Custom Practice Test - 01-Feb
Custom Practice Test - 01-Feb
′
1
2
λ
3. λ
<
1
′
> 1
λ
1. 2.4
2. 1.2 8. An interference pattern is obtained with two coherent
3. 4.8 light sources of intensity ratio n. In the interference
4. 3.6 pattern, the ratio of their intensities (
Imax −Imin
) will be:
Imax +Imin
3. a = g cos θ
4. a = g tan θ
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
10. Two particles of mass 5 kg and 10 kg respectively 16. A car starts from rest and accelerates at 5 m/s . At 2
are attached to the two ends of a rigid rod of length 1 m t = 4 s, a ball is dropped out of a window by a person
with negligible mass. The centre of mass of the system sitting in the car. What is the velocity and acceleration of
from the 5 kg particle is nearly at a distance of: the ball at t = 6 s?
1. 50 cm (Take g = 10 m/s ) 2
2. 67 cm
3. 80 cm 1. 20√2 m/s, 0 m/s 2
potential energy of the dipole? pulse, where x and y are in meter and t is in seconds.
1. 1600 (N × m) k, −1200 J
^ Then which of these statement(s) is incorrect?
2. −1600 (N × m) k ^
, 1200 J 1. pulse is moving in (−x) direction.
3. −1600 (N × m) k
^
, −1200 J 2. wave speed is 0.5 m/s.
3. maximum particle displacement is 1 cm.
4. 1600 (N × m) k
^
, 1200 J
4. it is a symmetric pulse.
12. Dispersion of light is caused due to:
1. intensity of light 2. density of the medium
18. The molar specific heat (at constant volume) of a
3. wavelength of light 4. amplitude of light 3
monoatomic ideal gas is Cv = R while that of a
2
5
13. Let us consider two solenoids A and B, made from diatomic ideal gas is Cv = R, where R is the
2
the same magnetic material of relative permeability μ r universal gas constant. The molar specific heat (at
and of equal area of cross-section. Length of A is twice constant pressure) of an equimolar mixture of the two
that of B and the number of turns per unit length in A is will be:
half that of B. The ratio of self-inductances of the two 1 3 5
1. ( R + R)
solenoids, L : L is:
A B 2 2 2
1. 1 : 2 2 2
−1
2. 2 : 1 2. ( + ) R
3. 8 : 1 3 5
4. 1 : 8 3. 3R
8
4. R
14. The time period of revolution of the electron in the 15
n
th
Bohr orbit is proportional to:
19. A wire of length L meters carrying a current of I
1. n 3/2
2. n
3
4
15. A step-up transformer is connected to an AC mains I × πL
2
4
current in the secondary circuit, ignoring the power loss 2
2I L
in the transformer, is: 3. A-m
2
1. 8 mA π
2
2. 4 mA 4.
IL
A-m
2
3. 0.4 A 4π
4. 4 A
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
20. Three particles move along the three sides of a 23. The capacitance between two close parallel metallic
triangle ABC, starting from the three vertices plates (plate area: A, separation: d; d being small),
simultaneously. Each covers one side of the triangle and where half of the space between them is filled by a
reaches the next vertex; all the particles reaching their dielectric of dielectric constant K, is (see figure):
destinations at the same time. Suppose that the particles
move at constant velocities: → , v→ , v→ (see figure).
v A B C
Then:
ε0 A ε0 A (K + 1)
1. (K + 1) 2.
d d 2
ε0 A 2 ε0 A 2K
3. 4.
d K + 1 d K + 1
1. v→ A
→
+ vB = vC → 24. An electromagnetic wave given by:
2. v→ A
→
− vB = vC → → ^ ^
E = E ( i + j) sin(ωt − kz)
0
→
vC
3. v→ A
→
− vB =
2
is travelling in space, where E→ is the electric field at
4. v→ →
+ v →
+ vC = 0 (x, y, z) at time t. The amplitude of the electric field is:
A B
1. E0 2. √2E0
→
E, is travelling in space: 3. 2E0 4.
√2
→ ^
E = E j sin 2π(10 s
0 t −
x
)
3 −1
E0
1. 3 × 10 m/s 8
2. 3 × 10 m/s 6
1. 800 V, 2 A
2. 300 V, 2 A
3. 220 V, 2.2 A
4. 100 V, 2 A
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
27. When a particle with charge +q is thrown with an 30. The magnetic field at the centre of a semicircular arc
initial velocity v towards another stationary change +Q, of radius R, carrying current i is:
it is repelled back after reaching the nearest distance r μ i 0 μ i 0
3. β -decay.
+
4. K-electron capture.
R R √3
1. 2.
2 √3 + 1
R √3 R √3
3. 4.
2 √3 − 1
q q
1. 2.
ε0 2ε0
2. 29.5 ms −1
3. 31.5 ms −1
4. 28.5 ms −1
Page: 4
Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
34. The following graph represents the T -V curves of an 38. An object of mass 100 kg falls from point A to B as
ideal gas (where T is the temperature and V the volume) shown in the figure. The change in its weight, corrected
at three pressures P , P and P compared with those of to the nearest integer (R is the radius of the Earth), is:
1 2 3 E
1. 49 N
35. Which of the following gates, may be used to form
2. 89 N
all other gates?
3. 5 N
1. AND 2. OR 4. 10 N
3. NOT 4. NAND
39. All the resistances in circuit are 2 Ω each, E = 4 V
1
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
41. A rod XY of length l is placed in a uniform magnetic 44. The following figures show a liquid flowing ideally
field B, as shown in the diagram. The rod moves with a through a tapered tube. Single-tube manometers are
velocity v, making an angle of 60 with its length. The
∘
connected at three positions along the tube. Identify the
emf induced in the rod is: diagram showing the correct rise of liquid in the tubes.
1. 2.
vBl
1. vBl 2. 3. 4.
2
1
√3
3. vBl 4. vBl
2 √3
42. A pendulum-bob A, after being released as shown, 45. An object of mass m is suspended at the end of a
strikes a spring-block system when the bob A reaches its massless wire of length L and area of cross-section A.
lowest position; the mass of the bob A being equal to Young modulus of the material of the wire is Y . If the
that of the block (i.e., m) and the stiffness of the spring mass is pulled down slightly, its frequency of oscillation
being k. The collision between the block and the bob along the vertical direction is:
(A) is elastic. The time period of one complete
1. f =
1
√
mA
oscillation is: 2π YL
2. f =
1
2π
√
YL
mA
3. f =
1
2π
√
mL
YA
4. f =
1
2π
√
YA
mL
Chemistry
l m l m
46. A solution was prepared by adding 125 cm3 of
1. 2π√ + 2π√ 2. π√ + π√
isopropyl alcohol to water until the volume of the
g k g k
solution was 175 cm . The volume percent of isopropyl
3
3.
g
√
k
4. 1
g
1
√
k alcohol in the solution is:
√ + √ +
l m 2π l 2π m 1. 80.2 % 2. 71.4 %
3. 78.3 % 4. 84.5 %
1. 544 km
2. 136 km
3. 68 km
4. 34 km
Page: 6
Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
2aCr
3+
(aq) + bSO (aq) +
2−
H O(ℓ)
c 3. Statement I is correct, and Statement II is correct.
4 2
the coefficients a, b and c of a balanced equation are 4. Statement I is incorrect, and Statement II is
2
mm.
Mark the correct statement that is associated with it:
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
1. 75
4+ − 2+ o
Pb + 2e → Pb ;E = +1.67 V
2. 100 Ce
4+
+ e
−
→ Ce
3+
;E
o
= +1.61 V
3. 125 Bi
3+
+ 3e
−
→ Bi; E
0
= +0.20 V
4. 50 The oxidizing power of the species will increase in the
order:
56. Which is the correct statement among the following?
1. Starch is a polymer of α-glucose 1. 4+ 4+ 3+ 3+
Ce < Pb < Bi < Co
2. Amylose is a component of cellulose
2. Bi
3+
< Ce
4+
< Pb
4+
< Co
3+
57. Correct statement regarding the dichromate ion 61. Choose the option containing all isoelectronic
(Cr2O72–) is: species:
1. N , O , F , N a 3− 2−
58. The correct order of dipole moments for molecules 62. Which species among the following has the largest
N H , H S, CH and H F is :
3 2 4
ionic radius?
1. CH > H S > N H > H F 1. S 2−
4 2 3
2. Cl −
63.
What are the values of ΔH and ΔS, respectively? X and Y in the above-mentioned reaction are
1. ΔH = 0, Δ S = −ve respectively:
2. ΔH = 0, Δ S = 0 1. X = 2–Butyne; Y = 3–Hexyne
3. ΔH = −ve, Δ S = −ve 2. X = 2-Butyne; Y = 2-Hexyne
4. ΔH = +ve, Δ S = +ve 3. X = 1-Butyne; Y = 2-Hexyne
4. X = 1-Butyne; Y = 3–Hexyne
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
Both (A) and (R) are True and (R) is the correct
1.
True statements among the sbove are: explanation of (A).
1. I and II Both (A) and (R) are True but (R) is not the correct
2. II and III 2.
explanation of (A).
3. I, II and III 3. (A) is True but (R) is False.
4. I and III
4. Both (A) and (R) are False.
65. A compound that can form a zwitterion is - 70. Match the reagents (List-I) with the products (List-
1. Aniline 2. Acetanilide II) obtained from phenol:
List-I List-II
3. Benzoic acid 4. Glycine
(i) NaOH
(A) (ii) CO2 (I) Benzoquinone
66. Accumulation of lactic acid (HC3H5O3 a monobasic (iii) H +
acid), in tissues leads to pain and fatigue. In a 0.10 M (i) Aqueous NaOH +
aqueous solution, lactic acid is 3.7% dissociated. The (B) CHCl3 (II) Benzene
value of the dissociation constant, Ka, for this acid, will +
(ii) H
be: (C) Zn dust, Δ (III) Salicylaldehyde
1. 1.4 × 10–5 (D) Na2Cr2O7, H2SO4 (IV) Salicylic acid
2. 1.4 × 10–4
Choose the correct answer from the options given
3. 3.7 × 10–4 below:
4. 2.8 × 10–4 (A) (B) (C) (D)
1. (III) (IV) (I) (II)
67. The incorrect statement regarding enantiomers,
2. (II) (I) (IV) (III)
among the following, is:
3. (IV) (III) (II) (I)
1. Enantiomers have an identical refractive index.
4. (IV) (II) (I) (III)
2. Enantiomers have the same chemical properties.
Enantiomers are superimposable mirror images of
3.
each other.
71. According to the law of photochemical equivalence,
4. Enantiomers have equal but opposite optical rotation. the energy absorbed (in ergs/mole) is given as:
(h = 6.62 × 10–27 ergs, c = 3 × 1010 cm s–1, NA = 6.02 ×
23 –1
68. The molecules/ions that do not contain unpaired 10 mol )
electrons among the following is:
8
1.
1.196×10
λ
1. O 2−
5
2.
2.859×10
2
2. B2 λ
16
3.
2.859×10
3. N +
2 λ
16
4. O2 4.
1.196×10
Page: 9
Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
72. The major product D formed in the following 75. Propadiene, C H molecule contains: 3 4
2. Li+
3. N a+
4. M g 2+
+ −
2H (aq) + 2e ⇌ H2 ( g) 0.000V
3+ − 2+
Fe (aq) + e ⇌ Fe (aq) 0.770V
1. Zn(s)
2. Cr(s) 1. Position isomer 2. Chain isomer
3. H (g)
2 3. Metamer 4. Ring chain isomer
4, F e (aq)
2+
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Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
1. 180 g/mol
Reason Equilibrium constant changes only with
2. 360 g/mol
(R): temperature.
3. 420 g/mol
4. 60 g/mol
In light of the above statements choose answer from the
81. A compound that does not undergo SN1 reaction options given below:
Both (A) and (R) are True and (R) is the correct
with OH- is: 1.
explanation of (A).
1. 2. Both (A) and (R) are True but (R) is not the correct
2.
explanation of (A).
3. (A) is True but (R) is False
4. Both (A) and (R) are False.
3. 4.
Page: 11
Custom Practice Test - 01-Feb
Contact Number: 9667591930 / 8527521718
87. Identify the graph that correctly depicts the variation 89. The product that cannot be formed in the following
of momentum with the de-Broglie wavelength of a reaction is:
particle.
1. 2.
1.
2.
3. 4.
3.
1. [Fe(SCN)] 2+
2. Fe [Fe(CN) ] ⋅ xH O
4 6
3
2
3. NaSCN
4. [Fe(CN) NOS]
5
4−
90. The rate law for the dimerisation of N O is:
2
d[NO2 ] 2
− = k[NO2 ]
dt
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Contact Number: 9667591930 / 8527521718
Page: 13