MOLECULAR BASIS

OF INHERITANCE
1. What is the role of RNA polymerase-II in the process of transcription in eukaryotes.
(1) Transcription of tRNA, 5SrRNA and SnRNA
(2) Transcription of precursor of mRNA.
(3) Transcription of only SnRNA's
(4) Transcription of rRNA (28S, 18S, 5.8S)
;wdSfj;ksV~l es vuqys[ku dh izfØ;k es RNA ikfyejst-II dh D;k Hkwfedk gksrh gS \
(1) tRNA, 5SrRNA vkSj SnRNA dk vuqys[kuA

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(2) mRNA ds vxzxkeh dk vuqys[kuA
(3) dsoy SnRNA's dk vuqys[kuA
(4) rRNA (28S, 18S, 5.8S) dk vuqys[kuA
2. Sequence annotation refers to :-
(1) All genes that are expressed as protein
(2) Sequencing of all the coding and non coding sequence.
(3) Certain important expressed genes.
(4) All genes that are expressed as RNA only.
vuqØe fVIi.k D;k gSA
¼a1½ os lHkh thu] tks çksVhu ds :i esa vfHkO;Dr gksrs gaSA
¼2½ lHkh O;Drsd o vO;Drsd vuqØeksa dh tkudkjh izkIr djukA
¼3½ dqN egRoiw.kZ vfHkO;Dr thuA
¼4½ os lHkh thu tks vkj-,u-,- ds :i es vfHkO;Dr gksrs gaSA
3. Given below are two statements :-
Statement-I : DNA mutates at a faster rate.
Statement-II : Virus having RNA genome and shorter life span mutate and evolve faster.
(1) Both Statement I and Statement II are incorrect.
(2) Statement I is correct but Statement II is incorrect.
(3) Statement I is incorrect but Statement II is correct.
(4) Both Statement I and Statement II are correct.
uhps nks dFku fn;s x;s gS :-
dFku-I : DNA vis{kkd`r rhoz nj ls mRifjorhZ gksrk gSA
dFku-II : vkj-,u-,- thukse ,oa NksVs thou dky okys fo"kk.kq rhozrk ls mRifjofrZr ,oa fodflr gksrs gaSA
(1) dFku&I vkSj dFku&II nksukas xyr gaSA
(2) dFku&I lgh gS ysfdu dFku&II xyr gSA
(3) dFku&I xyr gS ysfdu dFku&II lgh gSA
(4) dFku&I vkSj dFku&II nksukas lgh gSA
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4. Given below are two statements:-
Statement-I : In eukaryotes the positively charged DNA is held with same negatively charged protein in a
region called nucleoid.
Statement-II : In prokaryotes, the negatively charged DNA is wrapped around the positively charged histone
octamer to form nucleosome.
(1) Both Statement I and Statement II are incorrect.
(2) Statement I is correct but Statement II is incorrect.
(3) Statement I is incorrect but Statement II is correct.
(4) Both Statement I and Statement II are correct.
uhps nks dFku fn, x, gSa :-
dFku-I : ;qdSfj;ksV~l eas /kukRed vkosf'kr DNA dqN _.kkRed vkosf'kr izksVhukas ds lkFk ca/kdj ,d {ks= ftls
dsUnzdkHk dgrs gS] esa jgrk gSA
dFku-II : izksdSfj;ksV~l esa =`.kkRed vkosf'kr DNA /kukRed vkosf'kr fgLVksu v"Vd ds pkjkas vksj fyiVdj
U;wfDy;kslkse cukrk gSA

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(1) dFku&I vkSj dFku&II nksukas xyr gSaA (2) dFku&I lgh gS] ysfdu dFku&II xyr gSA
(3) dFku&I xyr gS ysfdu dFku&II lgh gSA (4) dFku&I vkSj dFku&II nksukas lgh gSaA
5. Which one of the following is the sequence on corresponding coding strand, if the sequence on mRNA formed
is as follows.
5' AGG GGA CCC UUU GGG 3'
(1) 5' UCC CCU GGG AAA CCC 3' (2) 3' UCC CCU GGG AAA CCC 5'
(3) 5' AGG GGA CCC TTT GGG 3' (4) 5' TGG CCT AAA AAA CCC 3'
;fn cus gq, mRNA dk Øe uhps fn;k x;k gS] rc fuEu es dksfMax jTtq dk Øe D;k gksxk \
5' AGG GGA CCC UUU GGG 3'
(1) 5' UCC CCU GGG AAA CCC 3' (2) 3' UCC CCU GGG AAA CCC 5'
(3) 5' AGG GGA CCC TTT GGG 3' (4) 5' TGG CCT AAA AAA CCC 3'
6. Read the following statements and choose the set of correct statement :-
(a) Euchromatin is tightly packed chromatin.
(b) Heterochromatin is transciptionally active.
(c) Histone octamer is wrapped by ⊕ charged DNA in nucleosome.
(d) Histones are rich in lysine and leucine.
(e) A typical nucleosome contains 200 bp of DNA helix.
Choose the correct answer from the options given below :
(1) (a), (c) and (d) only (2) (b), (c) and (e) only
(3) (e) only (4) All of the above
fuEufyf[kr dFkukas dks if<+;s vkSj lgh dFkukas ds leqPp; dks pqfu,A
(a) ;qØksesfVu ,d n`<+rk ls ca/kk gqvk ØksesfVu gSA
(b) gsVjksØksesfVu vuqys[ku esa lfØ; gksrk gSA
(c) U;qfDy;kslkse eas fgLVksu v"Vd /kukRed vkosf'kr DNA }kjk fyiVk jgrk gSA
(d) fgLVksu es ykbflu vkSj Y;wlhu izpqj ek=k eas gksrs gSA
(e) ,d izk:ih U;wfDy;kslkse eas DNA gSfyDl ds 200 bp ({kkj ;qXe) gksrs gaSA
(1) dsoy (a), (c) ,oa (d) (2) dsoy (b), (c) ,oa (e)
(3) dsoy (e) (4) mijksDr lHkh
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7. E.coli cell with 15N-dsDNA are incubated in medium containing 14N nucleotide. After 60 minutes, how many
E.coli cells will have DNA totally free from 15N ?
(1) 8 cells (2) 4 cells (3) 6 cells (4) 2 cells
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N-dsDNA okyh bZ-dksykbZ dh dksf'kdk,¡ 14N U;qfDy;ksVkbM okys ek/;e es lsbZ xbZ] 60 feuV i'pkr bZ-dksykbZ dh
fdruh dksf'kdk,¡ 15N ls iw.kZr% eqDr gksxh \
(1) 8–dksf'kdk,¡ (2) 4–dksf'kdk,¡ (3) 6–dksf'kdk,¡ (4) 2–dksf'kdk,¡
8. Complete the flow chart of central dogma.
(a) (b) (c)
DNA mRNA Protein

(1) (a) - Transcription, (b) - Translation, (c) - Replication

(2) (a) - Replication, (b) - Transcription, (c) - Translation
(3) (a) - Replication, (b) - Translation, (c) - Transcription
(4) (a) - Translation, (b) - Replication, (c) - Transcription
lsUVªy MksXek ds ¶yks pkVZ dks iw.kZ dfj, %&

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(a) (b) (c)
DNA mRNA Protein

(1) (a) - vuqys[ku, (b) - vuqoknu, (c) - izfrd`frdj.k

(2) (a) - izfrd`frdj.k, (b) - vuqys[ku, (c) - vuqoknu
(3) (a) - izfrd`frdj.k, (b) - vuqoknu, (c) - vuqys[ku
(4) (a) - vuqoknu, (b) - izfrd`frdj.k, (c) - vuqys[ku
9. Identify the incorrect statement :
(1) In capping, 7-methylguanosine triphosphate is added to the 5' end of hnRNA.
(2) Okazaki fragments are joined by ligase.
(3) Generally split gene arrangement is characteristic of eukaryotes.
(4) RNA polymerase bind with rho factor to initiated the process of transcription in bacteria.
fuEufyf[kr es ls xyr dFku pqfu,A
(1) dSfiax esa 7-esfFky Xokukslhu VªkbQkLQsV hnRNA dks 5' ds fljs ls tksM+k tkrk gSA
(2) vksdktkdh [k.M ykbxst ds }kjk tqM+rs gSaA
(3) lkekU;r;k foHkDr thu O;oLFkk ;qdSfj;kV~l dk fof'k"V y{k.k gSA
(4) thok.kq esa vuqys[ku dh izfØ;k dk vkjEHku djus ds fy, RNA polymerase, rho dkjd ds lkFk cfU/kr gks tkrk
gSA
10. Which of the following RNA is required for the synthesis of protein-
(1) mRNA (2) tRNA (3) rRNA (4) All of the above
fuEu es izksVhu la'ys"k.k ds fy, dkSulk RNA vko';d gS
(1) mRNA (2) tRNA (3) rRNA (4) mijksDr lHkh
11. If adenine makes 20% of the DNA molecule, what will be the percentage of Thymine, Guanine and Cytosine in
it ?
(1) T : 20, G : 30, C : 30 (2) T : 80, G : 10, C : 10
(3) T : 30, G : 20, C : 20 (4) T : 20, G : 35, C : 25
;fn ,d DNA v.kq eas ,sMsuhu dh ek=k 20% gS] rc blesa Fkkbehu] Xokuhu ,oa lkbVkslhu dk izfr'kr D;k gksxk \
(1) T : 20, G : 30, C : 30 (2) T : 80, G : 10, C : 10
(3) T : 30, G : 20, C : 20 (4) T : 20, G : 35, C : 25

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12. Statement - I : The codon AUG codes for methionine in eukaryotes.
Statement - II : CCC and GGG both codon codes for the proline and glycine amino acid, respectively.
In the light of the above statements, choose the correct answer for the options given below :
(1) Both Statement-I and Statement-II are incorrect.
(2) Statement-I is correct but Statement-II is incorrect.
(3) Statement-I is incorrect but Statement-II is correct.
(4) Both Statement-I and Statement-II are correct.
dFku - I : ;qdSfj;ksV~l esa izdwV AUG ehfFk;ksuhu dk dwV ys[ku djrk gSA
dFku - II : CCC ,oa GGG nksuksa izdwV izksyhu rFkk Xykbflu vehuks vEy dk Øe'k% dwV ys[ku djrs gaSA
mi;ZqDr dFkukas ds vk/kkj ij fuEu fodYikas ls lgh mÙkj dk p;u djksA
(1) dFku–I vkSj dFku–II nksuksa xyr gSaA (2) dFku–I lgh gS] ysfdu dFku–II xyr gSA
(3) dFku–I xyr gS] ysfdu dFku–II lgh gSA (4) dFku–I vkSj dFku–II nksukas lgh gSA
13. Match the column-I with column-II and find the correct answer.
Column I Column II
A. Monosomy (i) Mostly recessive
B. Trisomy (ii) 2n – 1
C. Mutation (iii) 2n + 1

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D. Mutagen (iv) UV light
dkWye&I vkSj dkWye&II dk feyku dhft, ,oa lgh mÙkj pqusA
dkWye-I dkWye-II
A. ekukslkeh (i) vf/kdka'kr% vizHkkoh
B. Vªkblkseh (ii) 2n – 1
C. mRifjorZu (iii) 2n + 1
D. mRifjorZd ¼E;wVktu½ (iv) UV ykbV
(1) A-(i), B-(ii), C-(iii), D-(iv) (2) A-(ii), B-(i), C-(i), D-(iii)
(3) A-(ii), B-(iii), C-(i), D-(iv) (4) A-(iv), B-(iii), C-(ii), D-(i)
14. Match the following genes of the lac operon with their respective products.
(a) z gene (i) β−galactosidase
(b) y gene (ii) Permease
(c) a gene (iii) Repressor
(d) i gene (iv) Transacetylass
Select the correct option :
(a) (b) (c) (d)
(1) (i) (ii) (iii) (iv)
(2) (i) (iii) (ii) (iv)
(3) (i) (ii) (iv) (iii)
(4) (ii) (i) (iii) (iv)
ySd vksisjkWu ds fuEu thukas dk muds mRiknkas ds lkFk feyku dhft,&
(a) z thu (i) β−xsysDVkslkbMst
(b) y thu (ii) ijeh,t
(c) a thu (iii) laned (fjizslj½
(d) i thu (iv) Vªkal,flVkbyst
lgh fodYi dks pqfu, :-
(a) (b) (c) (d)
(1) (i) (ii) (iii) (iv)
(2) (i) (iii) (ii) (iv)
(3) (i) (ii) (iv) (iii)
(4) (ii) (i) (iii) (iv)
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15. Select the correct match :-
(1) Alec jeffrey - DNA finger printing
(2) Alfred Hershey and Marthae Chase - T.M.V.
(3) Meselson and Stahl - Drosophila
(4) Jacob and Monad - Double Helix model of DNA.
lgh lqesy dks pqfu;s :-
(1) ,ysd tsQjh - DNA vaxqyh Nki
(2) vYÝsM g'ksZ vkSj ekFkkZ psl - T.M.V.
(3) eSlYlu vkSj LVkgy - MªkslksfQyk
(4) tSdc rFkk eksukWM - DNA dk Mcy gsfyDl ekWMy
16. Out of 64 possible genetic codons, how many codon codes for amino acids.
(1) 4 (2) 16 (3) 3 (4) 61
vkuqokaf'kd dksMkWu esa ls fdrus dksMkWu ,ehuks vEy dks dksfMr djrk gSA
(1) 4 (2) 16 (3) 3 (4) 61

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17. Select the correct match :-
(1) rRNA - Adapter RNA (2) mRNA - Soluble RNA
(3) tRNA - Smallest RNA (4) hn RNA - Precursor of rRNA
lgh lqesy dks pqfu;s :-
(1) rRNA - ,MkIVj RNA (2) mRNA - ?kqyu'khy RNA
(3) tRNA - lcls NksVk RNA (4) hn RNA - rRNA dk vxznwr
18. In bacteria, enzyme ribozyme is actually.
(1) 23S rRNA (2) 28S rRNA (3) 5S rRNA (4) 18S rRNA
thok.kqvksa esa ,Utkbe jkbckstkbe okLro esa gSA
(1) 23S rRNA (2) 28S rRNA (3) 5S rRNA (4) 18S rRNA
19. Discontinuous fragments of DNA which are formed during replication of DNA are joined by -
(1) DNA Polymerase (2) RNA Polymerase
(3) Ligase (4) Helicase
DNA ds vfujraj (vlrr~) [k.M tks DNA izfrd`frdj.k ds nkSjku curs gSa] fdlds }kjk tqMrs gaSA
(1) DNA Polymerase (2) RNA Polymerase
(3) Ligase (4) Helicase
20. How much of the genome code for proteins :
(1) < 2% (2) 5-10% (3) 15-20% (4) 25%
fdrus thukse izksVhu dks dksfMr djrs gaSA
(1) < 2% (2) 5-10% (3) 15-20% (4) 25%

ANSWER KEY : (MOLECULAR BASIS OF INHERITANCE)

Que. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Ans. 2 2 3 1 3 3 3 2 4 4 1 4 3 3 1 4 3 1 3 1
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