ELE 225
Electric Circuits and Devices
Department of Electrical Engineering
College of Engineering
American University of Sharjah
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ELE 225
Electric Circuits and Devices
Chap 3.
Capacitance and Inductance
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Learning Objectives
Perform current and voltage calculations for
capacitors and inductors.
Combine capacitors or inductors in series and
parallel.
Calculate stored energies in capacitors and
inductors.
Capacitance and Inductance | Learning Objectives 3
Energy Storage Devices
Resistors convert electrical energy into heat.
Capacitors and inductors are energy-storage
elements.
Store energy and later return it to the circuit.
They don’t generate energy Passive elements.
Capacitance: energy stored in electric fields.
Inductance: energy stored in magnetic fields.
Capacitance and Inductance | Energy Storage Devices 4
Capacitors
Capacitance
A typical capacitor is made of two sheets of conductors
separated by a layer of insulating material.
Capacitance value dependent on dimensions and material.
The insulating material is called dielectric.
This could be air, polyester, …
Unit of capacitance is Farad (F).
Typical values for capacitors are in μF.
Capacitor circuit symbol and passive sign convention:
i (t ) C
+
Capacitance and Inductance | Capacitance
v(t ) − 6
Some Typical Capacitors
Capacitance and Inductance | Some Typical Capacitors 7
How does a capacitor work?
As current flows through a capacitor, charges of opposite signs
collect on the respective plates.
Electrical energy is stored in material between the plates.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | How does a capacitor work? 8
Parallel-Plate Capacitor
An example of a simple capacitor is a parallel-plate capacitor.
It consists of two conductive plates separated by a dielectric
layer.
Dielectric constant of material
ε = ε 0ε r εA Surface area of plates (W × L)
Permittivity of Air
C=
ε 0 = 8.854 ×10 F/m −12 d Separation between plates
ε r relative dielectric constant
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Parallel-Plate Capacitor 9
Capacitor: Voltage and Current Relationships
The capacitance C of a device is defined as charge Q per voltage
V.
One Farad (F) is the capacitance of a device that can store one
Coulomb of charge per one Volt.
Thus:
Recall, current definition:
Further:
So, if voltage is constant i = 0.
A capacitor in steady state acts an open circuit.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Voltage and Current Relationships 10
Capacitor as Energy Storage Device
Remember to calculate the instantaneous power of a device
Recall capacitor voltage-current-charge relationships
Next to calculate the energy stored in the capacitor
Assuming t0 = 0 and w(0) = 0,
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Energy Stored 11
Example 1
The voltage through a 1 μF is shown in figure below. Plot q(t)
and i(t).
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Example 1 12
Example 2
The current through a 0.1 μF is given by i(t) = 0.5 sin (104 t).
Plot i(t), q(t), and v(t). Assume 𝑞𝑞 𝑡𝑡 = 0 = 0.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Example 2 13
Example 2
The current through a 0.1 μF is given by i(t) = 0.5 sin (104 t).
Plot i(t), q(t), and v(t). Assume 𝑞𝑞 𝑡𝑡 = 0 = 0.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Example 2 14
Example 3
The voltage through a 10 μF is shown in figure below. Find and
plot the current, power delivered, and energy stored for time
between 0 and 5 s.
10 𝜇𝜇𝜇𝜇
1000t 0 < t < 1 10 ×10 −3 A 0 < t < 1
dv(t )
v(t ) = 1000 1 < t < 3
500(5 − t ) 3 < t < 5
i(t ) = C = 0A 1 < t < 3
dt − 5 ×10 −3 A 3 < 3 < 5
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Example 3 (cont’d)
1000t 0 < t < 1
v(t ) = 1000 1 < t < 3
500(5 − t ) 3 < t < 5
10 ×10 −3 A 0 < t < 1
dv(t )
i(t ) = C = 0A 1 < t < 3
dt − 5 ×10 −3 A 3 < 3 < 5
p (t ) = v(t )i (t )
1
w(t ) = Cv 2 (t )
2
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Capacitances in Parallel and Series
Parallel Capacitors Series Capacitors
To get a high voltage than the source, charge capacitors in
parallel then connect them in series.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Capacitors in Parallel and Series 17
Example 4
Find Ceq
Source: Irwin’s Book Supplementary Material, 10th edition. Example 6.12, p. 267.
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Example 4
Find Ceq 6µ F
3µ F
3
C eq = µ F
2
C eq → 4µ F
12 µ F Source: Irwin’s Book Supplementary Material, 10th edition. Example 6.12, p. 267.
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Example 5
Find Ceq
All capacitors are 4 µF
Source: Irwin’s Book Supplementary Material, 10th edition.
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Example 5
Find Ceq
All capacitors are 4 µF
8µ F
8µ F
4µ F
8
+8=
32
C eq
32
µF 8µ F
3 3 12
8µ F
Source: Irwin’s Book Supplementary Material, 10th edition.
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Inductors
Inductance
A typical inductor is made of wire wound around a core.
Inductance value dependent on dimensions and core material.
The core is usually a magnetic material
This could be steel, ferrite, …
Unit of inductance is Henry (H).
Typical values for inductors are in mH.
Inductor circuit symbol and passive sign convention:
+ v(t ) −
i (t ) L
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Inductance 23
Some Typical Inductors
Capacitance and Inductance | Some Typical Inductors 24
How does an inductance work?
As voltage across the inductor changes, magnetic flux is
induced and magnetic energy is concentrated inside the core.
Direction of magnetic field determined using right-hand rule.
Typical inductor forms:
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | How does an inductor work? 25
Simple Inductor
An example of a simple inductor, is a wire wound around a
cylindrical core.
µA
Cross-sectional area of core
A
L= N 2 Number of turns
l Core length N l
Permeability of the core
µ = µ0 µr
Permeability of air
µ 0 = 4π ×10 −7 H/m
µ r relative permeability of the core
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Simple Inductor 26
Inductor: Voltage and Current Relationships
The inductance L of a device is defined as total magnetic flux φ
per current I.
Voltage across an inductor is equal to rate of change of
magnetic flux.
One Henry (H) is the inductance of a device that can store one
Weber of magnetic flux per one ampère of current.
Thus:
Further
So, if current is constant v = 0.
A inductor in steady state acts a short circuit.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Voltage and Current Relationships 27
Inductor as Energy Storage Device
To calculate the instantaneous power of a device
Recall inductor voltage-current relationship
Next to calculate the energy stored in the inductor
Assuming t0 = 0 and w(0) = 0,
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Energy Storage 28
Example 6
The current i(t) is applied to a 5 H inductance. Find and plot the
voltage, power delivered and energy stored for time between 0 and 5 s.
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Capacitance and Inductance | Example 4 Source: Hambley’s Book Supplementary Material
Example 6
The current i(t) is applied to a 5 H inductance. Find and plot the
voltage, power delivered and energy stored for time between 0 and 5 s.
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Capacitance and Inductance | Example 4 Source: Hambley’s Book Supplementary Material
Example 7
Consider the circuit shown in the figure. In this circuit, we have a switch
that closes at t = 0, connecting a 10 V source to a 2-H inductance. Find
the current as a function of time.
t
1
i (t ) = ∫ v(t )dt + i (t0 )
L to
t
1
= ∫ 10dt = 5t t > 0
2 to
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Capacitance and Inductance | Example 5 Source: Hambley’s Book Supplementary Material
Inductors in Series and Parallel
Series Inductors
Parallel Inductors
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Inductors in Series and Parallel 32
Example 8
Find the equivalent inductance for each of the circuits shown
in the figure.
Source: Hambley’s Book Supplementary Material
Capacitance and Inductance | Example 6 33
Example 9
Find the equivalent inductance for each of the circuits shown
in the figure.
ALL INDUCTORS ARE 4mH
Source: Irwin’s Book Supplementary Material, 10th edition.
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LEARNING EXTENSION
ALL INDUCTORS ARE 4mH
CONNECT COMPONENTS BETWEEN NODES
a 4mH
WHEN IN
DOUBT… 4mH
REDRAW!
Leq d c
2mH
2mH
2mH
IDENTIFY ALL NODES
PLACE NODES IN CHOSEN LOCATIONS
b
Leq = (6mH || 4mH ) + 2mH = 4.4mH
Source: Irwin’s Book Supplementary Material, 10th edition.
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Example 8
Find the equivalent inductance for each of the circuits shown
in the figure.
ALL INDUCTORS ARE 6mH
Source: Irwin’s Book Supplementary Material, 10th edition. E6.14, p. 269.
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LEARNING EXTENSION
ALL INDUCTORS ARE 6mH a
2mH
6 || 6 || 6
Leq b
6mH
6mH
6mH c
48 24
Leq = 6 + [(6 + 2) || 6] = 6 + = 6 mH
14 7
NODES CAN HAVE COMPLICATED SHAPES. 66
Leq = mH
KEEP IN MIND DIFFERENCE BETWEEN 7
PHYSICAL LAYOUT AND ELECTRICAL
CONNECTIONS
Source: Irwin’s Book Supplementary Material, 10th edition. E6.14, p. 269.
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Summary
Energy Storage Devices
Resistor Capacitor Inductor
i (t ) i (t ) C + v(t ) −
+ v(t ) − + v(t ) − i (t ) L
Unit: Ohm (Ω) Farad (F) Henry (H)
At Steady State: Normal Open-circuit Short-circuit
Capacitance and Inductance | Summary 38
Example 9
FIND THE TOTAL ENERGY STORED IN THE CIRCUIT
Source: Irwin’s Book Supplementary Material, 10th edition. Example 6.5, p. 255.
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LEARNING EXAMPLE FIND THE TOTAL ENERGY STORED IN THE CIRCUIT
In steady state inductors act as
short circuits and capacitors act
as open circuits
1 1 2
WC = CVC W L = LI L
2
2 2
81
⇒ VA − [V ]
5
I L1 + 3 A = I L 2 ⇒ I L1 = −1.2 A V = 6 V = 10.8V
C2
6+ 3 A
VC 1 = 9 − 6 I L1 ⇒ VC 1 = 16.2V VA
I L2 = = 1.8 A
9
Source: Irwin’s Book Supplementary Material, 10th edition. Example 6.5, p. 255.
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ELE 225
Electric Circuits and Devices
End of Lecture 6. Capacitance and Inductance
Some materials/figures in this presentation are adapted/taken from (with permission):
Basic Engineering Circuit Analysis, 10th Edition. By Irwan, J.D, & Nelms, R.M.,
Electrical Engineering, Principles and Applications, 6th Edition. By Hambley, A.R.,
Lecture notes from Dr. Mohamed Hassan, Dr. Amer Zakaria, Dr. Ming, Dr. Mostafa Shaaban
and Other online resources.
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