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This document contains information and calculations related to equations of state and thermodynamic properties for various substances and processes. It includes: 1. Redlich-Kwong equations of state parameters for a substance at 348.16K and 15 bar. 2. Calculations using the Redlich-Kwong and other equations of state for multiple problems involving substances at various temperatures and pressures. 3. Calculations of thermodynamic properties like heat capacity and enthalpy for different substances and processes.

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Diego Esquivel Barber
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20 views14 pages

Calculos

This document contains information and calculations related to equations of state and thermodynamic properties for various substances and processes. It includes: 1. Redlich-Kwong equations of state parameters for a substance at 348.16K and 15 bar. 2. Calculations using the Redlich-Kwong and other equations of state for multiple problems involving substances at various temperatures and pressures. 3. Calculations of thermodynamic properties like heat capacity and enthalpy for different substances and processes.

Uploaded by

Diego Esquivel Barber
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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Redlich/kwong

Tc(K) 318.7 V(cm^3/mol) 1714.21889


Pc(Bar) 37.6
T(K) 348.16
P(Bar) 15

R(cm^3 * bar/mol*K) 83.14

Ec. -1.3283E-06

a 142496158
b 61.0552034

H Y O
15 17.5094714 2.50947009
V.D.W.

Tc(K) 318.7
Pc(Bar) 37.6

T(K) 348.16
P(Bar) 15

Formas basicas

a 7877349.4634
b 88.087493351

H 15
Y -17.63302366
O 2.6330236983

Ec. 4.015125E-08

problema 5

V.D.W.
mol 10
Tc(K) 282.3
Pc(Bar) 50.4

T(K) 298
P(Bar) 129.30753926

Formas basicas

a 4610999.2371
b 58.210372024
H 129.30753926
Y -592.8676851
O 461.09992371

Ec. -2.460222147

problema 7 Pitzer Virial


proceso 1 A 2

Pc 220.55
Tc 647.1

T
P

Bo
B1

FACTOR A. 0.345

w 0
R(cm^3 * bar/mol*K) 83.14

V(cm^3/mol) 1729.66768749

Z 0.89632402524

H Y O

R(cm^3 * bar/mol*K)

problema 6

mol 10
R(cm^3 * bar/mol*K) 83.14 Tc(K) 282.3
Pc(Bar) 50.4
V2(cm^3/mol) 100
T(K) 298
P(Bar) 129.307539

a 4610999.24
b 58.210372
itzer Virial R(cm^3 * bar/mo 83.14
PROCESO 3 2 isobarico

Pc 220.55
Tc 647.1

T1(K) 823.16 T1(K) 823.16


T2(K) 623.16 T2(K) 623.16
V1(cm^3/mol) 2491.35606776 V2(cm^3/mol) 1824.5167

P(bar) 27 P(bar) 27

Tr1(K) 1.27207541338 Tr2(K) 0.96300417


Pr(bar) 0.12242121968 Pr(bar) 0.12242122

Bo -0.20413879737 Bo -0.36523667
B1 0.07639998454 B1 -0.062507

Z0 0.98035421462 Z0 0.95356955
Z1 0.00735253523 Z1 -0.00794616
Z 0.98289083927 Z 0.95082812

W(barcm^3/mol) 18004.6628291
W(J/mol) 1800.46628291

Wtotal(J/mol) -288.782829

problema 9

Pc(bar) 42.72 R(cm^3 * bar/mo 83.14


Tc(K) 305.3

T(K) 323.16

V(cm^3/mol) 233.93676313

P(bar) 65

Tr(K) 1.05849983623
Pr(bar) 1.52153558052

Bo -0.3023072481
B1 0.00353499816

Z0 0.5654498768
Z1 0.00508136638
Z 0.56595801344

w 0.1
VIRIAL

Z 0.892519293041647 V(cm^3/mol) 1722.32556

B(cm^3/mol) -194
C(cm^6/mol^2) 15300

Ec. -0.184424518258311

T(K) 348.16
P(Bar) 15

R(cm^3 * bar/mol*K) 83.14

a b c d
2647574.00214365 -2966405.34583951 334131.15927 -15300

R(cm^3 * bar/mol*K) 83.14

V2(cm^3/mol) 100 -0.142926010924 LN

w(bar*cm^3/mol) 418531.026

V1(cm^3/mol) 10 -414989.9313384

W(J/mol) 41853.1026
W(J) 418531.026
proceso 2 a 3
T(K) 823.16
V2(cm^3/mol) 2491.3560678 V1(cm^3/mol)
Tc(K) 647.1
Tr(K) 1.2720754134
P1(bar) 36.639070648
p2(bar) 27
Pc(bar) 220.55

a 0.0266595961
b -0.0007276217
c 9.3949061E-05
b
Bo -0.2041387974
B1 0.0763999845

W(barcm^3/mol) -20892.491115
W(J/mol) -2089.2491115
1824.5167
Cp(co) 0.02895 0.00000411 3.54E-09 -2.22E-12
Cp(co2) 0.03611 0.00004233 -2.887E-08 7.464E-12

a b c d
Hes1 0.02895 0.000002055 1.18E-09 -5.55E-13
Hes2 0.03611 0.000021165 -9.623333E-09 1.866E-12
Hes3 0.3776002688 (KJ)
Hes4 9.89939636 (KJ)

0.0355372 0.0000196362 -8.759067E-09 1.67232E-12

0= 0.0087166046
Ejercicio 8.22
n[=]+B21:M25 a b c d
51.875 Cp(O2) 0.0291 0.00001158 -6.076E-09 1.311E-12
975.744 Cp(N2) 0.029 0.000002199 5.723E-09 -2.871E-12
105 Cp(CO2) 0.03611 0.00004233 -2.887E-08 7.464E-12
205 Cp(H2O) 0.03646 0.00000688 7.604E-09 -3.593E-12

Ejemplo 8.4-4
a b c d A(dT)
CpBl 0.1265 0.000234 8.86765
CpBv 0.07406 0.0003295 -0.000000252 7.77E-11 -2.229206
CpTl 0.1488 0.000324 14.972256
CpTv 0.09418 0.00038 -2.786E-07 8.033E-11 -5.7091916
Tb=80.1°C Tb=110.62°C
Benceno Tolueno [=}KJ/mol
∆H ̂v[=]KJ/mol 30.765 33.47 H ̂_1 5.3408
H ̂_2 6.3408
H ̂_3 37.529245777
H ̂_4 42.960451881
T2 282.488376
T1 500

- 15.1015625 (KJ/mol*K) 0.002316 0.0000001644 9.44E-11


- 22.2599583 (KJ/mol*K) 0.0332212 0.0000194718 -8.853467E-09

+ -11.41029 -12.16

El -12.16 no me queda

A(dT) B(dT)^2/2 C(dT)^3/3 D(dT)^4/4 T1 T2 ∆𝑯 ̂(KJ/mol)


-13.095 -3.517425 1.2919095 -0.2015969765625 900 450 -15.522112477
-13.05 -0.66794625 -1.216852875 0.4414835390625 900 450 -14.493315586
-16.2495 -12.8577375 6.13848375 -1.1477649375 900 450 -24.116518688
-16.407 -2.0898 -1.6168005 0.5525079609375 900 450 -19.561092539

Q=

B(dT)^2/2 C(dT)^3/3 D(dT)^4/4 T1 T2 ∆𝑯 ̂(KJ/mol) n[=]mol


0.73897317 10 80.1 9.60662317 0.259
-0.64516265 0.03266948 -0.000678227 80.1 50 -2.842377393 0.241
1.96615907 10 110.62 16.938415073 0.389
-1.84998904 0.11409906 -0.002881616 110.62 50 -7.447963192 0.111

n[=]mol H[=]KJ Q= ∆H= 17.6629967909573


0.259 1.3832672
0.389 2.4665712
0.241 9.04454823
0.111 4.76861016
-4.44E-14 - 1.208125 KJ
1.71672E-12 - 20.4791617 KJ

n*(∆𝑯 ̂)[=]KJ
-805.2095847
-14141.76572
-2532.234462
-4010.023971

-21489.23374

∆𝑯 ̂[=]KJ a b c d A(dT) B(dT)^2/2


CpBl 0.1265 0.000234 5.06 0.2808
CpTl 0.1488 0.000324 5.952 0.3888
C(dT)^3/3 D(dT)^4/4 T1 T2 ∆𝑯 ̂(KJ/mol)
10 50 5.3408
10 50 6.3408

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