8/17/24, 12:23 PM TestLo
WORKSHEET
Test / Exam Name: Alternating Current Standard: 12th Science Subject: Physics
Student Name: Section: Roll No.:
Questions: 21 Time: 01:00 hh:mm Marks: 21
Q1. The values of XL, XCand R in series with an A.C. circuit are 8Ω, 6Ω and 10Ω respectively. The 1 Mark
total impedance of the circuit will be ________Ω
A 10.2 B 12.2 C 10 D 24.4
Q2. The phase difference between alternating emf and current in a purely capacitive circuit will be. 1 Mark
A zero B π C − π2 D π
2
Q3. In the AC network shown in figure, the rms current flowing through the inductor and capacitor are 0.6A and 0.8A respectively. 1 Mark
Then the current coming out of the source is.
A 1.0A B 1.4A C 0.2A D None of the above
10Ω
Q4. An inductor 60∘
is connected to a 5Ω resistance in series. Find net impedance. 1 Mark
A 15Ω B 12Ω C 13.2Ω D 18Ω
Q5. In the circuit shown in the figure, (neglecting source resistance) the voltmeter and ammeter readings will respectively be. 1 Mark
A 0 V, 8 A B 150 V, 8 A C 150 V, 3 A D 0 V, 3 A
ω
Q6. Alternating current is flowing in inductance L and resistance R. The frequency of source is 2π
Which of the following statement 1 Mark
in correct:
A For low frequency the limiting value of impedance is L. B For high frequency the limiting value of impedance is ωL..
C For high frequency the limiting value of impedance is R. D For low frequency the limiting value of impedance is ωL.
Q7. A series R-C circuit is connected to an alternating voltage source. Consider two situation: 1 Mark
(a) When capacitor is filled
(b) When capacitor is mica filled
Current through resister is i and voltage across capacitor is V then:
A V a = V b B Va < Vb C Va> Vb D ia= ib
Q8. A mixer of 100Ω resistance is connected to an A.C. source of 200V and 50 cycles/ sec. The value of average potential difference 1 Mark
across the mixer will be:
A 308 V B 264 V C 220 V D zero
Q9. An AC source is rated 220V, 50Hz. The average voltage is calculated in a time interval of 0.01s, It: 1 Mark
A Must be zero. B May be zero.
C Is never zero. D Is ( 200 )V.
√2
Q10. A series LCR circuit is tuned to resonance. If the angular frequency of the applied AC voltage at resonance is ω the impedance of 1 Mark
the circuit then is:
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1
A R + ωL + ( ωC ) B R
C √R2 + ωL + ( 1 )2 D √R2 + (ωL − 1 2
)
ωC ωC
Q11. The reading of voltmeter and ammeter in the following figure will respectively be: 1 Mark
A 0 and 2A B 2A and 0V C 2V and 2A D 0V and 0A
Q12. In an L - C - R circuit the value of XL, XCand R are 300Ω, 200Ω, and 100Ω respectively. The total impedance of the circuit will be. 1 Mark
A 600Ω B 200Ω C 141Ω D 310Ω
Q13. An inductance of 0.2 H and a resistance of 100Ω are connected in series to an A.C. 180 V, 50 Hz supply. The apparent current 1 Mark
flowing in the circuit will be.
A 0.525 A B 5.25 A C 1.525 A D 15.25 A
Q14. In an LCR circuit the capacitance is made 1th
4
then what should be the change in inductance that the circuit remains in resonance 1 Mark
again?
1
A 8 times B 2
times
C 2 times D 4 times
Q15. An alternating voltageV = 200√2 sin 100t, Where V is in volt and t is in seconds, is connected to a series combination of 1μF 1 Mark
capacitor and 10kΩ resistor through an AC ammeter. The reading of the ammeter will be_____.
A √2mA B 10√2mA
C 2mA D 20mA
Q16. In an LCR series a.c. circuit, the voltage across each of the components. L, C and R is 50 V. The voltage across the LC combination 1 Mark
will be:
A 50 V B 50√2v C 100 V D 0V (zero)
Q17. In an A.C. circuit, the current flowing in inductance is I = 5 sin ( 100−t−π ) ampers and the potential difference is 1 Mark
2
V = 200 sin(100t) volts. The power consumption is equal to.
A 1000 watt B 40 watt C 20 watt D Zero
Q18. When an AC voltage of 220V is applied to the capacitor C: 1 Mark
A The maximum voltage between plates is 220V. B The current is in phase with the applied voltage.
C The charge on the plates is in phase with the applied D Power delivered to the capacitor is zero.
voltage.
Q19. A coil of 10mH and 10Ω resistance is connected in parallel to a capacitance of 0.1μF The impedance of the. 1 Mark
A 102 Ω B 104 Ω C 106 Ω D 108 Ω
Q20. For the circuit shown in the Figure, the current through the inductor is 0.9 A while the current through the condenser is 0.4 A. 1 Mark
1
A current drawn from generator I = 1.13 A B ω=
(1.5L.C)
C I = 0.5 A D I = 0.6 A
Q21. If the values of L, C and R in a series L - C - R circuit are 100mH, 100μF and 100Ω respectively then the value of resonant 1 Mark
frequency will be.
10
A 2π
Hz B 2 × 103 Hz
3
C 2 × 10 Hz D 103 Hz
pi
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