Name:______________________________Class:__________________ Date:__________________
Assessment
  Chapter Test A
Teacher Notes and Answers
Electromagnetic Induction
CHAPTER TEST A (GENERAL)
 1. c                                                                        14. b
 2. d                                                                            Given
 3. b                                                                            V1 = 115 V
 4. d                                                                            V2 = 2.3 V
 5. a                                                                            Solution
                                                                                               V    115 V
 6. d                                                                              N1 : N 2 = 1 =           = 50 : 1
 7. b                                                                                          V2 2.3 V
 8. c                                                                        15. c
 9. c                                                                        16. b
10. d                                                                        17. b
11. c                                                                        18. b
    Given                                                                    19. Move the circuit loop into or out of the
    Vmax = 220 V                                                                magnetic field. Rotate the circuit loop in the
    Solution                                                                     magnetic field so that the angle between the
    Vrms = 0.707Vmax =                                                         plane of the circuit loop and magnetic field
      (0.707)(220 V) = 160 V                                                     changes. Vary the intensity of the magnetic
12. a                                                                            field by rotating the magnet.
    Given
                                                                             20. to turn wire loops (or a coil of wire) in a
     I rms = 3.6 A
                                                                                 magnetic field
    Solution                                                                 21. the rms current multiplied by the resistance
    Rearrange the equation, I rms =
                                                                                 (or I rms • R )
       0.707 I max , to solve for I max .                                    22. The energy of an electromagnetic wave is
                  I rms   (3.6 A)                                                stored in the electromagnetic fields, which
       I max =          =         = 5.1 A
                 0.707 (0.707)                                                   exert an electromagnetic force on charged
13. d                                                                            particles. This energy transported by an
    Given                                                                        electromagnetic wave is called
     V1 = 120 V                                                                 electromagnetic radiation.
        N 1 = 95 turns
       N 2 = 2850 turns
       Solution
              V2 N 2            2850 turns 
       V2 =          = (120 V)             
                N1               95 turns 
           = 3600 V
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             1                                                      Chapter Tests
Name:______________________________Class:__________________ Date:__________________
23. 149 V                                                                   24. 297 V
    Given                                                                        Given
     N = 275 turns                                                               Vmax = 4.20  102 V
       A = 0.750 m2                                                              Solution
                                                                                 Vrms = 0.707Vmax =
       B = +0.900 T
                                                                                   (0.707)(4.2  102 V) = 297 V
       t = 1.25 s                                                           25. 1.6  104 V
       = 0.00°                                                                  Given
      Solution                                                                    V1 = 120 V
      Substitute values into Faraday’s law of
                                                                                     N 1 = 38 turns
      magnetic induction.
                                                                                     N 2 = 5163 turns
             N M          ABcos 
      emf =            = N           =                                             Solution
                 t              t                                                             N         5163 turns 
                    B                                                              V2 = V1 2 = (120 V)            
         NAcos                                                                                N1        38 turns 
                    t
                                                                                          = 1.6  10 4 V
      =  (275 turns)(0.750 m2 )
                          (0.900 T)
         (cos 0.00°)                = 149 V
                           (1.25 s)
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             2                                                      Chapter Tests
Name:______________________________Class:__________________ Date:__________________
  Assessment
  Electromagnetic Induction
Chapter Test A
MULTIPLE CHOICE
In the space provided, write the letter of the term or phrase that best completes
each statement or best answers each question.
_____ 1. A current can be induced in a closed circuit without the use of a battery
         or an electrical power supply by moving the circuit through a
         a. high temperature field.          c. magnetic field.
         b. gravitational field.             d. nuclear field.
_____ 2. A loop of wire is held in a vertical position at the equator with the face
         of the loop facing in the east-west direction. What change will induce
         the greatest current in the loop?
         a. raising the loop to a higher elevation
         b. moving the loop north
         c. rotating the loop so its face is vertical
         d. rotating the loop so its face is north-south
_____ 3. Electricity may be generated by rotating a loop of wire between the
         poles of a magnet. The induced current is greatest when
         a. the plane of the loop is parallel to the magnetic field.
         b. the plane of the loop is perpendicular to the magnetic field.
         c. the magnetic flux through the loop is a minimum.
         d. the plane of the loop makes an angle of 45° with the magnetic field.
_____ 4. According to Lenz’s law, the magnetic field of an induced current in a
         conductor will
         a. enhance the applied field.
         b. heat the conductor.
         c. increase the potential difference.
         d. oppose a change in the applied magnetic field.
_____ 5. According to Lenz’s law, if the applied magnetic field changes,
         a. the induced field attempts to keep the total field strength constant.
         b. the induced field attempts to increase the total field strength.
         c. the induced field attempts to decrease the total field strength.
         d. the induced field attempts to oscillate about an equilibrium value.
_____ 6. Which of the following options can be used to generate electricity?
         a. Move the circuit loop into and out of a magnetic field.
         b. Change the magnetic field strength around the circuit loop.
         c. Change the orientation of the circuit loop with respect to the magnetic
            field.
         d. all of the above
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             3                                                      Chapter Tests
Name:______________________________Class:__________________ Date:__________________
  Chapter Test A continued
_____ 7. Which conversion process is the basic function of the electric motor?
         a. mechanical energy to electrical energy
         b. electrical energy to mechanical energy
         c. low voltage to high voltage, or vice versa
         d. alternating current to direct current
_____ 8. In a two-coil system, the mutual inductance depends on
         a. only the geometrical properties of the coils.
         b. only the orientation of the coils to each other.
         c. both the geometrical properties of the coils and their orientation to
            each other.
         d. neither the geometrical properties of the coils nor their orientation to
            each other.
_____ 9. In a primary-secondary coil combination, which of the following
         conditions is met in the primary coil when the current in the secondary
         coil is at its maximum?
         a. The current is maximum in a positive direction.
         b. The current is maximum in a negative direction.
         c. The rate of current change is maximum.
         d. The voltage is maximum in a positive direction.
_____ 10. What is rms (root-mean-square) current?
          a. the value of alternating current that gives the same heating effect
             that the corresponding value of direct current does
          b. an important measure of the current in an ac circuit
          c. the amount of direct current that would dissipate the same energy in
             a resistor as is dissipated by the instantaneous alternating current
             over a complete cycle
          d. all of the above
_____ 11. A generator’s maximum output is 220 V. Calculate the rms potential
          difference.
          a. 110 V                         c. 160 V
          b. 150 V                         d. 310 V
_____ 12. The rms current in an ac current is 3.6 A. Find the maximum current.
          a. 5.1 A                             c. 2.8 A
          b. 4.7 A                             d. 1.8 A
_____ 13. A step-up transformer used on a 120 V line has 95 turns on the primary
          and 2850 turns on the secondary. What is the potential difference
          across the secondary?
          a. 30 V                            c. 2400 V
          b. 1800 V                         d. 3600 V
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             4                                                      Chapter Tests
Name:______________________________Class:__________________ Date:__________________
  Chapter Test A continued
_____ 14. A potential difference of 115 V across the primary of a step-down
          transformer provides a potential difference of 2.3 V across the
          secondary. What is the ratio of the number of turns of wire on the
          primary to the number of turns on the secondary?
          a. 1:50                              c. 25:1
          b. 50:1                              d. 1:25
_____ 15. Electromagnetic waves are _________________ electric and magnetic
          fields.
          a. transverse                    c. oscillating
          b. constant                      d. parallel
_____ 16. All of the following statements about the electromagnetic force are true
          except which one?
          a. It is one of the four fundamental forces in the universe.
          b. It exerts a force on either charged or uncharged particles.
          c. It obeys the inverse-square law.
          d. It is produced by—and produces—electric and magnetic fields.
_____ 17. Where is energy stored in electromagnetic waves?
          a. in the wave’s moving atoms
          b. in the oscillating electric and magnetic fields
          c. in the electromagnetic force
          d. in the wave’s directional vector
_____ 18. What do radio waves, microwaves, X rays, and gamma rays all have in
          common?
          a. They are produced in the same way.
          b. They are electromagnetic waves.
          c. They are detected in the same way.
          d. They store the same amount of energy.
SHORT ANSWER
19. List three ways to induce a current in a circuit loop, using only a magnet.
       _________________________________________________________________
       _________________________________________________________________
       _________________________________________________________________
20. What is a turbine’s rotational motion used for in commercial power plants?
       _________________________________________________________________
       _________________________________________________________________
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             5                                                      Chapter Tests
Name:______________________________Class:__________________ Date:__________________
  Chapter Test A continued
21. The rms emf across a resistor is equal to what?
       _________________________________________________________________
       _________________________________________________________________
22. Explain how the terms energy, electromagnetic force, electromagnetic wave,
    and electromagnetic radiation are related to one another.
       _________________________________________________________________
       _________________________________________________________________
       _________________________________________________________________
       _________________________________________________________________
PROBLEM
23. A coil with 275 turns and a cross-sectional area of 0.750 m2 experiences a
    magnetic field whose strength increases by +0.900 T in 1.25 s. The plane of
    the coil moves perpendicularly to the plane of the magnetic field. What is the
    induced emf in the coil?
24. An ac generator has a maximum output emf of 4.20  102 V. What is the rms
    potential difference?
25. A step-up transformer used on a 120 V line has 38 turns on the primary and
    5163 turns on the secondary. What is the potential difference across the
    secondary?
Original content Copyright © by Holt, Rinehart and Winston. Additions and changes to the original content are the responsibility of the instructor.
Holt Physics                                                             6                                                      Chapter Tests