Air Practice Sheet (2025-26) : Alternating Current
Air Practice Sheet (2025-26) : Alternating Current
Single Choice Correct Type Questions 4. An alternating voltage E = 200 2 sin (100t) is
1. The instantaneous voltages at three terminals marked connected to 1µF capacitor through an ideal ac
X, Y and Z are given by ammeter. The reading of the ammeter shall be:
Vx = V0 sin ωt
2 (1) 10 mA (2) 20 mA
Vy = V0 sin t + and (3) 40 mA (4) 80 mA
3
2 5. An alternating current source of frequency 100 Hz is
Vz = V0 sin t +
3 joined to a combination of a resistance, a capacitance
An ideal voltmeter is configured to read rms value of and a coil in series. The potential difference across
the potential difference between its terminals. It is the coil, the resistance and the capacitor is 46, 8 and
connected between point X and Y and then between Y 40 volt respectively. The electromotive force of
alternating current source in volt is:
and Z. The reading (s) of the voltmeter will be
(1) 94 (2) 14
(3) 10 (4) 76
1
rms
(1) VYZ = V0
2 6. A capacitor C is charged to potential difference V0 at
3 t = 0. If is connected to LC circuit as shown. Switch
rms
(2) VXY = V0 S is closed at t = 0. Maximum current passing through
2
inductor, is:
(3) Depends on the choice of the two terminal
rms
(4) VXY = V0
t + ( / 3)
(1) E0 sin 3L 3L
C V C
t + ( / 6)
(2) E0 sin (3) V0 (4) 0
2L 2 L
(3) 3E0 sin ( t + ( / 3))
7. For the circuit shown in figure, current (I) through the
(4) t + ( / 2)
3E0 sin circuit is 5 sin (ωt + ϕ) A. At a particular instant
potential difference across capacitor is 24 V. Then the
3. When 100V DC is applied across a solenoid, a current potential difference across resistance at that instant, is
of 1 A flows in it. When 100V AC is applied across
the same coil, the current drops to 0.5A. If the
frequency of the AC source is 50 Hz, the impedance
and inductance of solenoids are:
(1) 100 Ω, 0.93 H (2) 200 Ω, 1.0 H
(1) 18V (2) 24 V
(3) 10 Ω, 0.86 H (4) 200Ω, 0.55 H
(3) 40 V (4) 30 V
2
D S
7
58. When sine waves propagate in an infinite LC-grid 61. In the circuit shown in the figure, the sinusoidal input
(see the figure below) the phase of the AC voltage voltage has a fixed amplitude V0 and frequency f.
across two successive capacitors differs by ϕ. What is the maximal amplitude of the output voltage,
(a) Determine how ϕ depends on ω, L and C (ω is and for which values of the variable resistances R1,
the angular frequency of the sine wave). R2, and R3 is the maximal amplitude achieved?
(b) Determine the velocity of propagation of the
waves if the length of each unit is l.
(c) State under what conditions the propagation
velocity of the waves is almost independent of
ω. Determine the velocity in this case.
(d) Suggest a simple mechanical model which is an
analogue to the above circuit and derive JEE Mains Previous Year Questions
equations which establish the validity of your 62. If R,XL , and X C represent resistance, inductive
model. reactance and capacitive reactance. Then which of the
following is dimensionless: [2023]
R
(A) (B) RXL XC
X L XC
59. A circuit consists of two identical inductances, two XL R
(C) R (D)
identical capacitors, and one resistor, see figure. The XC X L XC
applied voltage is U0 = 10V, and the total current at
the input leads is I0 = 1A; the voltage measured at the 63. An alternating voltage source V = 260sin(628t) is
left capacitor is 10V, and 10V is also measured at the connected across a pure inductor of 5mH . Inductive
left inductance. What is the active power dissipated
reactance in the circuit is :
in this circuit and what is the resistance of the
[2023]
resistor?
(A) 6.28 (B) 3.14
(C) 0.318 (D) 0.5
65. In the given circuit, rms value of current (Irms) through 69. Given below are two statements:
the resistor R is: Statement-I: The reactance of an ac circuit is zero. It
is possible that the circuit contains a capacitor and an
inductor.
Statement-II: In ac circuit, the average power
delivered by the source never becomes zero.
In the light of the above statements, choose the
[2023] correct answer from the options given below:
(A) 2 A (B) 20 A [2022]
(A) Both Statement I and Statement II are true.
1
(C) A (D) 2 2 A (B) Both Statement I and Statement II are false.
2
(C) Statement I is true but Statement II in false.
(D) Statement I is false but Statement II is true.
66. In an LC oscillator, if values of inductance and
capacitance become twice and eight times, 70. A resistance of 40 Ω is connected to a source of
respectively, then the resonant frequency of oscillator alternating current rated 220 V, 50 Hz. Find the time
becomes x times its initial resonant frequency 0 . taken by the current to change from its maximum
The value of x is: [2023] value to rms value : [2022]
(A) 4 (B) 16 (A) 2.5 ms (B) 1.25 ms
(C) 1 / 4 (D) 1/16 (C) 2.5 s (D) 0.25 s
74. The current flowing through an ac circuit is given by 78. The rms value of conduction current in a parallel
I = 5sin (120πt ) A plate capacitor is 6.9 μA. The capacity of this
capacitor, if it is connected to 230 V ac supply with
How long will the current take to reach the peak value
an angular frequency of 600 rad/s, will be:
starting from zero? [2022]
[2022]
1
(A) s (B) 60s (A) 5 pF (B) 50 pF
60 (C) 100 pF (D) 200 pF
1 1
(C) S (D) S
120 240 79. In a series LR circuit XL = R and power factor of the
circuit is P1. When capacitor with capacitance C such
75. For a series LCR circuit, I vs ω curve is shown:
that XL = XC is put in series, the power factor
(a) To the left of ωr, the circuit is mainly capacitive.
(b) To the left of ωr, the circuit is mainly inductive. P1
becomes P2. The ratio is: [2022]
(c) At ωr, impedance of the circuit is equal to the P2
resistance of the circuit. 1 1
(A) (B)
(d) At ωr, impedance of the circuit is 0. 2 2
3
(C) (D) 2 : 1
2
B I 0, V2 > Q
V1
106. A series R-C combination is connected to an AC
voltage of angular frequency ω = 500 radian/s. If the
impedance of the R-C circuit is R 1.25, the time
C V1 = 0, V2 = R constant (in millisecond) of the circuit is
V [IIT JEE- 2011]
107. In the given circuit, the AC source have w = 100 rad/s.
Considering the inductor and capacitor to be ideal,
the correct choice (s) is (are)
D I 0, V2 is S
proportion
al to I
Paragraph
104. A series R-C circuit is connected to AC voltage A thermal power plant produces electric power of 600 kW
and 4000 V, which is to be transported to a place 20 km
source. Consider two cases ; (A) when C is without a
away from the power plant for consumers' usage. It can be
dielectric medium and (B) when C is filled with
transported either directly with a cable of large current
dielectric of constant 4. The current IR through the
carrying capacity or by using a combination of step-up and
resistor and voltage VC across the capacitor are
step-down transformers at the two ends. The drawback of
compared in the two cases. Which of the following the direct transmission is the large energy dissipation. In the
is/are true? [IIT JEE-2011] method using transformers, the dissipation is much smaller.
16
In this method, a step-up transformer is used at the plant side (3) Immediately after A is connected to D, the
so that the current is reduced to a smaller value. At the current in R is 10 A.
consumers' end, a step-down transformer is used to supply (4) Q = 2 × 10−3C
power to the consumers at the specified lower voltage. It is
reasonable to assume that the power cable is purely resistive 111. In the circuit shown L = 1µH, C = 1µF and R = 1 kΩ.
and the transformers are ideal with a power factor unity. All They are connected in series with an A.C. source V =
the currents and voltages mentioned are rms values. V0 sin ωt as shown. Which of the following options
[IIT JEE -2013] is /are correct [IIT JEE 2017 (P-1)]
110. At time t = 0, terminal A in the circuit shown in the 112. The instantaneous voltages at three terminals marked
figure is connected to B by a key and an alternating X, Y and Z are given by [IIT JEE 2017 (P-2)]
current I (t) = I0 cos (ωt), with I0 = 1A and ω = 500 Vx = V0 sin t,
rad/s starts flowing in it with the initial direction 2
VY = V0 sin t + and
7 3
shown in the figure. At t = , the key is switched
6 4
VZ = V0 sin t +
from B to D. Now onwards only A and D are 3
connected. A total charge Q flows from the battery to An ideal voltmeter is configured to read rms value of
charge the capacitor fully. If C = 20µF, R = 10Ω and the potential difference between terminals. It is
the battery is ideal with emf of 50V, identify the connected between points X and Y and then between
correct statement(s): [IIT JEE- 2014] Y and Z. The reading(s) of the voltmeter will be
3
(1) VXYrms
= V0
2
1
(2) VXZrms
= V0
2
rms
(3) VXZ = V0
(1) Magnitude of the maximum charge on the (4) Independent of the choice of the terminals
7
capacitor before t = is 1 × 10−3C
6
(2) The current in the left part of the circuit just
7
before t = is clockwise.
6
17
ANSWER KEY
1. (3) 3
2. (1) 42. ( )
5
3. (3)
V0
3R,VAX = 3 ( 0) , VYX = 30 ( −120)VZX = 30 (120)
43. V V
4. (3)
5. (2)
6. (1) 44. (90°)
7. (2) 45. (5)
8. (1) 1 R 2
46. f = 1 −
9. (2) 2 LC L2
10. (2)
11. (2) 1 1
47. ( i = V0 sin t + C − cos t )
12. (4) R L
13. (1, 3, 4) 2
L
14. (1, 3, 4) 1 +
15. (1, 4) 48. (a) R
2
L 1
16. (2, 4) 1 + −
17. (1, 2) R RC
18. (1, 3, 4) (b) 1
19. (1, 2, 4) (c) ωRC
20 (1, 2)
R
21. (2, 3, 4) 49. ( f = )
22. (1, 3) 2L
23. (2, 3, 4) 50. (a) S1
(b) L = 100 mH, C = 100 µF
24. (8)
25. (2)
26. (9)
27. (2)
28. (6) 51. (a)
29. (4)
30. (72)
31. (3)
32. (3)
33. (1)
34. (1)
35. (2)
36. (4)
37. (A(p, r), B(p, q, r), C(p, q, r), D(p, q, r)) (b)
38. (A(p, q), B(r, s), C(r, s), D(p, q))
39. (A(S), B(R), C(P), D(Q))
40. (1)
(c)
R LCV 2
41. (E = )
L
R + 2.25
2
C
18
LC I +I 76. (2)
52. ( ( I1 +I 2 ) and 1 2 ) 77. (3)
7 7
78. (2)
53. ( 2 )
79. (2)
1 80. (3)
54. ( V0 )
3 81. (3)
55. ( )
( V 1 + 3 sin t ) 82. (4)
83. (4)
1 1 1
56. ( 1 = , 2 = , 3 = ) 84. (3)
LC 4 4 85. (25)
LC LC
3 7 86. (18)
C 1 LL 87. (8)
57. (R ; with L = 1 2 and C = C1 + C2; 88. (1)
L LC L1 + L2
89. (40)
0.1 A; 0.2A)
1 l 90. (3872)
58. ( = 2arcsin LC ; ; 1 when
2 91. (242)
l 92. (242)
v0 = ; infinite chain of masses
LC 93. (22)
connected by springs) 94. (400)
59. (10W, 30Ω) 95. (0)
2 5 1 96. (975)
60. ( 0; ; )
L2C2 2 L1C1 97. (15)
98. (100)
61. (V0; R1 = R2 = 0, R3 = L/Cr.)
99. (0)
62. (4)
100. (5)
63. (2)
64. (1) 101. (44)
65. (1) 102. (10)
66. (3) 103. (2)
67. (1) 104. (2)
68. (2) 105. (3)
69. (3) 106. (1)
70. (1) 107. (1)
108. (2)
71. (2) 109. (3)
72. (1) 110. (1)
73. (4) 111. (BONUS) at no option is correct, phase diff
74. (4) 150°
112. (4)
75. (3)
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