CE 41-C
QUIZ NO. 1
July 16, 2018
NAME: ________________________________________
SCORE: _________
SOLVE THE FOLLOWING PROBLEMS:
1. Two tangents AB and BC intersects at an angle of 24°. A point P is located 21.03 m from point B
and has a perpendicular distance of 2.79 m from line AB.
a. Calculate the radius of the simple curve connecting the two tangents and passing point P.
b. Find the length of chord P.C and P.T. (50 points)
2. A straight railroad IP intersects the curve highway route AB. Distance on the route is measured
along the arc. Using the data in the figure, compute station at the intersection x where sta.
A=P.C is 50 + 000 and PV is 180 m. (50 points)
I R = 600 m
A B
P.C
X
I = 104
v
CE 41-A
QUIZ NO. 1
July 18, 2018
NAME: ________________________________________
SCORE: _________
SOLVE THE FOLLOWING PROBLEMS:
1. A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of
180° and BC has an azimuth of 230°. The stationing of the point of curvature at A is 10 + 140.26.
if the degree of curve of the simple curve is 4°: (50 points)
a. Compute the length of the chord.
b. Compute the length of the tangent, AB.
c. Compute the stationing of a point “x” on the curve on which a line passing through the
center of the curve making an angle of 58° with the back tangent, intersects the curve at
point “x”.
2. The offset distance of the simple curve from the P.T to the tangent line passing through the P.C.
is equal to 120.20 m. the stationing of the P.C. is 2+540.26. The simple curve has an angle of
intersection of 50°. (50 points)
a. Compute the degree of curve
b. Compute the external distance
c. Compute the length of the long chord
CE 41-B
QUIZ NO. 1
July 18, 2018
NAME: ________________________________________
SCORE: _________
SOLVE THE FOLLOWING PROBLEMS:
1. From a point A on a simple curve, the perpendicular distance to the tangent at point Q is x. The
tangent passes through P.C. Point A is at station 20 + 250 and P.C is at station 20 + 150. If the
radius of the curve is 800 m, find x. (50 points)
2. A 5° curve intersects a property line CD at point D. The back tangent intersects the property line
at point C which is 105.270 m from the PC which is at station 2+040. The angle that the property
line CD makes with the back tangent is 110°50’. (50 points)
a. Determine the distance CD
b. Determine the stationing of D.
CE 41-A
QUIZ NO. 1
July 9, 2019
NAME: ________________________________________
SCORE: _________
SOLVE THE FOLLOWING PROBLEMS:
1. A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of
180° and BC has an azimuth of 230°. The stationing of the point of curvature at A is 10 + 140.26.
if the degree of curve of the simple curve is 4°: (35 points)
a. Compute the length of the chord.
b. Compute the length of the tangent, AB.
c. Compute the stationing of a point “x” on the curve on which a line passing through the
center of the curve making an angle of 58° with the back tangent, intersects the curve at
point “x”.
2. A straight railroad IP intersects the curve highway route AB. Distance on the route is measured
along the arc. Using the data in the figure, compute station at the intersection x where sta.
A=P.C is 50 + 000 and PV is 180 m. (35 points)
R = 600 m
I
Sta. 50+000
A B
P.C
X
20°
P
I = 104
180 m
v
3. The two intersecting streets are to be connected by a simple curve. The centerline of the curve
is to be connected such that point B of the building is to be 50 m from the curve shown.
Compute the radius of the curve. (30 points)
120 m
50°
C 100 m
80 m
50 m A
60 m
