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What is Merchant Payment Limit?
a) Encourage loans a) 2000 b) 2002 c) 1999 d) 2006 a) Performance guarantees
BA N KIN G KN O W LEDG E / b) to remove delays in the resolution process e) None of these b) Deferred Payment guarantees
FIN A N C IA L AW A REN ESS c) promoting advertisements
d) encouraging industrialists
21. 'Acquisition' of a company
called as what?
is also c) Financial Guarantees
d) All the above 3 types
e) None of these a) merger b) take over of a company e) None of these
1. 'PSB Manthan' is relating to which of
10. Recenlty Central Government has c) amalgamation d) strategic alliance 30. A mutual fund is set up in the form of
the following?
released the much-required equity cap- e) None of these _______ .
a) Milk churning
b) Discussions about banks, and their
ital for which PSBs? 22. How many types of mergers (of compa- a) a trust
a) BOI : Rs.2,257 Cr b) BoM : Rs.650 Cr nies) are there? b) a company incorporated under the
competencies, opportunities to buy or
c) DB: Rs.243 Cr. a) horizontal mergers Indian Companies Act
swap loan assets etc. c) Sea Churning
d) IDBI Bank: Rs.2729 Cr b) vertical mergers c) extension mergers c) By an Act of parliament
d) Doubts clarification e) None of these
e) All the above d) conglomerate mergers d) partnership e) None of these
2. Who are advised to strengthen 'cluster
based lending'?
11. Banks are mandated to maintain how e) All the above 4 types 31. Apart from its sponsors, a mutual fund
much Capital Adequacy Ratio (CAR) (plus 23. Tier- I capital of a bank consists which will have which of the following?
a) insurance companies b) Banks
c) mutual funds d) NBFCs
a capital conservation buffer 2.5 % )? of the following? a) trustees
a) 9% b) 5% c) 4% a) paid-up equity capital b) Asset Management company
e) None of these
d) 3% e) 2 % b) issued and fully paid ordinary shares/ c) custodian
3. Which is called as (Pure) commodity
money economy? d) All the above e) None of these
32. What is the main function of an Asset
a) where money consists of gold or silver
or oxen b) Paper Notes
BANK PO/ CLERKS EXAM SPECIAL Management Company (AMC)?
c) Promissory Notes d) Shares a) hold the securities of various schemes
e) Debentures
12. Recently RBI only sold Rs.4,000 Crore b) manage the funds by making invest-
4. 'Credit-money economy' consists
bonds and cancelled how much worth ments in various types of securities
which of the following?
bonds? c) hold its property for the benefit of the
a) Rs.11,000 crores (i.e., Rs.3,000 crores unit holders
a) negotiable debt certificates
in bonds due in 2022, Rs.8,000 crores in d) All the above e) None of these
b) promises to pay of financial intermedi-
bonds due in 2031) 33. NAV is required to be disclosed by the
aries which are convertible only in the
b) Rs.20,000 Crores c) Rs.15,000 Crores mutual fund on which basis?
sense that they can be exchanged into
d) Rs.25,000 Crores e) None of these a) once in 5 years
other forms of debt
c) Both (a) and (b) d) Currency Notes
13. Which of the following are called as b) once in 15 years
e) None of these
paper - based instruments? c) depending on the type of scheme
a) Cheque b) Draft c) Both (a) and (b) d) for every 10 years e) None of these
5. Direct Benefit Transfer (DBT) is
Government's major reform initiative to d)Share certificates e) None of these 34. The aim of 'balanced funds' is to
re-engineer the existing delivery process- 14. In India, the payment and settlement provide _______
es, ensuring better and timely delivery of systems are regulated by which act? a) growth ( capital appreciation)
benefits using Information & a) Banking Regulation Act, 1949 common stock and perpetual non-cumu- b) regular income
Communication Technology (ICT).DBT b) Payment and Settlement Systems Act, 2007 lative preference shares and disclosed c) both'growth and regular income'
c) RBI Act,1934 d) ID Act reserves d) lumpsum income e) None of these
focuses on which of the following?
e) None of these c) authorized capital d) All the above 35. How many 'bancassurance models' are
a) better targeting of beneficiary
b) timely disbursal of benefits
15. Pre-paid payment instruments can be e) None of these there?
issued in which form? 24. How may pillars are there in the 'Basel a) corporate agency model or distribution
c) curbing of pilferage by de-duplication
a) Smart card b) Magnetic stripe card II based Framework '? alliance model
d) elimination of ghost beneficiaries etc.
c) internet accounts d) internet wallets a) 4 b) 2 c) 3 d) 1 b) Joint venture model
e) All the above
e) All the above e) None of these c) Merger between a bank and an insurer
6. What is the mandatory information
16. In the government securities market, 25. Who released 'Basel III : A global reg- d) Build or buy own insurance operation
required to make an RTGS & NEFT
which are introduced? ulatory framework for more resilient e) All the above
payment?
a) Amount to be remitted. a) zero coupon bonds banks and banking systems ( also
b) Remitting customer's account number b) floating rate bonds known as Basel III : capital regula-
c) capital index bonds tions) in December, 2010? Praturi Potayya Sarma
which is to be debited
d) All the above e) None of these a) WB b) Basel Committee on
c) Name of the beneficiary bank.;Name of Answers
the beneficiary. 17. Who brought out its 'Bankers' Fair Banking Supervision(BCBS)
d) Account number of the beneficiary; Practice' code in June 2004? c) IMF d) ADB e) OECD 1) b 8) d 15) e 22) e 29) d
Sender to receiver information, if a) IRDAI 26. What are the aims / objectives of the 2) b 9) b 16) d 23) b 30) a
any&IFSC code of the destination bank b) Indian Banks' Association (IBA) Basel III? 3) a 10) e 17) b 24) c 31) d
branch e) All the above c) PFRDA d) SEBI e) None of these a) Improve the banking sector's ability to 4) c 11) a 18) e 25) b 32) b
18. Which of the following are credit infor- absorb shocks arising from financial and 5) e 12) a 19) c 26) d 33) c
7. What is Merchant Payment Limit
mation companies? economic stress, whenever the source. 6) e 13) c 20) b 27) e 34) c
(MPL)?
a) CIBIL b) Improve risk management and gover- 7) c 14) b 21) b 28) d 35) e
a) Merchant Payment Limit is merely a
pre-authorization of payment limit where b) Experian Credit Information Company nance
the Corporate can set a limit by pre- (India) Pvt. Ltd. c) Strengthen banks' transparency
approving it for the purpose making pay- c) Equifax Credit Information Services d) All the above
ment to any Merchant (Utility bills/taxes)
in a single session.
Pvt. Ltd.
d) High Mark Credit Information 27.
e) None of these
Tier - 2 capital includes which of the
7Ø˲ "sÒ˝O–í˛$' –˛*yÊ˛Ãå˝ GÖÚ‹så˝
b) Actual payment can take place only if Company Ltd. e) All the above following? ¥˘sÓ˝ Á≥»-ÑʸÀ {Á≥–ö˛$$Q M¯_ÖVä¸ Á‹ÖÁ‹¶ "sÒ˝O–í˛$'.. GÖÚ‹-så˝Mʸ$
sufficient balance is available in the 19. What is 'Credit Score'? a) Undisclosed reserves Ì‹ßÊ˛Æ-–ö˛$-–ö˛#-ô˲$Ø˲≤ –È«-M¯Á‹Ö D Ø˛À 7Ø˲ ÚflO˝ßÊ˛-Δ>-ªÍ-
account. c) Both (a) and (b) a) It is a number statistically generated b) Revaluation reserves ßä˛ÃZ E_ô˲ Bب˛-ÃÒ˝O-ب˛ –˛*yÊ˛Ãå˝ GV>j-–í˛$Ø˲$ ∞ΔÊˇ”-Ìfl˝Ö-^˲-Ø˲$-
d) Payment to insurance companies which indicates credit worthiness of an c) General provisions/ general loan - loss Ø˲≤®. D Hyë® Ø˲$Ö_ ô˛ÀÖ-V>◊˝ GÖÚ‹så˝ Mʸ*yë Bب˛-
e) None of these individual . reserves ÃÒ˝O-ب˛-ÃZ ∞ΔÊˇ”-Ìfl˝Ö-^˲-Ø˲$Ø˲≤ —ÁŸƒÊ˝$Ö ô˛Õ-Ì‹ÖßÛ˛. AßÛ˛
b) It indicates the probability that a per- d) Hybrid(debt/equity) capital instruments
8. Who are the whole-time members In
son will be able to repay or not a debt e) All the above
—´ßÊ˛ÖV> —ßë≈-ΔÊˇ$¶À$ D Ø˛À 8Ø˲ "sÒ˝O–í˛$' –˛ªå˝-Ú‹O-så˝ÃZ
SEBI?
extended to him / her on credit. 28. 'Subordinated term debt' includes
Bب˛-ÃÒ˝O-ب˛ –ö˛*Mä¸ sÒ˝Á‹$tÀ$ Mʸ*yë {¥ÎMÓ¸tã‹ ^Û˛Á‹$-M¯-–ö˛^˲$a.
a) MadhabiPuriBuch b) G.Mahalingam ô˲”ΔÊˇÃZ TIME4EAMCET ı≥ΔÊˇ$ô¯ JMʸ –˛$$ªÒ˝OÃå˝
c) Sanjeev Kaushik d) All the above c) Both (a) & (b) d) Loan limit which of the following?
e) None of these a) conventional b) unsecured ƒÊ˝*ã≥Ø˲$ sÒ˝O–í˛$ {¥ÎΔÊˇÖ-¿Ö-^˲-Ø˲$Ö®. Bب˛-ÃÒ˝O-ب˛ –˛*yÊ˛Ãå˝
e) None of these GÖÚ‹-så˝Ø˲$ Δ>ƒÊ˝*-À-Ø˲$-Mʸ$ØÛ˛ –ÈΔÊˇ$ MϸÖßÊ˛ C_aØ˲ –˛ªå˝-
20. When Securitization and Reconstruction c) subordinated debt capital instruments
9. What is the role of Insolvency and Ú‹Oså˝ ÕÖMä¸ÃZ «h-ı‹â-ÁŸ-ب˛ ^Û˛Á‹$-M¯-–ö˛^˲$a.
of Financial Assets and Enforcement of d) All the above e) None of these
Bankruptcy Code (IBC) in the present
scenario?
Security Interest Act was, originally, 29. 'Guarantees' can be broadly classified –˛ªå˝Ú‹Oså˝: https://www.time4education.com/
enacted in India? into how manytypes? local/articlecms/page.php?id=1319
www.andhrajyothy com . ‘Ë˝ì{Mʸ–ÈΔÊˇÖ 5 fØ˲–ö˛« 2018 Á‹tyÓ˛ 11
gÍqØÈô˲√Mʸ ΔÊˇÖV>∞Mϸ ^˛ÖßÊ˛∞® H®?
2012˝ÃZ AyÏ˛WØ˲ {Á≥‘Ë˝≤À$ –Û˛VʸÖô¯ AøÊ˝≈Ì‹›Î¢yÊ˛$ AØÛ˛® M>ΔÊˇ≈{Mʸ–ö˛$ƒÊ˝$$ô˲ „M> Á‹*{ô˲Ö? 35. "gÍqØË˛Ö –ö˛$«Öô˲ gÍqØ˲
AøÊ˝≈Á‹ØÈ∞Mϸ ^˛Ö®Ø˲ D Mϸ֮ Á‹*{ô˲Ö. 1) Á‹–˛$O-Mʸ≈ôÈ Á‹*{ôË˛Ö 2) MʸÕÌ≥ EÖ^Û˛ Á‹*{ôË˛Ö Á‹–ö˛$$-¥Î-ΔÊˇjØ˲ M¯Á‹Ö' AØÛ˛
1. ‘Ë˝îØ˲≈ Á≥«MʸÀµØ˲Mʸ$ EßëÁfl˝ΔÊˇ◊˝ 1) {MϸƒÊ˝*-ô˲√Mʸ {Á≥Ü-Á‹µÖ-ßÊ˛Ø˲ Á‹*{ôË˛Ö 3) Á≥«-ΔÊˇ-Ñʸ◊˝ Á‹*{ôË˛Ö 4) EÁ≥-ƒÒ˝*-WôÈ Á‹*{ôË˛Ö øÍ–È∞≤ ›Î´®Ö-^˲-yë-∞Mϸ
1) ±sÏ˝ ÃZô˲$Mʸ$ Ô≥yÊ˛-ØÈ-∞Mϸ Á‹Ö∫Ö´ßÊ˛Ö EÖ® 2) ô˲Ñʸ◊˝ Á≥#Ø˲-‘Ë˝a-ΔÊˇ◊˝ Á‹*{ôË˛Ö 27. Ú‹Oب˛fi ¥ÎuÊˇÖ-ÃZ∞ {Á≥ßÊ˛-ΔÊˇÿØ˲ –ö˛Á‹$¢-–ö˛#-ÀØ˲$ {Á≥´ßë-Ø˲ÖV> EÁ≥-ƒÒ˝*-Vʸ-Á≥yÛ˛
2) ±sÏ˝ ÃZô˲$Mʸ$ Ô≥yÊ˛-ØÈ-∞Mϸ Á‹Ö∫Ö´ßÊ˛Ö EÖyÛ˛ AM>‘Ë˝Ö 3) Ô‹”ƒÊ˝$-Vʸ-–ö˛$Ø˲ Á‹*{ôË˛Ö –ö˛$*ÃÍ≈Ö-MʸØË˛Ö ^Û˛ƒÊ˝$-yë-∞Mϸ Gب˛-Ì‹-C-B-Δäˇ-sÏ˝ –È« —À$–ö˛?
AÁ‹À$ ÃÙ˝ßÊ˛$ 4) —ßë≈«¶ Á≥»Ñ>- Á‹*{ôË˛Ö ∞ƒÊ˝$-–ö˛*-–ö˛„ {Á≥M>ΔÊˇÖ D Mϸ֮ AÖ‘È-∞Mϸ 1) Ø˛OÜMʸ 2) ªõ®ÆMʸ
3) ±sÏ˝ ÃZô˲$Mʸ$ Ô≥yÊ˛-ØÈ-∞Mϸ Á‹Ö∫Ö´ßÊ˛Ö ÃÙ˝ßÊ˛$ 16. "Á‹*Ñʸ√ ªZ´ßÊ˛Ø˲ ô˲WYÖ_Ø˲ ªZ´ßÊ˛ØÈ –ö˛N≈Áfl˝Ö'. M>± GMʸ$P–ö˛ –ö˛*ΔÊˇ$PÀ$ C^ÈaΔÊˇ$. 3) ›ÎÖÁ‹Pñ-ÜMʸ
4) ±sÏ˝ ÃZô˲$Mʸ$ Ô≥yÊ˛-ØÈ-∞Mϸ Á‹Ö∫Ö´ßÊ˛Ö EÖyÊ˛-–ö˛^˲$a. ©∞ÃZ D Mϸ֮ AÖ‘Ë˝Ö ô˲WYÖ^˲∫yÊ˛ßÊ˛$. 1) ‘ÈÔ‹àƒÊ˝$ Á≥ßÊ˛ÆÜ 2) Ø˲“Ø˲ MʸÀµØÈ ‘Ë˝Mϸ¢ 4) –ö˛ñÜ¢-Á≥-ΔÊˇ-–˛$OØ˲
2. Mϸ֮–È∞ÃZ {Á≥ƒÒ˝*V>ô˲√Mʸ gÍqØÈ∞Mϸ EßëÁfl˝ΔÊˇ◊˝ 1) ÀÑ>≈-ô˲√Mʸ Á≥«-÷-ÀØ˲ 3) Ñʸ$◊˝ô˲ 4) ›ÎÖMÛ¸-ÜMʸ Ø˛OÁ≥#◊˝≈Ö 36. "—À$-–ö˛À –ö˛»Y-Mʸ-ΔÊˇ◊˝ AÖô˲ ÷ÀÖ ßÛ˛–Û˛ÖßÊ˛ΔäˇΔˇyÏ˛z
M>∞® 2) ô˲ΔÊˇ-VÊ¸Ü M>ÀÖ 28. Ú‹MʸÖ-yÊ˛» —ßë≈-ΔÊˇ$¶À M¯Á‹Ö MÛ¸ΔÊˇ‚Ê˝ ‘ÈÁ‹à ›ÎÌfl˝ô˲≈ Á‹Öô˲ñ-Ì≥¢-Mʸ-ΔÊˇÖV> ÃÙ˝ßÊ˛$' Ô‹∞-ƒÊ˝$Δäˇ ∏Î≈Mʸ-Œt
1) ›Îı≥Ñʸ Ì‹ßëÆÖôË˛Ö 3) ¥Îu>≈Ö‘Ë˝ ∞yÏ˛— Á≥«-ÁŸ-ô¨˛ {Á≥^˲$-«Ö^Û˛ –ö˛*Á‹-Á≥-{ÜMʸ? A∞ ∫*œ–í˛$ —ßë≈-À-Ñ>≈À
2) Ø˲*≈r-ب˛ Vʸ–ö˛$Ø˲ ∞ƒÊ˝$–ö˛$Ö 4) ô˲ΔÊˇ-VÊ¸Ü Á≥«-–ö˛*◊˝Ö 1) ƒÊ˝$$◊Ï˝M> 2) ‘ÈÁ‹à MÛ¸ΔÊˇ‚Ê˝Ö –ö˛»Y-Mʸ-ΔÊˇ-◊˝Ø˲$ —–ö˛$«ÿÖ_Ø˲ –ÈΔÊˇ$?
3) ªÍΔˇ$$Ãå˝ ∞ƒÊ˝$–ö˛$Ö 4) A«P-–˛$-yÏ˛ã‹ Á‹*{ôË˛Ö 17. D Mϸ֮-–È-∞ÃZ Á‹—$√-„ô˲ Mʸñô˲≈Ö M>∞® 3) ‘ÈÁ‹à-VÊ¸Ü 4) Á≥«-ÁŸ-ô¨˛ –ÈΔÊˇ¢ 1) ›ÎM¸så˝ 2) gÍMʸfi-ب˛
3. "{ßÊ˛–ö˛ΔÊˇ*Á≥ÖÃZ À¿Ö^Û˛ ÃZÁfl˝Ö ¥ÎßÊ˛ΔÊˇÁ‹Ö'& C® 1) Ì‹Ö‡-–ö˛-ÃZ-MʸØË˛Ö 2) {Á≥ßÊ˛-ΔÊˇÿØ˲ 29. ΔÊˇ›Î-ƒÊ˝$Ø˲ Á‹“$-Mʸ-ΔÊˇ-◊ÍÀ$ Δ>ƒÊ˝$yÊ˛Ö, Vʸ◊Ï˝Ö-^˲- 3) À*≈r-ب˛ 4) BΔˇ≤Ãå˝
JMʸ? 3) ›Î–ö˛*-±≈-Mʸ-ΔÊˇ◊˝Ö 4) ∞ƒÒ˝*-fØË˛Ö yÊ˛ÖÃZ —ßë≈-ΔÊˇ$¶-ÀMʸ$ VʸÀ {Á≥ôÛ˛≈Mʸ AyÊ˛zÖ-Mʸ$-ÀØ˲$ 37. "MʸÖÌ≥Ö^Û˛ {Á≥Ü –ö˛Á‹$¢–ö˛# ´ßÊ˛”∞∞ Eô˲µÜ¢ ^Û˛Á‹$¢Ö®'
1) Ì‹ßëÆÖôË˛Ö 2) Á‹ô˲≈Ö 18. D Mϸ֮ –È∞ÃZ JMʸsÏ˝ Á≥Δ¯Ñʸ AØ˲$-øÊ˝–ö˛Ö. MʸØ˲$-Vˆ-Ø˲-sÍ-∞Mϸ D Mϸ֮ –ö˛$*ÃÍ≈Ö-Mʸ-ØÈ∞≤ –ÈyÊ˛- AØÛ˛ øÍ–ö˛-ØÈ-øÊ˝≈-Á‹-Ø˲ÖÃZ A¿-–ö˛ñ®Æ AƒÙ˝$≈ –ö˛$$Q≈
3) ›Î´ßë-ΔÊˇ-◊Ó˝-Mʸ-ΔÊˇ◊˝Ö 4) Á≥«-Mʸ-ÀµØ˲ 1) —ßë≈«¶ {Á≥ßÊ˛-ΔÊˇÿ-Ø˲Ø˲$ Á≥«-÷-ÕÖ-^˲$r ôÈΔÊˇ$? Á‹µÔŸt-Mʸ-ΔÊˇ◊˝
4) ^˲Ö{ßÊ˛$∞ ^˲ÀØÈ∞≤ —–ö˛«Ö^Û˛ 27 Ø˲Ñʸ{ôÈÀ 2) —ßë≈«¶ ÑÛ¸{ô˲ Á≥ΔÊˇ≈-r-Ø˲Mʸ$ –˛‚Ê˝ìœr 1) ΔÊˇ*Á≥Ø˲ 2) Á‹ÖMʸ-ÀØ˲ 1) ›Î´ßë-ΔÊˇ-◊Ó˝-Mʸ-«Ö-^˲$Ø˲$
Vʸ$«Ö_ —–ö˛«Ö_Ø˲ –Û˛ßÊ˛Ö? 3) —ßë≈«¶ –ö˛$*≈h-ƒÊ˝*∞≤ ßÊ˛«ÿÖ-^˲$r 3) Á‹–ö˛$Á‹≈ ∞Δ>Æ-ΔÊˇ◊˝ 4) ›Î¶Ø˲ ∞«Æ-ÁŸtô˲ 2) Á‹ΔˇOØ˲ {Á≥ƒÒ˝*Vʸ —´ßëØË˛Ö Á‹*_Ö-^˲$Ø˲$
1) ΔÊˇ$VÛ¸”ßÊ˛Ö 2) ƒÊ˝$k-ΔÛˇ”ßÊ˛Ö 30. D Mϸ֮-–È-∞ÃZ JMʸsÏ˝ Á‹ΔˇOØ˲ Á‹–ö˛*-´ßë-ØÈ∞≤ 3) M>ΔÊˇ-◊ÍÀ$ ô˛À$-Á≥#Ø˲$ 4) {¥ÎVʸ$-MÓ¸¢-Mʸ-«Ö-^˲$Ø˲$
3) A´ßÊ˛-ΔÊˇ”◊˝ –Û˛ßÊ˛Ö 4) ›Î–ö˛$-–Û˛ßÊ˛Ö GÖÌ≥Mʸ ^Û˛ı‹ ΔÊˇMÊ¸Ö M>ßÊ˛$ 38. —ßë≈-ΔÊˇ$¶À$ ——´ßÊ˛ ΔÊˇM>À ßëΔ>À –ö˛$Ößë-ÀØ˲$
5. p —À$–ö˛Ø˲$ Mʸ_aô˲ÖV> ÃÒ˝MϸPÖ^˲yë∞≤ ô˛ÕƒÊ˝$
gÙ˝Ì‹Ø˲ ‘ÈÁ‹à–Û˛ô˲¢?
sÏ˝BΔäˇsÏ˝ & 2017 1) ô˲Á≥#µ JÁ≥#µ Á‹–ö˛*-´ßëØ˲ {Á≥‘Ë˝≤À$
2) fô˲-Á≥-«^Û˛ {Á≥‘Ë˝≤À$ 3) R͉-ÀØ˲$ Á≥N«Ö^Û˛ {Á≥‘Ë˝≤
MʸØ˲$-Vˆ-Ø˲-yë-∞Mϸ ^Û˛ı‹ {¥ÎgÒ˝Mʸ$t?
1) A´ßÊ˛≈-ƒÊ˝$Ø˲ 2) AØÛ˛”-ÁŸ◊˝
1) øÍÁ‹P-Δ>-^ÈΔÊˇ≈ 2) M¯Á≥-«≤-Mʸ㋠Á‹*PÃå˝ AÌ‹Ú‹tÖså˝ & ÌúhMʸÃå˝ Ú‹Oب˛fi –˛$£Ê˛yëÀi 4) ∫Áfl˝ì-‚Ò˝OÂ-_aMʸ {Á≥‘Ë˝≤À$ 3) Á≥«-÷-ÀØ˲ 4) Á‹ñf-ØÈ-ô˲√-Mʸô˲
3) BΔÊˇ≈-øÊ˝r$t 4) A«-›Ît-sÏ˝Ãå˝ 31. Á≥«-Á≥#^˲e ∞ΔÊˇ”-Ìfl˝Ö^Û˛ –ÈΔÊˇ$ Mˆ∞≤ {Á≥‘Ë˝≤-ÀØ˲$ 39. ΔˇÖyÊ˛$ –Û˛ΔÛˇ”ΔÊˇ$ Á≥ßë-Δ>¶-Àô¯ ô˲ƒÊ˝*ΔÊˇ$ ^Û˛Ì‹Ø˲
6. H ∞ƒÊ˝$–ö˛*∞Mϸ Iب˛Ô‹tب˛Mʸ$ {Á≥£Ê˛–ö˛$ دªÒ˝Ãå˝ AyÏ˛W –ÈsÏ˝ Á‹µÖßÊ˛-Ø˲-ÀØ˲$ Á‹”ƒÊ˝$ÖV> Mϸ֮ H ΔˇÖyÊ˛$ HMʸ-»Ü M>Ôú MʸÁ≥#µÃZœ EÁŸ~ ∞À” ´ßÊ˛Δ>√∞≤
∫Áfl˝ì–ö˛$Ü À¿Ö_Ö®? GÖMʸ”-Δˇ$$» ∏ÎΔÊˇ-–í˛$ÃZ ∞ÖÁ≥#-ôÈΔÊˇ$ ¥˘ÃÙ˝a {Á≥ƒÒ˝*VÊ¸Ö ΔÊˇMʸÖ?
1) {ßÊ˛–ö˛≈-Δ>’ ‘Ë˝Mϸ¢ Á‹–ö˛$-ô˲$-À≈ô˲ 1) {Á≥‘È≤-–ö˛„ 2) ÚŸyÊ˛*≈Ãå˝ 1) Eßë-Áfl˝-ΔÊˇ◊˝ 2) Eôȵ-ßÊ˛Ø˲3) Á≥«-–ö˛*-◊Í-ô˲√Mʸ
2) ΔˇÃÒ˝-sÏ˝-—sÏ˝ Ì‹ßëÆÖôË˛Ö 3) ∏˜sZ GÀ-MϸâMä¸ GÚúMä¸t 3) ^˛Mä¸-Õã‹t 4) H©-M>ßÊ˛$ ÁúÕ-ôÈÀ$ MʸØ˲$-Vˆ-Ø˲yÊ˛Ö 4) ∞ΔÊˇ*-Á≥◊˝
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13
What can you say about their slope? Heron's Formula ∴The slope of AB cannot defined, because
Ķæ*Æý‡ÏVýSyýlz Ð]l¯]l…Æ>k � If a, b, c are three sides of ΔABC then the the line segment AB is parallel to Y–axis.
çÜ*PÌŒæ AíÜòÜt…sŒæ, area of ΔABC = 6. Find the area of the triangle whose
{糿¶æ$™èlÓ E¯]l²™èl ´ëuý‡Ô>Ë a +b+c vertices are (0, 0), (3, 0) and (0, 2).
= s (s − a )(s − b )(s − c ) where s =
2 A. Area of triangle
Slope: 1
x1 (y2 − y3 ) + x2 (y3 − y1 ) + x3 (y1 − y2
= )
CO-ORDINATE GEOMETRY � If a straight line makes the angle θ with X- 2
axis then the slope of that straight line is 1
= 0 (0 − 2 ) + 3 (2 − 0 ) + 0 (0 − 0 )
Section Formula m = tanθ. 2
The coordinates of the point P(x, y) which � Slope of the line passing through the 1
= 6 = 3 sq.units
divides the line segment joining the points A y 2 − y1 2
points (x1, y1) and (x2, y2) is m = Ð]l*Å£ýlÐðl$sìæMŠæÞ (C….Ò$.)
(x1, y1) and B (x2, y2) internally in the ratio x2 − x1 Note: Area of the triangle whose vertices
m1: m2 are: � Slope of X-axis is '0' are(0,0), (x1,y1), (x2,y2) is:
m1 x 2 + m2 x1 m1 y2 + m2 y1 � Slope of Y-axis is not defined. ⇒ 3x+2 = 20 ⇒ x = 6 =
1
x1 y 2 − x2 y1
,
m + m m + m y +1 2
�
1 2 1 2
This is known as the section formula.
Model Problems 2 + y − 3 y + 1 + 2y − 6 9. If x–2y +k = 0 is a median of the triangle
= −2 ⇒ = −2
� If the ratio in which P divides AB is k : 1 1. Find the coordinates of the point which 2 4 whose vertices are at points A (–1, 3),
then the coordinates of the point P are divides the join of (–1,7), (4,–3) in the B (0, 4) and C (–5, 2), find the value of K.
kx2 + x1 ky2 + y1 ratio 2 : 3. ⇒ 3y–5 = –8 ⇒ 3y = –8+5 ⇒ y = –1. A. The coordinates of the centroid G of ΔABC
,
k +1 k +1 Sol: Given points (–1, 7), (4, –3) 4. The points (2, 3), (x, y), (3, –2) are (−1) + 0 + (−5) 3 + 4 + 2
, = ( −2,3)
� The coordinates of mid point P of the line given ratio 2 : 3 = m1: m2 vertices of a triangle. If the centroid of the 3 3
segment joining the points A(x1, y1) and Let P(x, y) be the required point triangle is origin, then find (x, y). Since G lies on the median x–2y + k = 0,
x +x y + y Using the section formula A. Centroid of (x1, y1), (x2, y2) and (x3, y3) = ⇒ Coordinates of G satisfy its equation
B (x2, y2) are: 1 2 , 1 2
2 2 m x + m2 x1 m1 y2 + m2 y1
P(x, y) = 1 2 , x1 + x2 + x3 y1 + y2 + y3 ∴ – 2– 2(3) + k = 0 ⇒ k = 8.
,
� The coordinates of centroid of triangle m 1 + m 2 m1 + m2 3 3 10. Determine x so that 2 is the slope of the
ABC with vertices A(x1, y1), B(x2, y2) 2(4) + 3( −1) 2( −3) + 3(7) Given that centroid of (2, 3), line through P (2, 5) and Q (x, 3)
⇒ ,
and C(x3, y3) are 2 + 3 2 +3 (x, y), (3, –2) is (0, 0) A. Given points P (2, 5) and Q (x, 3)
x 1 + x2 + x3 y1 + y2 + y3 8 − 3 −6 + 21 5 15 Slope of PQ is 2
, ⇒ , ⇒ , ⇒ (1,3 ) 2+x+3 3+y − 2
i.e. (0,0)= , y 2 − y1 3−5 −2
3 3 5 5 5 5
3 3 i.e.2 = ⇒2= ⇒2=
� The point of concurrence of medians of a 2. If A and B are (–2, –2) and (2, –4) respe- x2 − x1 x−2 x−2
5 + x y + 1 5 + x
triangle is called its centroid. ctively. Find the coordinates of P such (0,0) = , ⇒ = 0 ⇒ x= − 5 ⇒ – 2 = 2(x–2) ⇒2x = 2 ⇒ x = 1.
3 3 3
� Centroid divides each median in the ratio 3 11. The coordinates of one end point of a
that AP = AB , P lies on the segment AB.
2 : 1. 7 y +1 diameter of a circle are (4, –1) and the
= 0 ⇒ y = −1
� The points which divide a line segment 3 AP 3 3 ∴ (x, y) = (–5, –1) coordinates of the centre of the circle are
A. We have AP = AB ⇒ =
into 3 equal parts are said to be the 7 AB 7 5. If the points A (6, 1), B (8, 2), C (9, 4) and (1, –3). Find the other end point.
trisectional points. AP 3
= (∵ AB= AP+AB)
D(p, 3) are the vertices of a parallelogram, A. Let AB be a diameter of the circle having
� If P and Q be the points of trisecion of AB AP + PB 7 taken in order find the value of p. its centre at C (1,–3) such that the
line segment then AP = PQ = QB. 7AP = 3(AP+PB) ⇒ 7AP–3AP = 3PB A. We know that diagonals of parallelogram coordinates of one end A are (4, –1)
AP 3 bisect each other. Let the coordinates of other end be B (x, y)
A P Q B ⇒ 4AP = 3PB ⇒ =
PB 4 Given A (6, 1), B (8, 2), C (9, 4), D (p, 3) since C is the mid point of AB.
� If P, Q are the points of trisection of AB So P divides AB in the ratio = 3 : 4 So, the coordinates of the midpoint of AC x + 4 y −1
∴The coordinates of C are ,
line segment, then P divides AB in the A= (–2, –2); B = (2, –4) = Coordinates of the midpoint of BD. 2 2
ratio 1:2 and Q divides AB in the ratio 2:1. ∴ Coordinates of P are 6 +9 1+ 4 = 8+ p , 2 + 3 But, the coordinates of C are given to be
i.e. ,
� Area of a triangle = ½ (Base × Height) 3(2) + 4( −2) 3( −4) + 4( −2) 2 2 2 2 (1, –3)
,
� Area of ΔABC with vertices A (x1, y1), 3+ 4 3+ 4 15 5 8 + p 5 8 + p 15 x + 4 y −1 x+4
⇒ , = , ⇒ = ∴ , = (1, − 3) ⇒ =1
B (x2, y2) and C (x3, y3) is the numerical 6 − 8 −12 − 8 −2 −20 2 2 2 2 2 2 2 2 2
P( x, y) = , ⇒ , ⇒ p = 15 − 8 = 7 ∴ p = 7
value of expression 7 7 7 7 x+4
⇒ = 1⇒ x + 4 = 2 ⇒ x = − 2
1 3. If the mid point of the line segment joining 7. Find the slope of the line joining the two 2
= x1 (y2 − y3 ) + x2 (y3 − y1 ) + x3 (y1 − y2 )
2 x y +1 points A (–1.4, –3.7) and B (–2.4, 1.3) y −1
A , and B (x+1, y–3) is ⇒ = − 3 ⇒ y = −5
� Area of ΔAOB with vertices A(x1, y1), 2 2 A. Given points A (–1.4, –3.7), B (–2.4, 1.3) 2
B (x2, y2) and O (0, 0) is the numerical C (5, –2), then find x, y. slope of AB = ∴Other end point of daimeter is (−2, −5)
1 A. Midpoint of the line segment joining y 2 − y1 (1.3) − ( −3.7)
value of the expression = x1 y 2 − x2 y1 =
2 x2 − x1 − 2.4 − (− 1.4)
A (x1, y1), B (x2, y2) is x 1 + x2 , y 1 + y2
� If the vertices of triangle O(0, 0), 2 2 1.3 + 3.7
= = −5
A (a, 0) and B (0, b) then the area of x y +1 −2.4 + 1.4
Given that midpoint of A , and
1 2 2 8. Justify that the line AB line
ΔOAB = ab
2 B (x+1, y−3) is C (5, −2) segment formed by(–2,8),
� Area of quadrilateral ABCD x y +1 (–2,–2) is parallel to Y–axis.
2 + x +1 2 + y− 3
= Area of ΔABC + Area of ΔACD ∴ (5, − 2) = , What can you say about
2 2
D C their slope? Why?
A. Slope of AB =
x y 2 − y1 −2 − 8 −10
2 + x +1 x + 2x + 2 = = =
⇒ =5⇒ =5 x2 − x1 (−2 ) − (−2 ) 0
2 4
A B underfined.
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ntnews.com ntbhadradri.com 5, 2018- 07
NEET MODEL PAPER
Continue From Dec 30th (2017) 32) Nitrification is done in two steps. In
24) (A): Chloroplast, mitochondria and first step NH3 is converted into
peroxisomes are not considered as a nitrite and in second step nitrite is
part of the endomembrane system converted into nitrate by
(R): Function of chloroplast , 1) Nitrosomonas & Nitrococcus
mitochondria and peroxisomes are not respectively
coordinated with ER, golgi complex , 2) Nitrosomonas & Nitrobacter
lysosomes and vacuoles respectively
c) Neutrophils 2) Allergic reactions
1) If both A & R are true and R is the 3) Nitrococcus & Nitrobacter
correct explanation of the A respectively
d) Lymphocytes 3) Responsible for Nakrekanti Seenaiah
e) Monocytes immune response Senior Lecturer
2) If both A & R are true but R is not 4) Both 2 & 3
4) Phagocytic cells Expert in Neet
the correct explanation of the A 33) The evidence that during
5) Gas transport Hyderabad
3) If A is true , but R is false photosynthesis oxygen comes from
4) If both A & R are false water A) a-4,b-5,c-1,d-2,e-3
25) Read the following statements and 1) Photosynthetic bacteria employ H2S B )a-2,b-1,c-4,d-3,e-5
find out the incorrect statement & CO2 to form carbohydrates , water C) a-1,b-2,c-3,d-4,e-3 This is the result of
1) Palmitic acid is saturated while and sulphur D) a-2,b-1,c-4,d-3,e-4 1) Cancer of the thyroid gland
arachidonic acid is unsaturated 2) Isolated illuminated chloroplasts 2) Over secretion of pars distalis
fatty acid release oxygen if provided with 41) Match the columns I & II , and
3) Deficiency of iodine in diet
2) Monoglycerides, diglycerides and potassium ferrocyanide choose the correct combination
4) Low secretion of growth hormone
triglycerides are lipids having both 3) Isotopic 180 provided as H2 180 from the options given
46) The two cells at which pollen grains
glycerol and fatty acids appears as 1802 liberated in Column I Column II are discharged are
3) Saturated fatty acids have one or photosynthesis a) Superior p) Carries deoxygenated 1) Larger generative cell & smaller
more C=C double bonds while 4) All the above Vena Cava blood to lungs vegetative cell
unsaturated fatty acids are with-out 34) CAM plants do not show q) Carries oxygenated 2) Larger vegetative cell & smaller body
double bonds photorespiration due to b) Inferior blood from lungs cell
4) Fat and oils are differentiated on the 1) Keeping stomata closed during day time Vena Cava r) Brings deoxygenated 3) Smaller vegetative cell & larger body
basis of melting point 2) Using PEP carboxylase blood from lower cell
26) Find the incorrect matching 3) Fixing CO2 into organic acid in night c) Pulmonary parts of body to right 4) Smaller generative cell & larger
1) Essential oils- Lemon grass oil and releasing Co2 during day Artery atrium vegetative cell
2) Terpenoids-Monoterpenes , 4) Performing Calvin cycle at night t) Brings deoxygenated 47) Minerals required for the germination
diterpenes 35) How many molecules of NADH are d) Pulmonary blood from upper of pollen grains on stigma are
3) Polymeric substances- Rubber, gums, produced when four molecules of Vein parts of body into 1) Ca, B 2) Mn, Ca
nucleotides phosphoglyceraldehyde are converted right atrium 3) N, S 4) Fe, Ca
4) Pigments- Carotenoids, anthocyanins into four molecules of pyruvate ? 48) The chemical complex which controls
1) a-q,b-t,c-r,d-p 2) a-t,b-p,c-q,d-r
27) Glycosidic bond is formed between 1) 2 2) 6 3) 8 4) 4 the chemotropic movement of Pollen
3) a-t,b-r,c-p,d-q 4) a-t,b-p,c-r,d-q
1) Carbon and oxygen atoms of two 36) Interfascicular cambium and cork tube in style is
adjacent monosaccharides cambium are able to divide and 42) Match the columns 1) K+, salts, amino acids
2) Carbon and hydrogen atoms of two produce cells that once again lose the 2) Organic acids , K+
Column I Column II
adjacent monosaccharides capacity to divide but mature to 3) Ca,B inositol sugar complex
a) Uremia 1) Excess of protein level
3) Hydrogen and oxygen atoms of two perform specific function. This 4) Phenols & lignins
b) Haematuria in urine
adjacent monosaccharides phenomenon is called 49) When pollen grains of a flower fall on
c) Ketonuria 2) Presence of high
4) Two carbon atoms of two adjacent 1) Differentiation the stigma of another flower of the
d) Glycosurria ketone bodies in urine
monosaccharides 2) Dedifferentiation same plant, this condition is called
e) Proteinuria 3) Presence of blood cells
28) The key features of metaphase are 3) Redifferentiation 1) Genetically self-pollination
of urine
1) Spindle fibers attach to kinetochores 4) Heterophylly 2) Genetically self-pollination &
4) Presence of glucose in
of chromosomes 37) Vermiform appendix is part of ecologically cross pollination
urine
2) Chromosomes are moved to spindle 1) Reproductive system 3) Ecologically cross-pollination
5) Presence of excess
equator and get aligned along 2) Alimentary canal 4) Genetically cross-pollination and
urea in blood
metaphase plate 3) Vascular system ecologically self-pollination
3) Splitting of centromere 4) Nervous system A) a-2, b-1,c-3, d-4, e-5
50) When the body of he ovule , the
38) Which group of three of following B) a-3, b-5, c-2, d-1, e-4
29) Select the correct option embryo sac, and the micropyle lie at
statements ( 1-5) contains all the three c) a-5, b-3, c-4, d-2, e-1
II a) Synapsis 1) Anaphase-II right angles to the funiculus , the
statements regarding beriberi ? D) a-5, b-3, c-2, d-4, e-1
b) Synthesis of RNA ovule is called
1) A crippling disease prevalent among 1) Amphitropous 2) Anatropous
and protein 2) Zygotene the native population of Africa 43) The entire process of response to
c) Action of enzyme 3) Campylotropous 4) Hemianatropous
2) A deficiency disease caused by lack peripheral nervous stimulation , that
recombinase 3) G2 – phase 51) Umbilical cord suspends embryo in
of thiamine occurs involuntarily, i.e without
d) Centromeres do not amniotic cavity and is attached to the
3) A nutritional disorder in infants and conscious effort or thought and
separate but 4) Anaphase -I midgut region of the embryo. In
young children requires the involvement of a part of
chromatids move eutherians, this umbilical cord is
4) Occurs in those countries where the CNS is called a
towards opposite 5) Pachyte formed of the stalk of
staple diet is polished rice 1) Limbic system
poles 1) Yolk sac & amnion
5) The symptoms are pain from neuritis, 2) Sensory reception
2) Allantois & chorion
paralysis muscle wasting, progressive 3) Reflex arc 4) Reflex action
1) a-1,b-2,c-5,d-4 3) Yolk sac & chorion
oedema, mental deterioration and 44) During transmission of nerve impulse
2) a-2,b-3,c-4,d-5 3) a-2,b-1,c-3,d-4 4) Allantois & Yolk sac
finally heart failure through a nerve fiber , the potential
4) a-2,b-3,c-5,d-4 52) Find the incorrect match with
A) 2,4,5 B) 1,2,4 c) 1,3,5 D) 2,3,5 on the inner side of plasma membrane
respect to increase in the levels of
4) Both 1 &2 39) Gaseous ( O2 & CO2 ) exchange would change
following hormones :
30) Meiosis is evolutionary significant between alveoli and blood, and blood 1) First negative , then positive &
1) Oxytocin- Uterine contraction during
because it result in and tissues takes place by continue to be positive
labor
1) Genetically similar daughters A) Simple diffusion 2) First positive, then negative &
2) Prolactin- Lactation after child birth
2) Four daughter cells B) Facilitated diffusion continue to be negative
3) Progesterone- Uterine contraction
3) Eggs and sperms 4) Recombinations C) active transport 3) First positive, then negative & again
4) Luteinizing hormone- Stimulates
31) Once water is absorbed by the root D) All of the above back to positive
ovulation
hairs, it can move deeper into root 40) Match the columns I & II and choose 4) First negative , then positive & again
back to negative Key
layers by two distinct pathways the correct combination from the
45) A pregnant female delivers a baby 24) 1 25) 3 26) 3 27) 4 28) 4 29) 4 30) 4 31) 3
1) One is xylem & second in phloem options given
who suffer from stunted growth, 32) 4 33) 4 34) 3 35) 4 36) 3 37) 2 38) 1 39) 1
2) One is active & second is passive Column I Column II
3) One is apoplast & second is symplast mental retardation low intelligence 40) 4 41) 3 42) 4 43) 4 44) 4 45) 3 46) 4 47) 1
a) Eosinophils 1) Involved ininflamma
4) One is tracheid & second is vessel quotient & abnormal skin. 48) 3 49) 2 50) 4 51) 2 52) 3
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08 5, 2018- ntnews.com ntbhadradri.com
: A = {1, 2, 3, 4}, n = 3 . P(A) .
A ={Ø, {1}, {2}, {3}, {1, 2}, :
{2, 3}, {1, 3}, {1, 2, 3}} A = {1, 2}
A = 2n-1 = 23-1 = 7 ={Ø , {1}, {2},{1, 2}}
A = 2n-1 = 23-1= 7 P(A) = {Ø, {1}, {2}, {1, 2},
A = 2n-2 = 23-2 = 6 : n(A) = x [n(P(A))] = 2x
:
8. n(A) = 2 [n(P(A))] = 22 = 4
A A , .
?
- .
A, B A=B .
-1: ,
� A= {x/x follow } ,
‘ ’. B= {x/x wolf } 9441022571
� ‘ ’ . C= {f,o,w,l} [c]
. � A = {f, o, l, w} .
, , � B = {w, o, l, f} � A, B .
. � C = {f,o,w,l} � A, B A<——
� ‘’ A = B = C . ->B (A~B) .
{ } . : A = {1, 2, 3, 4}, B = {a,b,c,d}
� A, B, C -2: n(A)=4, n(B) = 4
. E = {a, e, i, o, u} � n(A)= n(B)
: . K= {x/xεR, x2 =1} F = { } � A, B .
. R= {x/xεN, x+1=2} A<——->B
. . E = {a, e, i, o, u}, F = {a, e, i, o, u} :
: : E=F . � .
A= {2, 4, 6, 8} 2. .
K= {a, e, i, o, u}
� 5.
R= {O.U } � � B A
. .
1. ? : B A .
. � A n(A) .
N ={1,2,3,4, ......} � B⊂A
. : A = {1, 2, 3, 4} n(A) =4
Z = {.......-3, -2, -1, 0, 1, 2, 3, .......} 1. K = {1, 2, 2, 3, 3, 4} n(A) =?
. W = {0, 1, 2, 3, ........} 1. A = {1, 2, 3, 4,5, 6}, B = {2, 4, 6}
. : K = {1, 2, 3, 4} = n(A) =4 B⊂A .
3. 2. R= {x/x ε mathematics} n(A) =8
: � . 2. B = {2, 4, 6}, B = {2, 4, 6}
( ) B ⊂A
Ø, { } . 1. n(Ø) =
1. / : :
� ‘,’ . 0 . 1 . Ø . 1. .
1. ?
{ , } . . {Ø} . {0} . Ø . A⊂A ( )
: 2. v= {x/x εQ, 0<x<2} n(v) =? 2. .
2. ? : n(v) = ∞
. A = { }
. Reason: 6.
. K = { . � B⊂A, B≠A B A
A= {a, e, i, o, u} - / }
N = {1, 2, 3, 4, .......} - .
. R= {x/x εN, x+2=2} 1. B = {x/x εN, x+4 = 2} n(B) = :
2. / .
� . 1 . 0 . Ø . A = {1, 2, 3, 4,5, 6}, B = {1, 3, 5}
: 1-, 2- : B⊂A, B≠A
.
: 7.
A= {a, e, i, o, u} - x+4 = 4 N = {1, 2, 3, .....} � B A A B
1.
A= {x/x } � 0+4 = 4 but 0 ∉N . A⊃B
- . n(B) = 0 .
N = {1, 2, 3, 4, .......} : . 2. C = {x/x εW, x+4 = 4} n(C) = :
N= {x/x } . A = { . 1 . 0 . Ø . 1. A = {1, 2, 3, 4}, B = {1, 2, 3}
: } {} : B⊃A, B≠A
� ε ‘’ (belongs to) . K = { } B, A .
. {0} x+4 = 4 A, B . A⊃B
� ∉ ‘’ . R= {x/x εN, x2=4} 0+4 = 4 so that 0εN 2. A = {1, 2, 3, 4}, B = {1, 2, 3, 4}
. . w = {0, 1, 2, 3 .... ....} B⊂A, B=A
: X ={1,2,3,4,5} : n(c) = 1 B, A , .
3 X . 2. 3. F = {x/x εIR, x2 = 1} n(F) = :
3εX . � . 1 . 2 . 0 . ∞ 1. A⊂B, B⊂A A=B .
3 X . . Ω µ : .
6∉X . . 2. A⊂B, B⊂C A⊂C .
- ( ) µ= {10 } F = {x/x εIR, x2 = 1} - .
1. A = {2} = { } 1εIR , 12 = 1 ; -1εIR, (-1)2 = 1 3. A n .
� F = {1, -1} i. =2n
. 3. n(F) = 2 ii. = 2n-1
: ? � A B , B 4. iii. = 2n-1
. A= {x/xεZ, x2 < 30} A A, B � A, B
iv. = 2n-2
12 Ð-û¦-è[ª -øŒ‰vÚÛî¦ô¢Ù 5 áì÷J 2018
In the last few years reasoning section has seen major changes.
The difficulty level in reasoning section has tremendously
increased, and it has been increasing year on year by introducing
new models. Earlier this section used to be considered as the
REASONING scoring area where in students could easily score around
20 questions from these topics which were regular feature in the
After the introduction of prelims and mains, paper. (Coded inequalities (5), Coding decoding (5),
the regular models in the above said scoring Input and output (5), Syllogisms (5)).
topics were shifted to prelims. Very few ques-
tions, that too new and different questions from
'yap lap map' would mean...?
these topics were given in the mains. Thus
making it very difficult for the students to score
in this reasoning section. Today, let us discuss
about the latest changes in the reasoning sec-
tion.
CODED INEQUALITIES
happiness-yap, depends-map, memories-nap.
(Old Pattern): Writer: The code for 'Focus have memories' is 'cap
Model-I: G.Shashi Kumar pap nap'.
Some statements given followed by two or Subject Expert Ans: Choice (5)
three conclusions. For example: 2. 'yap lap map' would mean
1. Statement: E > A = B ≥ C ≤ H > N From Choice (1) A ≤ B is false as there are 1) happiness on goal
Conclusions: I. E > N II. C < E two opposite symbols between A and B it can- 2) people goal happiness
Solution: not be the answer.
3) successful depends focus
As two opposite symbols are there between Choice (2) if false, as two opposite symbols
4) goal depends happiness
E and N, no relation can be established are there, no relation can be established.
5) None of these
between E and N. So, I does not follow. From Choice (3), C ≤ D = E < B ≥ F ≥ A, from this
First one should convert the statements Solution:
the statements as E > C is true, obviously A ≤ B as well as B > C both follow.
C < E also follows. So, only conclusion II according to the information given, 'yap lap map' is the code for 'happiness
Ans: Choice (3)
follows. N≥O≥M?P≥D<Q goal depends'.
2. Which of the following symbols replace the
Model-II: D ★ O means D < O, in order to make D < O Ans: Choice (4)
question marks in that order in the given
In this model, the meanings for the symbols expressions to make expressions K < V and true the symbol that has to be replaced is $. Condition based:
will be given. First we should convert the sym- Z ≥ S definitely true? Ans: Choice (3) This model is frequently given in clerical
bols according to their meanings and then start U?W?S?K?Z?V 2. In which of the following statements both the examinations.
solving the questions. conclusions A $ D and F @ B definitely false? In this some elements will be given in row-I,
1) >, ≥, =, <, ≤ 2) ≤, <, =, ≥, <
For example: 1) B % M # F ★ A $ Q # D and their corresponding codes in row-II.
3) ≥, >, =, ≤, < 4) <, ≤, =, ≥, <
A@B means 'A is not greater than B' 2) D $ F # A $ L # K % B Below this table some conditions will be given
5) =, ≤, <, ≥, >
A ★ B means 'A is neither greater than nor followed by questions.
Solution: 3) M $ F @ D @ B # K ★ A
equal to B' Study the following information carefully and
From Choice (1), K < V is true but Z ≥ S is 4) D % Q $ F # A @ B @ T
A # B means 'A is neither greater nor smaller answer the questions given below it.
false. 5) None of these
than B' Digits in the numbers are to be coded as
From Choice (2) no relation can be established Solution:
A $ B means 'A is not smaller than B' follows:
between K and V The conclusions A > D and F ≤ B should be
A © B means 'A is neither smaller nor equal Digit 4 7 1 8 2 6 0 9 3 5
From Choice (3), both the conclusions K < V definitely false.
to B'
and Z ≥ S are true. From (1), we have A > D is true. So (1) can- Code W R Q M D U K E Z I
1. Statements: E$V, K#V, K©P, W@P, W#X
Ans: Choice (3) not be the answer.
Conclusions: (i) X ★ V (ii) W # K Following conditions are to be observed:
3. Which of the following set of symbols should From (2), we have A < D and F > B, hence
Solution: the conclusions A > D and F ≤ B definitely false. (i) If the first digit is even and the last digit is
replace the question marks in that order in
Here @ stands for ≤, ★ stands for <, # odd-prime, they are to be coded as # and ©
the given expression in order to make the Ans: Choice (2)
stands for =, $ stands for ≥, © stands for >. respectively.
expressions X > S and A ≤ X are definitely
Statements: E ≥ V, K = V, K > P, W ≤ P, W = X. false? CODING & DECODING (ii) If the first digit is odd and the last digit is
Conclusions: (i) X < V (ii) W = K zero, then they are coded as & and @.
"T ≥ S ? V ≥ X; S = L ≤ D ? A" (Old Pattern):
By combining the above statements, we get 1) >, = 2) ≥, > 3) <, ≥ (iii) If '0' is preceeded by even and followed by
In this topic one can witness huge variation
E≥V=K>P≥W=X prime then '0' is coded as ★ and the codes
4) ≥, = 5) None from one exam to the next examination. Some
From this as V > X follows ⇒ X < V also surprise element is being introduced every time, of first and last digits in the number will inter-
Solution:
follows let us have a glance through these changes. change.
From Choice (1), we have
As K > W follows W = K does not follow. Earlier this model used to be a regular fea- (iv) If '0' is preceeded by odd (non-prime) and
T ≥ S > V ≥ X, S = L ≤ D = A followed by even (non-prime) then '0' is
ture in the bank exams where the students can
New Pattern Combining the two statements coded as '$' and the codes of first and last
rely upon this model for five marks.
Now let us discuss in detail about the new X≤V<S=L≤D=A digits in the number will interchange.
From this both the conclusions X > S and For example:
patterns in this topic. The major differences Note:
between the old pattern and new pattern is that A ≤ X are definitely false. According to a certain code, ★ 0 (Zero) is not considered as either even or
in the old pattern we used to have a set of 5 Ans: Choice (1) Sentences Codes odd.
questions but where as in the new pattern each 1 focus on your goal lap tap cap gap ★ If no condition is being followed then the
Set - 1
question is of a different type and that to at the codes for the digits are according to the
most only 2 or 3 questions used to be given. This model is a combination of model-II of 2 successful people sap pap lap zap
the old pattern and model-I of new pattern. have goal given table.
For example: 1. 20375826
For example: 3 people depends gap sap yap map
1. Which of the following elements replace the A @ B means 'A is not greater than B' on happiness 1) #KZRIMD© 2) U★ZRIMDD
question marks in that order in the given 3) UKZRIMDD 4) D★ZRIMDU 5) None
A ★ B means 'A is neither greater than nor 4 your happiness pap nap tap yap
expressions to make the expressions A ≤ B
equal to B' have memories Solution:
and B > C definitely true?
A $ B means 'A is neither smaller than nor This satisfies condition (iii), hence the code
?≤?=?<?≥?≥ ?
equal to B' 1. 'Focus have memories' would be written as for 20375826 is U★ZRIMDD.
1) D, A, C, E, B, F 2) F, B, E, C, A, D
A % B means 'A is not smaller than B' 1) sap pap tap 2) cap lap yap Ans: Choice (2)
3) C, D, E, B, F, A 4) D, C, B, E, A, F
A # B means 'A is neither greater than nor 3) pap map cap 4) map zap nap 2. 35724910
5) D, C, E, F, B, A
smaller than B' 5) pap nap cap 1) ZIRDWEQ& 2) @IRDWEQ&
Solution:
1. Which symbol should come in place of ques- Solution: 3) &IRDWEQ@ 4) &IRDWEQK 5) None
For these type of questions students should
tion mark (?) in the given expression so as to Comparing (1) & (2), the code for 'goal' is Solution:
always go through each choice, making it time
make the conclusion D ★ O definitely true? 'lap'. From (1) & (3), the code for 'on' is 'gap'.
consuming. This satisfies condition (ii), hence the code
N $ O % M ? P% D ★Q From (1) & (4) the code for 'your' is 'tap'. From for 35724910 is &IRDWEQ@.
For Bank exams Study materials, 1) # 2) % 3) $ 4) ★ 5) @ (1) the code for 'focus' is 'cap'. Ans: Choice (3)
Online tests please visit... Solution: Similarly, we can find the codes for the other
www.eenadupratibha.net In this @ means ≤, ★ means <, $ means >, words. The codes for the remaining words is as
% means ≥ and # means = follows: people-sap, have-pap, successful-zap, (To be continued...)
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10. £æ›´÷-ߪ‚Ø˛ Åç-õ‰..? 1) -ê’-v®Ωç 2) ÆæMç 3) °∂æ-Kü˛ 4) Å©ç-U®˝
26. véÃ.¨¡. 1611 ™ ¢Á’£æ«-®Ω’-Fo-≤ƒ-†’ N¢√-£æ«-´÷úÕ-† ®√V?
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æ ç-ûª’úø’ ï£æ«ç-U®˝ -Ç¢Á’èπ◊ -à-´’-E Ê°®Ω’ °-ö«d-úø’?
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11. véÃ.¨¡. 1564 ™ Åéπs-®˝ûÓ -O®Ó-*-ûªçí¬ §Ú®√-ôç-îËÆ œ 1) ü¿’®√_-üΔÆæ’ 2) P¢√@
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´’®Ω-ùÀç-*† íÓçú≈yØ√ §ƒ©-èπ◊-®√©’? 27. ≥ƒï-£æ…Ø˛ °æJ-§ƒ-©† 鬙«Eo Ææy®Ωg-ߪ·-í∫çí¬ ´Jgç- 3) Uû√-üΔÆæ’ 4) ®√´’-üΔÆæ’ 3) ï£æ«ç-U®˝ 4) å®Ωç-í∫-ñ‰-¶¸
1) ®√ùÀ ü¿’®√_-´A 2) ®√ùÀ °æCtE 42. ¢Á·í∫-©’© îªJ-vûª™ -á-´-J -§ƒ-©-Ø√ é¬-™«-Eo Ææy®Ωg-ߪ·-
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3) ®√ùÀ ¶μ«®· 4) î√çü˛-H-H
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12. Ê≠®√{ véÃ.¨¡ 1545 ™ -à ü¿’®√_Eo ´·ôd-úÕç-îË 3) 1, 2 4) N.á.-Æ œtû˝ 1) Åéπs®˝ 鬩ç 2) ≥ƒï-£æ…Ø˛ 鬩ç
61. P¢√@ ´’çvA ´’çúøL Ê°®Ω’?
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3) Å≠æd Ø√ߪ’-èπ◊©’ 4) Å≠æd C¢√-†’©’
13. Ê≠®√{ ûª† ®√ñ«uEo -à Nüμ¿çí¬ N¶μº->ç-î √-úø’? 1) ¶«•®˝, £æ›-´’-ߪ‚Ø˛, Åéπs®˝, ï£æ«ç-U®˝
à®√pô’ îËÆœçC? 62. P¢√@ véÃ.¨¡. 1674 ™ îμªvûª-°æ-Aí¬ °æö«d-GμÊ≠éπç îËÆæ’-
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15. °æJ-§ƒ-©-†™ Åéπs®˝éÀ -´÷®Ω_-ü¿-®Ωz-èπ◊úø’? 3) å®Ωçí∫-ñ‰-¶¸ 4) -≠æfl-ñ« 1) ≥ƒï-£æ…Ø˛ 2) Åéπs®˝ 1) ûª’鬮√ç, ¢√´’Ø˛ °æçúÕö¸ 2) àé˙-Ø√ü∑˛
1) Ê≠®√{ 2) ¶«•®˝ 30. °æJ-¨¡Ÿü¿l¥ ¨»Ææ-Ø√©’ ñ«K-îË-Æ œ† Ø√-ù‰-©Â°j êM´÷ 3) å®Ωçí∫ñ‰-¶¸ 4) Ê≠®√{ 3) Ø√´’-üË¢˛, Ææ´’®Ωn ®√´’-üΔÆæ’ 4) °j ¢√®Ωç-ü¿®Ω÷
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2-1 15-1 28-3 41-2 54-1
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