends
By using condition (i) we get, The most suitable solution is
y(x, t) = (C1 cos mx + C2 sin mx) (C3 cos mct + C4 sin cmt) …(1)
we get C1 = 0 then by using (ii)C4 =………………..
a) 0 b) 1 c) – 1 d) 2
u  2u
20) For t = c2 2 if (i) u is finite ∀ t, (ii) u(0,t) = 0 ∀ t, (iii) u(𝜋, 𝑡)= 0 ∀ t, (01)
x
– m2 t
The most general solution is, u(x ,t) = ( C1 cos mx + C2 sin mx) e
By using (i) & (ii) the solution becomes,
– m2 t
u(x ,t)= C2 sin mx e
by using (iii) , the value of m = …………

a) N𝜋
b) 0
c) n
d) 1

Answers:

1-b 2-a 3-a 4-d 5-c 6-a 7-b 8-d 9-c 10-d
11-b 12-d 13-b 14-a 15-b 16-a 17-b 18-a 19-a 20-c

You might also like