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Ejercicio 2 Control 4

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0% found this document useful (0 votes)
31 views7 pages

Ejercicio 2 Control 4

Uploaded by

oscarosisc98
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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File:Ejemplo 1 SRCV.

EES 22/12/2022 20:30:57 Page 1


er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

"ESTADO 1"
x[1]=1
T[1]=-10
h[1]=Enthalpy(R12,x=x[1],T=T[1])
s[1]=Entropy(R12,T=T[1],x=x[1])
P[1]=Pressure(R12,T=T[1],x=x[1])
"ESTADO 2"
s[2]=s[1]
P[2]=P[3]
h[2]=Enthalpy(R12,s=s[2],P=P[2])
T[2]=Temperature(R12,P=P[2],s=s[2])
"ESTADO 3"
x[3]=0
T[3]=50
h[3]=Enthalpy(R12,x=x[3],T=T[3])
s[3]=Entropy(R12,T=T[3],x=x[3])
P[3]=Pressure(R12,T=T[3],x=x[3])
"ESTADO 4"
h[3]=h[4]
P[4]=P[1]
s[4]=Entropy(R12,h=h[4],P=P[4])
T[4]=Temperature(R12,P=P[4],h=h[4])
x[4]=Quality(R12,P=P[4],h=h[4])

Q_dot_B=35.2[kW] "POTENCIA DE REFRIGERACION EN EL EVAPORADOR"


"HALLANDO FLUJO MASICO DEL REFRIGERANTE"
m_dot_r*(h[1]-h[4])=Q_dot_B
"HALLANDO EL COEFICIENTE DE PERFORMANCE COP"
COP=(h[1]-h[4])/(h[2]-h[1])
"HALLANDO LA POTENCIA DEL COMPRESOR"
W_dot_c=m_dot_r*(h[2]-h[1])
"HALLANDO EL CALOR RETIRADO EN EL CONDENSADOR"
Q_dot_A=m_dot_r*(h[2]-h[3])

SOLUTION
Unit Settings: SI C kPa kJ mass deg
COP = 3.215 mr = 0.3582 [kg/s] QA = 46.15 [kW]
QB = 35.2 [kW] Wc = 10.95 [kW]

No unit problems were detected.

Arrays Table: Main


hi Ti xi si Pi
[kJ/kg] [C] [kJ/kg-C] [kPa]

1 183.2 -10 1 0.7019 218.9


2 213.7 58.87 0.7019 1218
3 84.92 50 0 0.3036 1218
4 84.92 -10 0.3714 0.3285 218.9
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:57 Page 2
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

4 R12
5x10

K
g-
/k
4

kJ
10

0 .7

0.8

0.9

1
1.
1
P [kPa]

58.87°C
3 50°C
10

0°C
-10°C

2
10
0.2 0.4 0.6 0.8
1
5x10
0 50 100 150 200 250 300 350 400 450 500
h [kJ/kg]
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:58 Page 3
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

3 R12
6x10

58.87°C

3 50°C
10
P [kPa]

0°C

-10°C

2
10
75 100 125 150 175 200 225
h [kJ/kg]
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:58 Page 4
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

R12
250

200

3
06
0.0

21

/kg
38
0.0

m3
71
0.0

3
150

0.0
0.1

4
0.2
T [°C]

100

50 1218 kPa

500 kPa
0
218.9 kPa

0.2 0.4 64.66 kPa0.6 0.8


-50
0.0 0.2 0.4 0.6 0.8 1.0 1.2
s [kJ/kg-K]
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:58 Page 5
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

R12
75

50
1218 kPa
T [°C]

25

500 kPa

218.9 kPa

-25
0.3 0.4 0.5 0.6 0.7 0.8
s [kJ/kg-K]
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:58 Page 6
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

R12
300
1218
1000 kPa
kPa
500 kPa
218.9 kPa
250

200
h [kJ/kg]

150
0.9
0.8
100
0.6

50 0.4

0
0.20 0.30 0.40 0.50 0.60 0.70 0.80 0.90 1.00 1.10
s [kJ/kg-K]
File:Ejemplo 1 SRCV.EES 22/12/2022 20:30:58 Page 7
er. 9.944: #4402: EASY ENGINEERING, https://www.youtube.com/channel/UCjC8ulmve2QNRJXhDpk-L2A+ CN xJID_JLN yNINGGBDE CJH@NYX _NJF

R12

200

175
h [kJ/kg]

150

0.9
125
0.8

100

75 0.6

0.30 0.40 0.50 0.60 0.70


s [kJ/kg-K]

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