PERCENTAGE
1   If Sukhbeer sold 12 pen for a rupee and he had a loss of       11. The length breadth and height of the room is in 4 : 2 : 1.
    20%. How many pens he sold for a rupee if he wants to              If the breadth and height are one fourth of the original
    make a profit of 20%.                                              while the length is doubled, then, the total area of the
    (a) 8                        (b) 9                                 four wall of the room will …….
    (c) Can’t be determined      (d) 10                                (a) remain the same            (b) decrease by 60%
2
                     3
    Sahnaaz spends of his salary. Now his salary increased             (c) decrease by 64.5%          (d) decrease by 66.2%
                     4
                                                                   12. A student took five papers in an examination, where the
    by 20% and his expenditure is increased by 10%. Find
                                                                       full marks of first two paper is 100 and for last three is
    out the percentage increment in his savings?
                                                                       150. His marks in these were in the proportion of 5 : 7 : 8
    (a) 75%                       (b) 25%
                                                                       : 9 : 10. In all paper together candidate got 60% of total
    (c) 50%                       (d) Can’t be determined
                                                                       marks. Then number of papers in which he got more
3   X’s salary is 20% less of y’s. Now find out how much
                                                                       than 50% marks is.
    percent y’s salary is more than that of x’s salary.                (a) 4                          (b) 3
    (a) 20%                       (b) 40%                              (c) 5                          (d) 6
           1
    (c) 16 %                      (d) 25%                                                     3
                                                                   13. A college has raised th of the amount it need for a new
           6
                                                                                              4
4   How much percent the markup price of a product is                  charity fund by receiving an average donation of 600
    greater than that of its cost price when a shopkeeper              from 60% of the people. If the college is to raise exactly
    gives a discount of 10% and had a profit of 17%                    the amount needed for the new charity fund. What
    (a) 10%                      (b) 20%                               should be average remaining donation from the
    (c) 30%                      (d) Can’t be determined               remaining people which is not given?
5   Price of a commodity is increased by 20%. By what                  (a) 300                        (b) 250
    percentage the consumption of the commodity is                     (c) 400                        (d) 500
    decreased by the consumer, if the expenditure on this          14. Forty percent of the employees of a certain company are
    commodity remain constant.                                         men and 75% of the men earn more than Rs 25,000 per
           2
    (a) 16 %                     (b) 25%                               year. If 45% of the company’s employees earn more than
           3
   (c) 15%                        (d) 8%                               Rs. 25,000 per year, what fraction of the women
6 The tank-full of petrol in Anil’s car lasts for 10 days. If he       employed by the company earn maximum of Rs 25,000
   starts using 25% more everyday. How many days will                  per year?
   the tank full of petrol last?                                       (a) 2/11                       (b) 1/4
   (a) 5                          (b) 6                                (c) 1/3                        (d) 3/4
   (c) 7                          (d) 8                            15. One amoeba splits into 16 amoeba of the next
7 In an XII class examination out of 480 students, 85% of              generation, but due to environment only 25% of one
   the girls and 70% of the boys passed. How many girls                generation can produce the next generation. If the
   appeared in the examination. If total pass percentage               seventh generation number is 4096 million, what is the
   was 75%.                                                            number in first generation.
   (a) 320                        (b) 160                              (a) 0.25 million               (b) 1 million
                                                                       (c) 4 million                  (d) 16 million
   (c) 370                        (d) 120
8 An Alloy of Zinc and Iron weighs 50gm. It contains 80%
   zinc. How much zinc should be added to the alloy, so that
   percentage of zinc is increased to 90%?
   (a) 50 gm                      (b) 60 gm
   (c) 30 gm                      (d) 45 gm
9 The profit percentage of a product when it is sold for Rs.
   1128 is equal to the loss percentage when the product is
   sold for Rs. 872. Find the cost price of the product.
   (a) 1000                       (b) 928
   (c) 1100                       (d) Can’t be determined
10 If the price of a commodity is decreased by 10%, then it
   is increased by 10%. Find out the final percentage
   change in the price of a commodity.
   (a) No change                  (b) 1% decreased
   (c) 1% increased               (d) Can’t be determined.
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16. A man earn 𝑥% on the first Rs. 2000 and 𝑦% on the rest          24. Using only 2, 5, 10, 25 and 50 paise coins, what will be
    of his income. If he earns Rs. 700 from Rs. 4000 and 900            the minimum number of coins required to pay exactly 78
    from Rs. 5000 of income. How much he earn in the                    paise, 69 paise and Rs. 1.01 to three different persons?
    income of Rs. 11000.                                                (a) 19                         (b) 20
    (a) 2400 Rs.                   (b) 2300 Rs.                         (c) 17                         (d) 18
    (c) 2200 Rs.                   (d) 2100 Rs.                     25. From each of two given numbers, half of the smaller
17. The rate of increase of the price of petrol per year                number is subtracted so the larger one is three times the
    observed to be two percent more than inflation rate                 smaller. By what percent larger number is greater than
    expressed in percentage. The price of petrol on January             the smaller number.
    1, 1994 is 40 Rs. per litre. The inflation rate of the year         (a) 50%                        (b) 100%
    from 1994 to 1996 expected to be 8% each year. The                  (c) 150%                       (d) 200%
    expected price of petrol per litre on January 1, 1997
    would be                                                                                           SOLUTIONS
    (a) 52 Rs.                     (b) 52.5 Rs.
    (c) 53.24 Rs.                  (d) 54 Rs.                       1.   (a) In starting he has a loss of 20%
                                                                                 80
18. A report consists of 20 sheets each of 55 lines and each             ∴ CP ×     = SP1                                   …(1)
                                                                                        100
    such line consists of 65 characters. This report is                                                     1
                                                                         and S.P1. of a pen =
    reduced onto sheets each of 65 lines such that each line                                  12
    consists of 70 characters. The percentage reduction in               put this value in equation(1)
                                                                               80     1
    number of sheets is closest to                                       CP ×      =
                                                                                   100         12
    (a) 20%                        (b) 5%                                CP = ×
                                                                                    1         100
                                                                              12    80
    (c) 30%                        (d) 35%
                                                                         Now he wants a profit of 20%
19. A milkman mixes 20L of water with 80L of milk. After                        120
    selling one fourth of this mixture he add water to                   ∴ CP ×     = SP2
                                                                                      100
                                                                         1         100    120
    replenish quantity that he has sold. What is the current                  ×         ×           = SP2
                                                                         12        80         100
    proportion of water to milk?                                                    1
                                                                         SP2 =
    (a) 2 : 3                      (b) 1 : 2                                   8
    (c) 1 : 3                      (d) 3 : 4                             Now he will sell 8 pen for a rupee.
20. A piece of string is 40 cm long. It is cut into three pieces.   2.   (c) Let his salary is 100
                                                                                    3
    The longest piece is 3 time as long as the middle-sized              He spends × 100 = 75
                                                                                    4
    and the shortest piece is 23 cm shorter than the longest             His savings is 25
    piece. By how much percentage longest piece is greater               Now increased salary = 120
                                                                                                         10
    than the shortest piece.                                             New expenditure = 75 + 75 ×        = 82.5
                                                                                                        100
    (a) 125%                       (b) 300%                              Now savings = 120 – 82.5 = 37.5
    (c) 600%                       (d) 575%                                                                 37.5 − 25
                                                                         Percentage increment in saving =             × 100
21. Instead of walking along two adjacent sides of a                          12.5
                                                                                                                           25
    rectangular field, a boy took a short cut along the                  =      × 100 = 50% .
                                                                             25
    diagonal and saved a distance equal to half the longer          3.   (d) Let y’s salary = 100
    side. Then, the ratio of the shorter side to the longer side                                  80
                                                                         So x’s salary = 100 ×        = 80
                                                                                                  100
    is
        1                              2                                 y’s salary is greater than x by 20
    (a)                            (b)                                                     difference in salary
          2                              3                               In percentage =          ′             × 100
          1                              3                                                                  X salary
    (c)                            (d)                                        20
          4                              4                               =         × 100 = 25%
22. Fresh grapes contain 90% water by weight while dried                      80
    grape contain 20% water by weight. What is percentage
    of reduction in weight of dried grapes from the fresh
    grape.
    (a) 33.3%                    (b) 66.6%
    (c) 25%                      (d) 87.5%
23. You can collect rubies and emeralds as many as you can.
    Each ruby is of Rs 4 crore and each emerald is of Rs 5
    crore. Each ruby weighs 0.3 kg. And each emerald
    weighs 0.4 kg. Your bag can carry at the most 12 kg.
    What you should collect to get the maximum wealth?
    (a) 20 rubies and 15 emeralds
    (b) 40 rubies
    (c) 28 rubies and 9 emeralds/
    (d) None of these
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4.   (c) Let the C.P = 100                                                          11. (c); Let the original length, breadth and height of the
                117                                                                     room are 4𝑥, 2𝑥 and 𝑥 respectively.
     SP = CP ×
                           100
                                                                                        Area of four wall = height× (perimeter of base)
     S.P = 117
                                      90                                                = 𝑥 × 12𝑥 = 12𝑥 2
     Markup price ×                         = 117                                                                                        1   1
                                      100                                               New length, breadth and height are 8𝑥, 𝑥, 𝑥
         117 × 100                                                                                                                       2   4
     =                                                                                  respectively (according to question given)
                 90
                                                                                                                       1        1
     Markup price = 130.                                                                So, new area of the four wall = 𝑥 (8𝑥 + 𝑥)
                                                                                                                                2       2
     So it is 30% greater than C.P.                                                           17
                                                                                          =         𝑥2
5.   (a) Formula of successively percentage change                                              4
                          ab                                                                                             17𝑥2
                                                                                                                  12𝑥 2 −
     =a+b+                                                                                % decrease in area =             4
                                                                                                                            × 100
                          100
                                                                                                                     12𝑥 2
     Here the final change is zero.                                                       =64.5%
                           ab
     So a + b +                  =0                                                 12.   (a); Maximum marks in total subject
                           100
     Here a = 20% and b = x%                                                              = 100 × 2 + 150 × 3
              20 × 𝑥                                                                      = 650
     20 + x +        =0                                                                                   650 × 60
                     1
                          100                                                             Student got =
                                                                                                            100
     𝑥 [1 + ] = −20                                                                       = 390
                     5
         6
     𝑥 [ ] = −20                                                                          39x = 390
         5
         −100                                                                             X = 10
     =                                                                                    Student marks in five subject is 50, 70, 80, 90 and 100
             6
                     2
     = −16 %                                                                              So, except first subject (50 mark), student got more than
                     3
                 2                                                                        50% mark in each subject.
     = 16 % decreased.                                                              13.   (a); Let total number of people = 𝑥
                 3
6.   (d) Let in starting he uses 10 lit. a day.                                           3                            60𝑥
                                                                                            𝑡ℎ of raised fund = 600 ×
                                                                                          4                            100
     So total fuel capacity of tank = 10 × 10 = 100 lit
                                                                                          = 360𝑥
     Now use is increased by 25%                                                              1                         360𝑥   4
                                  125                                                     So, 𝑡ℎ of the raised fund =        × = 120𝑥
     Now he uses petrol = 10 ×        = 12.5 lit a day                                        4                          3     4
                                                     100                                  According to question given,
                                            Total fuel
     Number of days =                                                                     120𝑥 = (average fund) × Number of people which is not
                                           use in a day
         100                                                                              given
     =               = 8 days.                                                                                      40
         12.5                                                                             120𝑥 = average fund ×        𝑥
7.   (b) 85% of the girls passed and 70% of the boys passed                                                        100
     marks 75% of students passed.                                                        Average fund = 300 Rs.
                                                                                    14.   (d); Let number of man and women be 40 and 60
                                                                                          respectively.
                                                                                          ∴ Number of men earning more than Rs 25,000 = 30
                                                                                          Total number of employees earning more than Rs 25,000
                                                                                          = 45
                                                                                          ∴ Number of women earning more than Rs 25,000
                                                                                          = (45 – 30) = 15
                                                                                          Now, fraction of the women earning Rs. 25,000 or less
                                                                                             60−15    45    3
                                                                                          =        = =
                                                                                               60     60    4
     x + 2x = 420                                                                   15.   (b); Let the first generation number = 𝑥
     3x = 480                                                                             According to question given,
     x = 160
     ∴ Number of girls = 160.
                                                      80
8.   (a) Zinc present in Alloy =                           × 50 = 40 gm.
                                                     100
     Now we need to make it 90%                                                         It mean after one generation number become 4 time of
     40 + 𝑥   90
            =                                                                           first generation
     50 + 𝑥              100
     400 + 10x = 450 + 9x                                                               So 𝑥(4)6 = 4096
     x = 50                                                                             𝑥 = 1 million
     So we needed 50 gm of zinc.                                                    16. (d); According to question given,
                                                                                         𝑥             𝑦
9.   (a) C.P =
               1128 + 872                                                                   × 2000 +     × 2000 = 700      …(1)
                                                                                          100             100
                                 2                                                         𝑥               𝑦
         2000                                                                                 × 2000 +     × 3000 = 900       …(2)
     =                = Rs. 1000                                                          100          100
             2
                                                                  ab                      From (1) and (2)
10. (b) Final percentage change = a + b +                                                 𝑥 = 15%
                                                                 100
                               10 × 10                                                    𝑦 = 20%
     = 10 – 10 –                         = −1
                                100                                                           15           20
     = 1% decreased.                                                                      ⇒      × 2000 +     × 9000 = 2100 Rs.
                                                                                              100           100
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17. (c); Price increase per year = 2% + 8% = 10%             22. (d); Let the weight of fresh grape = 100 kg
    So price of petrol per litre on 1 January 1997               Water content in fresh grape = 90 kg
    = 40 × 1.1 × 1.1 × 1.1 = 53.24 Rs.                           In dried grapes 80% is the dry part which is = 10kg
18. (a); Total number of characters = 20 × 55 × 65 = 71500       So weight of dried grapes = 10*100/80
    Number of pages required, if the report is retyped           = 100/8 kg
                                                                                         100
        71500                                                                    100 −
                                                                                          8
    =           = 15.70                                          % reduction =                 ∗ 100 = 87.5%
        65×70                                                                         100
                                                                                                   4
    Hence, 16 pages are required. Hence, % reduction         23. (b); Price of each kg ruby = crore
                                                                                               3
        20−16
    =           × 100 = 20%.                                     = 13.33 crore
         20                                                                                    5
19. (a); Initially milkman has 100 litre at mixture              Price of each kg emerald = = 12.5 crore
                                                                                               4
    After selling one fourth and adding water to replenish       Price of ruby > price of emerald.
    Quantity                                                     For maximizing wealth you can only purchase ruby.
    milk : water = 60 : 15 + 25                                  Hence, option (b) would be correct.
    = 60 : 40 ⇒ 6 : 4                                        24. (a); Minimum number of coin required to pay exactly 78
                                                                 paise
    Hence, current proportion of water and milk = 4 : 6
                                                                 = 1 × 50 + 10 × 2 + 2 × 4
    =2:3
                                                                 = 7 coin
20. (d); Let middle-sized piece in long = 𝑥 cm.                  To pay exactly 69 paise
    Longest length of piece = 3𝑥 cm.                             = 1 × 50 + 1 × 10 + 1 × 5 + 2 × 2
    And shortest piece = 3𝑥 − 23 cm.                             = 5 coin
    According to question given,                                 To pay exactly 1.01 = 50 × 1 + 25 × 1 + 10 × 2 + 2 × 3
    𝑥 + 3𝑥 + 3𝑥 − 23 = 40                                        = 7 coin
    7𝑥 = 63                                                      Total coin = 19 coin.
    𝑥 = 9 cm.                                                25. (b); Let the larger number = 𝑦
    So, longest piece = 27 cm.                                   Smaller number = 𝑥
                                                                 According to question given,
    Shortest piece = 4 cm.                                             𝑥            𝑥
    required % =
                    23
                          × 100 = 575%                           (𝑦 − ) = 3 (𝑥 − )
                     4                                                 2            2
                                                                      4𝑥
21. (d); Let longer side be-a                                    𝑦=
         And smaller side be-b                                         2
                                                                 𝑦 = 2𝑥
                                                                                 𝑦−𝑥    2𝑥 − 𝑥
                                                                 Required % =         =        = 100%
                                                                                  𝑥            𝑥
    According to question given,
                        𝑎
    𝑎 + 𝑏 − √𝑎2 + 𝑏 2 = (Suppose a in the length of the
                        2
    longer side)
    𝑎
      + 𝑏 = √𝑎 2 + 𝑏 2
    2
      𝑎2
    =    + 𝑏 2 + 𝑎𝑏 = 𝑎2 + 𝑏 2
       4
         3𝑎2 𝑎 4
    𝑎𝑏 =      ⇒ =
           4     𝑏 3
                   𝑏   3
    Required ratio =
                      𝑎     4
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