(1) As a Quantity Surveyor calculate the quantities of materials required for 12.
5mm plastering in (1:6) cement sand mortar
for the wall of length 15.5m and height 2.75m both sides
Project: Building Construction
Place: Pokhara-30, Dhungepatan
DETAILED ESTIMATE
S.N. Description of Work No. Length (m) Breadth (m) Height (m) Quantity
12.5mm plastering in (1:6) cement
1 sand mortar for the wall 2 15.50 2.75 85.25
Compact wet volume of mortar= 85.25x 12.5/1000 1.07
Total wet volume adding 15% volume to fillup the depression on the wall=1.07+15% of 1.07 1.23
Total dry volume adding 25% volume to wet volume=1.23+25% of 1.23 1.54
We have a ratio of mortar (c:s) i.e. (1:6)
Volume by one part= 1.54/(1+6) 0.22
Quantity of cement= (0.22x1470)/50 6.47
323.40
Quantity of sand= (0.22x6) 1.32
Quantity of water= (50% of 323.4) 161.7
Prepared by: Checked by: Approved by:
(2) As a Quantity Surveyor calculate the quantities of materials required for 15 sqm of a 230mm thick brick masonry in (1:4)
cement sand mortar with a window opening 1200mm x 1500mm.
Project: Building Construction
Place: Pokhara-30, Dhungepatan
DETAILED ESTIMATE
S.N. Description of Work No. Length (m) Breadth (m) Height (m) Quantity
Brick masonry in (1:4) cement sand
1 mortar 1 15.00 0.23 3.45
Deduction for window opening 1 1.20 0.23 1.50 0.41
Net Total 3.04
Assume brick used of size = 224x108x57 mm Area 15sqmx 0.23
Assume mortar thickness of 8mm
Then, size of a brick including mortar thickness in three dimensions=232x116x65 mm
Total brick required=(3.04x10^9)/(232x116x65)= 1737.86
nearly 1738.00
Compact wet volume of mortar= 3.04-1737.86*(224*108*57/10^9) 0.64
Total dry volume adding 50% volume to wet volume=0.64+50% of 0.64 0.96
We have a ratio of mortar (c:s) i.e. (1:4)
Volume by one part= 0.96/(1+4) 0.19
Quantity of cement= (0.19x1470)/50 5.59
279.30
Quantity of sand= (0.19x4) 0.76
Total quantity @ 130 litre per cum for 3.04 cum masonry in (1:4) = 395.20
Quantity of water for mortar= (50% of 279.30) 139.65
Extra quantity for brick soaking = 255.55
Note: Total quantity @ 150 litres per cum masonry in (1:3)
Total quantity @ 100 litres per cum masonry in (1:6)
Prepared by: Checked by: Approved by:
(3) As a Quantity Surveyor calculate the quantities of materials required for casting 5mx4m size RCC slab 125 mm thick
having duct of 600x600 mm. Assume reinforcement bars 1% of concrete volume. Use M20 grade of concrete.
Project: Building Construction
Place: Pokhara-30, Dhungepatan
DETAILED ESTIMATE
S.N. Description of Work No. Length (m) Breadth (m) Height (m) Quantity
RCC slab casting with M20 (1:1.5:3)
1 grade of concrete 1 5.00 4.00 0.125 2.500
Deduction for Duct opening 1 0.60 0.60 0.125 0.045
Total 2.455
Compact wet volume of concrete= 2.46
Quantity of reinforcement steel @1% of 2.46x7850 kg/cum= 193.11
Quantity of binding wire @1% of 193.11 kg = 1.93
Total dry volume adding 50% volume to wet volume=2.46+50% of 2.46 3.69
We have a ratio of concrete (c:s:a) i.e. (1:1.5:3)
Volume by one part= 3.69/(1+1.5+3) 0.67
Quantity of cement= (0.67x1470)/50 19.70
984.90
Quantity of sand= (0.67x1.5) 1.01
Quantity of aggregate= (0.67x3) 2.01
Quantity of water= (50% of 984.90) 492.45
Prepared by: Checked by: Approved by:
(1:6) cement sand mortar
Date: 2082/01/21
Code:
Remarks
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hick brick masonry in (1:4)
Date: 2082/01/22
Code:
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cum
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a 15sqmx 0.23
Nos
Nos
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litre
litre
CC slab 125 mm thick
of concrete.
Date: 2082/01/24
Code:
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kg
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