ESTIMATION & COST EVALUATION - I(Code : CET - 405) Full Ld ‘Time : 3 Hours wer any five questions. Figures in the right-hand margin indicate marks. 1.(a) ae down the units of measurements for the items : 2 (i) Honeycomb brick masonary. (ii) Reinforcement. (iii) Surface Dressing. (iv) Earthwork infilling. (b) A semi-circular arch has a span of 3 m, thickness of arch is 30 cm and width 40 cm. Calculate the quantity of arch masonry. [5 (© Find the material and labour component required for 10 cum cement concrete 1:2 - 4 with graded stone chips 20 mm down to 6 mm for R.C. work excluding shuttering and reinforcement (AS Per OPWD code). o 2.(a) What is the multiplying factor for painting in poth sides surfaces ofa panelled door and that for a grill gate ? R (b) Calculate the dry materials required for 550 mm? of 25 mm thick DPC in ‘cement concrete (ads): & (c) Find out the quantity ‘of cement concrete a 4:8) required for a trapezoidal square footing of size 2 mat bottom and 30 cm at top ™ 38 cm depth. 3.(a) Mention the type of inclined roof Sa (b) Find out the plinth area of the building in attached drawing. 6 (©) Calculate the quantity of earthwork in excavation of foundation in attached drawing. 7 4, From the attached drawing : (@) Calculate the quantity of 25 mm thick DPC inCC(1:2:4) (5 (6) Find out the quantity of dry material required [4 for the quantity calculated above. (©) Caleulate the Ist class KB Brick works in sub- structure from the attached drawing. [5 5, Fromthe attached drawing : (@) Calculate the quantity of 12 mm thick pt cement plaster (1 : 6) for inside to brickwork. (8 (b) Find out the quantity of dry material required for the quantity calculated above. (6 6. _ Fromthe attached drawing : (@) Calculate the quantity of first class brickwork in cement mortar (1 : 6) in superstructure.[8 () Analyse the rate of the above item with suitable rates of materials and labourers as per PWD Odisha rates. [6 7.(a) What do you mean by lead and lit? [2 (b) What are the two main roles of Divisional Accountant ? R (©) Briefly outline the duties and responsibility of [5x2 (Junior Engineer. (ii) Assistant Engineer.e I eas ahaa Tae be Section on AB |ANSWERS TO 2017(S)| 1.(a) Write down the units of measurements for the items : @ Honeycomb brick masonary. (ii) Reinforcement. (iii) Surface Dressing. (iv) Earthwork infilling. ‘Ans. (i) Honeycomb brick masonary —> Sqm/ im? (ii) Reinforcement > Quintal (iii) Surface Dressing —> m? (iv) Earthwork infiling — m° ()) A semi-circular arch has a span of 3 m, a epness of arch is 30cm and width 40 em, Calculate the quantity ofarch masonry ‘Ans. Data given, Span = 3m Thickness, width, w= f=30em=03m 40 cm= 0.4m . Span _3 Inner radius, t=—3—=3 = 15m t Mean radius, Tm mrt al se 2nty Length of mean are, /,, = —> +. Quantity (Q) =/,, *w x t= 1.7%04x 0.3 = 0.64 cum. (©) Find the material and labour component required for 10 cum cement concrete | ; 2:4 with graded stone chips 20 mm down to 6 mm for R.C. work excluding shuttering and reinforcement (As per OPWD code). Ans. Data given Volume of concrete = 10 cum Dry volum =m, =nx17 <. The material requirement is 4.34 cum sand and 8.68 cum chips. Volume of cement concrete = 10 cum. Proporation = 1:5: 10 ‘Labour Component Quanty ornos | Rate] Cort “Mistri (Head mason’ u ( ) | nos Y150/— per day | Re 15/- Mason id, i 58 | 125/-per day itor fro | oye, Boy or women coe oy oF women cool 18 50/~per da (locluding curing )Bhish 4 “ ‘Sundries, 7 & P ete L eed sumpsum | 40/-Ls, 2.(@) What is the mal “Tot —[- itiplying factor for paintin \ painting inboth sides surfaces of a panelled door and that for a grill gate 2 __ Ans. The muttiptyin sides Surfaces of a is 2.25, It, 8 factor for painting in both Panelled door and that for a grill gate ’Ans. 25 mm thick cement concrete 1 3 DPC for 550m? Volume of concrete = 0.025 x $50 = 13.75 cum ‘Summation of proportion = 1 + 1.5 +3=5.5 15.4. 13.75 ps5 73.85 cum =115.5 bags Sand = 3.85 « 1.5 = 5.77 cum. Stone chips = 3.85 x 3 = 11.55 cum. Water proofing compound = 3% by the wt. of cement. <. Cement = 3 pp 115:5%50=173.25 kg . The dry materials required Cement = 115.5 bags. Sand = 5.77 cum Stone chips = 11.55 cum, WP.C = 173.25 kg. .d out the quantity of cement concrete (1 : 4 : 8) required for a trapezoidal square footing of size 2 m at bottom and 30 cm at top with 38 cm depth. ‘Ans, Find out the quantity of cement concrete (1 : 4 : 8) required for a Trapezoidal square footing of size 2mt at bottom, 30 cm at top with 38 cm depth. © Top area + bottom area 2 ) 032034282 95 ‘Volume = x height Sg +4 «0.38 AP 0.38=0.7771 cum —{__03Mt_ ke} 0.38 Mt '—20m——1t a Material 54 x orm = 0.0921 cum cement 0. Sand = 0.0921 x 4 = 0.368 Metal = 0.0921 x 8 = 0.7368 cum3.(a) Mention the type of inclined roof. available. ‘Ans. (i) Ridged and Gabbled roof Gi) Hipped roof and valley roof (iii) Beam to roof or verandah roof etc. ) Rind out the plinth area of the building in attached drawing. ns, Plinth area of the Building L=8.90 MtB=5.6 Mt. ‘Area = L x B= 8.9 x 5.6 = 49.84 Sqm. © ae the quantity of earthwork in excavation of foundation in attached drawing. ns. Item Particulars of No. Length Breadth Height Quantities Explanatory aaa Note or Remarks 1. Long wall back 1 93 09 0.9 7.53 cum 9,9 8.64242 =9. ( +545 9.3m engi) 2. Room No. 1 Front wall 1 52 09 0.9 4.2 cum 2-2 3. Room No. | short wall 2 44 0.9 0.9 7.13 cum (s9+242-same Length 9 9 3-2-2 24.4 mt Leny (33 27204™ es) 4, Room No. 2 short wall 1 300 09° 092.43 cum 9 9 .0 + — -— = 3.00 mt. Li (s0+8 3 cng) 5. RoomNo. 2 Cross wall 1 3.4 0.9 0.9 2.75 cum (43 -2 223.4 Lengts) 2 6. Verandah Front Dwarf wall 1 4.15 06 = 06 1.49 cum 9,6 (3-3 2 7. Verandah side dwarf wall 1 155 06 = 06 =~ 0.56 cum =4.15Lengt] Total 26.1 CUM.EAE [eetwation « coor evauavion 1] 4. From the attached drawing : (a) Calculate the quantity of 25 mm thick DPC q in CC (1:2: 4). Ans. 25 mm thick damp proof course in c.c. (1 : 2: 4) Item Particulars of No. Length Breadth Height Quantities Explanatory No. Items of work or Depth Note or a 1, Long wall back 1 90 04 - 3.6 sqm 44 (sor4-4 =9.0Mt Lenets) 2. Room No. | Front wall 1047 04 = 1.9 sqm 44 434545547 ( +t AT Mt Length) 3. Room No. | short wall. 2 53 04 - 4.24 sqm 4.4 §3-—+5=53 ( att SaMt Lenets) 4, Room No. 2 short wall 1 3.0 04 - 1.2 sqm 44 3.0+-+-5 =3.0 Mt Length ( +577 73.0 Mt Leng 5. Room No. 2 Cross wall 1 39 04 - 1.56 sqm («2-4 4o39Mt Length 22 Total 12.50 sqm (b) Find out the quantity of dry material required for the quantity calculated above. ‘Ans, Find the quantity of dry material required for the quantity calculated in Q. No:3(b), Quantity of 25 mm thick D.P.C. in C.C. (1: 2:4) = 11.54 sqm Volume = 11.54 x 0.025 = 0.2877 cum 2877 Calculated material 7 7 = cement = 0.064 cum sand = 0,064 x 2 = 128 cum sand chips 0.064 x 4 = .256 cum chips. (© Calculate the 1st class KB Brick works in sub-structure from the attached drawing. . ' oe Ans, Data insufficient. » 5. From the attached drawing : / (@) Catoulate the quantity of 12 mm thick pt cement plaster (1 : 6) for inside to brickwork ‘Ans. 12 mm thick cement plaster (1: 6) for in side and outside to Brick work.Si SAMPLE PAPERS, No. Length Breadth Item Particulars of Height Quantities Explanatory No. Items of work or Depth Note or Remarks (1) INSIDE Room No.1 2 (+4) - 3.0 5.4 sqm Total perimeter of room 2(5+4) Assuming room height 3 mt as not given in the drawing Room No. 22(2.7 + 4) = 3.0 40.2 sqm Front verandah Room No. 2 side 1 40 - 3.0 12.0 sqm Room No. | side 1 20 - 3.0 6.0 sqm Verandah wall side 2 03 = 3.0 1.8 (End sides) Middle pillar in side face three side 1 09 - 3.0 2.7 sqm (0.3+03+03=0.9) End pillar two sides 1 06 - 3.0 1.8 sqm (3+.3=0.6) TOTAL 118.5 sqm DEDUCTION Door opening 2 12 - 21 5.04 sqm Window opening 1 10 - 15 1.50 sqm 6.54 sqm Net INSIDE plastering = Total — Deduction = 118.5 ~ 6.54 = 11.96 Sqm OUTSIDE PLASTERING Back long wall 1 89 - 3.0 26.7 sqm Lift side wall 1 56 - 3.0 16.8 sqm Front wall of room No. 1 46 = 3.0 13.8 sqm Right side wall 1 33 - 3.0 0.9 sqm Middle pillar front side 1 06 = 3.0 1.8 sqm TOTAL 89,01 sqm DEDUCTION Window opening 5 10 a 15 77.5 sqm Net = Total — deduction = 89.01 — 7.5 = 81.51 sqmFind out ) wad enttne quantity of dry material required for the quantity calculated above. linet quantity of dry material required for the quantity calculated in Q. No.3(b), Quantity of 25 mm thick D.P.C. in C.C. (1:2: 4) = 11.54 sqm. ‘Volume = 11.54 x 0.025 = 0.2877 cum pee Calculated material = ement = 0.064 cum sand = 0.064 x 2= 128 cum sand chips 0.064 x 4 = 256 cum chips. 6. From the attached drawing : (a) Calculate the quantity of first class brickwork in cement mortar (1 : 6) in superstructure. Ans, First class brickwork in cement mortar 1 : 6 in foundation and plinth with standard bricks ‘Ans, First class brickwork in cement mortar (1 : 6) in foundation and plinth. Consider first 10 cum. Calculate of materials ‘Cement = 4 =0.57cum Sand = 0.57 x 6 = 3.42 cum Labour grrg Unit = 1 cum Partic Quantity Rate Amount Rs. P Rs. P (@) Materials Brick (kiln) Metric 20 em 10m x 10.em $000 nos. 2900.00nos _14500.00 Traditional 125.4 x 12.4 * 7.6cm 4100 nos 22.9 mx 11.40m%7.6em 5000 nos. Sand 3.42 cum Cement 0.57 cum (&) Labour Head mason 08. 125/day 62.50 Mason 7 nos. 115.00/day 920.00 Mazdoor (2no. as Bhisti) 15 nos. 80/day 1200.00 Contigencies, T & P, risk ete Lsq(a+d) LS 10531 2116781 (©) Water charges @ 1% of total Total 211.68 (@ Profit and overhead @ 10% oif total Total 21379.49 2137.95 -. Rate percum Rs = 2361.74, Grand Total 23517.44 (b) Analyse the rate of the above item with suitable rates of materials and labourers as per PWD Odisha rates. ‘Ams. Cement concrete in foundation (1 : 2: 4)Consider first 10 cum, Calculation of materials. ‘Cement Da 2.2cum 7 Sand=2.2«2=4.4 cum Stone chips = 2,2 x 4=8.8 cum. Labour Gang Particulars Quantity (@). Materials Stone ballast (40 mm) 8.8 cum Sand 4.4cum Cement 2.2 cum = 66 bag (b) Labour ‘Head mason no. Mason Ino. Mazdor 20 nos. 1 Contigencies, T & Pete Ls>%a +b) (©) Water charges 1% of the total (4) Profit and over head @10% of the total ~. Rate per cum = Rs. 2596.634 7.(a) What do you mean by lead and lift ? Ans. Normally earthwork is estimated for 30 m lead for distance and 1.5 m lift for height or depth, and the distance of 0 m and the height of 1.5 m are known as lead and lift. Normal rate for earthwork is for 30 m lead and 1.5 m lift. For greater lead or lift the rates will be different for every unit of 30 m lead and for every unit of 1.5m lift. (b) What are the two main roles of Divisional Accountant ? ” ‘Ans, Main roll of divisional account « The divisional account play singularly vital role in proper accounting of public work transaction render prompt. . Timely advised to divisional officer. SAMPLE PAPERS) Unit = 1 cum Rate Amount Rs P Rs P 770.00/cum 6776.00 350.00/cum 1540.00 200.00/bag —-:13200.00 125.00/day 62.50 11S/day 115.00 80/day 1600.00 Ls 78.55 Total 23372.05 233.72 Total 23605.77 2360.57 Grand total 2596.34 + They have the right to use register of divisional accounts objection book. (©) Briefly outline the duties and responsibility of: @ Junior Engineer, Ans. Ans. Duties of Junior Engineer : The Junior Engineers are directly incharge of works they are to look after the execution and management of all works in their section and they are required to do all works connecting with stores, accounts and execution of works They should have sufficient fore-sight and should plan well in advance. They have to stay at the site of the ‘works and supervise the works and to maintain quality and progress of the works, They have to take ‘measurements of works done under their charge andprepare bills or payment. In general the duties of Junior Engineer may be classified and they are to control the quality of works under three heads. Works (i) Store Gi (Works : They are to supervise the execution of works on building, canal, road etc, and see the progress of works as they are directly incharge. (i) Store : They are entirely responsibility for all stock and store, tools and plants etc, and maintain the account of stock in upto date correctly. They are go safe guard the stock properly and maintain the articles are properly stacked and stored without any damage. (iii) Accounts : Regarding account the Junior Accounts Engineer has to maintain correctly with day to day receipt and issue. The imprest cash account has to be maintained regularly and submit the same account to the $.D.O. or Executive Engineer after closer in monthly basis. (ii) Assistant Engineer. Ans. Ans. Each division is divided in the nos of sub-divisions, each under change of S.D.O (Sub- Divisional Officer) or Asst. Engineer. Asst Engineers are directly in change of work falling under their charge and have to execute, supervise and manage the works and have to maintain the quality and progress of work. There may be more Asst. Engr (A.B) in a sub-division, if the work is heavy, who are directly responsible to the Executive Engineers with respect to the works. The S.D.O has the power of disbursement (paument) and has to maintain initial account and has to submit account monthly to the divisional officer. The work load of SDO or AE is 10 to 15 lakhs, Before preparing a bill, the JE must satisfy himself, that the work has actually been executed in accordance with the detailed measurement recorded and personally inspect all works of any magnitude before recommending final payment. The A.E take measurement of all important works and he must satisfy himself about the correctness of all the measurement recorded. [Code : CET - 405] Full Marks : 70 Time : 3 Hours Answer all questions. The figures in the right-hand margin indicate marks. 1. Estimate the quantities of the following items of work of the building (for the attached figure, answer any four questions) : (a) Earthwork in excavation in foundation. [10 (b) Cement concrete in foundation (1 : 4 : 8).[10 (© First class brick work (1 : 4) in foundation and plinth. to (@) 40 mm thick DPC with C.C. {1:2:4). [10 (©) First class brick work (1 : 6) in super-structure. flo 2. Calculate the dry materials required for the quantities calculated in Question No. 1 (b) and 1 (c). [10 3. Analyse the rate of the following items by taking cost of labour as per scheduled of rate of OPWD and assume material cost : [5x2 (a) Cement concrete in foundation (1 : 4 : 8). (b) First class brick work (1 : 6) in super-structure. 4, Write notes on (any four) : DAx4 (a) Name different Government and public sector organisation employing Civil Diploma holders in Odisha State. (b) Duties and responsibility of Junior Engineer. (©) Lead and lift. (@) Plinth area and carpet area of building. (©) Sundries and overhead charges.ANSWERS TO 2016(S) 1. Estimate the quantities of the following items of work of the building (for the attached figure, answer any four questions) : (a) Earthwork in excavation in foundation, (b) Cement concrete in foundation (1 : 4 : 8). (© First class brick work (1 : 4) in foundation and plinth. (@) 40 mm thick DPC with C.C. {1:2: 4). (©) First class brick work (1 : 6) in super-structure. Ans, Centre to centre lengths Room Long walls - 3.50 + 4.00 + 30 + (2 x 30/2) = 8.10 m combined total length. Room Short walls - 4.00 + (2 * .30/2)=4.30m ‘Verandah Front ~ Extreme outer length at plinth — (2 « .30/2) = {3.50 + 4.00 + (3 x .30) + (2 « .05)} -.30 = 8.20m Verandah sides - 250450420 75mDETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 5) Tem] Particulars of Helghe No. | items and details | No. |Length/Breadth] or |Quantity| Explanatory nate of works Depth 1. | Earthwork in exea- vation in foundation— Rooms Long walls 2 |9.00m| 90m} 90m) 14:58 |L=8.10+.90=9.00m Short walls 3 |3.40m| 90m} 90m| 8.26. |L=430-.90=3.40m Yerandah front 1 |8.90m| .70m| 90m} 5.61 |L=8.20+.70=8.90m comneah aiseg 2 |195m} 70m) 90m) 246 |L=2.75 20-20 = 195m Seep 1 |2.90 m|1.00m| .15m| 0.44 | L=2.70 + (2 .10) =2.90 m Total | 31.35 cum 2, | Earthwork in filing in plinth— Room (i) 1 [390 m|3.40m| S4m| 7.16 Room (ii) 1 [3.90 m|3.90m| 54m] 8.22 Verandah 1 |7,90m}2.40m| 54m} 10.23 Total | 25.61 cum 3. | Lime conerete in foundation Rooms — Long walls 2 |9.00m| 90m] .30m| 4.86 | May be taken 1/3 of excavation. Short walls 3 |340m| 90m| 30m] 275 Verandah front .:.| 1 | 890ml .70m{ .30m| 1.87 Verandah sides 2| 195m) 70m, 30m] 082 Step 1 |290m]1.00m| 15m} 0.44 Total | 10.74 cumNe creas Ne a ity] Explariatory note eee jo, | Length jBreadth| ce , Quantity} Exp! 4, | T-etass Brick-work in Foundation and Plinth in 1: 6 cement mortar— ROOMS — Long walls — Ist footing 2 |880m] .70m| .20m| 2.46 }L= 8.10 +.70= 8.80 m 2nd footing 2 |8.70m| .60m| .10m| 1.04 |L=8,80-.10=8.70m 3rd footing 2 |.60m| som| 10m) 0.86 |L=8.70-10=8.60 m Plinth wall 2 |8.50m| 40m| 80m| 5.44 |L=8.60-.10=8.50m Short walls — Ist footing 3 |3.60m| 70m} 20m] 1.51 |L=4.30-.70=3.60m 2nd footing 3 |3.70m| .60m| 10m] 0.67 |L=3.60* 10=3.70m 3rd footing 3 |3.80m| 50m] 10m] 057 |L=3.70+.10= 380m Plinth wall 3 |3.90m| 40m| 80m) 3.74 |L=3.80+.10=3.90m VERANDAH— Front wall (long)— Ist footing 1 |8.70m| .50m| 20m] 087 |L=8.20+.50=8.70m 2nd foot'ng 1 |8.60m| 40m) 10m] 0.34 |L=870-.10=8.60m Plinth wall 1 |850m| 30m) 90m| 230 |L=8.60~.10=8.50m Side wall (short) — Ist footing, 2 |2.15m| 50m| 20m] 043 |L=2.75 ~$0 29 5m 2nd footing 2 |2.25m| 40.m| 10m) 0.18 |L=2.75 -$0_$0.-9 250 CO. | 20.41== Item) * Height | No. | items and details) No. jLength ‘OF. |Quantity| Explanatory note Depth Plinth wall 10 em BE. | 2041 above footi me 2 |235m| 30m|o.tom| os |1=2.75--$2-32=2.35m Plinth wall remain- ingportion =... | 2 [240m] 30m] 80m] 1.15 | L=2.75 00-240 Steps — Ist step 1 {2.70m|] 90m] 15m} 0.36 2nd step 1 [210m] 60m] .15m] 0.19 3rd step 1 ]1.50m| 30m] 15m] 0.07 - Total | 22.32 cam 5, |2.m Damp proof course Rooms — Long walls 2 |850m| 40m] — | 6.80 | Length, breadth same as for plinth wall. Short walls 3 |3.90m| 4om| — | 4.68 Total | 11.48 Deduct door sills ...| 2 [120m] 40m] — | 0.96 Net | Total | 10.52 sqm 6. | I-ciass Brick-work in superstructure in lime mortar— Rooms — Long walls 2 |8.40m| .30m]4.00m| 20.16 | Length — Out to out. Short walls 3 |4.00m| .30m|4.00m| 14.40 | Length — Into in. Ver. above lintels (over pillars)— ‘ Front (long) 1 [840m] .20m| 30m] 0.50 Sides (short) 2 |250m] .20m] 30m) 0.30 Parapet — Over Rooms — Long walls 2/840 m| 20m} .60m| 2.02 |Ht.=47 + 10+3=60em : = 60m Short walls 2 [420m] .20m] 60m] 1.01 | L=4.00 + (2x .30) - (2 x .20) = 4.20m co. | 38.39 |Lebour Mistri (Head mason) 13 ho. 850,00 per da mn ; “ Masot an 2 nos. 300,00 per day Maoicor ; 12 nos. 220.00 per day Boy o aoe ieocli 20 nos. 220.00 per day Bhishti (including curing) 6 nos. 200.00 per day Forms ete. (according to " requirements) Lump sum 1300.00L.S. Sundries T. and P. etc. Lump sum 150.00LS. Total Total of materi a vib water changes of materials and labour ‘Add 10% concentrates profit Grand Total Rate per cum = Rs. $4943.40/10 = Rs, $494.00. (b) Dry materials for I-class Brick work in super structure with 1 116.70 600.00 2640.00 4000.00 1200.00 1300.00 150.00. 1006.70 49276.70 739.00 4927.70 5943.40 for 10 cm + 6 cement sand mortar (TAke - 10 cur). ae Quantity Rate Cost Rs. P. Bs. P Materials Brick I-class (500 brick per cum) 5000 nos. 4500.00 2500.00 Cement (13.5 bags) 0.45 cum 7650.00 3442.00 Sand (local) 2.7 cum 700.00 1890.00 Total 27832.50 Labour Mistri (Head mason) 1/2n0, 350.00 per day 172.00 Mason ....- 10 nos. 300.00 perday 3000.00 Mazdoor (Belder) 7 nos. 220.00 per day 1540.00 Boy or woman coolie 10 nos. 200.00 per day 2000.00 Bhishti 2 nos. 200.00 per day 400.00 ran Lume Fao 9000 i . Lump sum 90. Y Sundries, T, & P ete, Total 498.00 Total of materials and labour = 35.317.50 Add 114% water changes So ‘Add 10% concentrates profit crmttwal © S305 +. Rate per cum = Rs. 39373-25/ 3. Analyse the rate of the follor assume material cost = . . (a) Cement concrete in foundation (1 = Ans. Description ty Material 40 mm size metal A Sand c 2 Cement 17 10 = Rs. 3938.00 for 10 cum. wing items by taking cost of labour as per scheduled of rate of OPWD and 4:8). Unit Rate Cost RB. PB Rs. P cum 1879.68 1804.49 cum 763.84 366.64 cum 760.72 1308.99+ Total = 3479.57(>) Labour Mason 2nd class mead 0.18 nos. 240.00 43.20 women mulia 3.90 nos. 200.00. 780.00 Total = 823.20 (©) Add to OHC on (a +b) 7.5% 193.02 © Add to continuous profit 7.5 % 193.02 tate per one cum (a = b+e) 4688.81 1% labour less 41.68 For 1 cum (©) First class brick work (1 : 6) in super-structure. Ans. First class brick work (1 : 6) in super-structure. Ans, Description Qy Unit Rate Cost Rs. PR Rs P (a) Material Ist class K.B.brick 350 nos. 7619.50 2666.83 sand 0.28 cum 763.84 213.88 cement 0.672 cum 160.72 511.20 Total = 3391.90 (>) Labour Ist class mason 035 no. 260.00 91.00 2nd class mason 1.05 no. 240.00 252.00 ‘Men and women mulia 2.96 no. 200.00 592.00 Total = 935.00 (© Add to OHC on (a+b) 7.5% Rs. 248.14 (@Add to CP. 75% Rs. 248.14 Total = Rs, 4823.18 ‘Add cum 1% 48.23 Rs. 4871.41 4.(a) Name different Government and public sector organisation employing Civil Diploma holders in Odisht State. ‘Ans. Govt. organisation employing civil diploma holders in ODISHA state are > OPSC, SSC —» Housing Board Organisation > PWD, Irrigation department, NHPC, R & D department, RWSS ete, Public sector organisation employing civil diploma holders in ODISHA state = Indian oil | JINDAL, TATA, ONGC, OPTCL, NALCO, SAIL, HAL etc. () Duties and responsibility of Junior Engineer. ‘Ans; Duties of Junior Engineer : The Junior Engineers are directly incharge of works they are to look after the execution and management of all works in their section and they are required to do all works connecting with wre ex, accounts and execution of works. They, should have sufficient fore-sight and should plan well in advanct They have to stay at the site ofthe works and supervise the works and to maintain quality and progress of the Work They have to take measurements of works done under their charge and prepare bills or pay In general the duties of Junior Engineer may be classified and they are to control the quality of works under aces heads, (i) Works (ii) Store - Gi) Accounts _—Works : They are to su cof works on building, canal, road etc. and s of works are are directly incharge, Gi) Store : They are entirely | an stock and store, tools and plnat, ‘esponsliy fo the account of stock in upto date correctly They we ard the stock cetly. They are go safe gu Properly and maintain the article are properly stacked and stored without any aaa _ Gil) Accounts : Regarding account the Junior Engineer has to maintain correctly with day to da receipt and issue, The imprest cash account has to be maintained regularly and submit the same account to the $.D.O. or Executive Engineer after closer in monthly basis. (¢)\ Lead and lift. Ans. Normally earthwork is estimated for 30 m lead for distance and 1.5 m lift for height or depth, and the distance of 0 mand the height of 1.5 mare known as Jead and lift. Normal rate for earthwork is for 30 m lead and 1.5 m lift. For greater lead or lift the rates will be different for every unit of 30 m lead and for every unit of 1.5m lift. (@ Plinth area and carpet area of building. Ans. Plinth area is the built up covered area measured at the floor level of the basement or of any storey of a building, Plinth area can be calculated by taking the external dimensions of the building excluding plinth offsets. ‘The carpet area is the floor area less the area of the following portions. Verandah, corridor and passage, entrance hall and porch, staircase and stair cover , bathroom and lewatory and kitch and pantry, store, canteen, shaft and machine room for lift, air conditioning duct and plant room, shaft for sanitary piping. (© Sundries and overhead charges. ‘Ans, Sundries : It is the item of work which cannot be measured but it is required in the work at site: ipervise the execution ee the progress A lumpsum amount is ee to meet sundry , ee unhappen thing held. ‘Overhead Charges : It includes general office expense, rant, tax, then purcbase of stationbry petting of paper, telephone bill, electric bills and postage etc. This is expense of indirect and not productive. {CET - 405} Time : 3 Hours Full Marks : 70 ‘Answer any five questions. Figures in the right-hand margin indicate marks. 1. Answer any five questions : [2*5=10 (@) What are the units of dimension of the following materials and works ? (i) Glass panes (ii) Stone blocks (iii) Reinforcement (iv) Formwork (b) What is the size of the nominal brick and tranditional brick ? (©) Define Lump sump. (d) How the labourers are classified as per schedule of rate of Govt. of Odisha ? (@) What is the standard weight of a 12 mm diameter HYSD bar of lm? (® How can you estimate the requirement of binding wire ? (g) Explain the term A.R.Estimate. 2. Answer any four questions : [4x 5=20 (a) Explain the duties and liabilities of Owner, Engineer and Contractor. (b) Explain the different kinds of arbitration according to Arbitration Act 1940. (©) Differentiate between Revised Estimate and Supplementary Estimate. (@) Calculate the volume of the earthwork of the following fig.1.; te(L: 1: (©) Calculate the dry material required for 550 m? of 25 mm thick DPC cement concrete ( 3). ; . in figure-2. 3. Prepare a detailed estimate of a building from the given plan and cross-section as shown i ig 6 (a) Earthwork excavation for foundation in hard soil. No (b) 1* class brickwork in (1 : 4) in foundation and plinth, [4 (c) 2.5 cm thick DPC of cement concrete in (1:3 : 6). [lo () 1* class brickwork in 1 : 6 in super structure. ito (©) 12 mm thick cement plaster inside and outside the building. ‘VERANDAH(2) What are the units of di “ following materials aod yaeension of the @ Glass panes (ii) Stone blocks (ii) Reinforcement (iv) Formwork Ans. (i) Glass Panes : ; on m, thickness in mm, Length and breadth in om (ii) Stone Blocks : All dimensions are in em. (iii) Reinforcement : Quintal (iv) Formwork : Sqm () What is the size of the nominal brick and tranditional brick? ‘Ans. Size or nominal brick -2anx 10am 10 cm. Size of traditional brick ~ 19cm 9 em x 9 cm (©) Define Lump sump. Ans. Lumpsum in Estimating : Sometimes a jumpsum rate is provided for certain small items for which detailed quantities cannot be taken out easily or it takes suficient time to find the detail as front architectural or decoration work of a building, fire-place, site cleaning and dressing etc. (d) How the labourers are classified as per schedule of rate of Govt. of Odisha ? Ans. The labours are classified as per the following ( Head mason (mistri)/most skilled. i) Mason/Semi skilled (iii) Mazdoor/Non skilled (iv) Boy or women coolie/for helping in the work during execution. (¥) Bhishti/Most unskilled. (vi) Carpenter/skilled (vii) Blacksmith/Semi skilled (viii) Painter/Skilled. (© What is the standard weight of a 12 mm diameter HYSD bar of 1m? ‘Ans. The standard weight ofa 12 mm dia. HYSD bar or one meter is 0.89 kg. (®) How can you estimate the requirement of binding wire ? ‘Ans. According to IS 2502-1963, bars crossing, each other where required, shall be secured by binding wire (annealed) of size not less than 0.90 mm, in such a manner that they will not slip over other at the time of fixing and concreting. : — Every compression bar shall be tied at least in two perpendicular directions. (g) Explain the term A.R.Estimate. ; ‘Ans, A.R. Estimate also known as Annual Rapair Estimate. — It is also named as Annual Maintenance (Am) estimate. — After completion of a work it is necessary to maintain the same for its proper function and for the same, an estimate is prepared for the items which require renewal, replacement, repairs etc. in the form of a detailed estimate. 2.(a) Explain the duties and liabilities of Owner, Engineer and Contractor. Ans. (i) The duties and liabilities of the Owner and Employer are mainly as follows : — To appoint an Engineer and give him power to work on his behalf. He will also appoint other staff is consulation with the Engineer to carry out the project work. — To intimate the Engineer about the requirements of the project including his desired time of complete. — To obtain necessary sanction for its construction from complement authority in collaboration with the Engineer. — To give necessary section of the estimated cost to the Engineer. — To enter into a contract with the contractor by signing the contract documents. _~ To give possession of the site to the contractor. (i) i duties and liabilities of the Engineer : ‘he contrast imposes heavy responsibilities uy e Engineer. The owner employs a consulting Ei “pon hichimay cover the terms, condition and scope of work ign and detailed engineering i management, and stor ae ee © control, inspection assurance, construction s1 jon cost a tuality i supervision, cost control and~ To cheek up the soil conditions. ora of tender paper, nvting tender on imreriog the Over, sale ofthe tender paper ater a ing the soundness of the contractors, Picparation of comparative statement andadvsing Tes Tegarding acceptability of the tender. > To supervise the work and ensure that the Panes and specifications are faithfully - Hla duty of the Engineer to give necessary ions, to supply working drawing to the Contractor so that the progress of work is not 7 hampered due to his delayed direction. (iii) Contractor’s duties and liabilities In prescribing the duties and liabilities of the contractor, it should be kept in mind that the main Objective of the contract method is that the work shall be done by a skilled contractor in order to relieve the owner of all responsibilities in connection with management, purchase of materials, employment of labour, and construction operations. The contract price is assumed to include a reasonable profit to the contractor for the accomplishment of the objective. The vital duties and liabilities of a contractor are covered by the conditions of contract. Some specific duties and liabilities are mentioned below : — It is the duty of a contractor to inspect the site and study soil condition before tendering. He should investigate the accessibility, availability of electric power, water supply condition for construction purposes, and the local law and order condition. He should collect the local rates of materials and labour and accordingly prepare analysis of rates for all the items in the schedule attached to the tender. It is the duty of a contractor to go through the different clauses of the conditions of contract, fssue rates of materials, tools and plants if any before submission of tender. _ After receiving the work order itis the duty of a for to start the work in the time and carry accordance with the contract ifications. Any ommission in or any extrawork required to the notice of the Engineer ions or approval should be such work. contract ‘out the work in drawings and spec the specification, should be brought and his written direct obtained before starting should be required to designate cee iho is authorised to act for him entative wl on matters pertaining to the contract when he imself is not available. - Al voyalis ‘and lincense fees are to be paid by the contractor and he shall be responsible in all cases of suits or claims for infringement of patent rights. The contractor 1S usually required to provide all building permits in connection with os t kinds of arbitrati Explain the different kinds on a secording to Arbitration Act 1940. ‘Ans. Different kind of arbitration according to arbitration act 1940 are as follows : — Except where otherwise provided in the contract, all questions, disputes, meaning, claim arising out or or relating to the contract, estimates, specifications, designs, drawings, quality of workmenship or materials used on the work, instructions, order on those conditions on otherwise concerning the works on the execution or failure to execute the same arising at any stage shall be referred to the sole arbitration of the chief engineer of the department. = If the chief engineer be unwilling to act as such arbitrator he shall appoint a person as an arbitrator and such appointment shall be valid. — Its also a term or this contract that no person other than a person appointed by the chief engineer shall out as arbitrator. — The person thus appointed shall be the sole arbitrator and his award shall be final and binding onalll parties to the contract, unless it is set aside by the court. — The contractor invoking arbitration shall specify the disputes to be referred to arbitration together with the amount of claim. (©) Differentiate between Revised Estimate and Supplementary Estimate. Ans. Revised Estimate:- ue foguired when the sanctioned amount i due to change of rates or addition of works fairly dependent on the work at first Sanctioned.so a revised estimate is due to materi Tenn fom whe original proposal. fiateer aes aa with a comparative statement jowing the probale variations for quantity. rate and amount aj item of work involved in the pa each itemGi) are simats i roquied due to change of rate or quantity of materials, so no additions or revisions of es (® This is required due to supplementary works which are fairly indendent of the signer toned, so supplementary estimate is due to material deviation of a structural nature from the ® p No comparative abstract form is required. This is an estimate for additional works only. The abstract © Sopcast eertcne tania nae vast ager a revisions of deaving voy tee 10 change of design. so additions or (@) Calculate the volume of the earthwork of the following fig.1. 60 cm eat Fig. 1 Ans. Earth work in Execution = [Total centre length — (2 * ; xb)xbxd Total centre length = 2 x 5.2+2* 5.2 = 10.4 + 10.4 = 20.8 m. Earth work in execution = 20.8 - 0.48 = 19.52 cum. (©) Calculate the dry material required for 550 m? of 25 mm thick DPC cement concrete (1 : 1 : 3). ‘Ans. For 10 cum of concrete raw material required is dividing by 15.2. 15.2__ 152 T4385 = 167.2 cum (46 bags). Sand —> 3.04 1 = 3.04 cum — 167.2 cum. ‘Cement — Stone -» 3.04 x 3 = 9.12 cum > 501.6 cum. Materials | Quantity ,[__Gement |" 1672cum,, . now Sand 167.2cum Stone 301.6 cum 3. Prepare a detailed estimate of a building from the given plan and cross-section as shown i figure-2. Ans,(@) Long and Short wall Method Centre to centre distance — Rooms — Back and front, Long walls (2 nos.) = 443640204 920 ens Sides, Short walls (2 nos.) 4.2 +2 x oe Partition (having different sec.) =42+0.30 =45m ‘Verandahs ~ Entire back and front, Long walls (2 nos.) 0.20 = Q8+020+2%25)+2x Front verandah, Short walls (2 nos. = 1.85 m, (B) Centre line method — Length of centre line for — Main wall 30 em Outer walls of rooms = 2 [(4 + 0.20 + 3.6 + 0.30) +(4.2+0.30)) = 25.20 m. 20 cm walls Partition of rooms = 4.2 + 0.30 = 4.50 m. Front and back of building — 0.20 2[@8+0.20+2%25)+2% ——]. = 16.40m Front verandah sides — 0.20 , 0.30 =2{1.8- =3.70 (1 Bas } 70m. Back verandah sides and walls and 0.30, 0.20 Kitchen front = a2 44050,,020) = 7.95 m. Total = 32.55 m. Note that the number of joints = 7 nos. with main wall and 1 No. with 20 cm wall. Excluding partition wall total length of centre line =32.55-4.50 =28.05 m. Back verandah sides and kitchen front, Short Number of joints = 5 nos. with main wall and 1 No. 030 , 0.20 walls (3 nos.)= 24+-5-+-5> = 2.65 m with 20 m wall, SL.No. Description of Item No L, BH. Qty. Explanatory Notes m mo So Ear i cewvation (@) For foundation trenches Long-Short wall method — Long walls 2 8.90 oso r 2 3.70 0.80 Short walls TL. 25.20 0.80 Partition, Short walls 1 3.70 0.80 ‘Verandahs — fa 8.90 0.60 Long walls = 2 0.90 8.90=8.1+0.80 0.90 zal +o 090 1g 890814080 0.65 3.70=4.50~0.80 0.65 8.80=8.2 +0.60© 2.5 cm thick DPC of cement concrete in (1:3:6). Ans. 2.5 cm thick D.P.C. of cement concrete (1 : 3 : 6) Long-Short wall method — Rooms — Long walls Short walls Partition Short wall Verandahs — Long walls Front Short walls Back Short walls OR Centre line method — Main walls Verandah and 20 cm walls ... 0.30 0.20 Reemey) 2. 2 Deductions for — Door sills D Door sills D, Back veran. openings 7 2 8.40 030 - 2 4.20 0.30 - TL. 25.20 0.30 - 1 420 020 - 2 8.40 0.20 - 2 1.60 0.20 - 3 240 0.20 - TL. 31.40 0.20 Total before dedution 1 25.20 0.30 - 1 31.40 0.200 - Total before dedution 4 1.00 030 - 2 090 020 - 2 230 020 - Net total by andy method (@ 1* class brickwork in 1 : 6 in super structure. Ans. Ist class brickwork in super structure with cement mortar (1 : 6) (a) Wall — Long-Short wall method — Rooms — Long walls Short walls Partition Short walls Verandahs — Long walls 2 840 0.30 3.80 2 4.20 0.30 3.80 TL. 25.20 030 3.80 1 420 0.20 3.80 2 840 0.20 3.00 8.40 = 8.10 + 0.30 7.56 628 2.40 = 2.65 ——J~— > 7.56 6.28 3.40=32.55 13.84 1.20(-ve) For front verandah 0.36(-ve) D.P.C. is for openings. 0.92(-ve) also 1136 sq.m, 28.73 3.19Front Short walls Back Short walls OR Centre line method — Outer walls of rooms... 1 Partition wall wd ‘Verandahs and kitchen wall only 1 co. BE. . (b) Parapet wall by any method Back and front out to put... 2 Sides inner to inner, 2 Projections — Back and front out to put... 2 Sides in to in ~ 2 Deduction for — () Door openings D with intel .. Door openings D, with intel ... Window = W . Window W(comb) . Window = W, . Clearstory windows, CW ... Clearstory windows, CW, ... Shelf openings S Front verandah openings, Front ... Sides - Back verandah openings... 2 Lintel over pillers 1 Ss we ‘Net (@) Inside - (i) Rooms ~ Bigger room, Long walls 2 Bigger room, Short walls 2 co. o BI a Bigger from Ceiling 1 1.60 0.20 3.00 2.40 0.20 3.00 27.40 0.20 3.00 Total of (a) 25.20 0,30 3.80 420 0.20 3.80 27.20 0.20 3.00 Total of (a) 840 0.20 0.63 440 0.20 0.63 8.60 0.100 0.10 480 0.10 0.10 Total of (a) + (b) 1.00 030 2.25 0.90 0.20 2.25 1.10 030 1.35 2.70 030 1.35 0.90 0.20 1.35 0.75 030 0.55 0.60 0.20 0.35 1.10 0.20 1.55 227 0.20 2.65 1.60 0.20 2.65 230 2.20 2.65 2.00 0.20 0.15 total of (a) +(b) (© 12 mm thick cement plaster inside and outside the building. Ans, 12 mm thick cement plaster (1:6) 420 - 3.80 420 - 3.80 4.20 — 1632 48.24 28.73 3.19 16.32 48.24 48.24 2.12 LiL 0.17 0.10 51.74 2.70 (ve) 0.31 1.78 2.18 1.09 1.24 1.13 0.68 3.61 1.70 2.44 0.06 32.32 cum 31.92 30.40 62.32 62.32 16.80 4.20 is the clear distance 27.20 = 28.05 Height of parapet from the room height. 4.40=4.2+2%0.10 (offsets) Projections may alternatively be measured as string course. 2.25 =2.10 +0.15 (for lintel) 2.10 = 3.00-2 * 0.15 ie, 0.15 less” bearing consider shelf depth = 20 em 5 Pillers 40 cm lengthwise 15 cm bearing considered. 1.95 = 1.80+0.15 2.75 = 2.4 +0.20+0.15Smaller room, Long walls Smaller room, Short walls Smaller room Ceiling Webs of R.C. beams. Jambs, sills and soffts of shelves (ii)Kitchen — Long walls Short walls Ceiling (iil) Front verandah — Front of rooms Front above openings Side above openings Ceiling (iv) Back verandah — Back portion of rooms Long side above openings ... Side and kitched front Ceiling (v)Pillars three sides — Front pillars Back pillars Deduction for — Door openings D Door openings D, Window openings W .. Clear storey winddow CW Ends of front verandah. ‘Area of pillars (b) Outside — (@ Rooms with outside parapet Sides of rooms Front and back of rooms (above low roof) (ii) Verandah (as solid first) Front and back verandah long Front verandash side Back verandash side (ii) Parapet inside over — Back and front of rooms2 Sides of rooms (iv) Parapet top — Be Bees eye BWNanna v 8.00 420 - 3.80 3.60 - 3.80 4.20 3.60 - 420 - 0.15 5.00 0.20 - 280 - 3.0 240 - 3.0 280 240 - 840 - 3.0 800 - 0.50 160 - 0.50 840 180 - 5.00 - 3.00 500 - 0.50 240 - 3.00 5.00 260 - 080 - 2.50 080 - = 2.50 100 - 2.10 090 - 2.10 110 - 1.29 0.75 - 0.45 020 - 0.50 0.40 020 - Total of inside = 480 - 453 840 - 1.35 840 - 3.18 180 - 3.18 2.60 - 3.18 = 045 7.20 440 - 0.45 15.70 15.00 2.50 14.40 13.00 8.00 2.00 8.40(-ve) 3.73(-ve) 2.64(-ve) 2.02(-ve) 0.20(-ve) 0.40(-ve) 27787 43.49 22.68 53.42 11.45 16.54 5.0=2(1.1 +14) 8.0=8.4—2* 0.20 0.50 = 3.0-2.5 2.6 = 2.4 +0.20 0,80 = 0.40 +2 x 0.20 Following LS.1. for both faces deduct one side. Deduction for other window openings has been made in outside plastering 0.50=3.0-2.5 sq.m. 4.53 =3.8+0.10 +0.80+0.45+0.10 (projection) 1.35 = 4.53 (@s above — 3.0 - 0.10- 0.08 2.6=24+0.20 8.00 = 8.40—2 = 0.20 (parapet thickness) 3.96 8.6=8.4+2%0.10 (projections) ——Back & front (out to out) Side (in to in) co. BR (v) Sun shades both faces — Front verandah front Front verandah sides Over windows, W (pair) .. Over windows, W, Front edges Side edges Deduction for — Window openings, W Window openings, W, Clear-storey openings, CW ... Clear-storey openings, CW, ... Front verandah openings Front Sides Back verandah openings ... 4 3 4 2 ESTIMATION & COST EVALUATION 8.60 030 - 440 030 - 930 045 - 2.00 045 - 3.00 045 - 1.20 045 - 22,90 0.05 -— 045 0.06 (av) 110 - 1.20 0.90 — 1.20 075 04s 0.60 - 0.45 6.80 — 2.50 1.60 - 2.50 230 - 2.50 Total of outside = inside + outside 227.87 + 141.38= Dimensions are same as in item no. (8d) 22,90 is total length 6.80 = 8.40 — 4 x 0.40 ‘sq. m. sq.m.2. Answer any four of the following : 3. (Theory ~ 5) Full Marks ~ 80 Time : 3 Hours Answer all questions Figures in the right hand margin indicate marks. 1, Answer the following questions: [2x 10 (a) What is meant by Plinth area of a building ? (b) List out the enclosures/attachments to be submitted with an estimate. (©) Write down the units of measurement for the following items : (i) Cement (ii)Reinforcement (iii)Brick on edge (iv)Wood works in door and windows shutter. (d) What is meant by ‘Lead’ and ‘Lift’ in estimating ? (©) Inaroom of size 5.0 mx 3.0 mwith wall thickness 300 mm, calculate the length of Long Wall and Short Wall for construction of main wall. (©) How many bags of cement are required for 1 m? cement supply ? (g) What is meant by “Sundries and Overhead chages” ? (h) Calculate the number of standard bricks required for 12.5 m® of brick work. (@ What is meant by Lump Sum in estimating ? G) Explain the “Unit Rate Estimate”. [5x4 (a) Calculate the quantity of dry material for 10 m? of Cement Concrete with proportion (I : 1, 5: 3). (b) Calculate the cost of 1 Gum of brick work with cement mortar (1 : 6) adopt suitable rates for materials/labour. (c) What is the difference between “Approximate Estimate” and “Detailed Estimate” ? (d) Write down the duties and responsibilities of Junior Engineer. (©) Write down the dry material for Cement Plaster of 100 m? in mortar (I : 6). Calculate the quantities of the following item of works (Refer the supplied sketch) : (a) The earthwork in exacavation in foundation. [8 (b) Cement concrete in foundation, [6 (o) Ist Class KB Brick works in Footings ang Plinth ; flo (@) Ist Class KB Brick works in Main Walls. [10 Or RCC works in roof slab. fo (c) Wood works in Doors and Windows. (6 ot SECTION ON ABCD (Theory - 5) Full Marks ~ 80 Time : 3 Hours Answer alll questions Figures in the right hand margin indicate marks. 1. Estimate the quantities of the following items of work of the building (for the attached figure-1, Answer any four questions) : (a) Earthwork in excavation of foundation trenches in hard soil. fo (b) Ist class K.B, brick work in C.M. (1 : 6) for foundation and plinth. [10 (c) 40 mm thick DPC with C.C.(1:2:4) [10 (d) R.C.C. works for lintels and chajjas with (1 : 2: 4) over doors, windows and verandah openings. (10(@) 12.mm thick cement plaster (1 : 6) to inside brick masonry. AN 2. Calculate the dry materials required for the quantities calculated in Question. No. 1 (b), 1 (4) and 1 0 3. (a) Calculate the plinth area and carpet area of the building (plan/figure-1 attached). & (b) List the types of inclided roof greraly adopted for building and found out how the members of a king post roof truss and roofing members are calculated, if the pitch of the roof is given ? . & (©) Differentiate between royalty and conveyance of building materials required for rate analysis z eS xa 4. Write notes on (any four) : . in (a) Name different Govt. and public sector organisation employing Civil Diploma holders in Odisha State. (b) Duties and responsibility of Junior Engineer. (0) Proforma for details of “measurement form” and “abstract of estimate form”. (a) Multiplying factor for painting work in case of M.S. grills and fully panelled window. (©) Lead and lift. FOS Awe iten - 4 mop wo Tees HA mopUMd “UZ xz") - O 2000 +37(Theory ~ 5) Full Marks - 80 Time : 3 Hours Answer all questions Figures in the right-hand margin indicate marks 1.(@) State the unit of measurement of the following item of works: [1x5 RCC chajja, Rock excavation, C.W. shutters, R.B. works, barbed wire fencing. (b) Answer the following: [xs 1. What is the volume of a bag of cement available in the market ? 2. Mention the volume of a batch box usually used for volume batching. 3. Whats the standard weight ofa 12 mm dia HYSD bar of one metre. ° 4, Mention the nominal size of bricks usually manufactured in Odisha 5. How to estimate the requirement of binding wire ? 2. Find out the quantities of the following item of work referring to the attached sketch (Fig. 1): (a) Earth work in excavation for foundation in hard soil. 12 (b) Cement concrete (1:4:8) in foundation. 6 (©) Ist class K.B. brick Masonry with C.M (1:6) in foundation and plinth. 12 (d) Quantity of woodwork for door choukhats if section of choukhat is 8cm < 10cm. 10 3. (a) Find out the plinth area of the building as per the attached drawing (Fig.1) and calculate the cost of building as per prevailing market price in your locality. 10 (b) Find the quantity of dry materials for items in Question No.2(b) and 2(). 10 4. Answer any two: (a) Differentiate between Revised Estimate and Supplementary Estimate. 5 (b) Write on tools and plants and contingencies. 5 (©) Briefly outline the duties and responsibility of junior Engineer in respect of quality control. 5 (d) Prepare the proforma for details of measurement form and abstract of estimate form. 5 Time - 3 Hours Full Marks — 80 “Answer five Questions including No.1 and 2 Figures in the right-hand margin indicate marks 1. Answer all questions [210 (a) Units of measurements Damp Proof Course ( D.P.C.). String Course, Skirting of dado, Reinforcement. (b) What is the weight and volume of one bag of cement available in market ? (©) Mention the size of standard modular brick and traditional brick. (a) What is the quantity of dry material required for 1 cum of cement concrete ( ay 3) 2 (e) Distinguish between plinth area and carpet area of building. (8) State the limit of lead and lift for no extra payment to the contractor as per state PWD norms. (g) What is the quantity of reinforcement required for a roof of (10 mx 10 mx 0.1 m) size? (h) Define overhead charge in the analysis of rates. (i) Calculate the plinth area of the building in the diagram, () How many bags of cement required for 1 cum of cement concrete (1:2: 4). 2. Answer any four questions (a) Write the duties and responsibility of Assistant Engineer. (5 (b) Write the difference between centre line method and longwall and shortwall method. [5 1 (©) Calculate Dry materials required for [2 x ry (i) Ast class brickwork with brick size (23 em* 11 cm x 8 cm ) for 5 cum with 1.6 cement mortar. (Gi) Laterite stone masonry in 1:6 cement mortar. (d) Analysis the rate of any one of the following items by taking cost of labour as per scheduled of rate —2006 of PWD and following material cost. [ $Cement — Rs. 360 / qutl Sand —Rs. 120/cum Chips —Rs. 600/cum (®) Cement concrete (1:2:4) with 20 mm chips. (ii) 20 mm thick plaster with ( 1:4) cement sand ‘mortar. (©) Calculate the quantity of wood required for doors and windows of the building given in figure - 1. 5 3. Calculate the quantities of following items of works from given plan and sectional elevation in figure 1. (a) Earthwork in excavation. [8 (b) Cement concrete in foudation. [4 (c) Brickwork is foundation and plinth. [8 (d) Brickwork in superstructure. [8 (e) White washing with 2 couts over inside plastered surface. [6 (® RCC work with 1% reinforcement with 1:2:4 cement concrete in roof slab, sunshade and lintel. [6 eta tors SECTION ON AB FIGURE! {IseMCIVEL 01115 \NewY ESTIMATING THEORY) 2. Answer any five. TV - Sem/Civil/2010(S (Theory - 5) Full Marks : 80 ‘Time : 3 Hours The figures in the right hand margin indicate marks. 1. Answer all «10 (a) Write down the units of measurements for the items (i) Honeycomb brick masonry, (ii) Reinforcement. (b) Distinguish between plinth area and carpet area of a building. (©) What is the multiplying factor for painting in both sides surfaces of a panelled door and that for a grill gate. (@) What is the limit of lead and lift for payment to the contractor as per state ‘PWD’ no extra norms. (e) Differentiate between royalty and conveyance of building materials for analysis of rate. (8) Distinguish between gable roof and lean to roof. (g) Define sundries and overhead changes in the analysis of rates. (h) What isthe quantity of dry materials required for 1 cum of cement concrete (1:2: 4)? (i) What is the cubic content of a standard truck. (j) Find out the quantity of cement paint required for one sqm. paintaing with two coats of application ‘on outside plastering work. [6x5 (a) A semi circular arch has a span of 2 m, thickness of arch is 30 cm and width 40 em. Calculate the quantity of arch masonry, (b) Calculate the dry materials required for 550m? of ) (©) Calculate the plinth area of the building of the given diagram. (@) Calculate the quantify of woodwork for the frames and shutters of doors and windows of the building (given diag.) (e) Briefly outline the duties and responsibilities of a Junior engineer in respect of quality control. (® Analyse the rate of any one of the following intems with suitable rates of materials, and labourers as per PWD Orissa rates. 25 mm thick DPC in cement concrete ( :(@ First class brickwork in cement mortar 1 : 6 in foundation and plinth with standard bricks (ii) ‘cement concrete in foundation (1 :2 : 4). 3. Prepare quantity estimate for the following items of works from the given plan and section of the building (given diag) (@ Earthwork in excavation, (10 Gi 1st class brickwork in foundation and plinth. {10 {10 Inside cement plastering. Av. them Lats (20217) over (Theory - 5) Full Marks : 80 ; Answer all questions Figures in the right-hand margin indicate marks. Answer of each question must be done at one place 1.() Write down the anit of measurement of following item of sworks. (4 Blasting-and.quarrying.of stone. Jungle clearance anspeetction: of:read-and ‘building, String irting-or-Bado. (0) What isthe weight nd -xehame «of one bag of coment availaisle an market. 2 (c) Mention the size of standard modular ‘brick and traditional brick. 2 Time : Hours 2. 3, (@) Ina standard truck how many no. of tradition brick can be loaded. ; R (6) Mention the type of inclined roof availble(2 (f) Define “Spoil bank” and “Dead man” in a roag work. (g) How the payment will ‘be made for erection of lighting conduction wire in a temple? [2 Answer any four. [6x4 (a) Find out the plinth area of the building in attached drawing. (b) What do you mean by overhead charges/cost ina estimating ? What is thepresent rate of this component in current schedule of rates of state PWD. (©) Briefly outline the duties and responsibility for maintenance of stock and store when you are assigned with the charge. (d) Find out the quantity of cement concrete (1:4 8) required for a trapezoidal square footing of size 2mat bottom and 30 cm at top with 38 cm depth. (© Show with sketches the parts of a king-post truss. From the attached drawing claculate the following quantities (Answer any four) (0x4 (a) Earthwork in excavation of foundation ? (b) 25 mm thick Damp proof course in C.C. (1:2:4) (©) Quantity of steel reinforcement in roof slab with 1 | 11:3, ce ( 2 ) (@ 12 mm thick cement plaster (1 : 6) for inside and outside to brickwork. (©) Find out the quantity of dry material required {0 the quantity calculated in Q No. 3(b) (Write short notes on (any three) (i) Carpet area and floor area i) Dismantling and demolition (ii) Royalty and carriage cost (iv) Centring and shutteringDoor 12x2.1m Window 1.0%1.5m 251 It 1:24 femme een 48 gem thick Sand filing a Earth filling BL {20 Son aL = wat ‘Wall Gare? Section on AB em/Civil/2008(S (Theory - 5) Full Marks : 80 Time : 3 Hours ‘Answer any five question, including Q. No.t Figures in the right hand margin indicate marks. 1 Answer the following. (a) What do you mean by lead and lift? (2 (b) What are the two main purposes of approximate estimate ? R (©) Find the material required for 10 cum cement conerete 1:2: 4 with graded stone chips 20 mm Gown to 6 mm for R.C. work excluding shuttering and reinforcement (As per OPWD code) [4 (@ Find the labour-component required concrete 1 : 5: 10 with graded stone ballast 40 mm down in foundation. Take 10 cum unit and adopt OPWD' dot. 4 (e) What is specification ? What are its main two objectives ? 2 (f) What are the two main roles of Divisional Accountant ? 2 2. Fig. 1 shows the plan and section of wall for a proposed building estimate the following items. (@) First class brickwork in cement mortar (1 : 4) for walls in foundation and plinth. (b) First class brickwork in cement mortar (I : 6) in superstructure. [8+8 3. Fig. 1 shows the plan and section of wall for a proposed building estimate the following items. (a) The material estimate of items of (a) and (b) in Q.No. 2 (8 (b) 15 om thick lime concrete flooring (both quantity estimate and dry material estimate) [8 4, Prepare the quantity estimate of the following items ofa building from the given plan and section as shown in fig, 2. (a) Earthwork in excavation. 8 (b) Cement concrete in foundation. (8 5, Prepare the quantity estimate of the following items as per Fig. 2. (a) 2.5 em thick D.PC. (1: 2:4) [8 (d) Cement concrete (1 : 2 : 4) excluding reinforcement and shuttering. [8 6. Prepare the quantity estimate of the following items of the building as shown in fig. 2 (a) Sal woodwork for frames. [4 (b) 35 mm thick Indian teak wood panel shutters [4 (©) 25 mm thick artificial stone (1 : 2 : 4) flooring, [8 7. Answer the following (a) Duty of Junior Engineer. (4 (b) Duty of Assistant Engineer (4 (©) Find the unit rate of 12 mm thick cement plastering (1 : 6) on new brickwork per sqm as per OPWD code assuming market rate. [8ayes SAMPLE PAPERS, wy w, Ww w | wi] 6. aM. UBRARY upRaRy| ROOM ROOM Ww, wi SM cm s— D ww w, SECTION OF WALL PLAN (ENLARGED) __s0mmx100mm AV. Idem LC, (282:7) over (TSeing Come [dc R.E.c. SuaB cio feo | 15cm R.c.C. 200m Fan Band_Lintel Sem te j Som. sda TL ME bcm Wa x + al i | a 2 wiinow TIL r ~ wer i.iM x 1,5M. 2. Sqn BEC FRAME 1 pre. FRAME p.06m ese be siete ¢Rzoem 90cm S = 11M x 1.5M H0em 306m sem CC. Floor 5m Ls SECTIONAL ELEVATION ON ABCD 20cm20em PILLAR be—-2.4M—-1 Tread - 30-m SECTION ON ads Rise Ser eeIv - Sem/Civil/2007(S (Theory - 5) Full Marks : 80 Time : 3 Hours ‘Answer all questions ‘The figures in right-hand margin indicate marks. 1. Answer the following. «10 (@) Write the units of measurement and units of payment for following items of work. (i Supply of reinforcement. (i) Brick on edge flooring. (ii) Pointing (iv) Arch work. (b) Calculate the plinth area of building with given plan of building. [ix4 (©) How the labours are classified as per the schedule of rate of Govt. of Orissa ? p (4) What do you mean by lead and lift? [2 (e) Write the unit of lead of excavation up to 500 m. (Write the multiplying factor for calculation of paint area in (@ Grill R (ii) Panneled and battened door. R (g) How many bags of cement required for 1 cu. m of cement concrete (1 : 2 : 4) R (h) Write down the accuracy of measurement taken for length and area. R (i) Give a lead statement of bricks 20 km away from work site for 2500 Nos as per scheduled rate of Govt. of Orissa - 2006. 2 2. Answer any four. (@) Analysis the rate of any one of following items by taking cost of labour as per scheduled of rate - 2006 of P.W.D and followed material cost. Cement — Rs. 360/ ntl. Sand—Rs. 120/cu.m Chips — Rs. 600/cu.m (i Cement coneret (1 : 2 : 4) with 20 mm chips.[5 ii) 20 mm thick plaster with (1 : 4) cement sand mortar. (b) Write the duites and responsibility of Junior Engineer. (5 (©) Calculate dry material required for (i) Ist class brickwork with brick size (23 * 11 * 8 cm) for 5 cu, m with (1 : 4) cement and ‘mortar. (ii)Laterite stone masonry (1 : 6) cement sand mortar. R%x2 3. (@ Write short notes on () Supplimentary estimate Gi) Revised estimate. (©) Write the difference between centre line method and long wall, short wall method of estimate. Calculate the quantities of following items of work from given plan (Fig. 1) and section of building, (a) Cement concrete in foundation (1:4: 8) 6 (b) Brickwork in foundation upto plinth and super structure. [6+6 (©) White washing with 2coats over inside plastered surface. 6 @ R.C.C. work with 1% reinforcement with (1:2 = 4) cement concrete in roof slab, sunshade and lintel. 8 (e) Wood work in choukath and shutter. [4+4 w A All choukaths are 0. 10cm * 8 cm KITCHEN 2s«.7smM DI ‘Ww 2.5m ay WI D one D=09*2.1M WI D ‘VER DI .7*2.1M. 1.8M WIDE | W=0.9* 1.2 LT 5 CM GL. 120m thick R.C.C slab 1:2:4 emg. i jn] ROC LINTEL 35M “ALN, Thickness ‘em em SECTION AT AAFall Marks : 80 Tithe : 3 Hours Answer all questions Answer all questions as per direction therein. 1 The figures in right-hand margin indicate marks. (a) Write the units of measurement and units of Payment for following items of work: @ Ridges i) Roofing with GI sheets (iii) Thin partition wall (iv) Painting over doors and windows. (b) Calculate plinth area of the building with given plan and section of drawing. 2 (©) Above which materials the royalty is charged by Govt. R (@) What do you mean by Lump Sum ? 2 (€) What are the percentages adopted as contigencies in CPWD and PWD? R (6) What do you mean by carpetarea ? Write its definition only ? R (g) In 1 cu. mof cement conc. work of 1:3 : 6 how much bags of cement is required ? R (h) Calculate area of painting for partly panelled and partly glazed door of opening size 1 * 2.1 m. [2 (@ How many standard bricks are required for 3.5 cu. m of brick work ? R 2. Answer any four questions. [5x4 (a) An arch of span 3 m subtends an angle of 80° at the centre. The thickness of arch is 30 cm and breadth of wall is 40 cm. Calculate the quantity of arch masonry. (b) Analyse the rate of any one of following items with suitable rates of material and labours as per Orissa P.W.D. rules. (j) First class brick work in cement mortar 1 :6 in foundation and plinth width standard bricks. (ii) 12 mm thick plastering in 1 : 4 cement mortar. (©) Write the duties and responsibilities of Assistent Engineer. (@ Calculate dry materials required for following items of work. (i) 20cmthick plaster for 10m? with I : 4 cement sand mortar over brick work. (ii) R.C.C. work 3 cumwith 1 :2: 4 cement sand mortar over brick work. . Prepare detailed estimate of following items of > work from given plan and section of a building, (a) Earth work in-excavation. B (b) DPC. (©) First class bricl 4 4c work in foundation and plinth, [+4 .C. work in Roof Slab, Surshade and lintel (6 (©) Inside plstering. {io (d) RC. 3030em pillar Linc “Chowicaths 8106m with 90*90em — ffead30em 12.1 cae W-0.9x1.5M. ‘ounation $0.91. 8M PLAN SECTION ON ABCD(CET- 405) Full Marks : 70 Time : 3 hours Answer Question No. I which is compulsory and any five from the rest. The figures in right hand margin indicate marks. 1.(@ Write the unit of lead of excavation up to 500m. (b) Write the multiplying factor for calculation of paint area in (©) Calculate area of painting for partly panelled and partly glazed door of opening size 1 x 2.1 m. (4) How many standard bricks are required for 3.5 cu. m of brick work ? (e) Write down the units of measurements for the items (i) Honeycomb brick masonry, (ii) Reinforcement. (£) Find out the quantity of cement paint required for one sqm. paintaing with two coats of application on outside plastering work. 2. Assemi circular arch has a span of 2 m, thickness of arch is 30 cm and width 40 cm. Calculate the quantity of arch masonry. 3, Find the unit rate of 12 mm thick cement plastering (1 : 6) on new brickwork per sqm as per PWD code assuming market rate. 4. An arch of span 3m subtends an angle of 80° at the centre. The thickness of arch is 30 om and breadth of wall is 40 cm. Calculate the quantity of arch masonry. 5. Calculate dry materials required for following items of work. (@ 20cmthick plaster for 10m? with 1 : 4 cement sand mortar over brick work. (i R.C.C. work 3 cum with 1 : 2: 4 cement sand mortar over brick work. 6. Prepare detailed estimate of following items of work from given plan and section of a building. Earth work in excavation. 7. Prepare detailed estimate of following items of work from given plan and section of a building. First class brick work in foundation and plinth. (ANSWER TO MODEL -1 1.(a) Write the unit of lead of excavation up to 500 m. ‘Ans. The unit of lead is $0 Mt. for a distance up t0 500 Mts, (0) Write the multiplying factor for calculation of paint area in @ Grill ‘Ans. Grill - 1 time the area-of clear opening in between chowkhath for overall. (c) Calculate area of painting for partly panelled and partly glazed door of opening size 1 < 2.1m ‘Ans, Co-efficient of painting for partly panelled and partly glazed door opening = 2 times the surface area = 2x 1 x 2,1= 4,2 Sqm. \ (d) How many standard bricks are required for 3.5 cu. m of brick work ? Ans. 3.5 x 500 = 1750 nos. (e) Write down the units of measurements for the items (i) Honeycomb brick masonry, (ii) Reinforcement. Ans. Item of work Units Honey comb brick masonry ->'Sqm. Reinforcement — quintal (® Find out the quantity of cement paint required for one sqm. paintaing with two coats of application on outside plastering work. “ Ans. The quantity of cement paint required f. one sqmpainting with two coats of application Sia platrng verily 0.195 kg. . A semi circular arch has a span of 2 m, thickness of arch is 30 cm and width 40 cur Calculate the quantity of arch masonry. Ans. Inner radius, r=-E2 == =1.0m