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Atom Difficult Ques

The document discusses the Bohr model of the hydrogen atom, specifically focusing on the effects of replacing the electron with a muon. It calculates the first Bohr radius and ground state energy, concluding that the correct values are 2.56 × 10^-13 m and -2.8 keV, respectively. The document also includes a hint for solving the problem and provides options for the answer.

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Nikhilesh Dolai
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0% found this document useful (0 votes)
51 views1 page

Atom Difficult Ques

The document discusses the Bohr model of the hydrogen atom, specifically focusing on the effects of replacing the electron with a muon. It calculates the first Bohr radius and ground state energy, concluding that the correct values are 2.56 × 10^-13 m and -2.8 keV, respectively. The document also includes a hint for solving the problem and provides options for the answer.

Uploaded by

Nikhilesh Dolai
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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Result Analysis Summary

Question 12 of 32 | Bohr's Model of Atom | Q4 - Q20

The radius of the first permitted Bohr orbit for the electron in a hydrogen atom equals 0.5 A
˚
and its ground state energy equals
−13.6 eV. If the electron in the hydrogen atom is replaced by a muon (μ )[charge same as electron and mass 207 m ], the first Bohr

e

radius and ground state energy will be:


( m represents the mass of an electron)
e

1. m, eV
−13
0.53 × 10 − 3.6

2. 25.6 × 10
−13
m, − 2.8 eV

3. 2.56 × 10
−13
m, − 2.8 keV

4. 2.56 × 10
−13
m, − 13.6 eV

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Explanation:
Hint: r
2 2
n h
=
2 2
4π mkze

Step: Find the first Bohr radius and ground state energy.
The reduced mass is given by;
mM
μ =
m+M

The Bohr radius is given by;


2 2
n h
r =
2 2
4π mkze

The reduced mass is written as;


me Mnucleus

μ =
me +Mnucleus

207me ×1836me
⇒ μ =
207me +1836me

⇒ μ = 186me

The radius of the first orbit is written as;


me
r1 = × 0.51
186me

−13
⇒ r1 = 2.56 × 10 m

and energy of the first Bohr is written as;


μ
E1 = E
m
186me
⇒ E1 = × (−13.6)
me

⇒ E1 = −2.8 keV

Hence, option (3) is the correct answer.

1x 00:00

(1) 12% (2) 14%

(3) 51% (4) 25%

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