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Ethers/Epoxides
1 Terminology/Properties
O
Reactions With Brnsted Acids/Bases
(more...)
O
R
R
Symmetric
R'
R
Asymmetric
O
R'
R
~105
Tetrahedral
Epoxide
Generally unreactive although Epoxides are an exception
Good Organic Solvents
2 Nomenclature
Named as substituents (like halides), lowest priority
Substituent is named as the ALKOXY is equivalent to ALKYL, i.e. Me is methyl, thus, -OMe is methoxy etc.
the "main" chain" is according to the usual rules, the longest chain that contains the ,maximum number of
functional groups
Alkoxy substituent
R O
R'
More
2
complex
1
side Alkene
More complex side
is the main chain
3 2 1
1-ethoxybutane
substituent
4
(4S)-tert-butoxycyclohexene
ethoxy
substituent
Some Common Ethers and Common Names
O
diethyl ether
O
oxetane
ethylene oxide
(oxirane)
tetrahydropyran
tetrahydrofuran (THF)
3 Preparation of Ethers
3.1 Williamson Ether Synthesis (SN2 Reaction)
This is just an SN2 reaction, but we will analyze it using retrosynthetic analysis
Retrosynthetic strategy
R O
R O R'
R'
synthons
"put" negative charge on the oxygen and a leaving group on the carbon
Na
alkoxide anion R O
R'
R O R'
synthetic equivalents : reagents
The Williamson ether synthesis consists of Two Steps
Ethers/Epoxides
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First Step: preparation of an alkoxide anion (the nucleophile) by deprotonation of an alcohol
which base is useful for this?
R O
R O
Na + H2
sodium alkoxide
Na
H
sodium hydride
sodium hydride is a useful strong base to irreversibly deprotonate an aliphatic alcohol
Example
Na
OH +
Na
H3C OH
Na sodium methoxide
H3C O
Na sodium phenoxide
the conjugate base anions of alcohols are alkoxide anions (organic version of hydroxide)
the phenoxide anion can also be made simply with OH
Stonger acid
faster reaction
OH
Na
OH
Na +
H2O
pKa ~ 15
pKa ~ 10
Second Step; SIMPLE SN2 reaction with a halide (coupling reaction)
RO
R'
SN2
R O R'
preferably primary/allylic halide (SN2)
other good leaving groups will also work (SN2)
Example 1
1. NaH
OH
2. Br
preferred method
1.
NaH
HO
Br 3
2.
doesn't work
(SN2 on a 3 alkyl halide)
Example 2:
only do SN2 at a secondary carbon if you can't avoid it, in this case it can be avoided from the "other" direction
1. NaH
HO
2.
O
Br 1
1.
2.
preferred
Ethers/Epoxides
NaH
Br 2
OH
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3.2 Preparation Methods for Ethers/Epoxides Seen Before (Review)
1. Hg(OAc)2/H2O
H
()
Cl
OH
2. NaBH4
MCPBA
O
C OOH
1. Hg(OAc)2/EtOH
OEt
2. NaBH4
the formation of epoxides using MCPBA is described in more detail below
4 Reactions of Ethers/Epoxides (Acids and Bases)
4.1 Cleavage of Ethers Using Acids
Ethers are mainly unreactive, except ONE reaction that we can WORK OUT based on a reaction of alcohols that
we just learned, and reaction principles that we know fairly well
recall conversion of an alcohol to an alkyl bromide
makes a good leaving group
Me O H
H Br
Me O
Br Me
Br
makes a good leaving group
t-Bu O H
H Br
t-Bu O
Br
t-Bu
SN2
t-Bu Br
SN1
protonation of oxygen makes a good leaving group, allows C-O to be broken
SN2 OR SN1, depending upon the substituents on the alcohol
Ether Reaction: Cleavage with Acid
R O R'
Excess HX
Heat
R-X + R'-X + H2O
Mechanism
H
R O R' + H X
L/B Base
L/B Acid
R O R'
SN2
if possible
R-X + R'-OH
H X
R'-OH2
SN1
if SN2
X
R'
IMpossible
R'-X
the first step is related to the alcohol reaction above, the second step IS the alcohol reaction above
this substitution may be by SN2 or SN1 mechanisms, depending upon whether the protonated ether is attached
to a 1, 2 or 3 carbon, as usual
Ethers/Epoxides
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Examples
substitute here 3 = SN1
Br
H
O
substitute here 1 = SN2
Br
Excess HBr
Br
SN1
Br
Br
SN1
OH H Br
SN2 at 1
carbon
SN2 FASTER
OH2
Br
NO SN2 at
3 carbon
SN1 SLOWER
protonate the oxygen to create a good leaving group as usual, then
SN2 at the 1 carbon happens FIRST, because SN2 is always faster than SN1
SN1 at the 3 carbon
substitute here 1 = SN2
HBr
OH
Br
Stops here, cannot do
SN2 reaction at sp2 carbon
NO substitution here sp2 carbon
the -OH attached to the sp2 hybridized carbon can not be substituted by either SN1 or SN2 mechanisms
Example with ONE Equivalent of Acid
1 Equiv. HI
O
I
STRONG
LA/Elec.
CH3
+ Me-I
WEAK Nuc/LB
SN2
FASTEST at
the Me carbon
SN2 would be SLOWER
at this 2 carbon
Note 1 Equivalent of acid, only allows ONE substitution, substitution occurs at the carbon where SN2 is
FASTEST, in the example above it is the methyl carbon atom
Note, H-I is also a strong Bronsted acid, reacts the same way as H-Br
Iodide is a WEAK Lewis base/nucleophile, but the protonated ether is a STRONG Lewis acid/electrophile
4.2 Formation of Epoxides and trans-Diols
New reagent
O
R
Cl
O
O OH
peroxy acid
Ethers/Epoxides
peroxide
OH
carboxylic acid
4
O
C
OH
meta-chloroperbenzoic acid (MCPBA)
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Ethers/Epoxides
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Mechanism
C
O
H O
carboxylic acid
epoxide
concerted mechanism - all bonds made and broken at the same time
no chance for bond rotation "in the middle" - stereospecific reaction!
Examples
MCPBA
cis-alkene
cis-epoxide formed
reaction is STEREOSPECIFIC
Anti-Addition of two -OH across a C=C bond in an alkene
Synthesis of a trans-Diol
formation of an epoxide followed by ACID CATALYZED HYDROLYSIS of the epoxide
lysis = bond breaking, and hydro = with water, hydrolysis = bond breaking using water
hydrolysis
H3C
cis-alkene
achiral
()
CH3
C
OH
C
HO
CH3
H
ANTI-addition
(R)/(R) and (S)/(S)
stereoisomers formed
CH3
C C
MCPBA
H3C C C CH3
H
LB/BB
H CH3 OH
C C
CH3
H O
H
LA/BA
H
H
WEAK
nucleophile
LB/BB
LA/BA
H3O+ = H2O (solvent)
+ e.g. HCl, H2SO4 (cat.)
H
LA
O
C
H3C
(SN2)
H O
H
H
CH3
oxonium ion
H
LB
backside attack!
when H3O is a reagent, this means aqueous acid (e.g. HCl or H2SO4 in water)
the intermediate is an oxonium ion (onium means more than usual valence, in this case 3 for oxygen), compare
with bromonium etc.,
the driving force for opening the protonated epoxide (oxonium ion) is provided by release of ring strain energy
this reaction sequence makes a trans-diol when cis-/trans-isomers are possible, the overall addition of the two OH is ANTI- in all cases
NOTE: the (R)/(R) and (S)/(S) stereoisomers are formed in the above example (as a pair of enantiomers).
Although cis-/trans-isomers cannot be forme din this case, we still need to distinguish formation of the (R)/(R) and
the (S)/(S) pair of enantiomers from a (R)/(S) and (S)/(R) diastereomers, the addition is ANTI- and we can tell in
this example
Ethers/Epoxides
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Recall: 3-membered onium rings are attacked at most substituted carbon
In these reactions the attacking species is a WEAK nucleophile/Lewis base (Br-, H2O, ROH etc.)
smaller contribution to the mix
larger contribution to the mix
Br
Br
H
O
H
O
OAc
Hg
H O
H
H O
H
major
H
O
less minor
H
O
most + charge
intermediate
most minor + charge
"actual"
least +
charge
Example
1. MCPBA
2. H3
achiral
HO
O+
()
Racemic
OH
trans-diol
ANTI-addition
backside attack
Example NOT using aqueous acid
Me
O
H
H
OH
CH3OH
OCH3
HCl (cat.)
OH
STRONG Elec./LA
reaction is REGIOSPECIFIC
-OCH3 attached to the most
substituted carbon
O
H3C
H
WEAK Nuc/LB
H
H3C
H3C
NOTE, the solvent here is NOT water, this is not hydrolysis, it is "methanolysis" (bond breaking using methanol)
+
The acid catalyst is NOT H3O (there is no water), HCl dissolved in methanol will dissociate (not quite as much
as in water, but substantially)
Other strong organic acid catalysts (catalysts that can be dissolved in organic solvents) that can be used here
+
(when H3O cannot be used) include
TFA
O
S OH TsOH
O
trifluoroacetic acid: TFA
p-toluene sulfonic acid: TsOH
F3C C
OH
Ethers/Epoxides
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Related example (you should be able to extrapolate to examples such as this by knowing the mechanism)
Cl
HO
HCl
H Ether (inert solvent)
Me
STRONG Elec./LA
backside attack
Walden inversion
-H still dashed
-Me still wedged
but now both point "up"
Me
Cl
(SN2)
H
O
dashed -H and wedged
-Me are "pushed up"
H
Me
Cl
WEAK Nuc/LB
In his case the acid is the reagent, it ADDS to the epoxide, it is not just a catalyst
+
Obviously H3O can't be used here since we do not have water as the solvent
when the chloride anion acts as the nucleophile/LB it is doing an SN2 reaction on the carbonatom, the SN2
proceeds with a Walden inversion, the wedged -Me and the dashed -H change from both pointing "down" to both
pointing "up", but the wedged bond remains wedged and the dashed bond remains dashed when we look at the
reaction from the perspective shown
4.3 Formation of cis-Diols
This is normally part of CHM 233, we skipped this section last semester, it fits quite well here.
The are TWO sets of reagents that will accomplish this reaction
The reaction
cold KMnO4/-OH/H2O
OR
OH
syn-addition
(same side)
OH
OsO4 / H2O2
The mechanisms
+7 oxidation state
metal gets
reduced here
+5 oxidation state
O O
Mn
Mn
OH
+4 oxidation state
HO
OH
+ MnO2
syn-addition!
-OH
O
HO Mn
don't need to know!!
O
O O
HO Mn
O
O
HO Mn OH
O
O
-OH
aqueous
workup
O
radical
reduction
O
+ MnO2(OH)2
addition/elimination mechanism
although this is obviously complex, the important part is that the MnO4 ion starts the reaction by adding to both
ends of the alkene at the same side, which is why a cis-diol must be formed
note that in mechanisms involving metal atoms, the metal has enough electrons and empty orbitals to give and
take electrons on its own, almost at will (almost like cheating to an organic chemist!!)
Ethers/Epoxides
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metal gets
reduced here
+8 oxidation state
O
O
Os
+6 oxidation state
O O
Os
H2O2
HO
OH
+ OsO4
catalyst
syn-addition! regenerated!
H2O2
don't need to know.....
why TWO reagents?
KMnO4 - inexpensive, used for large scale reactions, variable yields
OsO4 - expensive, extremely toxic! good yields, is catalytic, used in small scale syntheses
This illustrates the principle that in general there will always be more than one reagent to accomplish any
transformation even if we only discuss one in this course
Examples
cold KMnO4/-OH/H2O
achiral
* *
OH
HO
H3C
CH3
C C
achiral
H
H
OsO4 / H2O2
H3C
H
C C
achiral
H
CH3
OsO4 / H2O2
H3C
*C
H
HO
solution not
optically active
meso compound
cis-diol
solution not
optically active
meso compound
CH3
C*
H OH
H
H3C
*C
H
HO
OH
()
H3C OH
HO
()
solution not
optically active
racemic mix.
Compare
1. MCPBA
trans-diol
H
2. H3
OsO4
H2O2
O+
cis-diol
H
OH
HO
OH
meso compound!
H
HO
() racemic mixture
4.4 Base Catalyzed Opening of Epoxides
Recall
Nu
Ethers/Epoxides
RNu
9
O-R
Poor leaving group
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Compare
Nu
better "leaving group",
release of ring strain
Nu
reaction works, driven by release of ring strain energy
only have an oxygen anion leaving group when you have high energy electrons in the Nucleophile/Lewis base
reactant, and in this case the strain energy of the epoxide helps a lot too
when NOT PROTONATED, strong nucleophiles attack epoxides at the least substituted carbon for steric
reasons, this is essentially an SN2 reaction and SN2 is fastest at the least substituted carbon
this is the OPPOSITE of what happens when the epoxide is protonated, when protonated the nucleophile
electron energy decreases more andf faster when it approaches the carbin with the larger partial positive charge,
so that charge effects "win" over the steric effect, but when the epoxide is NOT protonated, there are no charge
effects and the steric effect wins
a STRONG Lewis/Bronsted base is required to attack a non-protonated epoxide, but we have seen several of
these already
oxygen NOT
protonated!
O
HC
Me MgBr
HO
Nuc/LB attacks the LEAST
substituted carbon when the
oxygen is not protonated
These are STRONG Lewis bases/nucleophiles (actylide. Grignard, -OH, -OR etc.)
Hydrolysis example (recall, hydrolysis means breaking bonds using water, here, bonds in the epoxide ring)
WEAK LA/Elec.
OH
NaOH
H2O
OH
STRONG LB/nuc
O
H O
OH
HO
Example with different strong LB/nucleophile
Na OCH3
HOCH3
OCH3
(SN2)
backside attack
OCH3
CH3
OH
+
OCH3
OCH3
reaction is REGIOSPECIFIC
-OCH3 attached to the LEAST substituted carbon
the STRONG LB/nucleophile methoxide attacks the least substituted side for steric reasons (seen previously!)
RECALL: a different product (structural/REGIO isomer) is formed in the corresponding from acid catalyzed
reaction!
Ethers/Epoxides
10
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OH
CH3OH
reaction is REGIOSPECIFIC
-OCH3 attached to the
MOST substituted carbon
HCl (cat.)
H3CO
H
OH
O
H
H O CH
3
H3C
an abbreviated mechanism is shown here, you can solve problems using an ALGORITHMIC APPROACH,
where if you follow the correct algorithm (the mechanism in this context) you MUST get the correct answer
OR, you develop HEURISTIC PROBLEM solving skills that allow you to "jump" to the answer without writing out
the entire mechanism, this is much faster and the way that "real" chemists work out the products of reactions
the more problems you solve the better developed your heuristic problem solving becomes
4.5 Examples in Synthesis
Example
Br
()
+
Na OH
DMF
OH
1. BH3.THF
2. OH/H2O2
B
O
Br
O
NaH
best synthons from
bond B (not bond A)
Na
in this case the C-O bond that we are tempted to make to construct the ether (bond A) is not as good as bond B,
since to make bond A we would need to do an SN2 reaction on a secondary carbon atom
in ether synthesis you need to select the BEST C-O bond to make in an SN2 reaction
Example
OH
MCPBA
Na/NH3(l)
OH
O
()
1. Na+ C
2. H3O+
()
OH
CH3
()
H
OH
too difficult to
ensure transstereochemistry
can't make required C-C bond in last step, need to do a FGI that will allow the C-C bond to be made
convert (backwards) into an alkyne, NOW can make the C-C bond
Ethers/Epoxides
11
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Ethers/Epoxides
12
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5 Summary of Reactions (more)
Do NOT start studying by trying to memorize the reactions here!
Work as many problems as you can, with this list of reactions in front of you if necessary, so that you can get
through as many problems as you can without getting stuck on eth reagents/conditions, and so that you can learn
and practice solving reaction problems. Use this list AFTER you have worked all of the problems, and just before
an exam. By then you will have learned a lot of the reagents/conditions just by using them and you will only have
to memorize what you haven't learned yet. Then do the following:
Cover the entire page of reagents/conditions with a long vertical strip of paper, see if you can write down the
reagents/conditions for each reaction, check to see which you get correct, if COMPLETELY correct, circle Y, if
incorrect or even slightly incorrect, circle N. In this way you keep track of what you know and what you don't know.
Keep coming back to this list and so the same thing only for those reactions you circled N, until all are circled Y.
Knowing the reagents/conditions on this page is INSUFFICIENT to do well on an exam since you will ALSO need
to recognize how to use and solve reaction problems in different contexts, this page ONLY helps you to learn the
reagents/conditions that you have not YET learned by working problems.
Na+ H
OH
NaOH can NOT be used here
Na+ OH
OH
NaH could also be used here
Br
O
Na
(SN2)
Williamson ether synthesis
1. Hg(OAc)2 / CH3OH
2. NaBH4
MCPBA
1. MCPBA
2. H3O+
HBr / heat
O
O
CH3OH
H+ (cat.)
Y/N
Na
Y/N
Na
Y/N
()
Y/N
OCH3
O
Y/N
OH
Y/N
()
HO
Br + Br
Y/N
HO
Y/N
OCH3
must be an organic acid, HCl, TsOH etc.
OH
O
()
CH3OH
NaOCH3
Ph
Y/N
CH3O
Ph
OH
OsO4/H2O2
OH
cold KMnO4/-OH/H2O
Ph
Ethers/Epoxides
Ph
13
HO
OH
Ph
Ph
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