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Check Sum

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mehulamish2004
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1 views2 pages

Check Sum

Uploaded by

mehulamish2004
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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#sender

code="11001010101001010101111001110101"
d1=code[:16]
d2=code[16:]

#recv
code2="11001010101001010101111001110101"
d3=code2[:16]
d4=code2[16:]

def bsum(str1,str2):
carry="0"
final=""
for i in range(len(str1)-1,-1,-1):
final=final[::-1]
if(str1[i]=='0' and str2[i]=='0' and carry=='0'):
final+="0"
carry="0"

elif(str1[i]=='0' and str2[i]=='0' and carry=='1'):


final+="1"
carry="0"

elif(str1[i]=='0' and str2[i]=='1' and carry=='0'):


final+="1"
carry="0"

elif(str1[i]=='1' and str2[i]=='0' and carry=='0'):


final+="1"
carry="0"

elif(str1[i]=='0' and str2[i]=='1' and carry=='1'):


final+="0"
carry="1"

elif(str1[i]=='1' and str2[i]=='0' and carry=='1'):


final+="0"
carry="1"

elif(str1[i]=='1' and str2[i]=='1' and carry=='0'):


final+="0"
carry="1"

elif(str1[i]=='1' and str2[i]=='1' and carry=='1'):


final+="1"
carry="1"
else:
final=final[::-1]
break
final=final[::-1]
return(final)
s1=bsum(d1,d2)
s1_new=""
for i in range(0,len(s1)):
if(s1[i]=="1"):
s1_new+="0"
else:
s1_new+="1"
s2=bsum(d3,d4)

print("Check Sum = ",bsum(s1_new, s2))

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