CH 1 Biology
CH 1 Biology
AS PER
NEP MultipleChoice Questions
Plants 25
Sexual Reproduction in Flowering
9. Autogamy can occur in a chasmogamous flower if
[NCERT Exemplar|
(a) pollen matures before maturity of ovule.
(b) ovules mature before maturity of pollen.
() both pollen and ovules mature simultaneously.
(d) both anther and stigma ae of equal lengths.
lobes, theca and sporangia. The theca are
10. An anther is nade up of the following major parts:
cavities in which the sporangia develop.
develop into a tetrasporangiate anther?
Which of the following types of anther structure can |CBSE Question Bank|
(b) monothecous
(a) filamentous
(d) unlobed
(c) dithecous
following. [NCERT Exemplar
11. Choose the correct statement from the
autogamy.
(a) Cleistogamous flowers always exhibit
() Chasmogamous flowers always exhibit geitonogamy.
geitonogamy.
(c) Cleistogamous flowers exhibit both autogamy and
(d) Chasmogamous flowers never exhibit autogamy.
12. Which of the following structures are haploid in nature?
(a) Nucellus and antipodals (b) Microspore and antipodals
(c) Egg cell and antipodals (d) Egg and central cell
13. In a fertilized ovule, n, 2n and 3n conditions occur respectively in
[CBSE Sample Question Paper 2022, Term-I]
(a) antipodal, zygote and endosperm (b) zygote, nucellus and endosperm
(c) endosperm, nucellus and zygote. (d) antipodals, synergids and integuments
[CBSE 2020 (57/1/)]
14. Self-pollination is fully ensured if
(a) the flower is bisexual (b) the style is longer than the filament
(c) the flower is cleistogarmous (d) the time of pistil and anther maturity is different
pollen in large numbers and its stigmas
15. Aparticular species of plantproduces light, non-stickypollination by [NCERT Exemplar
are long and feathery. These modifications facilitate
(a) insects (b) water
() (i)
(i) (ii).
SEED X
SEED Y
(i) SeedX is dicot and
(ii) Seed X is dicot and endospermic or albuminous.
(ii) Seed is monocot and non-endospermic non-albuminous.
or
(iv) Seed Y is monocot and endospermic albuminous.
or
non-endospermic non-albuminous.
Choose the correct option with respect to the
or
(a) (i), (i) nature of the seed.
(b) (i), (üi) (c) (), (v)
32. A botanist studying Viola (d) (ü), (iv)
(common
and developed no further due to some pansy) noticed that one of the two flower types wither
unfavorable
the same plant survived and it resulted in an condition, but the other flower type
correct?
assured seed set. Which of the following will b
(a) The flower type which survived is
(b) The flower type which survived is cleistogamous
and it always exhibits autogamy.
chasmogamous and it alwaysexhibits geitonogamy.
28 Xam idea Biology-XIl
c) The flower type which survived is cleistogamous and it exhibits both autogamy and
geitonogamy.
(d) The flower type which survived is chas1mogamous and it never exhibits autooamy
33. To produce 400 seeds, the number of meiotic divisions required will be
(b) 200 (c) 500 (d) 800
(a) 400
34. Select the plant species, where emasculation is not required for artificial hybridisation
experiment?
(a) Castor (6) Lily (c) Papaya (d) Wheat
35. Which of the given statements are correct with respect to pollination in Vallisneria?
(i) Pollen grains are light and non-sticky.
(ii) Female flowers reach the surface of water by long stalks.
(iü) Pollen grainsare carried passively by water currents.
(iv) Female flowers remain submerged in water.
Choose the correct option:
(a) (i) and (v) (b) (i) and (iv)
(c) ()and () (d) (ii) and (ü)
Answers
1. (d) 2. (a) 3. (d) 4. (b) 5. (b) 6. (a) 7. (b) 8. (c) 9. (c) 10. (c)
11. (a) 12. (c) 13. (a) 14. (c) 15. (c) 16. (b) 17.(a) 18. (b) 19. (a) 20. (c)
21. (d) 22. (c) 23. (c) 24. (b) 25. (b) 26. (c) 27. (b) 28. (d) 29. (b) 30. (a)
31. (b) 32. (a) 33.(c) 34. (c) 35. (d)
CUSED
SONS
AS PER
In the following questions astatement of assertion followed by a statement of reason is given. Choose
the correct answer out of the following choices.
(a) Assertion and reason both are correct statements and reason is correct explanation for assertion.
(b) Assertion and reason both are correct statenents but reason is not correct explanation for assertion.
(c) Assertionis correct statement but reason is wrong statement.
(d) Assertion is uurong statement but reason is correct statement.
1. Assertion : The endosperm of angiosperms is generally triploid (3n).
Reason It develops from primary endosperm nucleus formed by fusion of haploid male
gamete and diploid secondary nucleus.
2. Assertion : Dichogamy refers to maturation of male and female sex organs at different times.
Reason This is a safeguard against cross fertilisation.
3. Assertion :
Megaspore mother cell undergoes meiosis to produce four megaspores.
Reason Megaspore mother celland megaspores are both haploid.
4. Assertion : Entomophilous plants produce less pollen when compared to anemophilous plants.
Reason The wastage of pollen is reduced to the minimum in entomophilousplants because
of the directional pollination.
5. Assertion :
A structure of a typical microsporangium in angiosperms consists of four wall
layers-epidermis, endothecium, middlelayers and tapetunm.
Reason Thefunction of outer three wall layers is protectionand also help in dehiscence of
anther to release pollen.
-Degenerating
antipodal cells
o 29. Namethe common function that cotyledons and nucellus perform. [NCERT Exemplar]
Ans. Cotyledons and nucellus provide nourishment.
20 Which are the three cells found in a pollen grain when it is shed at the three-celled stage?
[NCERT Exemplar]
Ans. One vegetative cell and two male gametes.
0.3 What features of flowers facilitate pollination by birds?
Ans. Presence of a large quantity of nectar, bright colours of petal, fragrance and large flowers attract
birds from long distances.
0.32,Näme the type of pollination in self-incompatible plants. [NCERT Exemplar]
Ans. Xenogamy.
o.35. Mention any two characteristics of pollen grains of plants such as maize and Cannabis.
Ans. () Pollen grains are small, dry and light in weight, non-sticky.
() Pollen are produced in large numbers.
Q.34. Define parthenocarpy.
Ans. Parthenocarpy is an economically important process in which seedless fruit is formed without
fertilisation, for example, banana.
0.35. In a case of polyembryony, if an embryo develops from the synergid and another from the
nucellus, which is haploid and which is diploid? [NCERT Exemplarl
Ans. Synergid embryo is haploid and nucellar embryo is diploid.
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[Topper's Answer2
Q. 6. Gynoecium of a flower may be apocarpous or syncarpous. Explain with the help of an exa
each.
[CBSE (AI))
Ans. The gynoecium represents the female reproductive part of the flower. When there are more
one pistil,if the pistils are fused together, the flower is said to be syncarpous and if the pisti
free, it is said to be apocarpous. For example, pistil of Papaver is syncarpous and that ot Ma
is apocarpous.
Q.7. Name all the haploid cells present in an unfertilised mature embryo sac of a flowering p
Write the total number of cells in it. [CBSE (A)2
Ans. The haploid cells in an unfertilised mature embryo sac are: egg cell,
synergids, antipodas
central cell. There are seven cells in total.
Q. 8. Draw a diagram of pollen grain with germ tube and two male gametes.
Ans.
Exine Intine
Male
gametes
Tube
nucleus
Pollen tube
o9. Why does the zygote begin to divide only after the division of primaryendosperm cell?
INCERT Exemplar]
The zvgote needs nourishment during its development. As the mature, fertilised embrvo sac
Ans.
and
offers very little nourishment to the zygote, the primary endosperm cell (PEC) divides
zygote. Hence, the zygote always divides
generates the endosperm tissue which nourishes the
after divisionof PEC.
entry into the embrvO
o10. (a) From which end of theovule, and how does the pollen tube gain its
sacof a Hibiscus flower?
pollen tube. [CBSE 2023 (57/1/1)]
(b) State the fate of the male nuclei present in the
the region of the
Ans. (a) The pollen tube enters the embryo sac between the two synergids through
filiform apparatus at the micropylar end of the ovule.
cell called zygote and
(b) One of the male gamete fuses with egg nucleus to form adiploid
the other male gamete fuses with polar nuclei at the centre to produce a triploid primary
endosperm nucleus.
0. 11. Which is the triploid tissue in a fertilised
ovule? How is the triploid condition achieved?
[NCERT Exemplar]
triploid condition is achieved by the fusion
Ans. The triploid tissue in the ovule isthe endosperm. Its triple fusion.
referred to as
of two polar nuclei and one nucleus of male gamete,
function.
0. 12. Fill in the following labels with the type of cell
B D
A
(b)
Syncarpous pistil Apocarpous pistil
1. The condition where allthe pistils are fused or 1.The condition where the pistils are free.
combined.
2. For example, tomato and cucumber. 2. For example, lotus.
(c)
Plumule Radicle
1. It is the part of the embryo that gives rise to 1.It is the part of the embryo that gives rises to
the shoot. the root.
2. It growsafter the radicle. 2. It grows before the plumule.
0.9. Draw a longitudinal section of the pistil from a flowering plant, where pollination has
occurred. Label the following:
(a) Stigma showing germinating pollen grains
(b) Style
(c) Pollen tube reaching the micropyle of the ovule
(d) Embryo sac
(e) Components of the egg apparatus [CBSE 2020 (57/2/1)]
Ans.
-Stigma /(a)
Style /(b)
Pollen tube (c)
-Embryo sac /(d)
o16. (a) Write the characteristic features of anther, pollen and stigma of wind-pollinated flowers.
(b) How do flowers reward their insect pollinators? Explain. [CBSE (A) 2010, 2012]
Ans. (a) The characteristics of wind-pollinated flowers are:
(i) Pollen grains are light in weight, non-sticky, dry and winged, so that they can be easily
transported.
(ii) Well-exposed stamens for easy dispersal of pollen grains in the wind.
(iüi) The stigma is sticky, large, feathery to trap pollen grains in air.
(io) Numerous flower are packed together to form inflorescence.
(0) The flowers are small and inconspicuous.
(b) Insect pollinators are rewarded in following ways:
() The flowers offer floral reward like nectar and pollen grain.
(ii) In some species floral reward provides safe place to lay eggs.
Q.17. (a) Mention any four strategies adopted by flowering plants to prevent self-pollination.
(b) Why is geitonogamy also referred to as genetical autogamy? [CBSE (AI) 2010]
Ans. (a) Refer to Points to remember 5[Contrivances for cross-pollination (Xenogamy/Allogamy)].
(b) Geitonogamy is the transfer of pollen grains from the anther to the stigma of another flower
of the same plant. Although geitonogamy is functionally cross-pollination involving a
pollinating agent, genetically it is similar to autogamy, since the pollen grains come from the
same plant.
Q. 18. State the signifcance of pollination. List any four differences between wind-pollinated and
animal pollinated fowers.
Ans. Pollination is the phenomena of transfer of pollen grains from anthers to the stigma of a pistil.
Pollination is prerequisite for the beginning of fertilisation.
Table 1.12: Differences between wind-pollinated and animal-pollinated flowers
S. No. Wind-pollinated lowers Animal-pollinated flowers
() This kind of flower is pollinated by abiotic This kind of flower is pollinated by biotic
pollinating agent. pollinating agent.
(ii) They are small and inconspicuous. They are large, colourful, fragrant and rich in nectar.
(111) The pollen grains are dry, light and non-sticky| The pollen gains are generally sticky in animal
so that they can be easily transported by wind. pollinated flowers.
(iv) The flowers are often clustered so as to carry Flowers reward pollinators in terms of pollen,
out pollination. nectar or safe place to lay eggs.
Q. 19, (a) How does cleistogamy ensure
autogamy?
(6) State one advantage and one disadvantage of cleistogamy to the plant.
[CBSE (A) 2012; Delhi 2013]
Sexual Reproduction in Flowering Plants 45
to land on
Ans. (a) Cleistogamous flowers do not open. Therefore, the pollens have the
same flower. This ensures autogamy.
(b) Advantage: Self-pollination is assured, thus ensuring seed formation.
stigma of
Disadvantage: Least variations observed and it leads to inbreeding depression
Q. 20. (a) Describe the endosperm development in coconut.
(b) Why is tender coconut considered a healthy source of nutrition?
(c) How are pea seeds different from castor seeds with respectto endosperm?
Ans. (a) The primary endospermnucleus(PEN) undergoes successive nuclear divisions 2|CBSE (
(AI) 201
to give
free nuclei. Subsequently, cell wallis formed towards the periphery and rise
cellular, leaving free nuclear endosperm in the central part. This division is endosperm becom
cytokinesis and thus endosperm becomes cellular and is called cellular endosperm
(b) It is rich in many nutrients like fats, proteins, carbohydrates, minerals, vitamins u
fol owed
tender coconut is considered a healthy source of nutrition.
(©) In peas,the endosperm is used up and there is no endosperm present in the mature seed:
castor, the endosperm remains intact in the mature seed.
Q.21. Differentiate between perisperm and endosperm by giving one example of each.
Ans.
Table 1.13: Differences between perisperm and endosperm
[CBSE (AI) 2011
S. No.
Perisperm Endosperm
(i) It is persistent nucellus. It is the nutritive tissue for embryo.
(1) It is diploid. It is triploid.
(ii) Example: black pepper, beet. Example: maize, rice, wheat, castor.
Q. 22. Explain any three advantages the seeds offer to angiosperms. [CBSE 2020, Dellhi 2014
Ans. () Since reproductive process such as pollination and fertilisation are
seed formation is more dependable.
independent of wak
(ii) Seeds have better adaptive strategies for dispersal to new
colonise in other areas.
habitats and help the species
(iii) As they have sufficient food reserves young seedlings are
nourished until they are capable
photosynthesis on their own.
(iv) The hard seed coat provides protection to the young embryo.
(v) Being products of sexual reproduction, they generate new genetic
variations.
combinations
(Any thra
O. 23. State what is apomixis. Comment on its significance. How can it be
commercially used?
[CBSE (AI) 2015; 2019 (57A!
Ans. It is a special mechanism of asexual reproduction that mimics sexual
reproduction (to produ
seeds without fertilization), there is no segregation of characters in the
progeny, farmers d
develop apomicts of hybrids and use them year after year to cut the cost.
[CBSE Marking Scheme 2019 (5714
o. 24. (a) How does a farmer use the dormancy of seeds to his
advantage?
(b) What advantages a seed provides to a plant? [CBSE (AI) 201
Ans. (a) Dormancy of mature seeds are important for storage of seeds which can be used as o
throughout the year and also to raise crop in the next season.
(b) Seeds offer several advantages to angiosperms. Firstly, since
reproductive processes s
pollination and fertilisation are independent of water, seed formation is more dependa
Alsoseeds have better adaptive strategies for dispersal to new habitats and help the spec
colonise in other areas. As they have sufficient food reserves, young seedlings are nourishe
026. Fora layman, both apple and banana are fruits. But a biology student categorises fruits as true
fruits, false fruits and parthenocarpic fruits. Justify. [CBSE 2020 (57/1/2)]
Ans. True Fruits: Fruits that develop from mature ovary and are a result of fertilisation. 1
False Fruits: Fruits that develops from ovary along with some other floral parts / thalamus. 1
polinatin e Coveede th
to
iology-XI
idea
Xam Q. Ans.
29. Q.
28.
(c) (6) Answer (a) A (e) (a) (c)
flower (b) (a) (c) (d) (c) (h) (a) Gire ()
Howpollination
What What aregermination.
Inrequired for persists
Toprotect uring The
formation. Toapplematures.
integuments mostreasons globular,
Refer
notapple Micropyle groundout
micropyle The
many would the
is tomato of true groundnut obtain and to 7\2ote
following
the and the embryo
and zxgotes
megaspore have of fruits. remain nutrition
cashew why: Iig. heart
minimum
its plant cashew,
embryo used
is remains
of seeds in 1.13 (in
beenpistil?questions
development. seeds shaped the
from are ovuleangiosperms
as an are (b ).
following apart and a up as embiyo
mother the number small
during are not exalbuminous
keep thecalled small a and
minimum from exalbuminous
pore harden mnat ure sa)
cells
giving
the the Whereas,
seed endosperm pore divide
ofprocess ovary, seed in true divdes
were pollenreasons: germinatiorn. the and inand cmbryo
number viable, fruits. the only
thalamus seed castor the
involved? because for castor after
grains sexual
of
until coat the
seed as
seeds water
of
favourable of developing coatseedscertain shown
ovules also
that
reproduction a are the content
contributes seed
endosperm ofa are in
present must albuminous seed. amount the
conditions for
embryo, albuminous.
is diagram.
have th e highly
in entry of
produce to is [CBSE
the been fruitretun because
completely zygotes, endosperm
ovary? of reduced,
water (AI)
involved 240 formation
for the divide 2011]
viable germira is
and endos Cons as
the
for.
(d) What is the minimum number of microspore mother cells involved in the above case?
(e) How many male gametes were involved in this case? |CBSE Delhi 2015) [HOTS]
Ans. (a) 240 pollen grains. One pollen grainparticipates in fertilisation ofone ovule.
(b) 240 ovules. One ovule after fertilisation forms one seed.
240 MMC were involved. Each MMC forms four megaspores out of which only one remains
functional.
( 60 MMCs (240/4 =60). Each microspore mother cell meiotically divides to form four pollen
grains.
i A80 male gametes (240 x 2 = 480). Each pollen grain carries two male gametes (which
participate in double fertilisation).
o30. Aflower of brinjal plant following the process of sexual reproduction produces 360 viable seeds.
Answer the following questions giving reasons:
(a) How many ovules are minimally involved?
(b) How many megaspore mother cells are involved?
(c) What is the minimum number of pollen grains that must land on stigma for pollination?
(d) How many male gametes are involved in the above case?
(e) How many microspore mother cells must have undergone reduction division prior to
dehiscence of anther in the above case? [CBSE Delhi 2015] [HOTS]
Ans. (a) 360 ovules are involved. One ovule after fertilisation forms one seed.
(b) 360 MMCare involved. Each MMC forms four megaspores out of which only one remains
functional.
(c) 360 pollen grains. One pollen grains participates in fertilisation of one ovule.
(d) 720 male gametes are involved. Each pollen grain carries two male gametes (which participate
indouble fertilisation) (360 x 2 =720).
(e) 90 MMC undergo reduction division. Each microspore mother cell meiotically divides to
form four pollen grains. (360/4 = 90).
Q. 31. (a) Acapsicum flower has 240 ovules in its ovary. But, it produces a fruit with only 180 viable seeds.
Explain giving a reason that could be responsible for such a result.
(b) Describe the development of an endosperm in a viable seed. Why does endosperm
development precede embryo development?
(c) Givean example of an angiosperm seed that has a perisperm. Name the part the perisperm
[CBSE Delhi 2017]
develops from.
Ans. (a) (i) 240 ovules giving rise to only 180 viable seeds, can be possible only if less number of
pollen grains or male gametes were available.
() Allpollen grains did not germinate or did not form pollen tubes.
(ii) Many pollen were not compatible.
(6) For the development of an Endosperm, Refer to Points to remenmber 9.
Cells of endosperm are filled with reserve food materials that are used for nutrition of
developing embryo. Thus endosperm needs to develop before embryo.
(c) Black pepper and beet have a perisperm. The perisperm develop from the nucellus.
Q.32. (a) Seeds offer several advantages to angiosperms. Describe any three such advantages.
(6) Why is banana called a parthenocarpic fruit? Would you call banana a true fruit? Give
reason in support of your answer.
Ans. (a) Following are their advantages:
() Better adaptive strategies for dispersal to new habitats.
(i) Hard seed coat provides protection to young embryo
(i) Sexual reproduction--newgenetic combinations.
Sexual Reproduction in Flowering Plants 55
(iv) Sufficient food reserves for the seedling.
() Basis of agriculture storage of seeds can occur due to seed dormancy
(6) Banana fruit develops without fertilisation therefore, it is called
Yes, it is a true fruit because it develops from ovary.
parthenocarpic
Questions for Practice
1. Choose and write the correct
option in the following questions.
(i) Filiform apparatus performs the
functions of
(a) opening the pollen tube.
(b) guiding the pollen tube to egg.
(c) entry of pollen tube into
synergids.
(d) prevents growth of more than
one pollen tube.
(i) Which of the following is true
for typical bilobed anther?
(a) 2 theca, 2
(c) 4 theca, 2
sporangia (b) 4theca, 4
sporangia
(iii) The sporangia (d) 2 theca, 4
sporangia
outermost and innermost wall layers of
respectively
(a)
microsporangium in an anthe
endothecium and tapetum
(c) epidermis and (b) epidermis and
endodermis
INCERT Exem
middle layer(d) epidermis and
(iv) Agroup of tapetum
compactly arranged homogenous mass
mierosporangium in an anther is: of cellsoccupying the centre of at
(a) Sporogenoustissue [CBSE 2022 (57/3/4), Ter
(b) Pollen sacs
(c) Micorspore tetrads
(u) Seeds of an (d) Spores
orange when taken out and
and shapes. The reason for this is as manysqueezed, show many embroys of different
embroys have developed from:
(a) Egg cells [CBSE 2022
fusing with different male
(b) PEN fusing with gametes forming embroys. (57/3/4), Ter
(c) Nucellarcells different male gametes forming embroys.
(d) Synergids dividing and developing into embroys.
(vi) Figure (i) anddividing anddeveloping intoembroys.
Figure (ii)
typical angiosperm plant. given below are showing two stages of
megasporogenesls
[CBSE 2022 (57/3/4), Tem
(Y) (X)
(Z)
Fig. ()
Fig.(i)
56 Xam idea Biology-XIl