Optics
Optics
Contents
I. Geometrical Optics                                                                                                                                         3
4 Optical Devices                                                                                                                                            11
  4.1 Thin lenses . . . . . . . . . . . . . . . . . .    .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   11
      4.1.1 Graphical methods for lenses . . . .         .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   11
  4.2 Camera . . . . . . . . . . . . . . . . . . . .     .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   12
      4.2.1 Focal length of the camera . . . . .         .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   12
      4.2.2 f-Number of a lens . . . . . . . . . .       .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   13
      4.2.3 Zoom Lenses and Projectors . . . . .         .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   14
  4.3 Eyes . . . . . . . . . . . . . . . . . . . . . .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   14
      4.3.1 Myopic (near-sighted) eye . . . . . .        .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   15
      4.3.2 Hyperopic (far-sighted) eye . . . . .        .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   16
      4.3.3 Astigmatism eye . . . . . . . . . . .        .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   16
      4.3.4 Diopter . . . . . . . . . . . . . . . .      .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   17
      4.3.5 Magnifying glass (simple magnifier)          .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   17
  4.4 Microscope and telescope . . . . . . . . . .       .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   17
      4.4.1 Microscopes . . . . . . . . . . . . . .      .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   18
      4.4.2 Telescopes . . . . . . . . . . . . . . .     .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   .   18
5 Electromagnetic waves 20
6 Electromagnetic spectrum 20
                                                     1
7 Dispersion (also in 1.2)       21
8 Polarization 22
9 Interference 23
10 Diffraction 25
11 Diffraction grating 27
                             2
I. Geometrical Optics
    Geometrical optics is the study of properties of light under the approximation that light travels in
a straight line.
    • Law of refraction (also called Snell’s Law): Relation of the incidence angle and the refracted
      angle are given by:
                                           n2 sin θ2 = n1 sin θ1                                 (2)
      where n1 , n2 are refractive indices.
      Refractive index are defined as the ratio of the speed of light in a vacuum to its speed in a specific
      medium.
                                                          c
                                                     n=                                                 (3)
                                                          v
      where c is the speed of light and v is the speed of light in a material. Some refractive indices
                                                        4
      that you should memorize: nair = 1, nwater = = 1.33
                                                        3
REMARK: Light traveling from medium a to medium b:
                                                     3
   • If na > nb , then the light ray is bent away from the normal.
   • If na < nb , then the light ray is bent toward the normal.
For example, blue light (4̃50 nm) has shorter wavelength than red light (6̃20 nm), so the blue ray will
be more bent than the red ray.
θb = 90◦
                                                      4
                                   Figure 3: Total internal reflection
                                                    5
In both figures, the rays do not actually pass through the image point P ′ . We have the concepts of
real and virtual images:
   • Real image: the outgoing rays really do pass through an image point.
   • Virtual image: the outgoing rays do not pass through the image point.
Figure 6: Construction for determination of the location of the image formed by a plane mirror
The diagram shows two rays diverging from an object point P at a distance s to the left of a plane
mirror. We call s the object distance. When we extend the two reflected rays backward, they intersect
at point P ′ , at a distance s′ behind the mirror. We call s′ the image distance.
 It can be easily shown that the image distance is equal to the object distance:
|s| = |s′ |
The sign of s and s′ , however, will have to follow sign rule. (Spoiler alert: s = −s′ )
                                                         y′
                                                 m=                                               (6)
                                                         y
   • m > 0 ⇒ The image is erect.
                                                     6
   • m < 0 ⇒ The image is inverted.
For plane mirror: Lateral magnification: m = 1 (unity).
CAUTION: For a three-dimensional object, only the front–back dimension is reversed (PR and P’R’).
                                                  7
3     Reflection and Refraction in Spherical surface
3.1    Sign rule for radius of curvature of a spherical surface (R)
    • R > 0 when C is on the same side as the outgoing light.
Figure 10: The sign rule for the radius of a spheical mirror.
Figure 11: Construction for finding the position P of an image formed by a concave spherical mirror.
                                                  8
3.3     Focal point and focal length
When s = ∞, the incoming rays are so far away that they can be considered parallel to the optical axis.
Figure 12: All parallel rays incident on a spherical mirror reflect through the focal point.
In this case, the reflected rays will converge at a point called the focal point (F), and the distance
from the mirror’s vertex to point F is called the focal length (f ).
                                                         R
                                                   f=                                                   (8)
                                                         2
                                                R             R
                                         s′ =     =⇒ s′ = f =                                           (9)
                                                2             2
                        R
Reversely, when s′ = f =   , we will have s′ = ∞.
                         2
We also have the important relation between s, s′ and f :
                                                 1   1   1
                                                   + ′ =                                               (10)
                                                 s s     f
                                                     9
Figure 13: Construction for finding the position of the image point P of a point object P formed by
refraction at a spherical surface.
Special case: R = ∞, spherical surface becomes a plane surface, then we have the plane refracting
surface equation:
                                            na    nb
                                               + ′ =0                                           (13)
                                             s    s
Magnification in this case is m = 1 (the image formed by the refracting plane is always erect and of
the same orientation as the object).
  3. A ray along the radius through or away from the center of curvature C intersects the surface
     normally and is reflected back along its original path.
  4. A ray to the vertex V is reflected, forming equal angles with the optic axis.
Figure 14: The graphical method of locating an image formed by a spherical mirror.
                                                 10
4       Optical Devices
4.1      Thin lenses
Definition: A thin lens is a lens with a small thickness compared to its radius of curvature. 2 types:
    • Convex lens (Converging lens): A lens that causes light rays initially parallel to the central axis
      to converge
    • Concave lens (Diverging lens): A lens that causes parallel rays of light to diverge.
Equations:
    • Object-image relationship, thin lens:
                                                   1    1     1
                                                     + ′ = ,                                           (14)
                                                   s s        f
        where s: object distance, s′ : image distance, f : focal length of lens.
    • Lensmaker’s equation for a thin lens:
                                              1            1    1
                                                = (n − 1)(    −    )                                   (15)
                                              f            R1   R2
        where f : focal length, n: index of refraction of lens material, R1 : the radius of curvature of the
        lens surface nearer the object and R2 : the radius of curvature of the second surface.
Some variations of converging lenses and diverging lenses:
                                                      11
               Figure 16: Graphical method of locating an image formed by thin lens.
4.2     Camera
A camera inclues 5 main parts:
   • Light-tight box or camera body
   • Converging lens
   • Shutter
   • Light-sensitive recording medium (electronic sensor or photographic film): can be understood as
     a surface for capturing light and converting it into an image.
   • Aperture: the opening of the lens that allow the amount of light passes through.
Since being created by a converging lens, the image produced by the camera is always a real image,
inverted, and usually smaller than the object.
Figure 17: Three photographs taken with the same camera from the same position, using lenses with
different focal lengths.
• Telephoto Lens:
                                                   12
        – They provide a smaller field of view but a larger image of a distant object.
• Wide-angle lens:
                                     50                                            f
                        f-number =      =2   or we can say it has an aperture of
                                     25                                            2
  2. A lens with focal length f from 100 mm to 200 mm, an aperture diameter D1 = 25 mm at
     f1 = 100 mm, and D2 = 35.7 mm at f2 = 200 mm.
                                                 13
4.2.3   Zoom Lenses and Projectors
Zoom Lens A zoom lens is a complex collection of several lens elements that gives a continuously
variable focal length, often over a range as great as 15 to 1. Its operation can be summarized as:
   • When the two key lenses are close together, they function like a single lens with a longer focal
     length.
   • When the two lenses move farther apart, they behave like a single lens with a shorter focal length.
Figure 19: A simple zoom lens uses a converging lens and a diverging lens in tandem
Projector A projector—used to display slides, digital images, or moving pictures—works much like a
camera in reverse: it shines light through an optical system to project an enlarged image (real, m > 1,
inverted) onto a screen.
4.3     Eyes
   • Sphere-like shape with a diameter of about 2.5 cm.
   • To be able to observe objects from different distances, the eyes will adjust their focal length. So,
     s can vary while s′ remains constant (the image must form on the retina, and the distance
     from the lens to the retina does not change).
   • An object at infinity (very far away) is brought into focus when the ciliary muscles are relaxed,
     allowing the lens to assume its minimum power (longest focal length).
   • As an object moves closer, the ciliary muscles contract, reducing the tension on the zonular fibers
     around the lens. This allows the lens to become more convex, thereby shortening its focal length.
The eye forms a real image: refraction at the cornea and the surfaces of the lens.
For normal eye:
                                                   14
Figure 21: (a) An uncorrected myopic (nearsighted) eye. (b) A negative (diverging) lens spreads the
rays farther apart to compensate for the excessive convergence of the myopic eye.
   • Solution: wear a divergent (concave) lens with focal length f = −dfar , where dfar is the
     distance to the far point of the myopic eye. This lens shifts the focal point back onto the retina
     so that distant objects can be seen clearly without accommodation.
                                                  15
                     Figure 22: One type of astigmatism and how it is corrected
   • In hyperopia (farsightedness), the eyeball is too short relative to the curvature of the cornea (or
     the cornea is insufficiently curved).
   • Consequently, incoming parallel light rays are focused at a point behind the retina rather than
     on it.
   • The near-point of a hyperopic eye is therefore located farther away than normal (objects closer
     than this point appear blurred).
   • Solution: wear a converging lens (convex), which brings the focal point forward so that
     images of near objects form on or just inside the near point of the eye.
   • A person with astigmatism may be unable to focus both the vertical and horizontal edges of a
     window frame sharply at the same time.
   • Solution: a cylindrical lens, which has focusing power in only one meridian.
   • Explanation: By orienting the cylinder axis appropriately, the lens leaves rays in one plane
     unchanged while adding or subtracting power in the perpendicular plane, so that both meridians
     are brought into sharp focus on the retina.
                                                  16
4.3.4   Diopter
Lenses used for vision correction are characterized by their optical power, called diopters, defined as
the reciprocal of the focal length (in meters):
                                                        1
                                                 P =                                                 (18)
                                                        f
Examples:
   • A lens with f = +0.50 m has P = +2.0 D.
   • A lens with f = −0.25 m has P = −4.0 D.
As we learned, a virtual image is most comfortable to observe when it is at infinity, at which point
the ciliary muscle of the eye is relaxed. Therefore, in the figure above, we place the object at the focal
point f of the magnifying glass, so that the image formed is at infinity. This virtual image can then
be treated as a real object subtending an angle θ′ at the eye. We have:
                                                    y     y
                                               θ′ = =                                                 (19)
                                                     s    f
                                                   17
4.4.1     Microscopes
   • To understand how an image is formed by telescopes, we apply the image formation rule of a
     single lens that the image formed by the first lens acts as the object for the second lens.
   • Basically, the object O is placed just before the focal point F1 (close enough that we can approx-
     imate f1 ≈ s1 ) of the objective lens, producing a real, inverted, and enlarged image I (located
     at the focal point F2 of the eyepiece). The eyepiece then acts as a magnifying glass to produce
     a virtual image l′ .
   • Just like with a magnifying glass, we are interested in the angular magnification M . The
     angular magnification of a simple microscope can be calculated as the product of the lateral
     magnification m of the objective lens and the angular magnification M of the eyepiece.
   • We have the magnification:
                                         s′1                          s′1
                                    m=       ,   with f1 ≈ s1 ⇒ m =
                                         s1                           f1
        Eyepiece magnification:
                                                        25
                                                  M=
                                                        f2
        ⇒ Angular magnification for a microscope:
                                                             25s′1
                                           M′ = M × m =                                           (21)
                                                             f2 f1
4.4.2     Telescopes
   • Basically, a telescope operates similarly to a microscope.
   • The main difference between these two optical instruments is that telescopes are used to observe
     large objects at great distances, while microscopes are used to observe small objects close
     at hand.
                                                   18
   • Additionally, some telescopes use curved mirrors (concave mirrors) as their objective lens.
   • In this case, the telescope uses a converging lens as its objective lens, so it is also called a
     refracting telescope or refractor.
   • The image formed by the objective lens is real and smaller than the object. Since the object is
     assumed to be at infinity, we consider l ≈ F1′ .
   • The eyepiece acts as a magnifier that creates a larger virtual image from the real image I ′ , and
     since I ′ is very close to the eyepiece, we can assume I ′ ≈ F2 .
   • The total length of the telescope is f1 + f2 .
Angular magnification M of a telescope is defined as the ratio between the final angular size of the
image θ′ and the angular size of the object θ:
                                               −y ′               y′
                                          θ=        ,      θ′ =
                                               f1                 f2
                                            θ′    y ′ /f2    f1
                                      M=       =− ′       =−                                       (22)
                                            θ    −y /f1      f2
   Note: For telescopes using a concave mirror as the objective lens, they are called reflecting
telescopes.
                                                      19
II. Wave Optics
5 Electromagnetic waves
Imagine if we throw a stone into a pond, it will create ripples that spread out through the surrounding
medium. Similarly, if we take a magnet and “stir” it around, it will create ripples in the electromagnetic
field.
6    Electromagnetic spectrum
The fundamental nature of light is that our eyes can detect electromagnetic waves with wavelengths
in the range 0.4–0.7 µm. Waves with wavelengths longer or shorter than this range are not visible to
us.
                                                   20
                                                   Within the visible region, each wavelength
                                                   corresponds to a distinct perceived color (as
                                                   in the table of spectral colors). What will we
                                                   see if we mix all the colors together?
    • The same effect produces rainbows: instead of a prism, raindrops act to disperse sunlight into
      its constituent colors.
                                                   21
8     Polarization
In this section, we focus on the Electric-field component of an electromagnetic wave.
• Polarized light: the electric field oscillates entirely within a single plane.
      The electric field is a vector quantity and can be added together. So if two polarized waves that
      are perpendicular to each other are superimposed, what kind of wave do we have?
    • Unpolarized light: the electric field oscillates in all directions perpendicular to the direction
      of propagation; it can be viewed as a superposition of two orthogonal polarized waves.
    • Polarizing filter: an optical element that blocks electric-field oscillations in one direction and
      transmits those in the perpendicular direction.
         – When unpolarized light passes through, the transmitted light is polarized and its intensity
           is reduced by half.
         – When polarized light with initial intensity I0 and electric-field oscillation at angle Θ to the
           filter’s axis passes through, the transmitted intensity I follows Malus’s law:
I = I0 cos2 Θ. (23)
                                                    22
                                     Figure 31: The polarizing filter
    • Polarization by reflection
      Reflection and refraction at interfaces can also alter the polarization state of light.
      At a specific angle of incidence, called the polarizing angle θp , the reflected light is completely
      polarized perpendicular to the plane of incidence.
      According to Brewster’s discovery, when the reflected and refracted rays are perpendicular to
      each other, i.e.,
                                             θb = 90◦ − θp ,
      then by Snell’s law:
                                        na sin θp = nb sin θb = nb cos θp .
9     Interference
    • Definition: The superposition of two or more coherent waves, resulting in a new wave pattern.
    • Coherent waves: Waves having the same frequency ν, wavelength λ, and a constant phase
      difference.
                                                    23
• Constructive interference:
• Destructive interference:
    – Path difference: ∆r = r2 − r1 = m + 21 λ m ∈ Z .
                                                     
∆r = d sin θ = m λ, m ∈ Z. (25)
                                              24
        – Conditions for dark fringes (destructive interferences):
                                      ∆r = d sin θ = m + 21 λ, m ∈ Z.
                                                             
                                                                                                    (26)
Note: In the test, it might ask about the number of bright/dark fringes, which is m.
ym = R tan θm
                                           ym ≪ R ⇒ tan θm ≈ sin θm
                                                 ⇒ ym = R sin θm
          We finally have:
                                                       mλ
                                                   ym = R                                    (27)
                                                        d
          R is the very small distance between the screen and the light source, d is the distance
          between 2 slits, λ is the wavelength.
        – Amplitude in 2-source interference:
                                                               ϕ
                                                 Ep = 2E cos                                        (28)
                                                               2
          where E is the amplitude of the wave from one source, ϕ is the phase difference between
          the waves, and EP is the resulting electric-field amplitude.
10    Diffraction
 • Huygens–Fresnel principle:
     Every point on a wavefront acts as a new source of waves (called secondary wavelets). The sum
     of these wavelets determines the subsequent propagation and explains diffraction phenomenon.
     Note: In interference problems, we usually deal with very narrow slits. In reality, slits often have
     significant width, and what we need to do in this section is to construct a more accurate model.
                                                  25
• Single-slit diffraction: A slit of finite width a can be modeled as a collection of infinite number
  of point sources, oscillating with a very, very small amplitude.
                                               26
        Then 2 slits with significant width will be the combination of the two:
                                                          λ                       λ                      λ
     The angular radii of bright rings:   sin θ1 = 1.22      ,    sin θ2 = 2.23      ,   sin θ3 = 3.24      ,
                                                          2r                      2r                     2r
                                                          λ                       λ                      λ
       The angular radii of dark rings:   sin θ1 = 1.63      ,    sin θ2 = 2.68      ,   sin θ3 = 3.70      .
                                                          2r                      2r                     2r
11   Diffraction grating
 • Diffraction grating:
d sin Θ = m λ, m ∈ Z,
                                               27
                                         Figure 38
    – Similar to diffraction grating but instead of letting light goint through the slits, we let
      X-ray reflect from the atomic planes to obtain images.
    – For a glancing angle Θ, maximum reflected intensity (Bragg peak) satisfies
28