Bio Molecules
Bio Molecules
BIOMOLECULES
183. Which functional group participates in disulphide bond      186. The function of enzymes in the living system is to
     formation in proteins?                                           (a) transport oxygen
      (a) Thioester               (b) Thioether                       (b) provide energy
                                                                      (c) provide immunity
      (c) Thiol                   (d) Thiolactone
                                                                      (d) catalyse biochemical reactions
184. Glycosidic linkage is actually an                           187. Vitamin C must be supplied regularly in diet because
      (a) Carbonyl bond           (b) Ether bond                      (a) it is water soluble hence excreted in urine and can’t be
      (c) Ester bond              (d) Amide bond                            stored in the body
                                                                      (b) it is fat soluble hence stored in the body and cannot
            O                                                               be used on regular basis
            ||
185. For    C N H (peptide bond )                                     (c) it is required in a large amount by the body hence
                                                                            supplied regularly
      Which statement is incorrect about peptide bond?                (d) it is water soluble hence used by the body on daily
      (a) C — N bond length in proteins is longer than usual                basis and is to be supplied regularly.
          bond length of the C — N bond                          188. In both DNA and RNA, heterocylic base and phosphate
                                                                      ester linkages are at –
      (b) Spectroscopic analysis shows planar structure of the
                                                                      (a)   C5' and C1' respectively of the sugar molecule
           — C — NH — group
                 ||
                 O                                                    (b)   C1' and C5' respectively of the sugar molecule
      (c) C — N bond length in proteins is smaller than usual         (c)   C '2 and C5' respectively of the sugar molecule
          bond length of the C—N bond
      (d) None of the above                                           (d)   C5' and C '2 respectively of the sugar molecule
BIOMOLECULES                                                                                                                      491
 FACT / DEFINITION TYPE QUESTIONS                                      16. (d) It is the most abundant organic compound on earth.
                                                                       17. (d) Tollen’s reagent is reduced by glucose due to aldehydic
1.     (c) Carbohydrates, proteins and fats are biomolecules.                  group and gives grey colour as silver metal.
2.     (a) Lactose is a disaccharide.                                  18. (b) The letter ‘D’ or ‘L’ before the name of any compound
3.     (c) It is found in the milk of all animals and imparts                  indicate the relative configuration of a particular
           sweetness to milk (hence named milk sugar).                         stereoisomer.
4.     (d) The disaccharides are sugars which on hydrolysis give       19. (a)      20. (a)
           two moles of the same or different monosaccharides.         21. (d) Glucose is a monosaccharide, others are disaccharides.
           Sucrose, maltose and lactose (C12H22O11 ) are the                   Sucrose is a combination of glucose and fructose.
           common examples.                                                    Maltose is a combination of two glucose units. Lactose
5.     (c) Aldo-(keto) pentoses having 5 carbon                                (or milk sugar) is a combination of glucose and
           Aldo-(keto) hexoses having 6 carbon                                 galactose (a hexose sugar).
           is an example of Pentose Sugar, arabinose                   22. (c) Glucose is considered as a typical carbohydrate which
           (aldopentose) glucose, galactose and fructose are                   contains –CHO and –OH group.
           important examples of hexose sugar.                         23. (a) Glucose contains an aldehyde group. It is oxidised
6.     (d) The most common disaccharide, Lactose has the                       into acidic group by bromine water and gluconic acid
           molecular formula C12H22O11.                                        is formed
7.     (a)     8. (d)                                                                                                 (O)
                                                                                  CH 2 OH (CHOH) 4              CHO
9.     (d) Monosaccharides cannot be hydrolysed to simpler
           molecules.                                                             CH 2OH (CHOH ) 4 COOH
10.    (b) Sucrose is an oligosaccharide and cellulose is a
           polysaccharide.                                                        Br2     H 2O              2HBr   O ob
11.    (c) All those carbohydrates which reduce Fehling’s              24. (d) Weak reagent like NaHSO3 is unable to open the chain
           solution and Tollens’ reagent are referred to as reducing           and can’t react with glucose. This explains the inability
           sugars.                                                             of glucose to form aldehyde bisulphite compound.
12.    (a) Glucose (C 6 H12O 6 ) is the simplest molecule which        25. (c) Glucose has 5 hydroxyl groups, hence it reacts with
           is monosaccharide while others are polysaccharides                  acetic anhydride to form a penta-acetate
           which on hydrolysis give monosaccharides.                   26. (d)
           Option (a) is correct.                                      27. (d) Red P + HI is reducing agent.
13.    (d) Glucose is aldohexose. Glucose is a monosaccharide,         28. (c) Pentaacetate of glucose does not react with
           i.e. it can not be hydrolysed further to simple sugars.             hydroxylamine
           Oligosaccharides on hydrolysis give 2-10 molecules          29. (c) Open chain structure is unstable and converted to
           of monosaccharides.                                                 cyclic.
14.    (b) To explain the properties which can not be explained        30. (b)
           by open chain structure of glucose it was proposed          31. (a) Natural glucose is dextrorotatory and thus, glucose is
           that one of the –OH groups may add to the –CHO                      also known as dextrose.
           group and form a cyclic hemiacetal structure as shown
                                                                       32. (c)
           below.                                                                            1
                                                                                    H              OH
                                 O
                                                                                             2
        1
      H—C—OH                    1                  1
                                                HO —C—H                             H              OH
                              H —C
        2                       2                   2                                        3              O
      H   OH                  H       OH         H    OH                          HO               H
        3                                           3
     HO   H                  HO 3     H         HO    H
                                                                                    H
                                                                                             4
                                                                                                   OH
      H 4     OH              H 4     OH          H 4      OH                                5
                                                                                    H
      H 5                     H 5                 H 5
                                6     OH                                                   CH2OH
        6CH2OH                    CH OH
                                6   2                 6CH2OH                            -D-(+) - Glucose
       – D – (+) – Glucose                      – D – (+) – Glucose
15.    (c) Glucose contain aldehyde group. Hence it give positive                       (Fischer formula)
                       5                         5
                                                                              In cyclic structure of fructose, ketonic group has
              H —C                         H —C                               reacted with an alcoholic group, it is said to be an
                       6                         6
                     CH2OH                     CH2OH                          example of an intramolecular cyclic hemiketal.
                  – D - glucose             – D - glucose           44.   (a) Sweet taste of fruits is due to fructose.
                                                                    45.   (a)
34. (b) T h e t wo i somer i c for m s ( – a n d –) of
        D-glucopyranose differ in configuration only at             46.   (c) Honey is collected from flowers by honey bee which
        C–1; hence these are called anomers.                                  contains fructose.
                                                                    47.   (c) Fructose is the sweetest sugar.
35.   (b)
                                                                    48.   (a) We know that cellulose (C 6 H12 O 6 ) n is the chief
36.   (d)                                                                     constituent of cell walls of plants. It is the most
                       1
              H              OH                                               abundant organic substance found in nature. It is a
                       2                                                      polymer of glucose with 3500 repeat units in a chain.
              H              OH                                     49.   (b) Sucrose is a disaccharide which on hydrolysis gives
                       3              O                                       one molecule of glucose (monosaccharide) and
            HO               H
                                                                              fructose (monosaccharide).
                       4
              H              OH
                                                                                                     H
                       5                                                        C12 H 22 O11 H 2 O              C6 H12 O 6 C6 H12 O 6
              H                                                                    sucrose                          glucose         fructose
                     CH2OH                                          50.   (b) RNA has D (–) – Ribose and the DNA has 2–Deoxy
                  -D-(+) - Glucose                                            D (–) – ribose as the carbohydrate unit.
                                                                                           O                    5          O
                  (Fischer formula)                                           HOCH2               OH          HOCH2              OH
                                                                                        H     H                  4     H     H     1
37.   (b) Glucose and fructose both are reduced by Fehling’s
          solution, Tollen’s reagent and Bendict’s solution.                      H                H              H               H
                                                                                                                         3     2
          Therefore, these three reagents can not be used to                           OH OH                          OH H
          distinguish between glucose and fructose.                                     ribose                     2-deoxy ribose
38.   (b) Maltose and glucose are reducing sugars.                            From the structures it is clear that 2nd carbon in DNA
                                                                              do not have OH group.
39.   (a) Glucose contains -CHO group and fructose contains
          > C = O group,. Hence these are functional isomers.       51.   (d) Carbohydrates are stored in the body as glycogen.
40.   (d) Glucose being an aldose responds to Tollen’s test         52.   (c)
          while fructose, although a ketose, undergoes              53.   (b) CH2OHCH2CHOHCHOHCH2OH does not correspond
          rearrangement in presence of basic medium (provided                 to Cx(H2O)y.
          by Tollen’s reagent) to form glucose, which then          54.   (d) Lactose (milk sugar) is a disaccharide, it is made of
          responds to Tollen’s test.                                            -D-galactose and -D-glucose
41.   (d)                                                                                                      CH2OH
                                                                                        CH2OH              H       O H
42.   (b) Fructose has the molecular formula C6 H12 O6. It                           HO     O                  H
                                                                                        H                      OH H
          belongs to D-series and is laevorotatory compound. It                         OH H                         OH
                                                                                      H       H
          also exists in two cyclic forms which are obtained by                                                H OH
                                                                                        H OH
          the addition of –OH at C-5 to the >C=O group. The
          ring thus formed is a five membered ring and is named     55.   (b)     56. (b)
          as furanose with analogy to the compund Furan. Furan      57.   (a) Sucrose does not have free — CHO or CO group, hence
          is a five membered cyclic compound with one oxygen                  it does not undergo mutarotation.
          and four carbon atoms.                                    58.   (b)     59. (d)
BIOMOLECULES                                                                                                                                493
60.   (b) Sucrose is dextrorotatory but after hydrolysis gives         73.   (d)   In neutral solution, amino acids exists as dipolar ion (also
          dextrorotatory glucose and laevorotatory fructose.                       known as zwitter ions or inner salts) where the proton of
          Since the laevorotation of fructose (–92.4°) is more                     –COOH group is transferred to the – NH2 group to form
          than dextrorotation of glucose (+52.5°), the mixture is                  inner salt, known as dipolar ion.
          laevororatory.                                                                R                              R
61.   (c) Chemically amylose is a long unbranched chain with                         .. |                     H 2O  .. |
                                                                                   H2N–CH–COOH                    H2N–CHOO–+H+
          200-1000 -D-(+ -glucose units held by C1-C4                                       -Amino acid
          glycosidic linkage.                                                                                     R
                                                                                                                + |
62.   (b) It is a branched chain polymer of -D-glucose units in                                               H3N–CH–COO–
          which chain is formed by C1-C4 glycosidic linkage                                                       Zwitter ion
          whereas branching occurs by C1-C6 glycosidic linkage.        74. (c) With the exception of glycine all the 19 other common
63.   (b) Cellulose is a straight chain polysaccharide.                        amino acids have a uniquely different functional group
64.   (b) The carbohydrates are stored in animal body as                       on the central tetrahedral alpha carbon.
          glycogen. It is also known as animal starch because
                                                                                                              H
          its structure is similar to amylopectin and is rather more                                          |
          highly branched.                                                                                H — C — COOH
                                                                                                              |
65.   (d) Carbohydrates are essential for life in both plants and
                                                                                                              NH 2
          animals. Honey has been used for a long time as an
          instant source of energy by ‘Vaids’ in ayurvedic system                                 glycine
          of medicine. Carbohydrates are used as storage               75. (d) Zwitter ion contains both +ve and –ve charge. Proton
          molecules as starch in plants and glycogen in animals.               of –COOH group is transferred to the –NH2 group.—
          Cell wall of bacteria and plants is made up of cellulose.            NH3+ group is acidic since it can donate a proton and
          We build furniture etc., from cellulose in the form of               —COO– group is basic since it can accept a proton.
          wood and cloth ourselves with cellulose in the form of       76. (a) Amino Acids are amphoteric in nature. So for it a special
          cotton fibre. They provide raw materials for many                    term is coined called Zwitter ion.
          important industries like textiles, paper lacquers and               They have following structure in solution
          breweries.                                                                                          R
66.   (b) There are 20 amino acids in man out of which 10 amino                                         +      –
          acids are essential amino acids. These essential amino                                     H3N–C–COO
          acids are supplied to our bodies by food which we                                                   H
          take because they cannot be synthesised in the body.                                        [Zwitter Ion]
          These are (1) valine (2) leucine (3) Isoleucine (4) Phenyl   77. (d) Proline is a secondary amine
          alanine (5) Threonine (6) Methionine (7) Lysine (8)          78. (a) Proteins and peptides are linked by peptide linkages
          Tryptho phone (9) Arginine (10) Histidine.
67.   (N) All the given options are example of neutral amino                          O
                                                                                       ||
          acids.                                                                   ( C NH) .
68.   (b)   - Amino acid is the building block unit of protein
                                                                       79. (c) The bond formed between two amino acids by the
          which is formed by polymerisation of amino acid
                                                                               elimination of a water molecule is called a peptide
          through peptide linkage.
                                                                               linkage or bond. The peptide bond is simply another
                             NH C                                              name for amide bond.
                                    ||                                                C OH H — N—                           — C– N— H 2 O
                                   O                                                   |                  |                   || |
                                                                                      O                   H                   O H
                                                                              Carboxyl group Amine group of                 Peptide bond
69.   (a) Except alanine, all amino acids are essential amino acids          of one amino acid other amino acid
          which cannot be synthesised in the body and must be
                                                                               The product formed by linking amino acid molecules
          obtained through diet.
                                                                               through peptide linkages. —CO—NH—, is called a
70.   (a)
                                                                               peptide.
71.   (c) Amino acids are the compounds having one or more             80. (b)     81. (c)
          amino groups and one or more carboxyl groups in the          82. (d) Proteins are highly complex, natural compounds,
          same molecule.                                                       composed of a large number of different -amino-acids
72.   (b) Except glycine, all other naturally occurring                        joined together with peptide linkage, i.e., they are
            - amino acids are optically active, since the -carbon              naturally occuring polypeptides.
          atom is asymmetric.                                          83. (d) All these are the examples of globular proteins. These
                                                                               are soluble in water.
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494                                                                                                                  BIOMOLECULES
84.  (c) Polypeptide chains in fibrous proteins are held together    102. (b) In this structure of protein atoms are highly coiled
         by disulphide and hydrogen bonds.                                    and form a spherical form.
85. (d) Proteins are building blocks of the body but they do         103. (d)
         not provide energy for metabolism.                          104. (d) When a protein, in its native form, is subjected to a
86. (c) Insulin is an example of globular protein.                            physical change like change in temperature, or a
87. (c)      88. (b)        89. (b)                                           chemical change like change in pH, the native
90. (c) These are generally insoluble in water.                               conformation of the molecule is disrupted and proteins
91. (b) The NH of the amide can act as a hydrogen bond donor                  so formed are called denaturated proteins.
         and the carbonyl group can act as a hydrogen bond                    The denaturation may be reversible or irreversible. The
         acceptor. Statements (a), (c) and (d) are false. The                 coagulation of egg on boiling is an example of
         peptide bond has double bond character due to the                    irreversible protein denaturation.
         interaction of the nitrogen lone pair with the carbonyl              However, it has been shown now that in some cases,
         group. This prevents bond rotation and makes the bond                the process is actually reversible. The reverse process
         planar. The trans isomer is favoured over the cis isomer.            is called renaturation.
92. (a)                                                              105. (c) Tertiary structure indicates the overall structure of the
93. (a) The sequence in which the -amino acids are linked to                  protein.
         one another in a protein molecule is called its primary     106. (b)
         structure.                                                  107. (b) Serine contains a hydroxyl functional group on its side
94. (a)                                                                       chain and so the strongest possible interaction will be
95. (b) The -helix structure is formed when the chain of                      hydrogen bonding where the hydroxyl group could
           -amino acids coils as a right handed screw (called                 act as a hydrogen bond donor or hydrogen bond
           -helix) because of the formation of hydrogen bonds                 acceptor.
         between amide groups of the same peptide chain, i.e.,       108. (a) When antigens enter in to the body cells and destroy
         NH group in one unit is linked to carbonyl oxygen of                 them, then antibodies being proteins are synthesised
         the third unit by hydrogen bonding. This hydrogen                    in the body and combine with antigens and destroy
         bonding between different units is responsible for                   these antigens by forming inactive complexes.
         holding helix in a position.                                         Therefore antibodies protein destroy antigens.
96. (c) During denaturation 2° and 3° structures are destroyed       109. (b) Enzymes are highly specific for a particular reaction
         but 1° structure remains intact.                                     and also for a particular substrate.
97. (a) Primary structure refers to the order of the amino acids
         in a protein.                                               110. (b) Enzymes being biocatalyst can increase the rate of a
98. (d) The hydrophilic/ hydrophobic character of amino acid                  reaction upto 10 million times. Even very small amount
         residues is important to tertiary structure of protein               can accelerate a reaction.
         rather than to secondary structure. In secondary            111. (b) Enzymes are made up of protein with specific structure.
         structure, it is the steric size of the residues that is    112. (b) Triglycerides are lipids, hence these are hydrolysed
         important and residues are positioned to minimise                    by lipases to glycerol and fatty acids.
         interactions between each other and the peptide chain.      113. (d) Enzymes are most reactive at optimum temperature.
99. (d) Quaternary structure refers to the overall structure of               The optimum temperature for enzyme activity lies
         a multiprotein complex where as primary, secondary                   between 40°C to 60°C.
         and tertiary structure refer to the different structural    114. (b) Insulin is a biochemically active peptide harmone
         levels of a single protein.                                          secreted by pancreas.
100. (a) The arrangement of polypeptide chains formed as a           115. (a)
         result of hydrogen bonding is called secondary              116. (d) Enzymes may or may not require a coenzyme for their
         structure of proteins.                                               catalytic action.
           -helix is formed by intramolecular H-bonding.             117. (c) Deficiency of vitamin D causes rickets.
           -pleated sheet is formed by intermolecular H-bonding.     118. (d) Vitamin D is a fat soluble vitamin.
101. (b) The secondary structure of a protein refers to the
                                                                     119. (b) Beri-Beri.
         shape in which a long peptide chain can exist. There
                                                                     120. (d) Vitamin           Disease caused by deficiency
         are two different conformations of the peptide linkage
                                                                                  B6                Dermatitis
         present in protein, these are -helix and -conformation.
         The -helix always has a right handed arrangement. In                     B1                Beri-beri
           -conformation all peptide chains are streched out to                   B2                Photophobia, glossitis
         nearly maximum extension and then laid side by side                      B12               Pernicious anaemia
         and held together by intermolecular hydrogen bonds.         121. (b) Vitamin E is mainly present in vegetable oils like wheat
         The structure resembles the pleated folds of drapery                 gram oil, sunflower oil, etc.
         and therefore is known as -pleated sheet.                   122. (a) Vitamin A or retinol.
BIOMOLECULES                                                                                                                            495
123. (b)                                                                  140. (d) The correct structure of thymine is
124. (c) It is found in liver, egg, milk, meat, and fish. Minute                                  OH
         amounts are probably present in all animal cells.
                                                                                              N             CH3
         Peculiarly, unlike other vitamins, B12 is not found in
         significant amounts in green plants.
                                                                                         HO       N
125. (a) DNA consists of two polynucleotide chains, each                                      Thymine (T)
         chain forms a right handed helical spiral with ten bases
         in one turn of the spiral. The two chains coil to double         141.   (c)
         helix and run in opposite direction held together by             142.   (d) Tyrosine is an -amino acid, and not a purine
                                                                          143.   (d)
         hydrogen bonding.
                                                                          144.   (c) DNA fingerprinting is same for every cell and cannot
126. (d)     O     Deoxyribose-Adenine ... Thymine -Deoxyribose      O               be altered by any known treatment.
           OH P    Deoxyribose-Guanine ... Cytosine -Deoxyribose
                                                                   P OH
            O                                                        O     STATEMENT TYPE QUESTIONS
              P                                                    P
           OH                                                        OH
            O      Deoxyribose-Guanine ... Cytosine -Deoxyribose     O    145. (a)
           OH P    Deoxyribose-Adenine ... Thymine -Deoxyribose
                                                                   P OH   146. (c) Sucrose is non-reducing in nature. It does not contain
                                                                                   a free aldehydic or ketonic group. Maltose is a
           The hydrogen bonds are formed between the base                          reducing sugar.
           (shown by dotted lines). Because of size and                   147. (b) Naturally occurring monosaccharides are 20 only.
           geometrics of the bases, the only possible pairing in                   Sucrose is a non–reducing sugar whereas maltose is a
           DNA and between G(Guanine) and C(Cytosine)                              reducing sugar.
           through three H-bonds and between A (Adenosine)                148. (b) The six membered cyclic structure of glucose is called
           and T (Thymine) through two H-bonds.                                    pyranose structure ( or ), in analogy with pyran.
127. (a)   In DNA the complimentary base are Adenine and                           Pyran is a cyclic organic compound with one oxygen
           thymine.                                                                atom and five carbon atoms in the ring. The cyclic
           Guanine and cytosine                                                    structure of glucose is correctly represented by
           The genetic information for cell is contained in the                    Haworth structure.
           sequence of bases A, T, G and C in DNA molecule.               149. (d) Sucrose is a dextrorotatory but on hydrolysis gives
128. (b)   The DNA sequence that codes for a specific protein is                   dextrorotatory glucose and laevorotatory fructose.
           called a Gene and thus every protein in a cell has a                    Since the laevorotation of fructose (–92.4°) is more
           corrosponding gene.                                                     than dextrorotation of glucose (+52.5°), thus the
129. (c)   The base pairs of the two strands of DNA are linked                     resulting mixture is laevorotatory. Glycogen is
           together through H-bonds.                                               structurally similar to amylopectin not amylose.
130. (d)   DNA has the property of self - replication . It is therefore   150. (a) For statement (i) correct Haworth structure for –D
           a reproducing molecule. This unique property of DNA                     glucose will be.
           is at the root of all reproduction. Through its                                        6
           replication, DNA acts as the key to heredity. In the                                    CH2OH
           replication of DNA, the two strands of a double helix                                    5         O
           unwind and separate as a template for the formation of                             H    H              H
           a new complementary strand.                                                       4                  1
131. (c)   Each chromosome is made up of DNA tightly coiled                                  OH OH                OH
                                                                                                              H
           many times around proteins called histones that                                           3      2
           supports its structure.
                                                                                                   H           OH
132. (a)                                                                  151. (c) Amylose is water soluble component which constitutes
133. (a) DNA has double stranded -helical structure.                               about 15-20% of strach. Amylopectin is insoluble in
134. (b) DNA is responsible for transmission of heredity                           and constitutes about 80-85% of starch.
         character.                                                       152. (c) Glycine is optically inactive.
135. (b)                                                                  153. (a) Gln stands for glutamine. Except glycine, all other
136. (a) Energy is stored in our body in the form of A.T.P.                        naturally occurring –amino acids are optically active.
137. (d)                                                                  154. (c) When the proteins are subjected to the action of heat,
138. (a) Phosphoric acid is the third component in DNA.                            mineral acids or alkali, the water soluble form of globular
139. (a) Synthesis of polypeptide is known as translation. For                     protein changes to water insoluble fibrous protein. This
         this process three type of RNA are essential.                             is called denaturation of proteins. During denaturation
                                                                                   secondary and tertiary structures of protein destroyed
                                                                                   but primary structures remains intact.
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496                                                                                                                       BIOMOLECULES
178. (c) The hydrolysis of sucrose by boiling with mineral acid                                          183. (c)   2R S H             R S S R
                                                                                                                       Thiol            Disulphide
         or by enzyme invertase or sucrase produces a mixture
                                                                                                                    Example :
         of equal molecules of D(+) glucose and
         D(–) Fructose.
                                                                                                                    2HO 2C CHC H 2SH
                                                                                                                            |
                                                      HCl                                                                  NH2
                 C12 H 22O11             H 2O                      C 6 H12O 6          C 6 H12O 6
                      sucrose                                       D glu cos e        D Fructose                         Cystine
                 [ D]       66.5º                               [ D ] 52.5º [ D ] 92 º
                                                                  Invert sugar ,[ D ] 20º                                             HO 2CCHC H 2S SCH 2 CHC O 2 H
                                                                                                                                            |              |
                                                                                                                                           NH 2           NH2
                  CH2OH                                         H           OH                                                                       Cystine
                       O
           HO                                                  OH                 H
179. (c)          H                                                         H                            184. (b) Glycosidic linkage is actually an ether bond as the
                                              O
                  OH    H                                      H
             H                       H                 H             O            OH                              linkage forming the rings in an oligosaccharide or
                  H             OH                              CH2OH                                             polysaccharide is not just one bond, but the two bonds
                    (Lactose)                                                                                     sharing an oxygen atom e.g. sucrose
             All reducing sugar shows mutarotation.
                 HO
180.   (b)              CH2                            OH
                            O                          CH2             O
                       OH                     +                        OH
                                         OH           HO
                 OH                                                         H2C
                                OH                                 OH                 OH
                 -D-Glucopyranose                      -D-Fructofuranose
                                                      HO
                                                               CH2        OH
                                                                   O      CH2      O
                                                               OH                  HO            + H2O
                                                                          O
                                                      OH                                   CH2
                                                                     OH           OH
                                                                                           OH
                                                           Fructose
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498                                                                                                              BIOMOLECULES
185. (a) Due to resonance C — N bond in protein acquires        187. (a) Vitamin C is water soluble. Therefore, it is readily
         double bond character and is smaller than usual                 excreted in urine and cannot be stored in our body and
         C — N bond.                                                     is supplied regularly in diet.
                                         –
            O                        O                          188. (b) In DNA and RNA heterocyclic base and phosphate
            C    NH                  C       NH                          ester are at C1' and C5' respectively of the sugar
                                                                         molecule.
186. (d) The function of enzymes in the living system is to
         catalyse biochemical reactions which occur in living
                                                                             HO                                           N
         systems. e.g. invertase, pepsin, amylase.                            |       5
                                                                                                                                  N
                                                                         HO – P – O – C H 2   4    O                  N
                        Invertase                                             ||                                              N
          Sucrose                        glucose + fructose                   O
                                                                                              C
                                                                                                             C
                                                                                                   H    H
          (polymer)                           (monomer)                                 H          |    |
                                                                                                  C3––– C2        H
                      amylase
          Starch                    glucose                                                        |    |
                                                                                                  OH OH
          (polymer)                 (monomer)