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Deformation Section A

igcse physics

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0% found this document useful (0 votes)
62 views17 pages

Deformation Section A

igcse physics

Uploaded by

gswtb6hrdn
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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120 awrite Pubtications physes Level P2 Workbook” section A mines the extension of a Spring i 4, Mid 18/P22/02 akes measurements and deter in experiment, & student t 7 ‘iront Toads. The apparatus is shown In Fig. 2 spring scale load: Fig. 2.1 ‘The table in Fig. 2.2 shows the results. [load/N o | 10 | 20 | 30 length of spring/mm | 200 | 235 | 270 | 305 extension/mm [0 | 3 | 7 | 105 Fig. 2.2 Only some of the extensions are shown in the table. Complete the table to show all of the extensions. Calculate the load that produces an extension of 49mm. @ (b) Scanned with CamScanner oLevelP-2 Workbook Unit 6: Deformation 129 The student pulls a load downwaris temesters : © postion B, as shown in Fig, te from position A to position B and holds it fixed at B ; Fig, 2.3 The load is stationary at A and at B. The load has no kinetic energy at either point. (il) Place ticks (V) in the boxes to show how the value of each of the forms of energy compares at A and B. equal atAandB larger atA larger at B energy stored in spring gravitational potential energy of load 1] : (ii) Work is done by the student to pull the load down. The law of conservation of energy ~~ states that energy cannot be created and cannot be destroyed. Explain how this principle applies in this case. 2. OIN17IP220Q2 0” : se @ ‘force applied to a solid object may cause it to accelerate so, thatits velocity changes. (2). State two other properties of the object which may change When a force is applied. OS 3 Scanned with CamScanner 130 Prysies O-Level 2 Workbook ‘ena 8 wnte PUDIEatIONS ing has a mass of 0.0129: ° me gravitational fold strength g's JON/Kg. Calculate the weight of the spring : . weight = . ; . fy (a) The spring is suspended vertically and a load Is attached ie i wor ond Th sa the limit of prop / extends by 2.7cm and does not pass * Fig. 2.1 shows the spring and load attached to the lower end of a second identical 2g, second spring load Fig. 2.1 ‘Suggest one reason why the extension of the second spring differs from 2.7cm, (iil) Explain what is meant by limit of proportionality. (6) The load in Fig. 2.1 is pulled down below its equilibrium position? @ (i) State the form of energy stored in the stretched sprngs? eS) ws & Jt! (li) The load is released and it mov 6 /eS upwards Ni each movement decreases until the Toad ‘stoy sr owns The lance teva? moyinig, y Explain why the load stops moving, @ , s Scanned with CamScanner Pa werk ie int: Dtomaten 16221083 We Puss Me three spring +3. Meudent has three springs A, B and C. He mea in tur, when ‘erent weights are placed on the end of each me the length of each spring, a is table of results is shown in Fig, 3.1, yi weight/N length of length of length of Spring Alem | spring B/em | spring C/cm 1.0 61 86 am 15 69 95 105 2.0 77 104 11.8 25 85 11.2 13.4 3.0 93 124 168 Fig. 3.1 (@) () State which spring has been stretched past the limit of proportionality. (ii) Using data from Fig. 3.1, explain how you obtained your answer to (a)(I). (iil) Calculate the unstretched length of spring A. unstretched length Scanned with CamScanner Workbook otevel Pe 133 3: Deforma . Read a Wale Pabtctons Unit: Detonation wis t6rP2v/a2 = 5, Metudent hangs various masses from the end of Fig. 2.1 shows the spring hanging vertically on a spring and determines the extension produced. its own and with an unknown mass X at one end. Spring 10m spring. xX Fig. 2.1 (not to scale) {a) The student plots a graph of the extension of the spring against the mass hanging on the . spring. Fig. 2.2 shows the student's graph. 40: extension/cm 30: 20: gA00_ O° 500 of massig, © Ko) 0 100 200 300 Fig. 2.2 (i) Atpoint P on the graph, the line begins to cave State the name of point P. 5 Scanned with CamScanner Unit: 14 Physics O-LevlP2 Workbook Read & wnt Pubeatons 2 torte, (li) Using Fig. 2.1 and Fig. 2.2, determine the mass X. mass = (iii) The gravitational field strength gis 10N/kg. Calculate the weight of X. weight (b) An identical spring is used with the original spring, as shown in Fig. 2.3. ‘Together they support the mass X. Fig. 2.3 (not to scale) State and explain how the extension in Fig. 2.9 compares with the extension in Fig. 2.1 6. OIN 15/P22I1Q2 g& (@) The surface of a runnin 9 track is made of oytrondy itexerts a large force on the rubber tracks ee A hageousi aaa State two effects that this force has on the rubber, ,>> & 1 Scanned with CamScanner Ce Read & Wrte Pubteations Unit 6: Deformation A spring is suspended from a support with a ©) daed othe pan untl the sping is extended wal Doro g ewer ng Masses are fig. 2.1 shows this apparatus, beyond the limit of proportionality. Fig. 2.1 Aruler is used when determining the extension of the spring. () On Fig. 2.2, sketch the extension-load graph for the spring and label the limit of proportionality P. ie) extension 0 0 load Fig. 22 BS (ll) The masses are then removed and the extension of the spring decredses: Suggest what is observed when all the masses are removed, SS" Scanned with CamScanner 26 unsavine an s pryses Level 2 WertBoot : . jon of a spring. re the extension 1 ws 15972101 re 4.1is used to measu! | The apparatus shown UZ - : spring. scale mass Fig. 1.1 e on the spring. (2) Explain how the mass causes a fore’ - tt} (0) ‘The force onthe spring is a vector quantity. State what is meant by @ vector quantity, (c) Fig, 1.2 shows a graph of the length of the spring plotted against the force on the spring, fer forces between 0 and 10N. 140 120 length/cm 100 S 80 Ge : ge Boo ay? 40 20; Fig. 1.207 @ 1. State a formula that re Sed h ring, the stretched ‘ate a formula that relates the unstretched length 1 of the spring, the stret 9s length Lof the spring and the extension e of the spring, Scanned with CamScanner th 2 werk 4 - 137 ao Read & Wite Pubicaions. Unt 6: Deformation | 2. Amass produces a fore ; e Of 9.( 7 caused by this mass. ON on the spring. Determine the extension ofthe spring ‘The limit of proportional Sxtension = o i ly ofthe spring is reached when the force is 10N. ‘The spring is easier to stretch ater the tmit of proportionality. On Fig. 1.2, continue } greater than 10N. the line to suggest how the length changes when the force ‘ 44IP22101 " j student suspends a spring from a clamp stand. He measures the unstretched length of the ring with no load attached. He then attache, and arasureS the new lengths of the spring, different loads to the lower end of the spring Fig. 1.1 shows how the total length of the spring depends on the load attached. 25 20 length/em 15 10 (@) At point P on Fig. 1.1, the line stops being saan State the name of point P. ad Scanned with CamScanner " : 138 ‘Unt 6: Pryscs Qe AZ Wort an Ohom, ©) (@_ Using Fig. 1.1, determine the unstretched length of the spring. unstretched length = (li) Calculate the extension of the spring for a load of 4.0N. * extension = (c) The student attaches a small block of wood to an identical spring. The extension of the is 2.7om. The gravitational field strength gis 10N/kg. Calculate the mass of the block of wood. } ‘Pring mass = 9. MIS 13/P21/01 Fig. 1.1 shows how the length of a spring varies as the force applied to it increases. 7 2. 5 10 15 20 length of gj Fig. 1.4 (@) Determine the length of the unstretched spring. SS Scanned with CamScanner © ti) is The spring is attached to a mass M of 0,201 kg and placed on a frictionless surface, as shown in Fig. 1.2, M spring frictionless surface : Fig. 1.2 (not to scale) ‘The apparatus is placed on the floor of a car. car accelerates in this direction When the car accelerates uniformly in the direction shown, the spring extends. (I) State what is meant by a uniform acceleration. (ii) The extension of the spring is 9.0em. Using Fig. 1.1, determine 1. the horizontal force on M, 2, the acceleration of M. Scanned with CamScanner aE Pays Level PZ Worth 0 tort peas s wre xtends by wire, The wire © Y 2.5mm 40. O1N 12/P22102 asa utente 7 of the 4 A pup reed te We ser ‘orig, Calculate the ™ASS O12 ASN ogg tional (2) (The grave mass = to plt tho extension toad graph for tis wie fora gg 1 to Use the grid in Fig. 2. : between 0 and 45N. Fig. 24 (b) Use the graph plotted in Fig. 2.1 to determine the load needed to 3mm. produce an extension load = 11, M/J 12/P22/Q1 Fig, 1.1 shows apparatus used to obtain the readings for a graph of force against extension fora spring. spring masses, Ban Fig.1.1 The masses added to the pan produce a force that stretches the spring. WA. Scanned with CamScanner_ Level P-2 Workbook Unit 6: Deformation 1a eas & we Pub (@) (State whats meant by the mass ofa body, a (b) Fig. 1.2 shows the force-extension = graphs for two different springs. 25: ‘spring A; force/N 9 20H z - spring B| 15: 10. 0 - 4 6 8 10 extension/om Fig. 1.2 ()) Astudent states that spring B is easier to stretch than spring A. Use values from Fig. 1.2 to explain what the student means. (it) The same force Is applied to each springs / O Using Fig, 1.2, determine the force that pfoducés an extension of spring B that is 1.06m Greater than the extension of spring A.” force = 1] Scanned with CamScanner 7 142 Physics 0-Lovel P.2 Workbook ead 8 Wate Publications 12. MIJ 10/P21/Q2 Fig. 2.1 shows a weight of 4.0N attached to a spring. Z . rule ° spring pointer weight 4.0N Fig. 2.1 The unstretched length ofthe spring is 8.0¢m. With the 4.0N weight attached to the spring the length is 14.0cm. The spring is within its limit of proportionality. J {@) State what is meant by the limit of proportionality of a spring. Scanned with CamScanner ‘_ unt Pa westook 143 Rend & Vite Petters Unt 6: Anwar Section (A) OS SI) (A) 4g/P22/Q2 ‘ ~ 450 and 220 in table 0 any use of proportionality 44N 4 line larger at B and 2% jj (e) ine larger at (Gg student loses eneray chemical eneroy da or (gravitational) potential energy dames es increases 8 and spring energy idea that increase in spring e; PE (so student provides Work nee araetdectease in (grav) 2 ON 4TIP221Q2 (e) shape size/ volume/density 0.12N (i) weight of first spring (increases i i (takes spring beyond the limit of propor ciiaatt of first spring (il) _ where/ point/load / extension /iimit be, ; fe proportional to load /extension-load oan whieh anes is not directly (©) @ elastic potential energy (i) fiction/air resistance mentioned or thermal energy /heat produced 4. Md 161P22/03 @ @ © (ii) data quoted to prove stretches more at end or extensions / changes in length increase /are not the same (at higher loads) (iti) 450m (b) (tie rock to spring A) + find weight/ force/newtons using length or extension and graph or match readings (in table) + find known weight/mass/force /N that gives same extension of spring + use of proportionality with length or extension + extension (inom)/1.6 (mass =) weight/9 or weight/ gravitational field (strength) 4, Mid 16/P22/08 (a) current/a.c (in primary coil) creates magnetic field or current/a.c_magnetises iron changing magnetic field (in secondary) (b) it/secondary has less turns (than primary) or primary has more turns (than secondary) or (some) flux escapes (€) (steel is) a permanent magnet or weaker fields produced oF (steel) difficult to magnetise/demagnetise or (steel) is a hard magnetic material Scanned with CamScanner 10. ps 16121102 : to (limit ‘of proportionality qi) 2509 (iil) 2.5N (b) half the ‘extension/10cm each /both/another spring tr both springs bear/ carry shares/ distributes the weight/mass the load COIN 151P22/02 (@) any two fro distort/stretch/ change in ‘compresses /change in size Change in termperature/gets hot (©) (straight line from origin : upward curve labelled clea from limit of proportionality (i). permanent extension or spring 'S longer than it was originally m different lines of: ape /squeezed] bends! dors Volume /density depth! height (ter)/generates hea My 151P22/01 {a) weight (puls spring down and causes tension) or forcelpull of gravity ‘or mass is in gravitation« (b) has a direction « (©) @) 1 lz bteor 2 36cm (i) curve upwards after 10N al field -eore=I-b om 14/22/01 {a) limit of proportionality (not breaking point) (b) (i) 85cm cao (i) 7.1-7.30m (@) 4.0% (27/7.2) or. x 2.7/9.0) oF 1.5 (N) oF read from graph or 11.2(cm) 0.148 — 0.152kg or 148 - 1529 Mig 13/P21101 w ttom b) (graph is) straight linefinear or has con i sta eae nt gradient or not curve ‘same change in uniformlsame time or i Ae isame time or in 15 2. (e=) Flmalgebraic or nu (eof 1. but not if F= 0) sielealeaiie 4(.0) mis? ON 12IP22/02 (a) (i) 4.5kg (ii) axes label aie ioe with quantity and unit straight line from cleat (b) answer from candidate's pias a Scanned with CamScanner va P-2 Workbook - oun eas 8. wit ubeatons Late Arawor Secon 4) : 2/Q1 - ya 12 IP 2: . 4 ei () (amount of) matter/materia/substance it contains (i) use of scale and subtractions oo ji) idea that Ais a straight line ang (GR aradient constant in Neer mathe OR same increase in F every cm for A but not B (il) 15N ws t01P21/02 12. (a) where extension/stretching st or extension/load = constant or point where length or extension against load graph curves (b) 4=K6 oF 4/6 or 6/4 oF 6 x 2/4 or 3 (cm) seen 41m (c) different weights/masses/oad and measure new length how extension is found e.g. reading on scale for loaded spring subtracted from reading with no load/mass/original ‘ops being proportional to force/loadiweightmass 1} i 1 Scanned with CamScanner

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