MBA Wallah

Batch: PIONEER (CAT)

Subject : Data Interpretation
DPP – 02
Topic : Pie - Chart

Direction : Raghav has 4 income sources- salary, Direction : Raghav has 4 expense points-
freelancing, stocks & other sources. The split is given as Groceries, Child Education, Rent & EMI. The split
below. The ratio of income from Salary & Stocks is 8 : 5. is given as below. The ratio of expenses from
Groceries & Rent is 3 : 2.

1. If his total income is 1 Lakh INR, then what is his

6. If the total expenditure is 60,000 INR then find the
earning from stocks?
rent he paid?
(a) 20,000 INR
(a) 10,000 INR
(b) 25,000 INR
(b) 15,000 INR
(c) 30,000 INR
(c) 18,000 INR
(d) 40,000 INR
(d) 12,000 INR
2. If his total income is 1 Lakh INR, then what is his
7. If the expenditure in EMI is 10,000 INR, then how
earning from Salary & Freelancing combined?
(a) 40,000 INR (b) 75,000 INR much does he spend on Groceries?
(c) 50,000 INR (d) 60,000 INR (a) 10,000 INR (b) 12,000 INR
(c) 15,000 INR (d) 18,000 INR
3. If it is known that the difference between earning
from stocks and other sources is 20,000 INR, then 8. If the condition in the above question is to be true,
what is the total amount earned by him? then what is the expenditure in rent?
(a) 100,000 INR (b) 160,000 INR
(a) 8,000 INR (b) 10,000 INR
(c) 120,000 INR (d) 200,000 INR
(c) 12,000 INR (d) 15,000 INR
4. If it is known that the difference between earning
from stocks and other sources is 20,000 INR, what 9. If in one month, the combined expenditure from
is the difference between earning from Salary & EMI & Rent is 45,000, then what is the groceries
Stocks? expenditure in that month (in INR)?
(a) 20,000 INR (b) 25,000 INR (a) 30,000 (b) 60,000
(c) 30,000 INR (d) 40,000 INR
(c) 45,000 (d) 48,000
5. If it is known that the difference between earning
from stocks and other sources is 20,000 INR, then 10. If Raghav paid 15,000 INR for groceries, then what
from which source of income Raghav earns least is the least expenditure he had out of the 4
income. expenditure sources (in INR)?
(a) 30,000 INR (b) 20,000 INR (a) 10,000 (b) 12,000
(c) 40,000 INR (d) 50,000 INR
(c) 8,000 (d) 6,000
 MBA Wallah

Directions: Study the information given below and Direction : Sahev appeared in a test where there are
then answer the question. 4 sections- Quant, DI, LR, Verbal. Each section has
The profit of a company XYZ across 4 quarters are equal full marks. The chart below shows the marks
as shown in the pie chart below. It is also known scored by Sahev in a section as a percentage of his
that the ratio of the Q1 and Q3 profits are in the ratio total score across the 4 subjects. It is known that the
of 3 : 2.
score in QA : LR is 5 : 4.

16. If Sahev scores 48% of the full marks in the LR

11. If the profit in Q1 is 108Cr, what is the profit in Q4
section, then find what is the % of the full marks
(in Cr)?
was scored by him in the DI section?
(a) 120 (b) 100
(c) 108 (d) 132 (a) 40% (b) 50%
(c) 36% (d) 45%
12. If the profit in Q1 is 108Cr, What is the difference
between the profit in Q2 & Q3? 17. If the conditions of the above question are to be
(a) 4 Cr (b) 28 Cr true, what is Sahev’s total score as a % of Total full
(c) 12 Cr (d) 20 Cr marks?
(a) 48% (b) 60%
13. What is the average profit across all the quarters if (c) 50% (d) 75%
it is given that the profit earned in Q1 is 27 Cr?
(a) 22 Cr 18. If the condition of question 1 is to be true, what is
(b) 30 Cr Sahev’s total score in the Verbal section given that
(c) 25 Cr the exam has a total full marks of 600?
(d) 35 Cr (a) 60 (b) 61
(c) 62 (d) 63
14. If the difference between the profits of Q1 & Q2 is
19. If Sahev scored full marks in one of the sections,
10 Cr, then what is the least profit generated by the
then what is his total approximate score as a % of
company across the 4 quarters?
full marks?
(a) 80 Cr (b) 90 Cr
(a) 80% (b) 75%
(c) 100 Cr (d) 120 Cr
(c) 83% (d) 60%

15. If the minimum profit generated across the 4

20. If the conditions of the above question are to be true,
quarters is 54 Cr, then what is the maximum profit
what is Sahev’s score in Verbal as a % of Sectional
out of the 4 quarters? full marks?
(a) 75 Cr (b) 81 Cr (a) 60% (b) 70%
(c) 90 Cr (d) 96 Cr (c) 75% (d) 63%
 MBA Wallah

Direction : Raghav has 4 income sources- salary, 23. If the condition of the above question is true, then what
freelancing, stocks & other sources. The split is is the total savings of Raghav?
given as below. The ratio of income from Salary & (a) 80,000 INR (b) 40,000 INR
Stocks is 8 : 5. (c) 20,000 INR (d) 50,000 INR

24. If the total savings is 20,000 INR, then find the

groceries expenditure (in INR).
(a) 18,000 (b) 9,000
(c) 12,000 (d) 6,000

25. The savings is :

(a) Equal to the Stocks
(b) Same as the Freelancing Income
(c) Same as Groceries
(d) Same as the Salary
He also has 4 expenditure sources- Groceries, Child
Education, Rent & EMI. The split is given as below. Directions: First Pie chart given below shows the
The ratio of expenses from Groceries & Rent is percent distribution of total number of students
3 : 2. (Boys + Girls) in five different classes and second
pie chart shows the degree distribution of difference
between the number of boys and that of girls for all
those five classes. All the data is given for 2017.
Total number of students in all the classes together
is 400 and the sum of differences between the
number of boys and that of girls for all the classes
is 120.

It is also given that his monthly savings is 40% of

his total income.
Note :
Total income = Income from (Salary +
Freelancing + Stocks + Others)
Total Expenditure = Expenses due to (Groceries
+ Education + Rent + EMI)

21. The rent cost is what percentage of the total

income?
(a) 8% (b) 10%
(c) 15% (d) 12%

22. If the EMI cost is 15,000 INR, then what is the total
income of Raghav from all 4 sources ?
(a) 100,000 INR (b) 40,000 INR
Note: Number of boys is more than that of girls for
(c) 20,000 INR (d) 50,000 INR
classes P and R only.
 MBA Wallah

26. What is the ratio of the total number of boys in 28. Ratio of number of boys to that of girls in class R in
classes P and T together to the total number of girls 2018 was 6: 7 and some new students joined class
in classes P and Q together? R in 2018. If a total of 60 new students joined class
(a) 6 : 7 R in 2018, then what is the difference between the
(b) 7 : 8 number of new boys who joined class R in 2018 and
the number of new girls who joined class R in 2018?
(c) 8 : 9
(Assume all the other data remains the same).
(d) 9 : 10
(a) 30 (b) 20
(c) 25 (d) 15
27. If in the year 2018, 60 new students took admission
in class P after which the number of boys and the 29. If in other class U, the number of boys is 20% more
number of girls in that class in 2018 becomes same, than that in class T and the number of girls in class
then what is the ratio of number of new boys to that U is 14 less than that in class T, then the number of
of new girls who took admission in class P in 2018? boys in class U is what percent of total number of
(All the other data remains the same.) girls in that class?
(a) 3 : 8 (a) 72.67% (b) 78.33%
(b) 2 : 7 (c) 55.55% (d) 66.67%
(c) 1 : 5
30. Total number of boys in Class P is what percent
(d) 4 : 9
more than the total number of girls in Class T?
 MBA Wallah

Answer Key
1. (b) 11. (a) 21. (d)
2. (d) 12. (b) 22. (a)
3. (d) 13. (c) 23. (b)
4. (c) 14. (b) 24. (b)
5. (a) 15. (c) 25. (d)
6. (d) 16. (b) 26. (c)
7. (b) 17. (c) 27. (c)
8. (a) 18. (d) 28. (b)
9. (a) 19. (c) 29. (d)
10. (a) 20. (b) 30. (20%)
 MBA Wallah

Hints & Solutions

1. (b) 4. (c)
Let’s assume that % split in salary is 8x % and that Let’s assume that % split in salary is 8x % and that
for Stocks is 5x%. for Stocks is 5x%.
So, So,
100% – (20 + 15)% = 8x% + 5x% 100% – (20 + 15)% = 8x% + 5x%
 65% = 13x%  65% = 13x%
 x% = 5%  x% = 5%
 8x% = 40%  8x% = 40%
 5x% = 25%  5x% = 25%
So, income from salary is 40% and income from So, income from salary is 40% and income from
stocks is 25% of the total monthly income. stocks is 25% of the total monthly income.
So, out of his total earning of 1 Lakh INR, his If 20,000 INR is (25% − 15%) = 10% of the total
earning from stocks is 100,000 × 25% = 25,000 income, then the total income is
INR. 20,000
INR = 200,000 INR.
10%
2. (d) Thus, the difference between earning from Salary
Let’s assume that % split in salary is 8x % and that & Stocks is 200,000 × (40% − 25%) = 30,000 INR.
for Stocks is 5x%.
So, 5. (a)
100% – (20 + 15)% = 8x% + 5x% Let’s assume that % split in salary is 8x % and that
 65% = 13x% for Stocks is 5x%.
 x% = 5% So,
 8x% = 40% 100% – (20 + 15)% = 8x% + 5x%
 5x% = 25%  65% = 13x%
So, income from salary is 40% and income from  x% = 5%
stocks is 25% of the total monthly income.  8x% = 40%
So, out of his total earning of 1 Lakh INR, his  5x% = 25%
earning from salary is : If 20,000 INR is (25% − 15%) = 10% of the total
1,00,000 × 40% = 40,000 INR. income, then the total income is
His earning from Freelancing is 20,000
1,00,000 × 20% = 20,000 INR. INR = 200,000 INR.
Total earning is (40,000 + 20,000) INR = 60,000 10%
INR. The least income has come from other sources.
Thus, the amount is
3. (d) 15% × 200,000 INR = 30,000 INR.
Let’s assume that % split in salary is 8x % and that
for Stocks is 5x%. 6. (d)
So, Let’s assume that the % split in Groceries is 3x%
100% – (20 + 15)% = 8x% + 5x% and that in Rent is 2x%.
 65% = 13x% So,
(3x% + 2x%) = 100 – (25 + 25)
 x% = 5%
 5x% = 50%
 8x% = 40%
 x = 10
 5x% = 25%
So, income from salary is 40% and income from  3x% = 30%
stocks is 25% of the total monthly income.  2x% = 20
If 20,000 INR is (25% − 15%) = 10% of the total Thus, the expenditure % split in Groceries is 30%
income, then the total income is and that in Rent is 20%.
If the total expenditure is 60,000 INR, then he paid
20,000
INR = 200,000 INR. a rent of 20% × 60,000 INR = 12,000 INR.
10%
 MBA Wallah

7. (b) (20% + 25%) of Total Expenditure = 45,000

Let’s assume that the % split in Groceries is 3x% Total Expenditure = 100,000
and that in Rent is 2x%. Groceries Expenditure = 30% of Total Expenditure
So, = 30,000.
(3x% + 2x%) = 100 – (25 + 25)
 5x% = 50%
10. (a)
 x = 10
Let’s assume that the % split in Groceries is 3x%
 3x% = 30%
and that in Rent is 2x%.
 2x% = 20
So,
Thus, the expenditure % split in Groceries is 30%
(3x% + 2x%) = 100 – (25 + 25)
and that in Rent is 20%.  5x% = 50%
Given, total expenditure in EMI is 25% of monthly  x = 10
expenditure.  3x% = 30%
So,  2x% = 20
25% × Total Expenditure = 10,000 Thus, the expenditure % split in Groceries is 30%
Total Expenditure = 40,000 and that in Rent is 20%.
30% Total Expenditure = 40,000 × 30% = 12,000 . 30% of Total Expenditure = 15,000
Thus, the answer is 12,000 INR. Total Expenditure = 50,000
20% of Total Expenditure = 50,000 × 20% = 10,000
8. (a) Thus, the answer is 10,000 INR.
Let’s assume that the % split in Groceries is 3x%
and that in Rent is 2x%. 11. (a)
So, Let’s assume the % split for Q1 profit is 3x% and
(3x% + 2x%) = 100 – (25 + 25) that for Q3 is 2x%
 5x% = 50% So,
 x = 10
5x% = 100 – (30 + 25)
 3x% = 30%
 5x% = 45%
 2x% = 20
Thus, the expenditure % split in Groceries is 30%  x% = 9%
and that in Rent is 20%. Thus, the split for Q1 and Q3 are 27% and 18%
Given, total expenditure in EMI is 25% of monthly respectively.
expenditure. Let’s assume that the total profit is 100P.
So, So,
25% × Total Expenditure = 10,000 27P = 108
Total Expenditure = 40,000 P=4
Amount spend on rent = 20% × Total Expenditure  30P = 120
= 40,000 × 20% = 8,000. So, the profit of Q4 is 120 Cr.

9. (a) 12. (b)

Let’s assume that the % split in Groceries is 3x% Let’s assume the % split for Q1 profit is 3x% and
and that in Rent is 2x%. that for Q3 is 2x%
So, So,
(3x% + 2x%) = 100 – (25 + 25) 5x% = 100 – (30 + 25)
 5x% = 50%  5x% = 45%
 x = 10  x% = 9%
 3x% = 30% Thus, the split for Q1 and Q3 are 27% and 18%
 2x% = 20 respectively.
Thus, the expenditure % split in Groceries is 30% Let’s assume that the total profit is 100P.
and that in Rent is 20%. So,
According to the question, 27P = 108
 MBA Wallah

P=4 Thus, the split for Q1 and Q3 are 27% and 18%
 (25P – 18P) respectively.
 7P = 7 × 4 = 28 cr Let’s assume that the total profit is 100P.
So,
So, the answer is 28Cr.
18P = 54
13. (c) P=3
Let’s assume the % split for Q1 profit is 3x% and  30P = 90
that for Q3 is 2x% Thus, the maximum profit is 90 Cr.
So,
5x% = 100 – (30 + 25) 16. (b)
 5x% = 45% Let’s assume that the % split of total marks scored
 x% = 9% by Sahev in QA is 5x% and that in LR is 4x%
Thus, the split for Q1 and Q3 are 27% and 18% So,
respectively.
100 − (21 + 25) = (4x% + 5x%)
Let’s assume that the total profit is 100P.
So,  54% = 9x%
27P = 27  x% = 6%
P = 1 Cr.  4x% = 24%
Average profit across all the quarters  5x% = 30%
100P
= = 25P Thus, he scored 24% of the total score in LR and
4 30% of the total score in QA.
Thus, the answer is 25 × 1 Cr = 25 Cr.
Let’s assume that he scored 100P marks. So, his
score in LR is 24P.
14. (b)
24P is the 48% of total marks in LR Section. Thus,
Let’s assume the % split for Q1 profit is 3x% and
that for Q3 is 2x% 24P
LR section has a full mark of = 50P
So, 48%
5x% = 100 – (30 + 25) As each section has the same full marks, the full
 5x% = 45% marks for DI is also 50P.
 x% = 9% Marks scored in DI = 25% of 100P = 25P
Thus, the split for Q1 and Q3 are 27% and 18% Thus, the % of the full marks scored by Sahev in DI
respectively. is
Let’s assume that the total profit is 100P. 100
So, 25P × % = 50%
50P
(27P – 25P) = 10
17. (c)
P=5
Let’s assume that the % split of total marks scored
 18P = 90
by Sahev in QA is 5x% and that in LR is 4x%
Thus, the minimum profit generated is 90 Cr.
So,
100 − (21 + 25) = (4x% + 5x%)
15. (c)
 54% = 9x%
Let’s assume the % split for Q1 profit is 3x% and
that for Q3 is 2x%  x% = 6%
So,  4x% = 24%
5x% = 100 – (30 + 25)  5x% = 30%
 5x% = 45% Thus, he scored 24% of the total score in LR and
 x% = 9% 30% of the total score in QA.
 MBA Wallah

Let’s assume that he scored 100P marks. So, his Thus, he scored 24% of the total score in LR and
score in LR is 24P. 30% of the total score in QA.
24P is the 48% of total marks in LR Section. Thus, In QA he scored the highest. So, QA score = Full
24P marks of the section. As in DI, LR & Verbal he
LR section has a full mark of = 50P
48% scored less than QA, in those sections he can not
As each section has the same full marks, the full score the full marks as that will lead to scoring more
marks for DI is also 50P × 4 = 200P. than 100% in QA section which is impossible.
100 Example- If we consider DI score as the full marks,
Thus, Sahev scored 100P × % = 50%
200P then the full marks for each of the sections is 25P.
This means that Sahev has scored more than the full
18. (d) marks in QA as his score in QA is 30P. This
Let’s assume that the % split of total marks scored scenario is not possible.
by Sahev in QA is 5x% and that in LR is 4x% Similarly for LR & Verbal as he scored even less
So, than that of DI, they can not be the full marks of the
100 − (21 + 25) = (4x% + 5x%) section. Thus, in QA Sahev scored the full marks.
 54% = 9x% Let’s assume that the total score scored by Sahev is
 x% = 6% 100P.
 4x% = 24% Then in QA he scored 30P which is also equal to
the sectional full marks.
 5x% = 30%
Thus, the total full marks = 30P × 4 = 120P
Thus, he scored 24% of the total score in LR and
Thus, the % scored by Sahev is
30% of the total score in QA.
100
Let’s assume that he scored 100P marks. So, his 100P × % = 83.33%
120P
score in LR is 24P.
24P is the 48% of total marks in LR Section. Thus,
20. (b)
24P
LR section has a full mark of = 50P Let’s assume that the % split of total marks scored
48%
by Sahev in QA is 5x% and that in LR is 4x%
As each section has the same full marks, the full
So,
marks for DI is also 50P × 4 = 200P.
100 − (21 + 25) = (4x% + 5x%)
200P = 600
 P=3  54% = 9x%

 21P = 63  x% = 6%
Thus, Sahev scored 63 marks in Verbal.  4x% = 24%
 5x% = 30%
19. (c) Thus, he scored 24% of the total score in LR and
Let’s assume that the % split of total marks scored 30% of the total score in QA.
by Sahev in QA is 5x% and that in LR is 4x% In QA he scored the highest. So, QA score = Full
So, marks of the section. As in DI, LR & Verbal he
100 − (21 + 25) = (4x% + 5x%) scored less than QA, in those sections he can not
 54% = 9x% score the full marks as that will lead to scoring more
than 100% in QA section which is impossible.
 x% = 6%
Example- If we consider DI score as the full marks,
 4x% = 24%
then the full marks for each of the sections is 25P.
 5x% = 30% This means that Sahev has scored more than the full
 MBA Wallah

marks in QA as his score in QA is 30P. This So, income from salary is 40% and income from
scenario is not possible. stocks is 25% of the total monthly income.
Similarly for LR & Verbal as he scored even less Let’s assume that the % split in Groceries is 3y%
than that of DI, they can not be the full marks of the and that in Rent is 2y%.
section. Thus, in QA Sahev scored the full marks. So,
Let’s assume that the total score scored by Sahev is (3y% + 2y%) = 100 – (25 + 25)
100P. 5y% = 50%
Then in QA he scored 30P which is also equal to y% = 10%
the sectional full marks. 3y% = 30%
Thus, Sahev’s score in Verbal is 2y% = 20%
100 Thus, the expenditure % split in Groceries is 30%
21P × % = 70%
30P and that in Rent is 20%.
Let’s assume that the total income is 100P.
21. (d) The savings is 40% × 100P = 40P
Let’s assume that the% split in salary is 8x % and Expenditure = 100P – 40P = 60P
that for Stocks is 5x%. EMI Cost = 60P × 25%
So,  15P = 15,000
100 – (20 + 15) = 8x + 5x 100P = 100,000
65% = 13x% Thus, the salary is 1,00,000 INR.
x% = 5%
8x% = 40% 23. (b)
5x% = 25% Let’s assume that the% split in salary is 8x % and
So, income from salary is 40% and income from that for Stocks is 5x%.
stocks is 25% of the total monthly income. So,
Let’s assume that the % split in Groceries is 3y% 100 – (20 + 15) = 8x + 5x
and that in Rent is 2y%. 65% = 13x%
So, x% = 5%
(3y% + 2y%) = 100 – (25 + 25) 8x% = 40%
5y% = 50% 5x% = 25%
y% = 10% So, income from salary is 40% and income from
3y% = 30% stocks is 25% of the total monthly income.
2y% = 20% Let’s assume that the % split in Groceries is 3y%
Thus, the expenditure % split in Groceries is 30% and that in Rent is 2y%.
and that in Rent is 20%. So,
Let’s assume that the income is 100P. (3y% + 2y%) = 100 – (25 + 25)
The savings is 40% × 100P = 40P 5y% = 50%
Expenditure = 100P – 40P = 60P y% = 10%
Thus, the rent cost is 20% × 60P = 12P 3y% = 30%
12P 2y% = 20%
Required % = × 100 = 12% of total income. Thus, the expenditure % split in Groceries is 30%
100P
and that in Rent is 20%.
22. (a) Let’s assume that the income is 100P.
Let’s assume that the% split in salary is 8x % and The savings is 40% × 100P = 40P
that for Stocks is 5x%. Expenditure = 100P – 40P = 60P
So, EMI Cost = 60P × 25%
100 – (20 + 15) = 8x + 5x  15P = 15,000
65% = 13x% 100P = 100,000
x% = 5% 40P = 40,000
8x% = 40% Thus, the savings is 40,000 INR.
5x% = 25%
 MBA Wallah

24. (b) 40% × 100P = 40P

Let’s assume that the% split in salary is 8x % and Salary = 100P × 40% = 40P
that for Stocks is 5x%. Thus, the right answer is option “D”.
So,
100 – (20 + 15) = 8x + 5x 26. (c)
65% = 13x% Classes Total Difference Boys Girls
x% = 5%
8x% = 40%
P 20% of 120 × (80 + 40) (80 − 40)
5x% = 25%
400  120  2 2
= 80  
So, income from salary is 40% and income from  360  = 60 = 20
stocks is 25% of the total monthly income. = 40
Let’s assume that the % split in Groceries is 3y% Q 30% of 120 × (120 − 20) (120 + 20)
and that in Rent is 2y%.
So,
400  60  2 2
=120  
(3y% + 2y%) = 100 – (25 + 25)  360  = 50 = 70
5y% = 50% = 20
y% = 10% R 17.5% 120 ×  70 + 10   70 − 10 
3y% = 30% of 400  30     
 2   2 
2y% = 20% =70  
Thus, the expenditure % split in Groceries is 30%  360  = 40 = 30
and that in Rent is 20%. = 10
Let’s assume that the income is 100P. Then the S 15% of 120 ×  60 − 20   60 + 20 
savings is 400 =  60     
 2   2 
40% × 100P = 40P 60  
 360  = 20 = 40
Then,
40P = 20,000 = 20
P = 500 T 17.5% 120 ×  70 − 30   70 + 30 
60P = 30,000 of 400  90     
 2   2 
60P × 30% = 30,000 × 30% =70  
 360  = 20 = 50
18P = 9,000
= 30
 Groceries Expenditure = 9000.

25. (d) Total number of boys in classes P and T together

Let’s assume that the% split in salary is 8x % and = 60 + 20 = 80
that for Stocks is 5x%. Total number of girls in classes P and Q together
So,
100 – (20 + 15) = 8x + 5x = 20 + 70 = 90
65% = 13x% Required ratio = 80 : 90 = 8 : 9
x% = 5%
8x% = 40% 27. (c)
5x% = 25%
Classes Total Difference Boys Girls
So, income from salary is 40% and income from
stocks is 25% of the total monthly income. P 20% of 120 × (80 + 40) (80 − 40)
Let’s assume that the % split in Groceries is 3y% 400  120  2 2
= 80  
and that in Rent is 2y%.  360  = 60 = 20
So,
= 40
(3y% + 2y%) = 100 – (25 + 25)
5y% = 50% Q 30% of 120 × (120 − 20) (120 + 20)
y% = 10% 400  60  2 2
=120  
3y% = 30%  360  = 50 = 70
2y% = 20% = 20
Thus, the expenditure % split in Groceries is 30%
and that in Rent is 20%.
Let’s assume that the income is 100P. Then the
savings is
 MBA Wallah

R 17.5% 120 ×  70 + 10   70 − 10  Let the number of boys and that of girls in class R
of 400  30     
 2   2  in 2018 be '6x' and '7x' respectively.
=70  
 360  = 40 = 30 According to the question:
= 10 (6x − 40) + (7x − 30) = 60
S 15% of 120 ×  60 − 20   60 + 20  13x = 130
400 =  60     
 2   2  x = 10
60  
 360  = 20 = 40 Total new boys who joined class R in 2018
= 20 = (6x − 40) = 20
T 17.5% 120 ×  70 − 30   70 + 30  Total new girls who joined class R in 2018
of 400  90     
 2   2  = (7x − 30) = 40
=70  
 360  = 20 = 50 Required difference = 40 − 20 = 20
= 30

29. (d)
Let the number of new boys and the number of new Classes Total Difference Boys Girls
girls who took admission in class P in 2018 be 'x' P 20% of 120 × (80 + 40) (80 − 40)
and '60 − x' respectively. 400  120  2 2
According to the question:  
= 80  360  = 60 = 20
(60 + x) = 20 + (60 − x)
x = 20 – x = 40
x = 10 Q 30% of 120 × (120 − 20) (120 + 20)
Required ratio = x : (60 − x) = 10 : 50 = 1: 5. 400  60  2 2
=120  
 360  = 50 = 70
28. (b) = 20
Classes Total Difference Boys Girls
P 20% of 120 × (80 + 40) (80 − 40)
R 17.5% 120 ×  70 + 10   70 − 10 
of 400  30     
400  120   2   2 
2 2 =70  
= 80    360 
 360  = 60 = 20 = 40 = 30
= 10
= 40
Q 30% of 120 × (120 − 20) (120 + 20) S 15% of 120 ×  60 − 20   60 + 20 
400 =  60     
400  60  2 2  2   2 
=120   60  
 360  = 50 = 70  360  = 20 = 40
= 20 = 20
R 17.5% 120 ×  70 + 10   70 − 10  T 17.5% 120 ×  70 − 30   70 + 30 
of 400  30         
 2   2  of 400  90   2   2 
=70    
 360  = 40 = 30 = 70
 360  = 20 = 50
= 10
= 30
S 15% of 120 ×  60 − 20   60 + 20 
400 =  60     
 2   2 
60   Total boys in class U = 120% of 20 = 24
 360  = 20 = 40
Total girls in class U = 50 − 14 = 36
= 20
 24 
T 17.5% 120 ×  70 − 30   70 + 30  Required percent =   ×100 = 66.67%
of 400  90       36 
 2   2 
= 70  
 360  = 20 = 50
= 30
 MBA Wallah

30. (20%) S 15% of 120 ×  60 − 20   60 + 20 

Classes Total Difference Boys Girls 400 =  60     
 2   2 
(80 + 40) (80 − 40) 60  
P 20% of 120 ×  360  = 20 = 40
400  120  2 2 = 20
 
= 80  360  = 60 = 20
T 17.5% 120 ×  70 − 30   70 + 30 
= 40 of 400  90     
 2   2 
(120 − 20) (120 + 20) = 70  
Q 30% of 120 ×  360  = 20 = 50
400  60  2 2 = 30
=120  
 360  = 50 = 70
= 20 Total number of boys in Class P = 60
R 17.5% 120 ×  70 + 10   70 − 10  Total number of girls in Class T = 50
of 400  30      60 − 50
 2   2 
=70   Required answer =  100 = 20%
 360  = 40 = 30 50
= 10

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