Sector

Area
⑦ a) area =
tre
↓
With radians :
I r20 with
degrees = XTr 2
↓ xx2x0 S
.

360

·
perimeter = 2r + 1

-sement
area 210-sing) 30 = (x + L al = rx

S
+ = xX0 S .

=
3 L =
0 5x
.

Examples : --
.. "M 30 = 2 +

O
,

a 28 35 .
/ 30 = 2 Sx .

b) Sit [Ti x= 12
tan(o 1)
= radius : 12
.

58/ b) E
a= 1 .

tab 11 75
Ex122x0
.

area of X = 34 .
11 .

S
34 11

~remember
:

~
34 -

11-28 33 .

units.
= S 76.

:
36cm2

①
Exercisede C)
Ex(x1XSin (0 5) .

a) 19 2

e) 3 26
.
.

x 34 51863878 = .

36 -
34 .
52
f) + 9 = 111 .
69

= 1 .
48136122

⑬ -148 an
Erro : A

tr ⑧
"E
= 1S
tr 1
a) =
rx0]
v2:
30 x IXI
vet 12

&
v=
3 96
* (4) **
.

I
⑤ DOCM radius

b2 + c ah
COS (A) =- -

a = 18 65

on
.

=
i 6
2bc

F
b = 10 r

COS(A) 102-18 63"

=
.

c = 18
I
2x10x10

S
Die

COSA) = 0 7591125
- .

A = 2 402548148
.
OFD
A = 2 40 -

of full circle 3600 It

13913) b)
a) = - 0 .

area :

0 739
=

= .

RED Sector
area of :
300 IT
b)absin()
2
= ISO
xOx 2T =

S
24 pieces :

3600 = 24
= ISOT

= 150

?
612 = 150H
12252 =

1=

Est
C Lerxo

Sit
area of
segment

a m resin
↓ XrEsinco)
= 2 (t-o-Sind)

sin
-sind
2r sin() = 22-220- Esine

Sino = -O-sin(t-o

Sin (TT-O sin

:. Sin(01 = IT-O-Sing
: Otsino = #

AED .

>
- y
of
area
triangle B2q
:
B

Ex 3 6 x3 6 xsin (E)

i
az b" + c (2b)C0s[A))

us
· . .
=
area -
a = 3

A b = 35 .

=
S 611844614
.

(22 = 3 6 .
+ 3 .
62 -
(2(3 .

6x3 -

6 x0S(T) C = 3 6
.

! ⑮ 72 38
=
.

88 A =π

S
scom

x= 6 .

23582907
area of
segment ↓

Es
half : 3.

) ABC :
3 6x3 6x +
a 22 44737847
.
. .

= 7 .
959835647

-
7 96
=
.

= 22 US

↓
.

s
+ = 1 . 37167982

13 57
.

z(r2 + 8r + 8 + 64)

,
⑳ a) OBCI
r O
Apj b) r = 100

[ (r 8) "0
coded
Ex(r)20 -4
area of arc
length : or
+

arc
length 6x0 =
6
·

G
2
100 = -
4
=
3 S .

100 + 4 =
% arc
length : 14x0 6 ·

160 + 640 = 96 -(100 + 4) = 6 =

8 .
4

↓
0((br + 64) = 96 1002 + 40 - 6 = 0

0(r + 4) = 6 Let O = t

ro + 40 = 6 10t2 + 47 -
6 = 0 8 + 8 + 3 6
.

+ 8 .
7

Ex1

-28an
ro =
6 -
48 =
-
60

- 1 4
5
+ =
r = -
4

10t + 10t -
Gt -6 = 0

10t(t + 1) -
G(t + 1) = 0

Cl0t-6((t+ 1) = 0
10t = 6 Et
5 t =

F S .

T
 or us
⑮
ora

33)
a)a2 = b + c -

(2bcCOS(A)
(2 = 7 S
.
+ 102 -
(21753103x10s(0 ·

x2: 12 . 95

x = 3 .

607
(

tried this Q and didn't match with

the solution !