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Bab 7 t4 Trial Biologi 2022

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norizan husain
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100% found this document useful (1 vote)
517 views6 pages

Bab 7 t4 Trial Biologi 2022

Uploaded by

norizan husain
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF or read online on Scribd
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“ Bahagian B [20 markah} Bahagian ini mengandungi dua soalan. Jawab satu soalan, 9. (a) Jadual 1 menunjukkan kadar pemafasan seorang pelajar semasa berehat dan semasa ‘melakukan aktiviti cergas. Table 1 shows the breathing rate of a student during resting and during vigorous activity A Kadar pernafasan (Pernafasan per minit) Breathing rate (Breath per minute) ‘Semasa rehat Semasa aktiviti cergas During resting During vigorous activity 16 30 Tadual 1/ Table T )__ Namakan proses respirasi yang berlaku sewaktu rehat dan semasa menjalankan aktiviti cergas ‘Name the process happen during resting and during vigorous activity. [2 markah/marks} )Terangkan mengapa kadar pernafasan pelajar itu berbeza semasa berchat dan semasa aktiviti cergas. Explain why the breathing rate of the student is different during resting and during vigorous activity [6 markah/marks} (b) Rajah 9.1 menunjukkan dua jenis tumbuhan di kawasan sawah padi bet Diagram 9.1 shows two plants in waterlogged paddy field. Tana pan Fa Rajah 9.1 / Diagram 9.1 (©2022 Hak Cita Jabatan Pendikan Pulau Pinang suuT Bcunseaance eo pt eg ein i oe i ‘remammeore Pat place eeepc a eae Stent, SULIT 8. Rajah 8.1 menunjukkan seorang individu yang menjalankan fermentasi X Diagram 8.1 shows an individual that carry out fermentation X. Rajah 8.1/ Diagram 8.1 (a) ()__ Terangkan kepentingan proses fermentasi X. Explain the importance of fermentation X process. (2 markah / 2 marks] 18 Beersame SULIT (ii) Nyatakan perbezaan antara proses fermentasi X dan respirasi aerob berdasarkan aspek berikut State the difference between fermentation X and aerobic respiration based on the following aspects: Aspek Fermentasi X Respirasi Aerob Aspect Fermentation X | ‘“¢r0bie respiration Penguraian glukosa Breakdown of glucose ‘Hasil tindak balas| penguraian glukosa The product of the breakdown of glucose ‘Tempat berlaku Places occur [3 markah / 3 marks] (iii) Penghasitan yogurt menggunakan kaedah fermentasi X ‘Terangkan mengapa yogurt menjadi rosak sekiranya tidak disimpan di dalam peti sejuk. Yogurt production uses the fermentation X method. Explain why yogurt spoils if itis not kept in the refrigerator. [2 markah / 2 marks] 19 Beanseannce SULIT 3 4551/2 For feaniner’ | 3, Rajah 3.1 menunjukkan dua persamaan penguraian glukosa di dalam sel badan manusia. Diagram 3.1 shows two equation of glucose breakdown in the cells of the human body. Glukosa , Oksigen X + Y = 2898KF tenaga Glucose ~ Oxygen * 3898 kJ energy Proses S / Process $ 150 KI tenaga 150 kJ energy Proses T / Process T Rajah 3.1 / Diagram 3.1 (a) Berdasarkan persamaan dalam Rajah 3.1, namakan: Based on Diagram 3.1, name: 34a) Proses S / Process S: a Proses T / Process T: [2 markah / marks] (b) Apakah yang berlaku sekiranya Z terkumpul di dalam sel otot manusia?” - What would happen when Z accumulates in human muscle cell? ) U1 markah / mark} (©) Mengapakah penguraian glukosa melalui proses T mengh berbanding proses $? an kurang tenaga Why does the broken down of glucose through the process T produced less energy than 36) process S? [1 markah / mark] 4551/2 [Lihat helaian sebelah SULIT SULIT 7 (@) Rajah 3.2 menunjukkan sejenis tumbuhan di sawah padi, Diagram 3.2 shows a type of plant in paddy field. 4551/2 Rajah 3.2 / Diagram 3.2 Terangkan mengapa tumbuhan itu dapat beradaptasi dalam persekitarannya? Explain why the plant can adapt in its surrounding? 4551/2 [3 markah / marks] [Lihat helaian sebelah SULIT For Examiner's Use 3@) ‘Total

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