Part 4
Part 4
Part 4
Diodes
• Diodes readily conduct current from anode to cathode, but do not allow
current to flow in the opposite direction.
• Forward-bias region : current flows easily through the diode in the
direction of the arrowhead of the circuit symbol.
• Reverse-bias region : for moderate negative values of VD , the current iD is
very small in magnitude.
•Reverse-breakdown region : for sufficiently large reverse-bias voltage, and
large magnitude flow of current.
Non-linear I-V Characteristic
“On”
“Off”
Zener Diodes
• Diodes that are intended to operate in the breakdown region are called
Zener diodes.
• Zener diodes are useful in applications for which a constant voltage in
breakdown is desirable.
Volt-Amper Characteristic
Load-Line Analysis of Diode Circuits
• Many of the techniques that we have studied for linear circuits do not
apply for circuits involving diodes.
• Graphical methods provide one approach to analysis of nonlinear circuits.
• Connecting points A and B results in a plot called the load line.
• The operating point is the intersection of the load line and the diode
characteristic
VSS = RiD + v D
VSS + RiD + vD = 0
Load-Line Analysis of Complex Circuits
•ofThe load line is constructed to find the operating point on the characteristic
the nonlinear device.
⎡ ⎛ vD ⎞ ⎤ kT
iD = I s ⎢exp⎜⎜ ⎟⎟ − 1⎥ VT =
⎣ ⎝ nVT ⎠ ⎦ q
• Is : Saturation current, n: emission coefficient , VT : Thermal voltage
k = 1.38 × 10–23 J/K is Boltzmann’s constant and q = 1.60 × 10–19 C is the magnitude
of the electrical charge of an electron. At a temperature of 300 K, we have :
VT ≅ 26 mV
⎛ vD ⎞
iD ≈ I s exp⎜⎜ ⎟⎟ for v D >> VT
⎝ nVT ⎠
iD ≈ −I s for vD << -VT until reaching reverse breakdown
William Shockley, (Nobel Laureate, 1956; from
Electrons and Holes in Semiconductors)
Ideal-Diode Model
• Graphical load-line and Shockley equation are too cumbersome for more
complex circuits. Instead, we use simpler models to approximate diode
behavior.
• The ideal diode acts as a short circuit for forward currents and as an open
circuit with reverse voltage applied.
• If iD is positive, vD is zero, the diode is in the on state
• If vD is negative, iD is zero, the diode is is in the off state
1. Assume a state for each diode, either on (i.e., a short circuit) or off (i.e., an
open circuit). For n diodes there are 2n possible combinations of diode states.
2. Analyze the circuit to determine the current through the diodes assumed to be
on and the voltage across the diodes assumed to be off.
3. Check to see if the result is consistent with the assumed state for each diode.
Current must flow in the forward direction for diodes assumed to be on.
Furthermore, the voltage across the diodes assumed to be off must be positive at
the cathode (i.e., reverse bias).
4. If the results are consistent with the assumed states, the analysis is finished.
Otherwise, return to step 1 and choose a different combination of diode states.
Analysis of Ideal-Diode Circuits
D1 would
be on!
Analysis of Ideal-Diode Circuits
i1 i2
i3
10V − 3V
i1 = = 1.75 mA
4 KΩ
3V
i3 = = 0.5 mA
6 KΩ
i1 + i2 = i3 → i2 = i3 − i1 = 0.5 mA − 1.75 mA = −1.25 mA
Not consistent with direction of current through D2!
Analysis of Ideal-Diode Circuits
v = Ra i + Va
Solution: Since the 3Vsource has a polarity that results in forward bias of the diode we assume
that the operating point is on line segment A. Consequently the equivalent circuit for the diode
is the one for segment A. Solving we find that i = 80mA.
D
Types of Diodes and Their Uses
PN Junction Diodes: Are used to allow current to flow in one direction while blocking
current flow in the opposite direction. The pn junction diode is
the typical diode that has been used in the previous circuits.
P N
A C
A C
Schottky Diodes:
Shockley Diodes:
Light-Emitting Diodes:
Photodiodes:
While LEDs emit light, Photodiodes are sensitive to received
light. They are constructed so their pn junction can be exposed to
A C the outside through a clear window or lens.
In Photoconductive mode, the saturation current increases in
proportion to the intensity of the received light.
• These circuits allow power to flow only from the source to the load,
unidirectional converters.
•There are many possible ways to construct rectifier circuits using diodes. The two
basic types of rectifier circuits are:
0 VO 0
R
• Diode is off for positive input voltages
• When diode is off the output voltage is the same as input voltage VO
Half Wave Rectifier -3-
output voltage
R VO
input voltage
VO 0
R
• Diode is off for negative voltages
• When diode is off the output voltage is the same as input voltage VO
Full-Wave Rectifier Circuits -1-
Graëtz bridge
Full-Wave Rectifier Circ
Full-Wave Rectifier Circuits -4-
Wave-Shaping Circuits :Clipper circuits
• Clippers, limiters or clipping circuits make use of non-linear properties of
diode, that is the diode conducts the current in forward direction and does not
conduct in reverse direction.
• These circuits are primarily wave shaping circuits.
• They clip or remove certain portion of ac voltage applied to the input of
circuit.
Diode Positive Clipper with positive bias voltage -1-
R
VB
VB VO 0
VB
0
0 VO 0
VB -Vb
-VB
VB
VB VO
VB 0
0 -VB
-VB
-VB
on and the output voltage is 6 V, because the diode connects the 6-V battery to the
9V
Diode
vo (V)
Section 10.7 Wave-Shaping C
rtion of vin clipped
off by diode A Diode (b) Waveforms
A on
6
Figure 10.29 Clipper circuit.
2k 2k
+ 8.4 V 1 8.4 V
+
1
vin(t) vin(t)
v (V)
t 5.4 V 9 6 5.4 Vin
•0.6Sketch the transfer characteristics to scale for the circuits below. Allow a
V forward drop for the diodes. And skectch the output waveform to
scale if Vin(t) = 15 sin(ⱳt).
9.4 V
Example :Clipper circuits -2-
For this circuit all of diodes are off if -1.8<v0<10. With the diodes off, no current
flows and V0=Vin When Vin exeeds 10V, D1 turns on and D2 is in reverse
breakdown. Then V0=9.4+0.6=10V. When Vin becomes less than -1.8V diodes D3,
D4, and D5 turn on and V0= -3 x 0.6 = -1.8V.
V0(V)
10 V 10 V
-1.8
Vin(V)
-1.8 -1.8
10 V
Wave-Shaping Circuits
Wave-Shaping :Clamp
Circuits circuits
: Clamp Circuits
•Clamping circuits are used to hold either positive or
negative extremity to a reference voltage level.
+C -
VP
0
0 + VP
VP R
-VP - 0
-
-VP
+
VO
C -2VP
R C
+ - -2VP
- VP
VP R
+
During the first positive half cycle the diode acts like a short circuit. The capacitor
charges to peak value of input voltage Vp. During this interval the output Vo which
is taken across the short circuit will be zero. During the negative half cycle, the
diode is open. C is very large, so Vc will stay almost constant for the next cycles.
Wave-Shaping Circuits :Clamp circuits
Positive peak clamps to +VB
C
VP
+ - VO=-(VP-VB)+VP
=VB
+ VP-VB
0 R
VP
-
VB
-VP
0
2VP
C
+ - VO
+ VP-VB
+
C
- VO=-(VP-VB)-VP
VP R =-2VP+VB
- VP-VB
- VB
VP R
+
During the positive half cycle of the input signal the diode is forward biased
and acts like a short circuit. The capacitor charges to Vp-VB .
Linear Small-Signal Equivalent Circuits
• The operating point or Q point of the diode is the quiescent or no-signal
condition. The Q point is obtained graphically.
• Find a linear small-signal equivalent circuit for the nonlinear device to use in
the AC analysis.
• The DC supply voltage results in operation at the quiescent point (Q point).
• The small-signal equivalent circuit for a diode is a resistance (dynamic
resistance).
−1
⎛ di D ⎞ ⎡⎛ di ⎞ ⎤
ΔiD ≅ ⎜⎜ ⎟⎟ Δv D rd ≅ ⎢⎜⎜ D ⎟⎟ ⎥
⎝ dv D ⎠Q ⎢⎣⎝ dv D ⎠Q ⎥⎦
vd
id =
Diode characteristic illustrating the Q point. rd
Linear Small-Signal Equivalent Circuits : Quiescent point