Table C
Table C
( A.3)
NOIe thm the Erlang C equation gives the probability of queue. PQo that an arriving caU
finds a busy system and has 10 wail. (I · Po is the probabi lity that call requests are being
serviced). The equatio n does not say how long the wait time is and for this another
equation is employed. The probability that a qllelled call waits for more than I is given by
(A.4)
where A. C and T are as defined for Erlang B fo rmula. On the o ther hand, the probability
that all cal/s, including those serviced immediately. are delayed for more than I is given
by PQ- PU" The unde rlying assumptions of traffic source behaviour for Erlang B also apply
to Erlang C. with some additional poi nts 3 5 noted be low.
• The queue size is assumed to be sufficiently large (ideally infinite) and queued calls
are served o n first-come first-served basis.
• Erlang C function makes sense only if p < I (or A < C) otherwise the queue would
overflow as the system cannot cope with the call requests.
£r:ample: An 8-channe l trunked TETRA system operates under a call queuing strategy
with up to 5% of call connections delayed. Determine the additional number of channe ls
required for lowering the de layed calls to I % o r less. What percent of the delayed calls
waits beyond the mean call holding time T. before and after increasing the channel?
Soll/tio,,: Given C = 8 and Po = 0 .05 (5%). from the Erlang C table on the next page, the
offered traffic can be found to be A = 3.87 . If Po has to be reduced to 0.01 ( 1%). for
approximately the same offered traffic the number of channels can be found to be 10. This
corresponds to the nearest safe value of A = 4.08 from the table. Hence two additionaJ
channels would be required. The probability of queued calls waiting for more than Ti s
given by equation A.4. Since the waiting time is equal to the mean call holding time T.
equation A.4 reduces to ~K""'j giving. Pw = 0.016 for C = 8, and Pw = 0.0022 for C = 10.
Hence. with 8 channels 1.6% of the queued calls wait for more than the mean call holding
ti me. As expected. this figu re is reduced to 0.22% after the channel is increased to 10.
Ap~tld jces 425
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9
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