Input Echo, Leg & Lug Item 1, Description: Channel Lug
Design Internal Pressure 0.00 MPa
Design Temperature for Attachment TEMP 20.00 C
Vessel Outside Diameter OD 1642.000 mm.
Vessel Wall Thickness Ts 15.0000 mm.
Vessel Corrosion Allowance Cas 1.5000 mm.
Vessel Material SA-240
Vessel Material UNS Number S31803
Vessel Allowable Stress at Design S 177.20 MPa
Analysis Type: Lifting Lug
Empty Weight of Vessel Wemp 21000.00 N 0.
Operating Weight of Vessel (vertical load ) W 0.00 N 0.
Lifting Lug Material SA-240
Lifting Lug Material UNS Number S31803
Lifting Lug Yield Stress YIELD 448.18 MPa
Lifting Lug Orientation to Vessel Perpendicular
Total Height of Lifting Lug w 200.0000 mm.
Thickness of Lifting Lug t 20.0000 mm.
Diameter of Hole in Lifting Lug dh 35.0000 mm.
Radius of Semi-Circular Arc of Lifting Lug r 50.0000 mm.
Height of Lug from bottom to Center of Hole h 100.0000 mm.
Offset from Vessel OD to Center of Hole off 100.0000 mm.
Minimum thickness of Fillet Weld around Lug tw 10.0000 mm.
Length of weld along side of Lifting Lug wl 200.0000 mm.
Length of Weld along Bottom of Lifting Lug wb 20.0000 mm.
Lift Orientation Vertical
Force Along Vessel Axis Fax 21000.00 N 0.
Force Normal to Vessel Fn 21000.00 N 0.
Force Tangential to Vessel Ft 5250.00 N 0.
Impact Factor Impfac 2.00
Occasional Load Factor (AISC A5.2) Occfac 1.00
Results for lifting lugs, Description : Channel Lug
Weld Group Inertia about the Circumferential Axis ILC 0.177E+08 mm^4
Weld Group Centroid distance in the Long. Direction YLL 110.000 mm.
Dist. of Weld Group Centroid from Lug bottom YLL_B 100.000 mm.
Weld Group Inertia about the Longitudinal Axis ILL 946665.562 mm^4
Weld Group Centroid Distance in the Circ. Direction YLC 20.000 mm.
Applying the Impact factor to the loads:
Fax = 21000.00 * 2.00 = 42000.00 N 0.
Ft = 5250.00 * 2.00 = 10500.00 N 0.
Fn = 21000.00 * 2.00 = 42000.00 N 0.
Primary Shear Stress in the Welds due to Shear Loads [Ssll]:
= Sqrt( Fax^2+Ft^2+Fn^2 ) / ( (2*(wl+wb)) * tw )
= Sqrt(42000^2+10500^2+42000^2) / ( (2*(200.0 +20.0 )) * 10.0000 )
= 13.71 MPa
Shear Stress in the Welds due to Bending Loads [Sblf]:
= (Fn*(h-YLL_B)) *YLL/ILC + (Fax*off *YLL/ILC) + (Ft*off *YLC/ILL)
= (42000 *(100.000 -100.000 )) * 110.000 /17746650 +
(42000 *100.000 * 110.000 /17746650 ) +
(10500 *100.000 * 20.000 /946665 )
= 48.22 MPa
Total Shear Stress for Combined Loads [St]:
= Ssll + Sblf
= 13.710 + 48.220
= 61.93 MPa
Allowable Shear Stress for Combined Loads [Sta]:
= 0.4 * Yield * Occfac (AISC Shear All.)
= 0.4 * 448 * 1.00
= 179.27 MPa
Shear Stress in Lug above Hole [Shs]:
= Sqrt( Fax^2 + Fn^2 + Ft^2 ) / Sha
= Sqrt( 42000^2 + 42000^2 + 10500^2 ) / 1300.000
= 46.40 MPa
Allowable Shear Stress in Lug above Hole [Sas]:
= 0.4 * Yield * Occfac
= 0.4 * 448 * 1.00
= 179.27 MPa
Pin Hole Bearing Stress [Pbs]:
= Sqrt( Fax^2 + Fn^2 ) / ( t * dh )
= Sqrt( 42000^2 + 42000^2 ) / ( 20.000 * 35.000 )
= 84.86 MPa
Allowable Bearing Stress [Pba]:
= Min( 0.75 * Yield * Occfac, 0.9*Yield ) AISC Bearing All.
= Min( 0.75 * 448 * 1.00 , 403.4 )
= 336.13 MPa
Bending stress at the base of the lug [Fbs]:
= Ft*off / (w*t^(2) / 6) + Fax*off / (w^(2)*t / 6)
= 10500 * 100.000 / (200.000 * 20.000^(2) / 6) +
42000 * 100.000 / (200.000^(2) * 20.000 / 6)
= 110.26 MPa
Tensile stress at the base of the lug [Fa]:
= Fn / (w * t) = 42000 / (200.000 * 20.000 )
= 10.50 MPa
Total Combined Stress at the base of the lug:
= Fbs + Fa = 120.8 MPa
Lug Allowable Stress for Bending and Tension:
= Min( 0.66 * Yield * Occfac, 0.75*Yield )
= Min( 0.66 * 448 * 1.00 , 336.1 ) = 295.8 MPa
Note: Check the Shell Stresses using method such as WRC-107.
Summary of Results
Stress (MPa) Actual Allowable P/F|
------------------------------------------------------------------------------
Primary Shear Stress of Weld : 61.93 179.27 Ok |
Shear Stress above Hole : 46.40 179.27 Ok |
Pin Hole Bearing Stress : 84.86 336.13 Ok |
Total Combined Stress at the lug base : 120.76 295.80 Ok |
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