1.
Find out the production per day of 24hrs in kg at 85% efficiency when machine gauge = 24, machine diameter = 30 yarn count = 30Ne; RPM = 30; stitch length = 2.60 mm. Solution: Here data given, Efficiency = 85% Machine diameter = 30 M/c gauge = 24 needles per inch Yarn count = 30Ne M/c rpm = 30 Stitch length = 2.60 mm
Machine circumference = d Number of needle = d G Length of yarn in a course = d G Stitch length Length of yarn used to produce courses in a minute = d G Stitch length m/c rpm = ( 30 24 2.6 30) mm/minute = 176342.4 mm/minute = 176.342 m/minute = 176.342 1.09 yards /minute = 192.21 yard/minute =
192.21 pounds/minute 840 x 30
= 0.0076 pounds/minute = 0.0076 60 24 pounds/day = 10.944 pounds/day =
10.944 kg /day 2.2
= 4.97 kg /day Production/m/c/day at 85% efficiency = 4.97 0.85 kg /day = 4.2245 kg /day
Alternate solution: Here data given, Efficiency = 85% Machine diameter = 30 M/c gauge = 24 needles per inch Yarn count = 30Ne M/c rpm = 30 Stitch length = 2.60 mm
d (inch) G Stitch length (mm) rpm 60 24 1.09 Efficiency 1000 x 840 x Count (Ne)x 2.2 30 24 2.6 30 60 24 1.09 0.85 = 1000 x 840 x 30 x 2.2 = 4.24 kg /day
Production in Kg per day =
For Practice.
2. Find out the production per hour in pounds at 70% efficiency when machine gauge = 32, machine diameter = 30 yarn count = 40 Ne; RPM = 24; stitch length = 2.20 mm.
3. What will be the production per shift (8 hrs) in kg at 95% efficiency when machine gauge = 24, machine diameter = 30 yarn count = 30 Ne; RPM = 30; stitch length = 2.45 mm.
4. Find out the stitch length of a fabric if that is produced from a machine 5 kg per day at 80% efficiency. And machine gauge = 24, machine diameter = 28 yarn count = 27Ne; and machine RPM = 26.
5. In a knitting factory, Fabric will be produced tomorrow from 28 Ne Yarn. It has 50 machines, all of them have 24 gauge, 30 diameter and stitch length should be = 3.00 mm. But 25 machines have an rpm of 24, and other 25 machines have an rpm of 28. What will be the production of that factory tomorrow?